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Adding empty rows in Pandas dataframe

I'd like to append consistently empty rows in my dataframe.
I have following code what does what I want but I'm struggling in adjusting it to my needs:
s = pd.Series('', data_only_trades.columns)
f = lambda d: d.append(s, ignore_index=True)
set_rows = np.arange(len(data_only_trades)) // 4
empty_rows = data_only_trades.groupby(set_rows, group_keys=False).apply(f).reset_index(drop=True)
How can I adjust the code so I add two or more rows instead of one?
How can I set a starting point (e.g. it should start with row 5 -- Do I have to use .loc then in arange?)
Also tried this code but I was struggling in setting the starting row and the values to blank (I got NaN):
df_new = pd.DataFrame()
for i, row in data_only_trades.iterrows():
df_new = df_new.append(row)
for _ in range(2):
df_new = df_new.append(pd.Series(), ignore_index=True)
Thank you!

import numpy as np
v = np.ndarray(shape=(numberOfRowsYouWant,df.values.shape[1]), dtype=object)
v[:] = ""
pd.DataFrame(np.vstack((df.values, v)))
I think you can use NumPy
but, if you want to use your manner, simply convert NaN to "":
df.fillna("")

pandas: calculate overlapping words between rows only if values in another column match (issue with multiple instances)

I have a dataframe that looks like the following, but with many rows:
import pandas as pd
data = {'intent': ['order_food', 'order_food','order_taxi','order_call','order_call','order_call','order_taxi'],
'Sent': ['i need hamburger','she wants sushi','i need a cab','call me at 6','she called me','order call','i would like a new taxi' ],
'key_words': [['need','hamburger'], ['want','sushi'],['need','cab'],['call','6'],['call'],['order','call'],['new','taxi']]}
df = pd.DataFrame (data, columns = ['intent','Sent','key_words'])
I have calculated the jaccard similarity using the code below (not my solution):
def lexical_overlap(doc1, doc2):
words_doc1 = set(doc1)
words_doc2 = set(doc2)
intersection = words_doc1.intersection(words_doc2)
return intersection
and modified the code given by #Amit Amola to compare overlapping words between every possible two rows and created a dataframe out of it:
overlapping_word_list=[]
for val in list(combinations(range(len(data_new)), 2)):
overlapping_word_list.append(f"the shared keywords between {data_new.iloc[val[0],0]} and {data_new.iloc[val[1],0]} sentences are: {lexical_overlap(data_new.iloc[val[0],1],data_new.iloc[val[1],1])}")
#creating an overlap dataframe
banking_overlapping_words_per_sent = DataFrame(overlapping_word_list,columns=['overlapping_list'])
#gold_cy 's answer has helped me and i made some changes to it to get the output i like:
for intent in df.intent.unique():
# loc returns a DataFrame but we need just the column
rows = df.loc[df.intent == intent,['intent','key_words','Sent']].values.tolist()
combos = combinations(rows, 2)
for combo in combos:
x, y = rows
overlap = lexical_overlap(x[1], y[1])
print(f"Overlap of intent ({x[0]}) for ({x[2]}) and ({y[2]}) is {overlap}")
the issue is that when there are more instances of the same intent, i run into the error:
ValueError: too many values to unpack (expected 2)
and I do not know how to handle that for many more examples that i have in my dataset

Do you want this?
from itertools import combinations
from operator import itemgetter
items_to_consider = []
for item in list(combinations(zip(df.Sent.values, map(set,df.key_words.values)),2)):
keywords = (list(map(itemgetter(1),item)))
intersect = keywords[0].intersection(keywords[1])
if len(intersect) > 0:
str_list = list(map(itemgetter(0),item))
str_list.append(intersect)
items_to_consider.append(str_list)
for i in items_to_consider:
for item in i[2]:
if item in i[0] and item in i[1]:
print(f"Overlap of intent (order_food) for ({i[0]}) and ({i[1]}) is {item}")

Append model output to pd df rows

I'm trying to put Pyomo model output into pandas.DataFrame rows. I'm accomplishing it now by saving data as a .csv, then reading the .csv file as a DataFrame. I would like to skip the .csv step and put output directly into a DataFrame.
When I accomplish an optimization solution with Pyomo, the optimal assignments are 1 in the model.x[i] output data (0 otherwise). model.x[i] is indexed by dict keys in v. model.x is specific syntax to Pyomo
Pyomo assigns a timeItem[i], platItem[i], payItem[i], demItem[i], v[i] for each value that presents an optimal solution. The 0807results.csv file produces an accurate file of the optimal assignments showing the value of timeItem[i], platItem[i], payItem[i], demItem[i], v[i] for each valid assignment in the optimal solution.
When model.x[i] is 1, how can I get timeItem[i], platItem[i], payItem[i], demItem[i], v[i] directly into a DataFrame? Your assistance is greatly appreciated. My current code is below.
index=sorted(v.keys())
with open('0807results.csv', 'w') as f:
for i in index:
if value(model.x[i])>0:
f.write("%s,%s,%s,%s,%s\n"%(timeItem[i],platItem[i],payItem[i], demItem[i],v[i]))
from pandas import read_csv
now = datetime.datetime.now()
dtg=(now.strftime("%Y%m%d_%H%M"))
df = read_csv('0807results.csv')
df.columns = ['Time', 'Platform','Payload','DemandType','Value']
# convert payload types to string so not summed
df['Payload'] = df['Payload'].astype(str)
df = df.sort_values('Time')
df.to_csv('results'+(dtg)+'.csv')
# do stats & visualization with pandas df

