I have a Dictionary :
Dict1= {“AAT”: 2, “CCG”: 1, “ATA”: 5, “GCG”: 7, “CGC”: 2, “TAG”: 1, “GAT”: 0, “AAT”: 3, “CCG”: 2, “ATG”: 5, “GCG”: 3, “CGC”: 7, “TAG”: 0, “GAT”: 0}
And I have to sum all the similar triplet codes in a new dictionary.
Output should be like this:
Dict2 = {“AAT”: 5, “CCG”: 3, “ATA”: 5, “GCG”: 10, “CGC”: 9, “TAG”: 1, “GAT”: 0}
How do I proceed with the code?
Dict1 is not a valid dictionary as dictionary keys have to be unique. In general if you have some (non-unique) strings and values assigned to them, you can write
if key in Dict2:
Dict2[key] += val
else
Dict2[key] = val
You are trying to sum up the values of same keys which not possible since python doesn't allow duplicate keys in dictionary. You can check this for reference:
https://www.w3schools.com/python/python_dictionaries.asp
Related
Reading about data structures and have a question.
This is a dictionary:
example = {'the': 8,
'metal': 8,
'is': 23,
'worth': 3,
'many': 3,
'dollars': 2,
'right': 2}
How to store to a variable the value of a key/value pair by order?
For example, how to store the value of the third pair, which is 23?
Tried this, which is not correct:
for k in example:
if k == 3:
a_var = example(k)
If you know the key/values have been inserted in the correct order, you can use islice() to get the third key/value pair. This has the benefit of not needing to create a whole list of values and is a bit simpler than explicitly writing a loop:
from itertools import islice
example = {
'the': 8,
'metal': 8,
'is': 23,
'worth': 3,
'many': 3,
'dollars': 2,
'right': 2
}
key, val = next(islice(example.items(), 2, None))
# 'is', 23
If you only want the value instead of the key/value pair, then of course you can pass values() instead of items() to islice():
val = next(islice(example.values(), 2, None))
# 23
This does what you need:
example = {'the': 8,
'metal': 8,
'is': 23,
'worth': 3,
'many': 3,
'dollars': 2,
'right': 2}
k=0
for key in example:
k+=1
if k == 3:
a_var = example[key]
print(a_var)
Output:
23
If you really think you need this:
def find( example, ordinal):
for k,value in enumerate(example.values()):
if k == ordinal:
return value
or
def find( example, ordinal):
return list(example.values())[ordinal]
a_var=example[list(example.keys())[3-1]]
I want to be able to index a dictionary and replace its values for particular keys by using keys from within a specific list and writing values to those keys from that list.
Code
dicty = {"NDS" : 1, "TCT": 2, "ET" : 3, "ACC" : 4,"Ydist" : 5, "Diam" : 6}
tem = ["NDS", "TCT"]
circ = ["ET", "ACC"]
jit = ["Ydist", "Diam"]
def cal_loop(cal_vers):
if cal_vers == temp_calibration:
print("DO TEMP CALIBRATION")
tem_results = [19,30]
dict_keys = tem
dicty[[dict_keys][0]] = tem_results[0]
print(dicty["NDS"])
temp_calibration = 6
cal_loop(temp_calibration)
print(dicty)
Traceback
Desired output
{'NDS': 19, 'TCT': 2, 'ET': 3, 'ACC': 4, 'Ydist': 5, 'Diam': 6}
#I also want to know how to do both keys in the list given e.g.
{'NDS': 19, 'TCT': 30, 'ET': 3, 'ACC': 4, 'Ydist': 5, 'Diam': 6}
tem = ["NDS", "TCT"]
tem_results = [19,30]
for k, v in zip(tem, tem_results):
dicty[k] = v
The issue is with dicty[[dict_keys][0]] = tem_results[0]. You have to loop thought the two lists and update the dictionary or instead create a new dictonary and update the existing one using:
dicty.update({k: v for k, v in zip(tem, tem_results)})
I want to create a dictionary by using a loop or similar technique. Something like the below variable assignment is possible.
my_dict = {v:int(v*random()) for v in range(10)}
Though the question I am stuck at- How can I generate similar names for the item keys? Giving an example below:
{'Item-1': 1, 'Item-2':3, 'Item-3':3 ....}
Thanks in advance!
from random import random
my_dict = {f'item-{v+1}': int(v*random()) for v in range(10)}
print(my_dict)
Output:
{'item-1': 0, 'item-2': 0, 'item-3': 1, 'item-4': 1, 'item-5': 0, 'item-6': 3, 'item-7': 2, 'item-8': 4, 'item-9': 6, 'item-10': 2}
This uses an f-string to create the key, the corresponding value is randomly generated like in your question.
You can use list comprehension in dictionaries too.
from random import randint
dic = {f"item-{i}": randint(0, 10) for i in range(1, 11)}
print(dic)
Create keys and values and add to my_dict in a loop
my_dict = {}
for v in range(10): my_dict[f'Item-{v}'] = v
print(my_dict)
{'Item-0': 0, 'Item-1': 1, 'Item-2': 2, 'Item-3': 3, 'Item-4': 4, 'Item-5': 5, 'Item-6': 6, 'Item-7': 7, 'Item-8': 8, 'Item-9': 9}
I have 2 python dictionaries:
x = {'bookA': 1, 'bookB': 2, 'bookC': 3, 'bookD': 4, 'bookE': 5}
y = {'bookB': 1, 'bookD': 2, 'bookF': 3, 'bookL': 4, 'bookX': 5}
I want to merge the above two dictionaries and create an another dictionary.
