I am trying to calculate the difference between the current date and a given (partially known) date. For example: Valid date formats (YYYY-MM-DD) are listed below.
YYYY-MM-DD
YYYY-MM-??
YYYY-??-??
????-??-??
Examples, for the current day (2021-07-04), the results would then be
2021-12-02 -> 0 years, 5 months, however many days.
2022-06-?? -> 1 year, however many months
2077-??-?? -> ~56 Years
????-??-?? -> Unknown
So basically, when there is a ??, that part is ignore and we only check the next higher part of the date, e.g. if the day is marked with ?? we only look at year and month etc.
Here is what I've thrown together so far:
#staticmethod
def calculate_time_left(release_date):
# Only year is known:
if re.match("([0-9]{4})-\?\?-\?\?", release_date):
release_year = int(re.search("([0-9]{4})-\?\?-\?\?", release_date).group(1))
current_year = int(datetime.datetime.now().year)
if release_year == current_year:
return "This year."
else:
return "~{} year(s).".format(release_year - current_year)
elif re.match("([0-9]{4})-([0-9]{2})-\?\?", release_date):
release_year = int(re.search("([0-9]{4})-([0-9]{2})-\?\?", release_date).group(1))
current_year = int(datetime.datetime.now().year)
release_month = int(re.search("([0-9]{4})-([0-9]{2})-\?\?", release_date).group(2))
current_month = int(datetime.datetime.now().month)
if release_year == current_year:
if release_month == current_month:
return "This month"
else:
return "~{} months".format(release_month - current_month)
else:
return "{} year(s) and {} months.".format(release_year - current_year, release_month - current_month)
elif re.match("([0-9]{4})-([0-9]{2})-([0-9]{2})", release_date):
release_year = int(re.search("([0-9]{4})-([0-9]{2})-([0-9]{2})", release_date).group(1))
current_year = int(datetime.datetime.now().year)
release_month = int(re.search("([0-9]{4})-([0-9]{2})-([0-9]{2})", release_date).group(2))
current_month = int(datetime.datetime.now().month)
release_day = int(re.search("([0-9]{4})-([0-9]{2})-([0-9]{2})", release_date).group(3))
current_day = int(datetime.datetime.now().day)
if release_year == current_year:
if release_month == current_month:
if release_day == current_day:
return "Today."
else:
return "{} days.".format(release_day - current_day)
else:
if release_day == current_day:
"~{} months.".format(release_month - current_month)
else:
return "~{} months and {} days.".format(release_month - current_month, release_day - current_day)
else:
if release_month == current_month:
if release_day == current_day:
return "{} year(s).".format(release_year - current_year)
else:
if release_day == current_day:
return "{} year(s) and {} months.".format(release_year - current_year, release_month - current_month)
else:
return "{} year(s), {} months and {} days.".format(release_year - current_year, release_month - current_month, release_day - current_day)
return "Release date unknown."
I am having a couple of problems here:
I am getting negative values for the differences of months and days. For example 2022-01-02 would return 1 year(s), -6 months and -2 days.
I feel like I don't need to do all this regex matching for every case. There is probably a better way to do this.
How do I solve this properly? I feel like my approach is pretty poor and error prone.
For the negative values, you can just use absolute value function to remove the negative. i am still looking at your code trying to figure out what you are trying to accomplish. Is this just for practice ? Also, since you are not using the script as an actual date for any real purpose, just treat the each part of the date (yyyy) (mm) (dd) , as a regular integer. No, I don't think you need regex just to figure this out but its good that you know a bit of regex. Treat the numbers as integers and just format them according to how you want to display the output. I am still learning python myself, just my two cents.
I'm not sure what your overall algo should return, but here is a way to evaluate the parts of the dates:
for date_string in ['2021-12-02', '2022-06-??', '2077-??-??', '????-??-??']:
year, month, day = date_string.split('-')
year_delta = month_delta = day_delta = 'unknown'
if year.count('?') == 0: # if there are no ? in the year string
year_delta = int(year) - datetime.now().year
if month.count('?') == 0:
month_delta = int(month) - datetime.now().month
if day.count('?') == 0:
day_delta = int(day) - datetime.now().day
Related
i'm working on making a program in python that uses arrays since it's the new chapter i'm learning. The goal of my program will ask the user for month day and day and I seem to have it almost done except that i have an issue with 2 lines in this whole code. I will write a comment in where i'm getting the errors.