I have no idea what is in the timeItem etc iterables from the code you've posted. However, I suspect that something similar to:
import pandas as pd
results = pd.DataFrame([timeItem, platItem, payItem, demItem, v], index=["time", "plat", "pay", "dem", "v"]).T
Will work.
If you want to filter on 1s in model.x, you might add it as a column as well, and do a filter with pandas directly:
import pandas as pd
results = pd.DataFrame([timeItem, platItem, payItem, demItem, v, model.x], index=["time", "plat", "pay", "dem", "v", "x"]).T
filtered_results = results[results["x"]>0]

You can also use the DataFrame.from_records() function:
def record_generator():
for i in sorted(v.keys()):
if value(model.x[i] > 1E-6): # integer tolerance
yield (timeItem[i], platItem[i], payItem[i], demItem[i], v[i])
df = pandas.DataFrame.from_records(
record_generator(), columns=['Time', 'Platform', 'Payload', 'DemandType', 'Value'])

python subtract every even column from previous odd column

Sorry if this has been asked before -- I couldn't find this specific question.
In python, I'd like to subtract every even column from the previous odd column:
so go from:
292.087 190.238 299.837 189.488 255.525 187.012
300.837 190.887 299.4 188.488 248.637 187.363
292.212 191.6 299.038 188.988 249.65 187.5
300.15 192.4 307.812 189.125 247.825 188.113
to
101.849 110.349 68.513
109.95 110.912 61.274
100.612 110.05 62.15
107.75 118.687 59.712
There will be an unknown number of columns. should I use something in pandas or numpy?
Thanks in advance.

You can accomplish this using pandas. You can select the even- and odd-indexed columns separately and then subtract them.
#hiro protagonist, I didn't know you could do that StringIO magic. That's spicy.
import pandas as pd
import io
data = io.StringIO('''ROI121 ROI122 ROI124 ROI125 ROI126 ROI127
292.087 190.238 299.837 189.488 255.525 187.012
300.837 190.887 299.4 188.488 248.637 187.363
292.212 191.6 299.038 188.988 249.65 187.5
300.15 192.4 307.812 189.125 247.825 188.113''')
df = pd.read_csv(data, sep='\s+')
Note that the even/odd terms may be counterintuitive because python is 0-indexed, meaning that the signal columns are actually even-indexed and the background columns odd-indexed. If I understand your question properly, this is contrary to your use of the even/odd terminology. Just pointing out the difference to avoid confusion.
# strip the columns into their appropriate signal or background groups
bg_df = df.iloc[:, [i for i in range(len(df.columns)) if i%2 == 1]]
signal_df = df.iloc[:, [i for i in range(len(df.columns)) if i%2 == 0]]
# subtract the values of the data frames and store the results in a new data frame
result_df = pd.DataFrame(signal_df.values - bg_df.values)
result_df contains columns which are the difference between the signal and background columns. You probably want to rename these column names, though.
>>> result_df
0 1 2
0 101.849 110.349 68.513
1 109.950 110.912 61.274
2 100.612 110.050 62.150
3 107.750 118.687 59.712

import io
# faking the data file
data = io.StringIO('''ROI121 ROI122 ROI124 ROI125 ROI126 ROI127
292.087 190.238 299.837 189.488 255.525 187.012
300.837 190.887 299.4 188.488 248.637 187.363
292.212 191.6 299.038 188.988 249.65 187.5
300.15 192.4 307.812 189.125 247.825 188.113''')
header = next(data) # read the first line from data
# print(header[:-1])
for line in data:
# print(line)
floats = [float(val) for val in line.split()] # create a list of floats
for prev, cur in zip(floats[::2], floats[1::2]):
print('{:6.3f}'.format(prev-cur), end=' ')
print()
with output:
101.849 110.349 68.513
109.950 110.912 61.274
100.612 110.050 62.150
107.750 118.687 59.712
if you know what data[start:stop:step] means and how zip works this should be easily understood.

