I have 1 question that I can't clicking on the button with javascript.
I use
driver.find_element(By.XPATH, "//li[#class='login']/a")
but it doesn't work at all.
it seems like javascripts.
Plz help me to clicking on the login button.
This might be more helpful if you can provide more of the source code or maybe a link to the site?
But from what I see. Did you actually click?
driver.find_element(By.XPATH, "//li[#class='login']/a").click()
You need to wait for the element to be clickable (remember to add proper imports), and here is a working code:
from selenium import webdriver
from webdriver_manager.chrome import ChromeDriverManager
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome(ChromeDriverManager().install())
driver.get("https://www.oliveyoung.co.kr")
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//li[#class='login']/a"))).click()
input()
driver.close()
Please check in the dev tools (Google chrome) if we have unique entry in HTML DOM or not.
xpath that you should check :
//li[#class='login']//a
Steps to check:
Press F12 in Chrome -> go to element section -> do a CTRL + F -> then paste the xpath and see, if your desired element is getting highlighted with 1/1 matching node.
If we have 1/1 matching node, Please make sure that :
This div is not under an iframe.
This div is not under a shadow-root.
You should not be on new tab/windows launched by selenium.
if it matches the desired element, then in Selenium there are 4 ways to click on it.
Code trial 1 :
time.sleep(5)
driver.find_element_by_xpath("//li[#class='login']//a").click()
Code trial 2 :
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//li[#class='login']//a"))).click()
Code trial 3 :
time.sleep(5)
button = driver.find_element_by_xpath("//li[#class='login']//a")
driver.execute_script("arguments[0].click();", button)
Code trial 4 :
time.sleep(5)
button = driver.find_element_by_xpath("//li[#class='login']//a")
ActionChains(driver).move_to_element(button).click().perform()
Imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains
Related
I'm using selenium 4 with python to automate webpage.
Click() method is not working.
Able to click a button using submit() method only if the path has type=submit, but couldnt able to select a link using click method. Please help if anyone knows alternative option for click() method to click a link.
The following is the code:
from selenium import webdriver
from selenium.webdriver.chrome.service import Service
from selenium.webdriver.common.by import By
s = Service("C:/Program Files/webdriver/Chrome Driver/chromedriver.exe")
driver = webdriver.Chrome(service=s)
driver.get("https://www.sololearn.com/users/login")
time.sleep(2)
#driver.find_element(By.CLASS_NAME, "sl-login-login-form").send_keys(Keys.ENTER)
#---click here fails--------
driver.find_element(By.CLASS_NAME, "sl-login-login-form").click()
#---click here fails
#driver.find_element(By.CLASS_NAME, "sl-login-login-form").submit()
#login.click()
time.sleep(5)
driver.quit()
**Also i have tried with the below code but still it is not working:**
driver.find_element(By.CLASS_NAME, "sl-login-login-form").send_keys(Keys.ENTER)
driver.find_element(By.CLASS_NAME, "sl-login-login-form").submit()
login.click()
Try the below
element = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CLASS_NAME, "CLASSNAME")))
element.click();
OR
element = driver.find_element(By.CLASS_NAME, "className")
driver.execute_script("arguments[0].click();", element)
Do not forget to import
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import org.openqa.selenium.JavascriptExecutor
Hi i'm new at selenium and webscraping and i need some help.
i try to scrape one site and i need and i dont know how to get span class.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import time
PATCH = "/Users/bobo/Downloads/chromedriver"
driver = webdriver.Chrome(PATCH)
driver.get("https://neonet.pl")
print(driver.title)
search = driver.find_element_by_class_name("inputCss-input__label-263")
search.send_keys(Keys.RETURN)
time.sleep(5)
i try to extract this span
<span class="inputCss-input__label-263">Szukaj produktu</span>
I can see that you are trying to search something in the search bar.
First I recommend you to use the xpath instead of the class name, here is a simple technique to get the xpath of every element on a webpage:
right-click/ inspect element/ select the mouse in a box element on the upper left/ click on the element on the webpage/ it will directly show you the corresponding html/ then right click on the selected html/ copy options and then xpath.