def calc_zellers_congruence(get_day: int, get_year: int, get_month: int) -> str:
# Calculates the month day and year
days = [""] * 7
day_Of_Week = 0
day_of_month = 0
century = 0
year_of_the_century = get_year % 100
days[1] = "Sunday"
days[2] = "Monday"
days[3] = "Tuesday"
days[4] = "Wednessday"
days[5] = "Thursday"
days[6] = "Friday"
days[0] = "Saturday"
dayOfWeek = day_of_month + 13 * get_month + int(1) / 5 + year_of_the_century + int(year_of_the_century) / 4 + int(
century) / 4 + 5 * century % 7
name_of_day = days[day_Of_Week]
return name_of_day
def displayResults():
print("Result" + day)
def get_day():
print("Enter a Day")
get_day = int(input())
return get_day
def get_month():
print("Enter a Month")
month = int(input())
return month
def get_year():
print("Enter a Year")
get_year: int(input())
return year
# Main
# This program will calculate birthdays using arrays and zellers congruence
# References...Programming Fundamentals WiKi, J Robinson, GeeksForGeek.com
year = get_year()
month = get_month()
day = get_day()
calc_Zeller_Congruence: calc_zellers_congruence(get_year, get_month, get_day)
displayResults(calc_zellers_congruence)
I've tried renaming them but have gotten more errors after switching them from uppercase to lowercase and also adding snake cases.
I need to check if a given date is exactly a month ago from today, for example, if today is 01-Nov-2021 then exactly a month ago will be 01-Oct-2021 (not exactly 30 days.)
I wrote a code and it works fine
today = fields.Date.from_string(fields.Date.today())
if today.month == 1:
one_month_ago = today.replace(year=today.year - 1, month=12)
else:
extra_days = 0
while True:
try:
one_month_ago = today.replace(month=today.month - 1, day=today.day -
extra_days)
break
except ValueError:
extra_days += 1
if one_month_ago == given_date:
# do something
else:
# do something
It handles well mostly all the cases but mishandles some cases. For example, the given date is 31-March-2021 and today date is 30-April-2021 and 31-April-2021 will not come to compare. I need my code to run daily and check something. It also mishandles cases of 29-31 January because 29-31 February will not come to compare.
From the given date, you can find the previous month and year and using these two obtained values, find the length of the previous month. The last thing to be done will be to compare the day of the given date with the length of the previous month and accordingly, return the desired date.
Demo:
from datetime import date
from calendar import monthrange
def date_a_month_ago(today):
x = today.month - 1
previous_month = 12 if x == 0 else x
year = today.year - 1 if x == 0 else today.year
last_day_of_previous_month = monthrange(year, previous_month)[1]
day = last_day_of_previous_month if today.day > last_day_of_previous_month else today.day
return date(year, previous_month, day)
# Tests
print(date_a_month_ago(date(2021, 11, 1)))
print(date_a_month_ago(date(2021, 1, 31)))
print(date_a_month_ago(date(2021, 12, 31)))
print(date_a_month_ago(date(2021, 3, 29)))
print(date_a_month_ago(date(2020, 3, 29)))
print(date_a_month_ago(date(2021, 3, 30)))
print(date_a_month_ago(date(2020, 3, 30)))
Output:
2021-10-01
2020-12-31
2021-11-30
2021-02-28
2020-02-29
2021-02-28
2020-02-29
ONLINE DEMO
May be like this:
from typing import Tuple
def last_month(year: int, month: int) -> Tuple[int, int]:
y, m = year, month - 1
if m == 0:
y, m = y - 1, 12
return y, m
def one_month_ago(today: datetime) -> datetime:
y, m = last_month(today.year, today.month)
dt = today.replace(year=y, month=m)
for day in range(today.day, 0, -1):
try:
return dt.replace(day=day)
except ValueError:
...
I did this and it's giving me the required output:
from datetime import date
from calendar import monthrange
def is_one_month(given_date, today):
x = today.month - 1
previous_month = 12 if x == 0 else x
year = today.year - 1 if x == 0 else today.year
last_day_of_previous_month = monthrange(year, previous_month)[1]
day = last_day_of_previous_month if today.day > last_day_of_previous_month else today.day
one_month_ago = date(year, previous_month, day)
if today.month == 2:
if given_date.month == today.month-1 and given_date.year == today.year and given_date.day >= 28:
return 'it is one month before'
if today.month == 4 or today.month == 6 or today.month == 9 or today.month == 11:
if given_date.month == today.month-1 and given_date.day == 31:
return 'it is one month before'
if one_month_ago == given_date:
return 'it is one month before'
else:
return 'it is NOT one month before'
print(is_one_month(date(2021, 1, 30), date(2021, 2, 28)))
Output:
it is one month before
This is my first question here so please forgive and educate on any formatting errors. I am new to Python and going through automate the boring stuff. Decided to expand the date detection project by using the clipboard and formatting some things also. The problem I have is in any operation taken on the year part of the REGEX.
