How can I get all the URLs from this particular link: https://www.oddsportal.com/results/#soccer
For every URL on this page, there are multiple pages e.g. the first link of the page:
https://www.oddsportal.com/soccer/africa/
leads to the below page as an example:
https://www.oddsportal.com/soccer/africa/africa-cup-of-nations/results/
-> https://www.oddsportal.com/soccer/africa/africa-cup-of-nations/results/#/page/2/...
https://www.oddsportal.com/soccer/africa/africa-cup-of-nations-2019/results/
-> https://www.oddsportal.com/soccer/africa/africa-cup-of-nations-2019/results/#/page/2/...
I would ideally like to code in python as I am pretty comfortable with it (more than other languages through not at all close to what I can call as comfortable)
and
After clicking on the link:
When I go to inspect element, I can see tha the links can be scraped however I am very new to it.
Please help
I have extracted the URLs from the main page that you mentioned.
import requests
import bs4 as bs
url = 'https://www.oddsportal.com/results/#soccer'
headers = {'User-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.114 Safari/537.36'}
resp = requests.get(url, headers=headers)
soup = bs.BeautifulSoup(resp.text, 'html.parser')
base_url = 'https://www.oddsportal.com'
a = soup.findAll('a', attrs={'foo': 'f'})
# This set will have all the URLs of the main page
s = set()
for i in a:
s.add(base_url + i['href'])
Since you are new to web-scraping I suggest you to go through these.
Beautiful Soup - Beautiful Soup is a Python library for pulling data out of HTML and XML files.
Docs: https://www.crummy.com/software/BeautifulSoup/bs4/doc/
requests - Requests is an elegant and simple HTTP library for Python.
Docs: https://docs.python-requests.org/en/master/
Selenium - Selenium is an umbrella project for a range of tools and libraries that enable and support the automation of web browsers.
Docs: https://selenium-python.readthedocs.io/
Related
I am dealing with BeautifulSoup and also trying it with MechanicalSoup and I have got it to load with other websites, but when I request that the website be requested it takes a long time and then never really gets it. Any ideas would be super helpful.
Here is the BeautifulSoup code that I am writing:
import urllib3
from bs4 import BeautifulSoup as soup
url = 'https://www.apartments.com/apartments/saratoga-springs-ut/1-bedrooms/?bb=hy89sjv-mN24znkgE'
http = urllib3.PoolManager()
r = http.request('GET', url)
Here is the Mechanicalsoup code:
import mechanicalsoup
browser = mechanicalsoup.Browser()
url = 'https://www.apartments.com/apartments/saratoga-springs-ut/1-bedrooms/'
page = browser.get(url)
page
What I am trying to do is gather data on different cities and apartments, so the url will change to have be 2-bedrooms and then 3-bedrooms then it will move to a different city and do the same thing there, so I really need this part to work.
Any help would be appreciated.
You see the same thing if you use curl or wget to fetch the page. My guess is they are using browser detection to try to prevent people from stealing their copyrighted information, as you are attempting to do. You can search for the User-Agent header to see how to pretend to be another browser.
import urllib3
import requests
from bs4 import BeautifulSoup as soup
headers = requests.utils.default_headers()
headers.update({
'User-Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/90.0.4430.93 Safari/537.36'
})
url = 'https://www.apartments.com/apartments/saratoga-springs-ut/1-bedrooms/'
r = requests.get(url, headers=headers)
rContent = soup(r.content, 'lxml')
rContent
Just as Tim said, I needed to add headers to my code to ensure that it was being read as not from a bot.
I have looked through the previous answers but none seemed to be applicable. I am building an open source quizlet scraper to extract all links from a class (e.g. https://quizlet.com/class/3675834/). In this case, the tag is a and class is "UILink". But when I use the following code, the list returned does not contain the element that I am looking for. Is it because of the JavaScript issue described here?
I tried to use the previous method of importing folder as written here but it does not contain the urls.
How can I scrape these urls?
import requests
from bs4 import BeautifulSoup
headers = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/85.0.4183.102 Safari/537.36"
}
url = 'https://quizlet.com/class/8536895/'
response = requests.get(url, verify=False, headers=headers)
soup = BeautifulSoup(response.text,'html.parser')
b = soup.find_all("a", class_="UILink")
You wouldn't be able to directly scrape dynamic webpages using just requests. What you see browser is fully rendered page taken care by browser.
Inorder to scrape data from these kind of webpages, you following any of below approaches.
Use requests-html instead of requests
pip install requests-html
scraper.py
from requests_html import HTMLSession
from bs4 import BeautifulSoup
session = HTMLSession()
url = 'https://quizlet.com/class/8536895/'
response = session.get(url)
response.html.render() # render the webpage
# access html page source with html.html
soup = BeautifulSoup(response.html.html, 'html.parser')
b = soup.find_all("a", class_="UILink")
print(len(b))
Note: this uses headless browser(chromium) under the hood to render the page. So it can timeout or be a little slow at times.
