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How to run a python file while one python file is running

I have two files main.py& test.py
Suppose the main file main.py is running and after a point of time I want to run test.py
I cannot use:
import test or os.system("python test.py") because this run python file in same terminal but I want to run the test.py in other terminal
So I mean to say in one terminal main.py is running after a point a new terminal opens and run test.py
Any solutions?
Thanks :D

If I understand correctly you want to run a python script when some condition is fulfilled so I would recommend calling the "test.py" using a subprocess library (bear in mind there are other methods) like this:
import subprocess
if(your_condition):
subprocess.call(['python', 'test.py', testscript_arg1, testscript_val1,...])
as mentioned here: Using a Python subprocess call to invoke a Python script

Linux, Python open terminal run global python command

Not sure if this is possible. I have a set of python scripts and have modified the linux PATH in ~/.bashrc so that whenever I open a terminal, the python scripts are available to run as a command.
export PATH=$PATH:/home/user/pythonlib/
my_command.py resides in the above path.
I can run my_command.py (args) from anywhere in terminal and it will run the python scripts.
I'd like to control this functionality from a different python script as this will be the quickest solution to automating my processing routines. So I need it to open a terminal and run my_command.py (args) from within the python script I'm working on.
I have tried subprocess:
import subprocess
test = subprocess.Popen(["my_command.py"], stdout=subprocess.PIPE)
output = test.communicate()[0]
While my_command.py is typically available in any terminal I launch, here I have no access to it, returns file not found.
I can start a new terminal using os then type in my_command.py, and it works
os.system("x-terminal-emulator -e /bin/bash")
So, is there a way to get the second method to accept a script you want to run from python with args?
Ubuntu 16
Thanks :)

Popen does not load the system PATH for the session you create in a python script. You have to modify the PATH in the session to include the directory to your project like so:
someterminalcommand = "my_command.py (args)"
my_env = os.environ.copy()
my_env["PATH"] = "/home/usr/mypythonlib/:" + my_env["PATH"]
combine = subprocess.Popen(shlex.split(someterminalcommand), env=my_env)
combine.wait()
This allows me to run my "my_command.py" file from a different python session just like I had a terminal window open.

If you're using Gnome, the gnome-terminal command is rather useful in this situation.
As an example of very basic usage, the following code will spawn a terminal, and run a Python REPL in it:
import subprocess
subprocess.Popen(["gnome-terminal", "-e", "python"])
Now, if you want to run a specific script, you will need to concatenate its path with python, for the last element of that list it the line that will be executed in the new terminal.
For instance:
subprocess.Popen(["gnome-terminal", "-e", "python my_script.py"])
If your script is executable, you can omit python:
subprocess.Popen(["gnome-terminal", "-e", "my_script.py"])
If you want to pass parameters to your script, simply add them to the python command:
subprocess.Popen(["gnome-terminal", "-e", "python my_script.py var1 var2"])
Note that if you want to run your script with a particular version of Python, you should specify it, by explicitly calling "python2" or "python3".
A small example:
# my_script.py
import sys
print(sys.argv)
input()
# main.py
import subprocess
subprocess.Popen(["gnome-terminal", "-e", "python3 my_script.py hello world"])
Running python3 main.py will spawn a new terminal, with ['my_script.py', 'hello', 'world'] printed, and waited for an input.

Executable .py file with shebang path to which python gives error, command not found

I have a self-installed python in my user directory in a corporate UNIX SUSE computer (no sudo privilege):
which python
<user>/bin/python/Python-3.6.1/python
I have an executable (chmod 777) sample.py file with this line at the top of the file:
#!<user>/bin/python/Python-3.6.1/python
I can execute the file like this:
python sample.py
But when I run it by itself I get an error:
/full/path/sample.py
/full/path/sample.py: Command not found
I have no idea why it's not working. I'm discombobulated as what might be going wrong since the file is executable, the python path is correct, and the file executes if I put a python command in the front. What am I missing?
EDIT:
I tried putting this on top of the file:
#!/usr/bin/env python
Now, I get this error:
: No such file or directory
I tried this to make sure my env is correct
which env
/usr/bin/env
EDIT2:
Yes, I can run the script fine using the shebang command like this:
<user>/bin/python/Python-3.6.1/python /full/path/sample.py

Your file has DOS line endings (CR+LF). It works if you run python sample.py but doesn't work if you run ./sample.py. Recode the file so it has Unix line endings (pure LF at the end of every line).

Try using #!/usr/bin/env python as described in this post. Let the OS do the work.

Running a python script in background using command prompt

I'm new to python, so my question may sound very absurd. Any help would be highly appreciated.
I'm running on windows system.
I have a python file sample.py that is a command line parser(made using argparse). The sample.py file in turn invokes many sub functions like compile,run etc based on parameters passed to file using command prompt.
#sample.py
<if command == complie>:call compile function(in another py file)
<if command == run>:call run function(in another py file)
To invoke the sample.py file:
cmd> python sample.py --Compile <argument list>
I want that after running above command, the command prompt is returned and python file does it work in background. Once the work is done i get message code compiled.
I want to this since the compile function will take some time and mean while i want to set-up other utilities using sample.py file.

python command line ok in python shell but not through windows cmd

I was about to test the ftpmirror builtin script (python322, winXP 32bits) from the cmd windows default shell and get this :
File "C:\Program Files\python322\Tools\Scripts\ftpmirror.py", line 161
print('Skip pattern', repr(pat), end=' ')
^
SyntaxError: invalid syntax
I tested the print() line directly in the python shell, trough cmd, and with idle (and in blender also) : this work obsiously.
I reproduce the error with a coucou.py file like this :
#! /usr/bin/env python3
pat = 'toto'
print("Skip pattern", repr(pat), end=" ")
when directly called from a cmd prompt :
C:\Program Files\python322\Tools\Scripts>coucou.py
same error than with ftpmirror
but :
C:\Program Files\python322\Tools\Scripts>python coucou.py
is ok
and my environment is ok I can execute py scripts directly from the windows ui by double-clicking a .py file, and I got working scripts working fine when called from .bat
I don't get it, it looks specific to the print() end argument, what did I not read yet about the way to execute python3 from the windows cmd shell ?
thanks,
Jerome

Try checking if you are running the same python interpreter when you double click or you run python from the command-line.
Save this in a .py file with this content and try running it with both methods:
import sys
print sys.version_info
I bet you are using different interpreters in each case.