I have commented out my last attempt to validate the year and gave up and changed the REGEX to only find dates from 1000 to 2999 and skipped code validation of the dates.
I now need to validate leap years but I'm back to having to work with the year variable, but once again no operation has any effect.
Basically the problem is I can extract the year value and display it but I cannot modify it or do checks against it.
#! python3
#! detect dates in a block of text
import pyperclip
import re
#!import numpy as np
text = str(pyperclip.paste())
def datedetection(text):
dateRegex = re.compile(
r"""(
(\d|\d\d) #! match day
(/{1}) #! match /
(\d|\d\d) #! match month
(/{1}) #! match /
([1|2][0-9][0-9][0-9]) #! match year
)""",
re.VERBOSE,
)
matches = []
for groups in dateRegex.findall(text):
day = str(groups[1])
slash1 = str(groups[2])
month = str(groups[3])
slash2 = str(groups[4])
year = str(groups[5])
month_range_30 = ["04", "06", "09", "11"]
month_range_31 = ["01", "03", "05", "07", "08", "10", "12"]
month_range_Feb = ["02"]
#!year_range = np.arange(1000, 3000, 1).tolist()
if len(day) == 1:
day = "0" + day
else:
day = day
if len(month) == 1:
month = "0" + month
else:
month = month
if month in month_range_31:
if int(day) > 31:
day = "Too many days in a month with only 31 days."
slash1 = month = slash2 = year = ""
elif month in month_range_30:
if int(day) > 30:
day = "Too many days in a month with only 30 days."
slash1 = month = slash2 = year = ""
elif month in month_range_Feb:
if int(day) > 29:
day = "Too many days in February."
slash1 = month = slash2 = year = ""
elif int(month) > 12:
day = "Found an invalid month."
slash1 = month = slash2 = year = ""
elif month in month_range_Feb:
if (
int(day) == 29
and (int(year) % 4 == 0)
and (int(year) % 400 == 0)
and (int(year) % 100 == 0)
):
day = day
elif month in month_range_Feb:
if (
int(day) == 29
and (int(year) % 4 == 0)
and (int(year) % 100 != 0)
):
day = "Found an invalid leap year."
slash1 = month = slash2 = year = ""
#!elif year not in year_range:
#!day = "Year is out of range."
#!slash1 = month = slash2 = year = ""
dates = "".join([day, slash1, month, slash2, year])
matches.append(dates)
if len(matches) > 0:
pyperclip.copy("\n".join(matches))
print("Copied to clipboard:")
print("\n".join(matches))
else:
print("No dates found.")
datedetection(text)
In my approach to this project, I considered validating the days, months, and year ranges as part of the regular expression. I then defined functions to check for the leap year, and validate the number of days according to the months.
I found that way simpler and easier to understand and follow. As below:
dateRegex = re.compile(r'([0-3][0-9])/([0-1][0-9])/([1-2][0-9]{3})')
def is_leap_year(year):
year = int(year)
if year % 4 == 0:
if year % 100 == 0:
return year % 400 == 0
else:
return True
else:
return False
def is_valid_date(day, month, year):
if month == '02':
if is_leap_year(year):
return int(day) <= 29
else:
return int(day) <= 28
elif month in ['04', '06', '09', '11']:
return int(day) <= 30
else:
return int(day) <= 31
You can find the rest of my code below.
https://gist.github.com/alialbusaidi/f56e4c9342f622434f8bff0549f94884
The problem was the operations before the year operations. The day and month operations were overwriting the year values. Not entirely sure how or why at this point, but moving the year code above the day and month code has started to fix the issue.
This question already has answers here:
Why does this python method gives an error saying global name not defined?
(3 answers)
Closed 4 years ago.
below is my code (all the methods are indented in original), after running that code I get this error:
NameError: global name 'checkDate' is not defined
the method are defined so i don't know whats the issue here (the code was in Java and work well there I just did the modification for this to work in python)
class Date:
def __init__(self, *args):
if len(args) == 3:
self._day, self._month, self._year = args
elif len(args) == 1:
self._day = args[0]._day
self._month = args[0]._month
self._year = args[0]._year
else:
raise TypeError("wrong number of arguments to Date constructor")
# methods
# checkDate - Check if the date is valid
def checkDate (self, day, month, year):
if year > 0 and month > 0 and month < 13 and day > 0 and day < 32:
if month == 1 or 3 or 5 or 7 or 8 or 10 or 12: return True
if month == 4 or 6 or 9 or 11:
if day == 31: return False
return True
if month == 2:
if (month % 4 == 0 and (month % 100 != 0 or (month % 100 == 0 and month % 400 == 0))):