I tried this code:
z = {**x, **y}
But the key values are overriding in this case. I want a dictionary in which if there are duplicates , add their values or some other action can also be there like subtraction, multiplication etc. So my motto is not to override the duplicate values but to perform some action if got any duplicate.
Any help would be highly appreciated.
Option 1
Convert x and y to collections.Counter objects and just sum them (Counter supports __add__ition.)
from collections import Counter
z = dict(Counter(x) + Counter(y))
z
{'bookA': 1,
'bookB': 3,
'bookC': 3,
'bookD': 6,
'bookE': 5,
'bookF': 3,
'bookL': 4,
'bookX': 5}
Option 2
You can write a neat little dict comprehension using dict.pop -
z = {k : x[k] + y.pop(k, 0) for k in x}
Now, update z with what's left in y -
z.update(y)
Or,
z = {**z, **y} # python3.6
z
{'bookA': 1,
'bookB': 3,
'bookC': 3,
'bookD': 6,
'bookE': 5,
'bookF': 3,
'bookL': 4,
'bookX': 5}
Refer to my previous question: How to extract the common words before particular symbol and find particular word
mydict = {"g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt" : 0,
"g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt" : 1,
"g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt" : 2,
"g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt" : 3,
"g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt" : 4,
"g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt" : 5,
"h18_84pp_3A_MVP1_GoodiesT1-HKJ-DFG-CMVP1_Y1000-FIX.txt" : 6,
"g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt" : 7,
"h18_84pp_3A_MVP2_GoodiesT1-HKJ-DFG-CMVP2_Y1000-FIX.txt" : 8,
"h18_84pp_3A_MVP3_GoodiesT1-HKJ-DFG-CMVP3_Y1000-FIX.txt" : 9,
"p18_84pp_2B_MVP1_GoodiesT2-HKJ-DFG-CMVP3_Y1000-FIX.txt" : 10}
and I already got my OutputNameDict,
OutputNameDict = {'h18_84pp_3A_MVP_FIX': 1, 'p18_84pp_2B_MVP_FIX': 2, 'g18_84pp_2A_MVP_MIX': 0}
Now what I want to do is to group three new dictionaries by using my common strings CaseNameString(refer to previous question) and values from OutputNameDict.
The idea result will like:
Group1. mydict0 using value 0 in OutputNameDict and string g18_84pp_2A_MVP_GoodiesT0 inCaseNameString.
mydict0 = {"g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt" : 0,
"g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt" : 1,
"g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt" : 2,
"g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt" : 3,
"g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt" : 4,
"g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt" : 5,
"g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt" : 6}
Group2. mydict1 using value 1 in OutputNameDict and string h18_84pp_3A_MVP_GoodiesT1 inCaseNameString.
mydict1 ={"h18_84pp_3A_MVP1_GoodiesT1-HKJ-DFG-CMVP1_Y1000-FIX.txt" : 0,
"h18_84pp_3A_MVP2_GoodiesT1-HKJ-DFG-CMVP2_Y1000-FIX.txt" : 1,
"h18_84pp_3A_MVP3_GoodiesT1-HKJ-DFG-CMVP3_Y1000-FIX.txt" : 2}
Group3. mydict2 using value 2 in OutputNameDict and string p18_84pp_2B_MVP_GoodiesT2 inCaseNameString.
mydict2 ={"p18_84pp_2B_MVP1_GoodiesT2-HKJ-DFG-CMVP3_Y1000-FIX.txt" : 0}
Any suggestion? Is there any function to call?
I'd change your OutputNameDict keys to be regular expression patterns, as follows:
OutputNameDict = {'h18_84pp_3A_MVP.*FIX': 1, 'p18_84pp_2B_MVP.*FIX': 2, 'g18_84pp_2A_MVP.*MIX': 0}
Then, using the re regular expression module, use that to match against the keys in mydict, and place the dictionary element into the appropriate key in output_dicts dictionary, as follows
import collections
import re
output_dicts = collections.defaultdict(dict)
for k, v in mydict.iteritems():
for pattern, suffix in OutputNameDict.iteritems():
if re.match(pattern,k):
output_dicts['mydict' + str(suffix)][k] = v
break
else:
output_dicts['not matched'][k] = v
This results in the output_dicts dictionary populated as follows
for k, v in output_dicts.iteritems():
print k
print v
print
Which outputs
mydict1
{'h18_84pp_3A_MVP2_GoodiesT1-HKJ-DFG-CMVP2_Y1000-FIX.txt': 8,
'h18_84pp_3A_MVP3_GoodiesT1-HKJ-DFG-CMVP3_Y1000-FIX.txt': 9,
'h18_84pp_3A_MVP1_GoodiesT1-HKJ-DFG-CMVP1_Y1000-FIX.txt': 6}
mydict0
{'g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt': 0,
'g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt': 1,
'g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt': 3,
'g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt': 4,
'g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt': 2,
'g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt': 5,
'g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt': 7}
mydict2
{'p18_84pp_2B_MVP1_GoodiesT2-HKJ-DFG-CMVP3_Y1000-FIX.txt': 10}