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Get Xpath from already known element

Friends, I'm doing a web scraping. I'm looking for an element that has the XPath changed every time it's searched. For that I'm looking for a way to get the correct xpath.
For this I will need to get the Xpath of an element that I can already locate, it is not the element that I need to locate. But with his Xpath I can find the Xpath of the desired element. so i'm searching:
element = self.chrome.find_element_by_xpath("//div[text()='Apelação']")
With that I need to get your XPath which is:
//*[#id="consultarProcessoForm:dtProcessos_data"]/tr[2]/td[4]/div
How can I do this?
I tried using this; but it returned nothing
print(element.get_attribute("id"))
This is the code of the page:
enter image description here

Find element in selenium based on attribute/value in div class

I'm using selenium in Python to try and scrape multiple pages. ID's and XPATH's keep changing per page, so I figured I'd best access them through their attribute-value combinations (see below).
I'm trying to access the text in the following element:
https://i.stack.imgur.com/ly1YU.png
which belongs to the following:
https://i.stack.imgur.com/strep.png
As I said, the ID's keep changing, so I wanted to access the element by data-fragment-name="articleDetail", or data-testid = "article-body". Can somebody help me how to do so?
Thanks in advance!

Try using the following CSS_SELECTOR
div[data-fragment-name='articleDetail'] div[data-testid='article-body']
Or XPath
//div[#data-fragment-name='articleDetail']//div[#data-testid='article-body']
The Selenium command can look like:
driver.find_element(By.CSS_SELECTOR, "div[data-fragment-name='articleDetail'] div[data-testid='article-body']")
Or
driver.find_element(By.XPATH, "//div[#data-fragment-name='articleDetail']//div[#data-testid='article-body']")

from selenium.webdriver.common.by import By
obj = driver.find_element(By.XPATH, "//div[#data-fragment-name='articleDetail']")
obj2 = driver.find_element(By.XPATH, "//div[#data-testid='article-body']")
where of course driver = webdriver.Firefox() or something like that and you already moved to the desired page.

Get XPath of element in Selenium [duplicate]

This question already has an answer here:
find element with xpath selenium
(1 answer)
Closed last year.
Suppose I get a list of elements on a webpage by class name, like so:
driver.find_elements_by_class_name("something")
How can I get the XPath of each element in that list?
Note: I am not trying to find elements using XPaths. I already have the elements from the code above. I just want the XPath of each of those elements I have already found.

driver.find_element_by_* and driver.find_elements_by_* are deprecated.
Best way to use it is as #undetected-selenium wrote.
First import By class
from selenium.webdriver.common.by import By
You can then use it with multiple location strategies.
XPath
driver.find_elements(By.XPATH, "//*[#attribute='something']")
CSS Selector
driver.find_elements(By.CSS_SELECTOR, "[attribute~=”value”]")
You should use this ones from now on since it's very common to get an error with the latest webdrivers saying find_element_by_* commands are deprecated

WebElement identified through classname as something can also be identified using the following Locator Strategies:
xpath:
driver.find_elements(By.XPATH, "//*[#class='something']")
css-selector:
driver.find_elements(By.CSS_SELECTOR, ".something")
Note: You have to add the following imports :
from selenium.webdriver.common.by import By

You can install XPath Finder extension for your browser and automatically generate the unique XPath for each element.
After that you can use the Function :
driver.find_element_by_xpath("XPath string") .

Click on li element searching specific displayed text

Using python 3 and chrome driver. I'm trying to click on my desired element searching for the text displayed on this page . For example, in case of "BEBES" I'm using:
WebDriverWait(browser, 10).until(EC.element_to_be_clickable((By.XPATH,'//*[contains(text(), "BEBES")]'))).click()
but nothing happens. Just throws the time out exception. What's my error?

Your xPath is not correct. Use this:
WebDriverWait(browser, 10).until(EC.element_to_be_clickable((By.XPATH,'//span[contains(text(), "Bebes")]'))).click()
Note: upper/lowercase makes difference
and

This post suggests using the following as text() returns a node set:
//*[text()[contains(.,'BEBES')]]
XPath contains(text(),'some string') doesn't work when used with node with more than one Text subnode

Selenium click on XPath button

I have the following code when I inspect on Chrome.
<span id="button-1111-btnInnerEl" class="x-btn-inner x-btn-inner-center" unselectable="on" style="">New Email</span>
I need to click on the label "New Email", but how should invoke it in Selenium (I'm using Python).
def CreateMail():
EmailButton="//*[contains(text(),'New Email')]"
driver.find_elements_by_xpath(EmailButton) // there is no method to enable click.

You can use execute_script
driver.execute_script("document.getElementById('button-1111-btnInnerEl').click()")

driver.find_element_by_id("button-1111-btnInnerEl").click()

Thanks all for your help. Finally i found the answer to my question.I had to add a wait statement, before finding the key. key wasn't present when the page loads, so had to wait a little bit to find the correct key.
def CreateMail():
try:
element = WebDriverWait(driver,10).until(EC.presence_of_element_located((By.ID, "button-1143-btnInnerEl")))
driver.find_element_by_id("button-1143-btnInnerEl").click()
except TimeoutException:
print ("Loading took too much time!")

Hope This XPath will work for you.If you want to validate xpath using your chrome browser just paste this text on your chrome console $x("//*[text()='New Email']") and check how many elements found using this XPath
driver.find_elements_by_xpath("//span[text()='New Email']")

Your statement : "driver.find_elements_by_xpath(EmailButton)" . Click does not work on group of elements. It is actionable only on single element. So you use a singular finder.
driver.find_**element**_by_id(EmailButton).click()

As per the HTML you have shared, the id attribute looks dynamic to me. So we must construct a dynamic xpath or css. Additionally instead of find_elements we have to use find_element so a single WebElement is returned and we can invoke the click() method. Finally, if you look at the node properly, the unselectable attribute is on so we will take help of JavascriptExecutor as follows :
myElement = driver.find_element_by_xpath("//span[starts-with(#id, 'button-')][#class='x-btn-inner x-btn-inner-center']")
driver.execute_script("arguments[0].click();", myElement);

Actually there is different way for locating elements
but in your case there is a ID,
so you can prefer id if its exists
find solution below :
driver.find_element_by_id("button-1111-btnInnerEl").click()