How to append a global list from inside a function - python

What is the best way to append and clear the list deriv_position = [] from inside the function test?
I got NameError: name 'deriv_position' is not defined
class TestClass:
deriv_position = []
def test():
if len(deriv_position) > 0:
print("trade is open")
deriv_position.clear()
else:
print("trade is close")
deriv_position.append("1")
test()

In python, you refer to class variables using the self keyword. So inside the function, you can pass in self and then use it...
class TestClass:
def __init__(self):
self.deriv_position = []
def test(self):
if len(self.deriv_position) > 0:
print("trade is open")
self.deriv_position.clear()
else:
print("trade is close")
self.deriv_position.append("1")
TestClass().test()
You may find it worthwhile to read up on how classes work in Python:
https://docs.python.org/3/tutorial/classes.html#a-first-look-at-classes
Alternatively, if you are not using the class as a class (in your example, you are not), then there is no need for it. Just declare a global variable at the top of the file, and the test function just a function in the file.

Related

What does self.function in __init__ do to a function?

I have recently tried to get into OOP to take a step into more advanced python. I wanted to do a list of functions in a class. I started by not using self.functionName = functionName, this led to an error where the functions could not be identified in the list. So I assumed that what you write in the __init__ function works as global function in the class, so I added self to the first two functions so that they could be used in the other function, and it worked fine. However when I added self to the last functions I did not get the same answer, why is that?
This is the code that I wrote:
>>> class number: #works fine, no self.ans
def __init__(self):
self.numOne = numOne
self.numTwo = numTwo
def numOne(self):
print("one")
def numTwo(self):
print("two")
def ans(self):
bruh = [numOne, numTwo]
for i in bruh:
i()
>>> a = number()
>>> a.ans()
one
two
>>> class number: #now when I write self.ans
def __init__(self):
self.numOne = numOne
self.numTwo = numTwo
self.ans = ans
def numOne(self):
print("one")
def numTwo(self):
print("two")
def ans(self):
bruh = [numOne, numTwo]
for i in bruh:
i()
>>> a = number()
>>> a.ans()
<generator object ans.<locals>.<genexpr> at 0x0000021476FDBF90> #this is the result
>>>
You don't need to assign the methods to the instance in the constructor. That's part of how classes work already.
This works correctly:
class Number:
def num_one(self):
print("one")
def num_two(self):
print("two")
def ans(self):
bruh = [self.num_one, self.num_two]
for i in bruh:
i()
n = Number()
n.ans()
Result:
one
two
Of course, you can still have an __init__ if you need to set some initial values, but a class doesn't require a custom constructor. Just by declaring it as a class, it will have a constructor that you can override as needed.
By the way, you would do well to name your classes with names starting with a capital letter. Naming the methods with camel-case is more of a taste-thing, but I feel the underscore is more pythonic - the capital is definitely something to use however, to avoid people confusing objects and classes.

Globals lost when function calls itself

I need to add a variable "a" to global variables at runtime and be able to recover it anytime from the Item class. Result: I can't see it in the global variables.
Below there is an example. When I print the globals() I don't find the new "a" variable.
Specifically I need to be able to save the printVal result in a variable called "a", which I can consult in next call to this function.
In my final program I plan to add as many different variables as I want (variable and value).
Example:
class Item():
def printVal(self,value):
return value
def func(self):
userInput = input("Input string:")
if userInput!="0":
exec("a=self.printVal(\""+userInput+"\")",globals(),locals())
else:
return
print(globals())
self.func()
if __name__ == "__main__":
item = Item()
item.func()
If you jus watn to set a global variable with a name generated at runtime you do:
globals()[name] = val
by the way printVal method is dummy. Just return whtat it gets.

How to define a callable that can only be called once?