Use selenium webdriver
Use driver.get(url) to get the page and pass the page source to beautiful Soup with driver.page_source
Note: run this in headless mode as well and there might be some latency at times.
i use code below to scrape results from bing and when I see the scraped web page it says "There are no results for python".
but when I search in the browser there is no problem.
import requests
from bs4 import BeautifulSoup
term = 'python'
url = f'https://www.bing.com/search?q={term}&setlang=en-us'
response = requests.get(url)
soup = BeautifulSoup(response.text, 'html.parser')
print(soup.prettify())
I searched and I didn't find any similar problem
You need to pass the user-agent while requesting to get the value.
import requests
from bs4 import BeautifulSoup
term = 'python'
url = 'https://www.bing.com/search?q={}&setlang=en-us'.format(term)
headers = {'User-Agent':'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.106 Safari/537.36'}
response = requests.get(url,headers=headers)
soup = BeautifulSoup(response.text, 'html.parser')
print(soup.prettify())
Since Bing is a dynamic website, meaning Javascript generates the code, you won't be able to scrape it using only Beautifulsoup. Instead, I recommend selenium, which opens a browser that you can control and parse the code with Beautifulsoup.
The same will happen for any other dynamically coded website, including Google and many others.
It's probably because there's no user-agent being passed into request headers (as already mentioned by KunduK) thus when no user-agent is specified while using requests library, it defaults to python-requests so Bing or other search engines understands that it's a bot/script, then it blocks a request. Check what's your user-agent.
Pass user-agent:
headers = {
'User-agent':
'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.102 Safari/537.36 Edge/18.19582'
}
requests.get('URL', headers=headers)
How to reduce the chance of being blocked while web scraping search engines.
Alternatively, you can achieve the same thing by using Bing Organic Results API from SerpApi. It's a paid API with a free plan.
The difference is that you don't have to spend time trying to bypass blocks from Bing or other search engines. Instead, focus on the data that needs to be extracted from the structured JSON. Check out the playground.
Disclaimer, I work for SerpApi.
i would like to scrape amazon top 10 bestsellers in baby-products.
i want just the titel text but it seems that i have a problem.
im getting 'None' when I'm trying this code.
after getting "result" i want to iterate it using "content" and print the titles.
thanks!
import requests
from bs4 import BeautifulSoup
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.3; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/54.0.2840.71 Safari/537.36'}
url = "https://www.amazon.com/gp/bestsellers/baby-products"
r=requests.get(url, headers=headers)
print("status: ", r.status_code)
soup = BeautifulSoup(r.content, 'html.parser')
print("url: ", r.url)
result = soup.find("ol", {"id": "zg-ordered-list"})
content = result.findAll("div", {"class": "a-section a-spacing-none aok-relative"})
print(result)
print(content)
You won't be able to scrape the Amazon website in this way. You are using requests.get to get the HTTP response body of the url provided. Pay attention to what that response actually is (e.g. by print(r.content)). What you can see in your web browser is different than the raw HTTP response, because of client-side rendering technologies used by Amazon (typically JavaScript and others).
I advice you to use Selenium, which sorts of "emulates" the typical browser inside the Python runtime, renders the site like the normal browser would do and allows you to access properties of the same website you see in your web browser.
I'm trying to scrape the left side of this news site (= SENESTE NYT):
https://www.dr.dk/nyheder/
But it seems the data isn't anywhere to be found? Neither in the html or related api/json etc. Is it some kind of push data?
Using Chrome's Network console I've found this api but it doesn't contain the news items on the left side:
https://www.dr.dk/tjenester/newsapp-content/teasers?reqoffset=0&reqlimit=100
Can anyone help me? How do I scrape "SENESTE NYT"?
I first loaded the page with selenium and then processed with BeautifulSoup.
from selenium import webdriver
from bs4 import BeautifulSoup
url = "https://www.dr.dk/nyheder"
driver = webdriver.Chrome()
driver.get(url)
page_source = driver.page_source
soup = BeautifulSoup(page_source, "lxml")
div = soup.find("div", {"class":"timeline-container"})
headlines = div.find_all("h3")
print(headlines)
And it seems to find the headlines:
[<h3>Puigdemont: Debatterede spørgsmål af interesse for hele Europa</h3>,
<h3>Afblæser tsunami-varsel for Hawaii</h3>,
<h3>56.000 flygter fra vulkan i udbrud </h3>,
<h3>Pence: USA offentliggør snart plan for ambassadeflytning </h3>,
<h3>Østjysk motorvej genåbnet </h3>]
Not sure if this is what you wanted.
-----EDITED----
More efficient way would be to create request with some custom headers (already confirmed this is not working)
import requests
headers = {
"Accept":"*/*",
"Host":"www.dr.dk",
"Referer":"https://www.dr.dk/nyheder",
"User-Agent":"Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36"
}
r = requests.get(url="https://www.dr.dk/tjenester/newsapp-content/teasers?reqoffset=0&reqlimit=100", headers=headers)
r.json()