if day > 28: return False
elif day > 27: return False
return False
# calculateDate - Computes the day number since the beginning of the Christian counting of years.
def calculateDate (self, day, month, year):
if month < 3:
year -= 1
month = month + 12
return 365 * year + year/4 - year/100 + year/400 + ((month+1) * 306)/10 + (day - 62);
# getDay - Return the day
def getDay(self): return self._day
# getMonth - Return the month
def getMonth(self): return self._month
# getYear - Return the year
def getYear(self): return self._year
# setDay - Sets the day (only if date remains valid)
def setDay(self, dayToSet):
if checkDate(dayToSet,_month,_year): _day = dayToSet
# setMonth - Sets the month (only if date remains valid)
def setMonth (self, monthToSet):
if checkDate(_day,monthToSet,_year): _month = monthToSet
# setYear - sets the year (only if date remains valid)
def setYear(self, yearToSet):
if checkDate(_day,_month,yearToSet): _year = yearToSet
def main():
birthDate = Date(1,1,2000)
print(birthDate.getDay())
print(birthDate.getMonth())
print(birthDate.getYear())
birthDate.setDay(8)
birthDate.setMonth(8)
birthDate.setYear(1987)
print(birthDate.getDay())
print(birthDate.getMonth())
print(birthDate.getYear())
if __name__ == "__main__": main()
You need to do self.checkDate() since checkDate is a method of your Date class.
Additionally, in setDay(), setMonth() and setYear() the variables being assigned to (_day, _month, and _year respectively) need a self. before them as well.
I am trying to program a calendar that checks how many days from now/ ago (past and present) from raw_input. I need a loop that counts the days through the current year and adds it to a variable called: Total_days and this loop has to go through each year until it hits the current date that the code ran on. The end result is that the output gives you the date you entered in a complete sentence: eg. "10/08/1700 was ___ days ago" Basically my teacher explained that the past days has to add up until it hits that certain date using a loop(loops are required. This is an assignment, i cant use any other functions like delta, but loops and datetime stuff is good!) and then for the future it has to say how many days from now until that futuristic date happens using loops. I am very stumped and i need your guys' help.
Heres what i got so far:
import datetime
input_date = raw_input("Enter in full format (mm/dd/yyyy):")
year = input_date[6:10]
yeara = int(year)
montha = int(input_date[1:2])
daya = int(input_date[4:5])
from datetime import datetime
from datetime import date
now = datetime.now()
year = now.year
month = now.month
day = now.day
def isleapYear(year):
if year % 4 == 0:
check = True
if year % 100 == 0:
check = False
if year % 400 == 0:
check = True
total_days = 0
n = 12
moNum = [0,31,28,31,30,31,30,31,31,30,31,30,31]
while n > montha:
if yeara > year:
if year == isleapYear(year):
total_days += 366
elif year != isleapYear(year):
total_days += 365
if montha == month:
break
total_days += int(moNum[n])
if n == 02:
if isleapYear(year) == True:
total_days += 1
n -= 1
ny = 365
h = total_days
if yeara > year:
if year == isleapYear(year):
total_days += 366
elif year != isleapYear(year):
total_days += 365
if yeara>year:
time = "future"
if yeara<year:
time = "past"
if yeara==year:
if montha>month:
time = "future"
if montha<month:
time = past
if montha == month:
if daya>day:
time = "future"
if daya<day:
time = "past"
if daya==day:
time = "present"
print str(h.days) + " days in the " + str(time)
Thanks for helping out! i appreciate your help :)
Must you use a loop? Else, you can build from the following:
refdatestr = "2010/08/23"
refdate = datetime.strptime(refdatestr, "%Y/%m/%d")
now = datetime.now()
difference_days = (now-refdate).days
difference_days is a datetime.timedelta object. If refdate (or refdatestr) was in the future, this would be negative.
Here is an updated code, with everything fixed:
import datetime
input_date = raw_input("Enter in full format (mm/dd/yyyy):")
year = input_date[6:10]
yeara = int(year)
montha = int(input_date[1:2])
daya = int(input_date[4:5])
from datetime import datetime
from datetime import date
now = datetime.now()
year = now.year
month = now.month
day = now.day
def isleapYear(year):
if year % 4 == 0:
check = True
if year % 100 == 0:
check = False
if year % 400 == 0:
check = True
end_date = input_date
start_date = now
delta = date(year,month,day)
delta2 = date(yeara,montha,daya)
h = delta-delta2
if yeara>year:
time = "future"
if yeara<year:
time = "past"
if yeara==year:
if montha>month:
time = "future"
if montha<month:
time = past
if montha == month:
if daya>day:
time = "future"
if daya<day:
time = "past"
if daya==day:
time = "present"
print str(h.days) + " in the " + str(time)
The most important thing that you forgot is that there are functions in datetime that will automatically find the number of days till the input...
Hope this helps!!!