Here is a code example that searches an element on the webpage, I also included the 'Webdriver-wait' option because sometimes the code runs to fast and can't find the next element so this function make the code wait till the element is visible:
from selenium import webdriver
from selenium.webdriver.common.by import By
from time import sleep
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome(executable_path="/Users/bobo/Downloads/chromedriver")
driver.get("https://neonet.pl") #loading page
wait = WebDriverWait(driver, 20) #defining webdriver wait
search_word = 'iphone\n' # \n is going to act as an enter key
wait.until(EC.visibility_of_element_located((By.XPATH, '//*[#id="root"]/main/div[1]/div[4]/div/div/div[2]/div/button[1]'))).click() #clicking on cookies popup
wait.until(EC.visibility_of_element_located((By.XPATH, '//*[#id="root"]/main/header/div[2]/button'))).click() #clicking on search button
wait.until(EC.visibility_of_element_located((By.XPATH, '//*[#id="root"]/aside[2]/section/form/label/input'))).send_keys(search_word) #searching on input button
print('done!')
sleep(10)
Hope this helped you!
wait=WebDriverWait(driver,10)
driver.get('https://neonet.pl')
elem=wait.until(EC.visibility_of_element_located((By.XPATH, "//span[contains(#class,'inputCss-input')]"))).text
print(elem)
To output the value of the search bar you use .text on the Selenium Webelement.
Imports:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
I am trying to use selenium to click on an element with x-onclick property not onclick.
I am using this element's xPath to click on it. These are the methods I have tried:
driver.execute_script("arguments[0].click();", element)
element.click()
but these don't work. I would love if someone can tell me a solution.
When you tried this
driver.execute_script("arguments[0].click();", element)
element is a web element. I do not know if you have defined it or not. If not defined then you must have got compile time error.
Anyway this looks to me an angular based application. So I would try with below code trials :
There are 4 ways to click in Selenium.
I will use this xpath
//a[#id='generater' and #x-onclick]
Code trial 1 :
time.sleep(5)
driver.find_element_by_xpath("//a[#id='generater' and #x-onclick]").click()
Code trial 2 :
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//a[#id='generater' and #x-onclick]"))).click()
Code trial 3 :
time.sleep(5)
button = driver.find_element_by_xpath("//a[#id='generater' and #x-onclick]")
driver.execute_script("arguments[0].click();", button)
Code trial 4 :
time.sleep(5)
button = driver.find_element_by_xpath("//a[#id='generater' and #x-onclick]")
ActionChains(driver).move_to_element(button).click().perform()
Imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains
Have you tried to click by creating xpath by using tag 'a' and 'id' by using simple selenium webdriver click method.
ele = driver.find_element_by_xpath("//a[#id='generater']")
ele.click()
or
driver.find_element_by_xpath("//a[#id='generater']").click()
if above xpath is unique then it should work else use javascript for clicking on above element 'ele'.
I am trying to scrape some google data but I first want to click the 'I agree' button that google pops up. This is the script I use to do that:
import time
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
search_question = input("Ask a question: ")
driver = webdriver.Chrome("*Your Webdriver location*")
driver.wait = WebDriverWait(driver, 5)
driver.get("https://google.com")
time.sleep(1)
agree = driver.wait.until(EC.presence_of_element_located((By.XPATH, '//*[#id="introAgreeButton"]/span/span')))
agree.click()
# time.sleep(0.2)
search = driver.find_element_by_class_name("gLFyf")
search.send_keys(search_question)
search.send_keys(Keys.ENTER)
The problem is selenium doesn't seem to locate the button and therefore I get a timeout error. (I have tried also with find_element_by_xpath and still not working).
If you scroll up in the devtools inspector you'll notice that your element is within an iframe:
You need to switch to that frame first, click your button then switch back to the default content (the main page)
driver.get("https://google.com")
#active the iframe and click the agree button
WebDriverWait(driver, 10).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH, "//iframe")))
agree = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, '//*[#id="introAgreeButton"]/span/span')))
agree.click()
#back to the main page
driver.switch_to_default_content()
That works for me.