To demonstrate what I want to do, here's a piece of code:
class CallOnce(object):
called=False
def web_service(cls,macid):
if cls.called:
print ("already called")
return
else:
# do stuff
print ("called once")
cls.called = True
return macid
To test our class, I proceed as follows:
for i in range(2):
macid = "123"
call_once_object = CallOnce()
call = call_once_object.web_service(macid)
print(call)
The expected result should be like this:
called once
123
already called
Except I got this as a result:
called once
123
called once
123
The idea is to store the value 123 only once in the call variable without using global variable.
cls.called is an attribute of the instance, not the class. Each time you create a new object, it gets its own attribute, which defaults to False.
If you want to share this among all the instances, you should use CallOnce.called, not cls.called.
BTW, the conventional name for the first argument of instance methods is self. cls is used for class methods.
So you're trying to save some state. What you could do is use an object instead.
class Test():
def __init__(self):
self.called = False
def call_me_maybe(self):
if (not self.called):
print('Hey, you called?')
self.called = True
else:
print("Stop calling me it's getting weird")
test = Test()
test.call_me_maybe() #-> Hey, you called?
test.call_me_maybe() #-> Stop calling me it's getting weird
You don't need a class for this. Functions can have their own attributes.
def web_service(macid):
if hasattr(web_service, 'called'):
print ("already called")
return
else:
# do stuff
print ("called once")
web_service.called = True
return macid
web_service(5)
web_service(6)
Output:
called once
already called

invoking a class method inside the class itself

Hi everyone i wanna use a calculated value from a method of the class itself for the rest of the class methods but it must calculate once for all and i need to invoke method inside the class itself i write an example:
class something():
def __init__():
pass
def __sum(self, variable_1, variable_2):
self.summation = sum(variable_1, variable_2)
# I need to calculate summation here once for all:
# how does the syntax look likes, which one of these are correct:
something.__sum(1, 2)
self.__sum(1, 2)
# If none of these are correct so what the correct form is?
# For example print calculated value here in this method:
def do_something_with_summation(self):
print(self.summation)
Something like this seems to be what you're looking for:
class Something:
def __init__(self):
self.__sum(1, 2)
def __sum(self, variable_1, variable_2):
self.summation = sum(variable_1, variable_2)
Not saying this is the ideal approach or anything, but you haven't really given us much to go off of.
In general, make sure self is the first argument in all class methods, and you can call that class method at any time using either self.method_name() if you are using it from within another class method or instance.method_name() if you're using it externally (where instance = Something()).
Assuming that you would receive variable1 and variable2 when you instantiate the class one solution could be:
class something():
def __init__(self, variable1, variable2):
self.summation = variable1 + variable2
def do_something_with_summation(self):
print(self.summation)
If instead you're creating variable1 and variable2 inside other methods, then you could make them class variables:
class Something():
def __init__(self):
#Put some initialization code here
def some_other_method(self):
self.variable1 = something
self.variable2 = something
def sum(self):
try:
self.summation = self.variable1 + self.variable2
except:
#Catch your exception here, for example in case some_other_method was not called yet
def do_something_with_summation(self):
print(self.summation)

Getting an instance name inside class __init__() [duplicate]

