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Triangle angle classification

I need to make a function to make that will give me an angle classification like acute right or obtuse and I need it to loop until the user wants to exit the function:
this is my code so far:
side_a = float(input('Enter length of side a: '))
side_b = float(input('Enter length of side b: '))
side_c = float(input('Enter length of side c: '))
def is_valid_triangle(a,b,c):
if a+b>=c and b+c>=a and c+a>=b:
return True
else:
return False
# Function definition for type of triangle
def type_of_triangle(a,b,c):
if a==b and b==c:
print('Triangle is Equilateral.')
elif a==b or b==c or a==c:
print('Triangle is Isosceles.')
else:
print('Triangle is Scalane')
return False
if is_valid_triangle(side_a, side_b, side_c):
type_of_triangle(side_a, side_b, side_c)
else:
print('Tringle is not possible from given sides.')
def triangle_angle (a, b, c, ) :
a = int(input ("enter side a: "))
b = int(input("enter side b : "))
c = int(input("enter side c : "))

I'm assuming you want to know how to constantly loop code.
You can use:
try:
while True:
pass # replace with whatever code you want to run
except KeyboardInterrupt:
print('Exiting...')
Which will constantly loop until the user presses Ctrl+C.
I think this answers your question.

Errors pertaining to the "!==" function in Python

I'm currently trying to make a program in Python that basically asks you math problems. For some reason, there's a lot of errors, and I have no idea why, such as the "!==" function, which seems to be incorrect. There might also be some other issues as I've only just started Python. Could someone direct me to how to use the !== function correctly and also my other issue: Making my input for "addition, subtraction, or multiplication" into a possible command?
# import random
import time
choice = 0
counterright = 0
counterwrong = 0
def add_question_to_file(a, b):
with open("wrong_answers.txt", 'a') as f:
f.write(f"{a} {operation} {b}\n")
def test(a,operation,b):
user_input = int(input(f"{a} {operation} {b} = "))
if user_input == a + b:
print("You got it right!")
counterright += 1
while user_input != a + b:
if user_input == a + b:
print("You got it right!")
counterwrong += 1
break
else:
add_question_to_file(a, b)
print("Try Again!")
user_input = int(input(f"{a} + {b} = "))
def get_question():
a = random.randint(1, 10)
b = random.randint(1, 10)
with open("calc_log.txt", 'a') as f:
if a<b: #insures a is always greater than b
a, b = b, a
f.write(f"{a} {operation} {b}\n")
def check_operation():
if operation !==t "+" or "-" or "*"
print("Sorry, that's invalid. You have to choose of the three operations!")
t1=time.perf_counter() #
m = input("What mode would you like to use? Review/Normal. Choose Normal if this is your first time!")
operat ion = input("Which operation would you like to use? +,-,or *?")
if m == "review":
with open("wrong_answers.txt", 'r') as f:
for line in f:
a, operation, b = line.split()
test(int(a), int(b))
elif m == "normal":
num_questions = int(input("How many questions would you like to do? "))
for i in range(num_questions):
print(f"You are on question {i + 1}: ")
get_question()
t2=time.perf_counter() #
print("It took you", t2-t1, "seconds for you to solve this problemset") #
print ("You got",counterright,"correct and",counterwrong,"wrong.")

The reason !== isn't working is because this is not an operator in python. Try using !=. It means not equal too.

The does not equal function in python is !=. The double equal sign (==) is only used when you want to check for equality. I hope this helps!

Python Formatting With Math In Print()

To print strings with math addition numbers in Python, what is the correct way doing something like:
# Read two inputs from users
a = input("Enter your First Number")
b = input("Enter your Second Number")
# perform type conversion
a = int(a)
b = int(b)
print (f"Result: {a}+{b}")
Output:
Enter your First Number10
Enter your Second Number10
Result: 10+10
Desired output: Result: 20

Your current format string Result: {a}+{b} prints out a and b individually as Result: 10+10 and doesn't perform the addition.
To achieve that, you need to change the f-string to f"Result: {a+b}" so that the addition happens within the formatting curly braces and the result gets printed
print (f"Result: {a+b}")
The output will be
Result: 20

a = input("Enter your First Number")
b = input("Enter your Second Number")
# perform type conversion
a = int(a)
b = int(b)
print (f"Result: {a + b}")

You should change
print (f"Result: {a} + {b}")
to
print (f"Result: {a + b}")

# Read two inputs from users
a = int(input("Enter your First Number"))
b = int(input("Enter your Second Number"))
print ("Result: {}".format(a+b))

Making a mathematics quiz in python

import random
def mathquiz():
name = str(input("Whats your name?:"))
a = random.randint(1,10)
b = random.randint(1,10)
c = (a * b)
timesby = ("*")
print('what is', + a, timesby, + b)
ans = input("Enter your answer here")
if ans == c:
print("Thats correct")
else:
print ("Incorrect the answer is", + c)
I am trying to create a maths quiz using random numbers and just say the question is 10 * 10 if i enter 100 if will say i have the wrong answer. Everything else works fine just this bit is wrong.

ans and c are of different types. Since you read ans from the console, it is a string, and not a number, while c is calculated through multiplying 2 numbers, so it is a number. there are 2 ways to fix this, convert ans to an int with int(ans) instead of ans, or convert c to a string with str(c) instead of c.

Python "if" statement not working

I was writing a complex program and I was getting an if statement...
(this isn't the complex code, this is just an example)
print("The 24 game will give you four digits between one and nine")
print("It will then prompt you to enter an ewuation one digit at a time.")
import random
a = random.randint(1,9)
b = random.randint(1,9)
c = random.randint(1,9)
d = random.randint(1,9)
print(a,b,c,d)
f=input("Enter one of the above numbers")
if f==a:
print("ok")
elif f != a:
print("No")
No matter what I type it always outputs "NO".

It would work after converting the user input string to a number:
if int(f) == a:
print("ok")