Pandas append perfomance concat/append using "larger" DataFrames

The problem: I have data stored in csv file with the following columns data/id/value. I have 15 files each containing around 10-20mio rows. Each csv file covers a distinct period so the time indexes are non overlapping, but the columns are (new ids enter from time to time, old ones disappear). What I originally did was running the script without the pivot call, but then I run into memory issues on my local machine (only 8GB). Since there is lots of redundancy in each file, pivot seemd at first a nice way out (roughly 2/3 less data) but now perfomance kicks in. If I run the following script the concat function will run "forever" (I always interrupted manually so far after some time (2h>)). Concat/append seem to have limitations in terms of size (I have roughly 10000-20000 columns), or do I miss something here? Any suggestions?
import pandas as pd
path = 'D:\\'
data = pd.DataFrame()
#loop through list of raw file names
for file in raw_files:
data_tmp = pd.read_csv(path + file, engine='c',
compression='gzip',
low_memory=False,
usecols=['date', 'Value', 'ID'])
data_tmp = data_tmp.pivot(index='date', columns='ID',
values='Value')
data = pd.concat([data,data_tmp])
del data_tmp
EDIT I:To clarify, each csv file has about 10-20mio rows and three columns, after pivot is applied this reduces to about 2000 rows but leads to 10000 columns.
I can solve the memory issue by simply splitting the full-set of ids into subsets and run the needed calculations based on each subset as they are independent for each id. I know it makes me reload the same files n-times, where n is the number of subsets used, but this is still reasonable fast. I still wonder why append is not performing.
EDIT II: I have tried to recreate the file structure with a simulation, which is as close as possible to the actual data structure. I hope it is clear, I didn't spend to much time minimizing simulation-time, but it runs reasonable fast on my machine.
import string
import random
import pandas as pd
import numpy as np
import math
# Settings :-------------------------------
num_ids = 20000
start_ids = 4000
num_files = 10
id_interval = int((num_ids-start_ids)/num_files)
len_ids = 9
start_date = '1960-01-01'
end_date = '2014-12-31'
run_to_file = 2
# ------------------------------------------
# Simulation column IDs
id_list = []
# ensure unique elements are of size >num_ids
for x in range(num_ids + round(num_ids*0.1)):
id_list.append(''.join(
random.choice(string.ascii_uppercase + string.digits) for _
in range(len_ids)))
id_list = set(id_list)
id_list = list(id_list)[:num_ids]
time_index = pd.bdate_range(start_date,end_date,freq='D')
chunk_size = math.ceil(len(time_index)/num_files)
data = []
# Simulate files
for file in range(0, run_to_file):
tmp_time = time_index[file * chunk_size:(file + 1) * chunk_size]
# TODO not all cases cover, make sure ints are obtained
tmp_ids = id_list[file * id_interval:
start_ids + (file + 1) * id_interval]
tmp_data = pd.DataFrame(np.random.standard_normal(
(len(tmp_time), len(tmp_ids))), index=tmp_time,
columns=tmp_ids)
tmp_file = tmp_data.stack().sortlevel(1).reset_index()
# final simulated data structure of the parsed csv file
tmp_file = tmp_file.rename(columns={'level_0': 'Date', 'level_1':
'ID', 0: 'Value'})
# comment/uncomment if pivot takes place on aggregate level or not
tmp_file = tmp_file.pivot(index='Date', columns='ID',
values='Value')
data.append(tmp_file)
data = pd.concat(data)
# comment/uncomment if pivot takes place on aggregate level or not
# data = data.pivot(index='Date', columns='ID', values='Value')

Using your reproducible example code, I can indeed confirm that the concat of only two dataframes takes a very long time. However, if you first align them (make the column names equal), then concatting is very fast:
In [94]: df1, df2 = data[0], data[1]
In [95]: %timeit pd.concat([df1, df2])
1 loops, best of 3: 18min 8s per loop
In [99]: %%timeit
....: df1b, df2b = df1.align(df2, axis=1)
....: pd.concat([df1b, df2b])
....:
1 loops, best of 3: 686 ms per loop
The result of both approaches is the same.
The aligning is equivalent to:
common_columns = df1.columns.union(df2.columns)
df1b = df1.reindex(columns=common_columns)
df2b = df2.reindex(columns=common_columns)
So this is probably the easier way to use when having to deal with a full list of dataframes.
The reason that pd.concat is slower is because it does more. E.g. when the column names are not equal, it checks for every column if the dtype has to be upcasted or not to hold the NaN values (which get introduced by aligning the column names). By aligning yourself, you skip this. But in this case, where you are sure to have all the same dtype, this is no problem.
That it is so much slower surprises me as well, but I will raise an issue about that.

Summary, three key performance drivers depending on the set-up:
1) Make sure datatype are the same when concatenating two dataframes
2) Use integer based column names if possible
3) When using string based columns, make sure to use the align method before concat is called as suggested by joris

As #joris mentioned, you should append all of the pivot tables to a list and then concatenate them all in one go. Here is a proposed modification to your code:
dfs = []
for file in raw_files:
data_tmp = pd.read_csv(path + file, engine='c',
compression='gzip',
low_memory=False,
usecols=['date', 'Value', 'ID'])
data_tmp = data_tmp.pivot(index='date', columns='ID',
values='Value')
dfs.append(data_tmp)
del data_tmp
data = pd.concat(dfs)