This question already has answers here:
Getting the name of a variable as a string
(32 answers)
Closed 3 years ago.
While building a new class object in python, I want to be able to create a default value based on the instance name of the class without passing in an extra argument. How can I accomplish this? Here's the basic pseudo-code I'm trying for:
class SomeObject():
defined_name = u""
def __init__(self, def_name=None):
if def_name == None:
def_name = u"%s" % (<INSTANCE NAME>)
self.defined_name = def_name
ThisObject = SomeObject()
print ThisObject.defined_name # Should print "ThisObject"
Well, there is almost a way to do it:
#!/usr/bin/env python
import traceback
class SomeObject():
def __init__(self, def_name=None):
if def_name == None:
(filename,line_number,function_name,text)=traceback.extract_stack()[-2]
def_name = text[:text.find('=')].strip()
self.defined_name = def_name
ThisObject = SomeObject()
print ThisObject.defined_name
# ThisObject
The traceback module allows you to peek at the code used to call SomeObject().
With a little string wrangling, text[:text.find('=')].strip() you can
guess what the def_name should be.
However, this hack is brittle. For example, this doesn't work so well:
ThisObject,ThatObject = SomeObject(),SomeObject()
print ThisObject.defined_name
# ThisObject,ThatObject
print ThatObject.defined_name
# ThisObject,ThatObject
So if you were to use this hack, you have to bear in mind that you must call SomeObject()
using simple python statement:
ThisObject = SomeObject()
By the way, as a further example of using traceback, if you define
def pv(var):
# stack is a list of 4-tuples: (filename, line number, function name, text)
# see http://docs.python.org/library/traceback.html#module-traceback
#
(filename,line_number,function_name,text)=traceback.extract_stack()[-2]
# ('x_traceback.py', 18, 'f', 'print_var(y)')
print('%s: %s'%(text[text.find('(')+1:-1],var))
then you can call
x=3.14
pv(x)
# x: 3.14
to print both the variable name and its value.
Instances don't have names. By the time the global name ThisObject gets bound to the instance created by evaluating the SomeObject constructor, the constructor has finished running.
If you want an object to have a name, just pass the name along in the constructor.
def __init__(self, name):
self.name = name
You can create a method inside your class that check all variables in the current frame and use hash() to look for the self variable.
The solution proposed here will return all the variables pointing to the instance object.
In the class below, isinstance() is used to avoid problems when applying hash(), since some objects like a numpy.array or a list, for example, are unhashable.
import inspect
class A(object):
def get_my_name(self):
ans = []
frame = inspect.currentframe().f_back
tmp = dict(frame.f_globals.items() + frame.f_locals.items())
for k, var in tmp.items():
if isinstance(var, self.__class__):
if hash(self) == hash(var):
ans.append(k)
return ans
The following test has been done:
def test():
a = A()
b = a
c = b
print c.get_my_name()
The result is:
test()
#['a', 'c', 'b']
This cannot work, just imagine this: a = b = TheMagicObjet(). Names have no effect on Values, they just point to them.
One horrible, horrible way to accomplish this is to reverse the responsibilities:
class SomeObject():
def __init__(self, def_name):
self.defined_name = def_name
globals()[def_name] = self
SomeObject("ThisObject")
print ThisObject.defined_name
If you wanted to support something other than global scope, you'd have to do something even more awful.
In Python, all data is stored in objects. Additionally, a name can be bound with an object, after which that name can be used to look up that object.
It makes no difference to the object what names, if any, it might be bound to. It might be bound to dozens of different names, or none. Also, Python does not have any "back links" that point from an object to a name.
Consider this example:
foo = 1
bar = foo
baz = foo
Now, suppose you have the integer object with value 1, and you want to work backwards and find its name. What would you print? Three different names have that object bound to them, and all are equally valid.
print(bar is foo) # prints True
print(baz is foo) # prints True
In Python, a name is a way to access an object, so there is no way to work with names directly. You could search through various name spaces until you find a name that is bound with the object of interest, but I don't recommend this.
How do I get the string representation of a variable in python?
There is a famous presentation called "Code Like a Pythonista" that summarizes this situation as "Other languages have 'variables'" and "Python has 'names'"
http://python.net/~goodger/projects/pycon/2007/idiomatic/handout.html#other-languages-have-variables
If you want an unique instance name for a class, try __repr__() or id(self)
class Some:
