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Change a list separator delimiter to another (python)

I need help using Python.
Supposing I have the list [22,23,45].
Is it possible to get an output like this: [22;23:45] ?

It's possible to change the delimiters if you display your list as a string. You can then use the join method. The following example will display your list with ; as a delimiter:
print(";".join(my_list))
This will only work if your list's items are string, by the way.

Even if you have more than one item
str(your_list[:1][0])+";" + ":".join(map(str,your_list[1:])) #'22;23:45'
Not sure why you want to wrap in the list but if you do just wrap around the above string in list()

my list which was [22,23,45] returned [;2;2;,; ;2;3;,; ;4;5;,] for both methods.
To bring more information, I have a variable:
ID= [elements['id'] for elements in country]
Using a print (ID), I get [22,23,45] so I suppose that the list is already to this form.
Problem is: I need another delimiters because [22,23,45] corresponds to ['EU, UK', 'EU, Italy', 'USA, California'].
The output I wish is [22,23,45] --> ['EU, UK'; 'EU, Italy'; 'USA, California']
I don't know if it's clearer but hope it could help

Try this I don't know exactly what do You want?
first solution:
list = [22,23,45]
str = ""
for i in list:
str += "{}{}".format(i, ";")
new_list=str[:-len(";")]
print(new_list)
and this is second solution
list = [22,23,45]
print(list)
list=str(list)
list=list.split(",")
list=";".join(list)
print(list)

Convert String to Dictionary of Lists in Python

So in my python script I have the following dictionary, except it's listed in string form:
{'MSVCRT.dll': ['atoi'], 'KERNEL32.DLL': ['VirtualFree', 'ExitProcess', 'VirtualProtect', 'LoadLibraryA', 'VirtualAlloc', 'GetProcAddress'], 'SHLWAPI.dll': ['PathFileExistsA'], 'USER32.dll': ['wsprintfA']}
I however would like to have this code as a dictionary of lists, as it clearly is. I tried the following code in orderto attempt to convert the string:
try:
dictimports = ast.literal_eval(stris)
print(dictimports)
except:
print("dict convert failed")
However it hits the except everytime :(
So to reiterate, I would like the keys to be say 'KERNEL32.DLL', and then those keys to have the list as the contents of the values, so have a list with the values ['VirtualFree', 'ExitProcess', 'VirtualProtect', 'LoadLibraryA', 'VirtualAlloc', 'GetProcAddress'] in this instance.

stris = {'MSVCRT.dll': ['atoi'], 'KERNEL32.DLL': ['VirtualFree', 'ExitProcess', 'VirtualProtect', 'LoadLibraryA', 'VirtualAlloc', 'GetProcAddress'], 'SHLWAPI.dll': ['PathFileExistsA'], 'USER32.dll': ['wsprintfA']}
stris is a dictionary. what seems to be the problem?
type(stris)
dict
stris.keys()
dict_keys(['MSVCRT.dll', 'KERNEL32.DLL', 'SHLWAPI.dll', 'USER32.dll'])
if your stris is a string - in which case you'd have
stris = "{'MSVCRT.dll': ['atoi'], 'KERNEL32.DLL': ['VirtualFree', 'ExitProcess', 'VirtualProtect', 'LoadLibraryA', 'VirtualAlloc', 'GetProcAddress'], 'SHLWAPI.dll': ['PathFileExistsA'], 'USER32.dll': ['wsprintfA']}"
and you will convert it to a dict
ast.literal_eval(stris)
{'MSVCRT.dll': ['atoi'], 'KERNEL32.DLL': ['VirtualFree','ExitProcess','VirtualProtect','LoadLibraryA','VirtualAlloc',
'GetProcAddress'],'SHLWAPI.dll': ['PathFileExistsA'],'USER32.dll':['wsprintfA']}

You could use eval() to convert the string to a dict.
The expression argument is parsed and evaluated as a Python expression
eval(stris) will execute the executions given as string an in your case return the parsed dictionary.
But be aware of this: Using python's eval() vs. ast.literal_eval()?

