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namelist() method not listing directories in python

I want to extract all the folder names from the zip file so that I can extract them separately. My login is working with one zip and but it is not working with another zip with strcuture.
root_dir = r'C:/Workspace/Neo4j/FileStore/RDAR/data.zip'
archive = ZipFile(root_dir, "r")
folder_paths = []
for file in archive.namelist():
print(file)
if file.endswith("/"):
folder_paths.append(file)
The above code is working with data10.zip but it is not listing directories in data.zip
folder strcuture of data.zip which is not working
folder structure of data10.zip
I am able extract list of folder in data10.zip as shown above, but cannot in data.zip
Any clue what might be the reason ?
Thanks
I am trying to list the directories from zip, although my code is working for one zip and is not working for another with same structure.

Python, Inconsistent zip file extraction

I am trying to extract zip files using the zipfile module's extractall method.
My code snippet is
import zipfile
file_path = '/something/airway.zip'
dir_path = 'something/'
with zipfile.ZipFile(file_path, "r") as zip_ref:
zip_ref.extractall(dir_path)
I have two zip files named, test (1.1 mb) and airway (520 mb).
For test.zip the folder contains all the files but for airway.zip, it creates another folder inside my target folder named Airway, and then extracts all the files there. Even after renaming the airway.zip to any garbage name, the result was same.
Is there some workaround to get only the files extracted in my target folder? It is critical for me as I'm doing this extraction automated from django
Python version: 3.9.6;
Django version: 2.2

I ran your code and it seems to be only a problem of the zipfile itself. If you create a zipfile by selecting only the elements you get the result you got with test.zip. If you create it by selecting a folder holding the elements the folder will be there if you extract it again, no matter what you name your zip file.

I have two articles related to this:
https://www.kite.com/python/docs/zipfile.ZipFile.extractall
https://www.geeksforgeeks.org/working-zip-files-python/
Even if both of these articles do not solve your problem then I think that instead of zipping the files in the folder you just zipped the folder itself so try by zipping the files inside the folder.

Copy file, rename it, iterate and repeat

I use os.renmae to rename files and move them about, but i am failing at doing the following task.
I have a main folder containing sub-folders with the structure below.
Main folder "Back", containing sub-folders named with letters and numbers e.g. A01, A02, B01, B02, etc.. inside each of those folders is a set of files, amongst them is a file called "rad" so a file path example looks something like this:
Back/A01/rad
/A02/rad
/B01/rad
.../rad
I have another sub-folder called "rads" inside the main "Back"
Back/rads
What i want to do is copy all the rad files only, from each of the folders in back and move them to the folder "rads" and name each rad file based on the folder it came from.
e.g. rad_A01, rad_A02, rad_B01, etc...
I couldnt really figure out how to increase the folder number when i move the files.
os.rename ("Back//rad, Back/rads/rad_")
I thought of making a list of all the names of the files and then do something like from x in list, do os.rename (), but i didnt know how to tell python to name the file according to the subfolder it came from as they are not a continuous series..
Any help is appreciated.
Thanks in advance

import os
for subdir, dirs, files in os.walk('./Back/'):
for file in files:
filepath = subdir+os.sep+file
if filepath.endswith("rad.txt"):
par_dir = os.path.split(os.path.dirname(filepath))[1]
os.system('cp '+filepath+' ./Back/rads/rad_'+par_dir)
save this python file beside Back directory and it should work fine!
This code iterates over each files in each subdirectory of Back, checks all files with name rad.txt, appends name of parent directory and copy to the rads folder.
Note: I saved rad files with .txt extension, change it accordingly.

Python name of latest folder created in a directory

I am new to python and have to play with directories.
Can someone help me with it?
I have to know a path with newly created folder. A new temp folder is generated by my code in which some files are copied. I have to know the path of this folder , but folder name is random , so I want to fetch the folder name of latest created folder.
What shall i do?

You can do something like this:
import os
directory = '.' # current dir
folders = os.walk(directory).next()[1]
creation_times = [(folder, os.path.getctime(folder)) for folder in folders]
creation_times.sort(key=lambda x: x[1]) # sort by creation time
Then you can pick the last element of this list:
most_recent = creation_times[-1][0]

Its a bad practice to fetch the latest folder created because some other application may create a folder right before you fetch the latest folder, but if you really want to try it out the code what elyase has demonstrated is fine.

How to make function "make_archive" to include the parent directory in python

I am using shutil.make_archive function to make archive
But it only archive the contents of directory.
i have the folder to backup like root_dir = /home/john/public_html
I use that then my archive contains the contents of public_html but i want to include public_html itself in archive.
Now in my john folder i have many other folders as well that i don't want to backup so i can't use /home/john

You want to pass the base_dir argument, as mentioned in the docs:
shutil.make_archive('public_html_backup', 'zip', '/home/john', '/home/john/public_html')