def __init__(self):
print(self.__repr__()) # = hex(id(self))
print(id(self))
It will print the memory address of the instance, which is unique.
Inspired by the answers of unutbu and Saullo Castro, I have created a more sophisticated class that can even be subclassed. It solves what was asked for in the question.
"create a default value based on the instance name of the class
without passing in an extra argument."
Here's what it does, when an instance of this class or a subclass is created:
Go up in the frame stack until the first frame which does not belong to a method of the current instance.
Inspect this frame to get the attributes self.creation_(name/file/module/function/line/text).
Perform an an additional check whether an object with name self.creation_name was actually defined in the frame's locals() namespace to make 100% sure the found creation_name is correct or raise an error otherwise.
The Code:
import traceback, threading, time
class InstanceCreationError(Exception):
pass
class RememberInstanceCreationInfo:
def __init__(self):
for frame, line in traceback.walk_stack(None):
varnames = frame.f_code.co_varnames
if varnames is ():
break
if frame.f_locals[varnames[0]] not in (self, self.__class__):
break
# if the frame is inside a method of this instance,
# the first argument usually contains either the instance or
# its class
# we want to find the first frame, where this is not the case
else:
raise InstanceCreationError("No suitable outer frame found.")
self._outer_frame = frame
self.creation_module = frame.f_globals["__name__"]
self.creation_file, self.creation_line, self.creation_function, \
self.creation_text = \
traceback.extract_stack(frame, 1)[0]
self.creation_name = self.creation_text.split("=")[0].strip()
super().__init__()
threading.Thread(target=self._check_existence_after_creation).start()
def _check_existence_after_creation(self):
while self._outer_frame.f_lineno == self.creation_line:
time.sleep(0.01)
# this is executed as soon as the line number changes
# now we can be sure the instance was actually created
error = InstanceCreationError(
"\nCreation name not found in creation frame.\ncreation_file: "
"%s \ncreation_line: %s \ncreation_text: %s\ncreation_name ("
"might be wrong): %s" % (
self.creation_file, self.creation_line, self.creation_text,
self.creation_name))
nameparts = self.creation_name.split(".")
try:
var = self._outer_frame.f_locals[nameparts[0]]
except KeyError:
raise error
finally:
del self._outer_frame
# make sure we have no permament inter frame reference
# which could hinder garbage collection
try:
for name in nameparts[1:]: var = getattr(var, name)
except AttributeError:
raise error
if var is not self: raise error
def __repr__(self):
return super().__repr__()[
:-1] + " with creation_name '%s'>" % self.creation_name
A simple example:
class MySubclass(RememberInstanceCreationInfo):
def __init__(self):
super().__init__()
def print_creation_info(self):
print(self.creation_name, self.creation_module, self.creation_function,
self.creation_line, self.creation_text, sep=", ")
instance = MySubclass()
instance.print_creation_info()
#out: instance, __main__, <module>, 68, instance = MySubclass()
If the creation name cannot be determined properly an error is raised:
variable, another_instance = 2, MySubclass()
# InstanceCreationError:
# Creation name not found in creation frame.
# creation_file: /.../myfile.py
# creation_line: 71
# creation_text: variable, another_instance = 2, MySubclass()
# creation_name (might be wrong): variable, another_instance
I think that names matters if they are the pointers to any object..
no matters if:
foo = 1
bar = foo
I know that foo points to 1 and bar points to the same value 1 into the same memory space.
but supose that I want to create a class with a function that adds a object to it.
Class Bag(object):
def __init__(self):
some code here...
def addItem(self,item):
self.__dict__[somewaytogetItemName] = item
So, when I instantiate the class bag like below:
newObj1 = Bag()
newObj2 = Bag()
newObj1.addItem(newObj2)I can do this to get an attribute of newObj1:
newObj1.newObj2
The best way is really to pass the name to the constructor as in the chosen answer. However, if you REALLY want to avoid asking the user to pass the name to the constructor, you can do the following hack:
If you are creating the instance with 'ThisObject = SomeObject()' from the command line, you can get the object name from the command string in command history:
import readline
import re
class SomeObject():
def __init__(self):
cmd = readline.get_history_item(readline.get_current_history_length())
self.name = re.split('=| ',cmd)[0]
If you are creating the instance using 'exec' command, you can handle this with:
if cmd[0:4] == 'exec': self.name = re.split('\'|=| ',cmd)[1] # if command performed using 'exec'
else: self.name = re.split('=| ',cmd)[0]

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