Use variable or item in list as part of code (not as string or variable) or variable itself?

I have a list of string.
list=['cretd_dt','rcvd_dt']
The actual code is:
query = table.update().values(
cretd_dt = Join_All_Dates.iloc[index]['cretd_dt'],
rcvd_dt= Join_All_Dates.iloc[index]['rcvd_dt'])
I want the cretd_dt= and rcvd_dt= to be used from inside the list. That is if the list has a,b, then inside the query it must be .values( a=join[index]['a']) etc.
list=['a','b']
query = table.update().values(
a = Join_All_Dates.iloc[index]['a'],
b= Join_All_Dates.iloc[index]['b'])

Build a dict and unpack it as arguments to values():
# Don't shadow builtins such as list
the_list = ['a', 'b']
query = table.update().values(**{k: Join_All_Dates.iloc[index][k] for k in the_list})
though you don't need to unpack, since Update.values() accepts a dict as a positional argument directly as well.

TypeError: 'str' object does not support item assignment (Python)

So this is what I'm trying to do:
input: ABCDEFG
Desired output:
***DEFG
A***EFG
AB***FG
ABC***G
ABCD***
and this is the code I wrote:
def loop(input):
output = input
for index in range(0, len(input)-3): #column length
output[index:index +2] = '***'
output[:index] = input[:index]
output[index+4:] = input[index+4:]
print output + '\n'
But I get the error: TypeError: 'str' object does not support item assignment

You cannot modify the contents of a string, you can only create a new string with the changes. So instead of the function above you'd want something like this
def loop(input):
for index in range(0, len(input)-3): #column length
output = input[:index] + '***' + input[index+4:]
print output

Strings are immutable. You can not change the characters in a string, but have to create a new string. If you want to use item assignment, you can transform it into a list, manipulate the list, then join it back to a string.
def loop(s):
for index in range(0, len(s) - 2):
output = list(s) # create list from string
output[index:index+3] = list('***') # replace sublist
print(''.join(output)) # join list to string and print
Or, just create a new string from slices of the old string combined with '***':
output = s[:index] + "***" + s[index+3:] # create new string directly
print(output) # print string
Also note that there seemed to be a few off-by-one errors in your code, and you should not use input as a variable name, as it shadows the builtin function of the same name.

In Python, strings are immutable - once they're created they can't be changed. That means that unlike a list you cannot assign to an index to change the string.
string = "Hello World"
string[0] # => "H" - getting is OK
string[0] = "J" # !!! ERROR !!! Can't assign to the string
In your case, I would make output a list: output = list(input) and then turn it back into a string when you're finished: return "".join(output)

In python you can't assign values to specific indexes in a string array, you instead will probably want to you concatenation. Something like:
for index in range(0, len(input)-3):
output = input[:index]
output += "***"
output += input[index+4:]
You're going to want to watch the bounds though. Right now at the end of the loop index+4 will be too large and cause an error.

strings are immutable so don't support assignment like a list, you could use str.join concatenating slices of your string together creating a new string each iteration:
def loop(inp):
return "\n".join([inp[:i]+"***"+inp[i+3:] for i in range(len(inp)-2)])
inp[:i] will get the first slice which for the first iteration will be an empty string then moving another character across your string each iteration, the inp[i+3:] will get a slice starting from the current index i plus three indexes over also moving across the string one char at a time, you then just need to concat both slices to your *** string.
In [3]: print(loop("ABCDEFG"))
***DEFG
A***EFG
AB***FG
ABC***G
ABCD***