FYI - There's only 1 iframe on the page, that's why the xpath //iframe works. If there were multiple you'd need to identify it with higher accuracy.
If you already have been agreed,then agree button would not appear. That why it is not be able to find given XPath.
Try this:
import time
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
search_question = input("Ask a question: ")
driver = webdriver.Chrome(".\chromedriver.exe")
driver.wait = WebDriverWait(driver, 5)
driver.get("https://google.com")
time.sleep(3)
# agree = driver.wait.until(EC.presence_of_element_located((By.XPATH, '//*[#id="introAgreeButton"]/span/span')))
# agree.click()
# time.sleep(0.2)
search = driver.find_element_by_class_name("gLFyf")
search.send_keys(search_question)
search.send_keys(Keys.ENTER)
Managed to get it working.
Seems like one of the few elements that are interactive in the popup when you first load the site is the language dropdown, which I found by class name.
Then the Agree button is detectable and you can find it by class too.
driver.get("https://www.google.com")
driver.maximize_window()
time.sleep(2)
#finds+clicks language dropdown, interaction unhides the rest of the popup html
driver.find_element_by_class_name('tHlp8d').click()
time.sleep(2)
#finds+clicks the agree button now that it has become visible
driver.find_element_by_id('L2AGLb').click()
you should now have the standard searchbar etc
i had some problems with clicking pop-ups and the problem turned out to be with that click().
im not sure that it might be the same issue with urs or not but try changing ur click to this :
agree = driver.find_element_by_xpath('//*[#id="introAgreeButton"]/span/span')
driver.execute_script("arguments[0].click();", agree)
The problem was that it didn't change frames here is the soulution code:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome('C:\\Users\\gassp\\OneDrive\\Namizje\\Python.projects\\chromedriver.exe')
url = 'https://www.google.com/maps/'
driver.get(url)
WebDriverWait(driver, 10).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH, '//*[#id="consent-bump"]/div/div[1]/iframe')))
agree = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, '//*[#id="introAgreeButton"]/span/span')))
agree.click()
#back to the main page
driver.switch_to_default_content()
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, '//*[#id="searchboxinput"]'))).send_keys('gostilne')
driver.submit()
I've created a script in python using selenium to click on a like button available in a webpage. I've used xpath in order to locate that button and I think I've used it correctly. However, the script doesn't seem to find that button and as a results it throws TimeoutException error pointing at the very line containing the xpath.
As it is not possible to hit that like button without logging in, I expect the script to get the relevant html connected to that button so that I understand I could locate it correctly.
I've tried with:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
link = "https://www.instagram.com/p/CBi_eIuAwbG/"
with webdriver.Chrome() as driver:
wait = WebDriverWait(driver,10)
driver.get(link)
item = wait.until(EC.visibility_of_element_located((By.XPATH,"//button[./svg[#aria-label='Like']]")))
print(item.get_attribute("innerHTML"))
How can I locate that like button visible as heart symbol using selenium?
To click on Like Button induce WebDriverWait() and wait for visibility_of_element_located() and below xpath.
Then scroll the element into view and click.
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
driver.get("https://www.instagram.com/p/CBi_eIuAwbG/")
element=WebDriverWait(driver,10).until(EC.visibility_of_element_located((By.XPATH,"//button[.//*[name()='svg' and #aria-label='Like']]")))
element.location_once_scrolled_into_view
element.click()
You can do it like this
likeSVG = driver.find_element(By.CSS_SELECTOR, 'svg[aria-label="Like"]')
likeBtn = likeSVG.find_element(By.XPATH, './..')
likeBtn.click()
likeBtn is equal to the parent of the likeSVG div as you can use XPATH similar to file navigation commands in a CLI.
Try using the .find_element_by_xpath(xPath) method (Uses full xpath):
likeXPATH = "/html/body/div[1]/section/main/div/div[1]/article/div[2]/section[1]/span[1]/button"
likeElement = driver.find_element_by_xpath(likeXPATH)
likeElement.click()