How to compare an element of a tuple (int) to determine if it exists in a list

I have the two following lists:
# List of tuples representing the index of resources and their unique properties
# Format of (ID,Name,Prefix)
resource_types=[('0','Group','0'),('1','User','1'),('2','Filter','2'),('3','Agent','3'),('4','Asset','4'),('5','Rule','5'),('6','KBase','6'),('7','Case','7'),('8','Note','8'),('9','Report','9'),('10','ArchivedReport',':'),('11','Scheduled Task',';'),('12','Profile','<'),('13','User Shared Accessible Group','='),('14','User Accessible Group','>'),('15','Database Table Schema','?'),('16','Unassigned Resources Group','#'),('17','File','A'),('18','Snapshot','B'),('19','Data Monitor','C'),('20','Viewer Configuration','D'),('21','Instrument','E'),('22','Dashboard','F'),('23','Destination','G'),('24','Active List','H'),('25','Virtual Root','I'),('26','Vulnerability','J'),('27','Search Group','K'),('28','Pattern','L'),('29','Zone','M'),('30','Asset Range','N'),('31','Asset Category','O'),('32','Partition','P'),('33','Active Channel','Q'),('34','Stage','R'),('35','Customer','S'),('36','Field','T'),('37','Field Set','U'),('38','Scanned Report','V'),('39','Location','W'),('40','Network','X'),('41','Focused Report','Y'),('42','Escalation Level','Z'),('43','Query','['),('44','Report Template ','\\'),('45','Session List',']'),('46','Trend','^'),('47','Package','_'),('48','RESERVED','`'),('49','PROJECT_TEMPLATE','a'),('50','Attachments','b'),('51','Query Viewer','c'),('52','Use Case','d'),('53','Integration Configuration','e'),('54','Integration Command f'),('55','Integration Target','g'),('56','Actor','h'),('57','Category Model','i'),('58','Permission','j')]
# This is a list of resource ID's that we do not want to reference directly, ever.
unwanted_resource_types=[0,1,3,10,11,12,13,14,15,16,18,20,21,23,25,27,28,32,35,38,41,47,48,49,50,57,58]
I'm attempting to compare the two in order to build a third list containing the 'Name' of each unique resource type that currently exists in unwanted_resource_types. e.g. The final result list should be:
result = ['Group','User','Agent','ArchivedReport','ScheduledTask','...','...']
I've tried the following that (I thought) should work:
result = []
for res in resource_types:
if res[0] in unwanted_resource_types:
result.append(res[1])
and when that failed to populate result I also tried:
result = []
for res in resource_types:
for type in unwanted_resource_types:
if res[0] == type:
result.append(res[1])
also to no avail. Is there something i'm missing? I believe this would be the right place to perform list comprehension, but that's still in my grey basket of understanding fully (The Python docs are a bit too succinct for me in this case).
I'm also open to completely rethinking this problem, but I do need to retain the list of tuples as it's used elsewhere in the script. Thank you for any assistance you may provide.

Your resource types are using strings, and your unwanted resources are using ints, so you'll need to do some conversion to make it work.
Try this:
result = []
for res in resource_types:
if int(res[0]) in unwanted_resource_types:
result.append(res[1])
or using a list comprehension:
result = [item[1] for item in resource_types if int(item[0]) in unwanted_resource_types]

The numbers in resource_types are numbers contained within strings, whereas the numbers in unwanted_resource_types are plain numbers, so your comparison is failing. This should work:
result = []
for res in resource_types:
if int( res[0] ) in unwanted_resource_types:
result.append(res[1])

The problem is that your triples contain strings and your unwanted resources contain numbers, change the data to
resource_types=[(0,'Group','0'), ...
or use int() to convert the strings to ints before comparison, and it should work. Your result can be computed with a list comprehension as in
result=[rt[1] for rt in resource_types if int(rt[0]) in unwanted_resource_types]
If you change ('0', ...) into (0, ... you can leave out the int() call.
Additionally, you may change the unwanted_resource_types variable into a set, like
unwanted_resource_types=set([0,1,3, ... ])
to improve speed (if speed is an issue, else it's unimportant).

The one-liner:
result = map(lambda x: dict(map(lambda a: (int(a[0]), a[1]), resource_types))[x], unwanted_resource_types)
without any explicit loop does the job.
Ok - you don't want to use this in production code - but it's fun. ;-)
Comment:
The inner dict(map(lambda a: (int(a[0]), a[1]), resource_types)) creates a dictionary from the input data:
{0: 'Group', 1: 'User', 2: 'Filter', 3: 'Agent', ...
The outer map chooses the names from the dictionary.