Right now, I am working on Chapter 3 of the book Python for the absolute beginner.
One of the challenges at the end of chapter 3 is to "Modify the Guess My Number game so that the player has a limited number of guesses" and that if the player fails to get the correct amount of guesses, a message should be displayed.
The code looks like this:
# Guess My Number
# The computer picks a random number between 1 and 100
# The player tries to guess it and the computer lets
# the player know if the guess is too high, too low
# or right on the money
import random
print("\tWelcome to 'Guess My Number'!")
print("\nI'm thinking of a number between 1 and 100.")
print("Try to guess it in as few attempts as possible.\n")
# set the initial values
the_number = random.randint(1, 100)
guess = int(input("Take a guess: "))
tries = 1
# guessing loop
while guess != the_number:
if guess > the_number:
print("Lower...")
else:
print("Higher...")
guess = int(input("Take a guess: "))
tries += 1
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")
input("\n\nPress the enter key to exit.")
From what I can see so far, I need to add a variable that counts how many lives a player has, which is set to an amount at the beginning, like 10 and an if command should be used to make sure that, when the player uses all their lives, the message is displayed.
However, I am unsure where to place the if command in the existing code.
Well, If I were you I would make a game loop instead of the guessing loop. And then I would just break the game loop when I reach the guessing limit. However if you wanna keep your code you can use this.
while guess != the_number:
if tries == 3: # Replace 3 with the limit you'd like to use
print("You lost :(")
exit()
else:
if guess > the_number:
print("Lower...")
else:
print("Higher...")
guess = int(input("Take a guess: "))
tries += 1
Also in your case don't use break, it will still cause to print in the end the winning msg
(the spacing might be a little bit off so u may need to fix it)
After you say tries+=1, put an if statement. Your code should look like this:
if tries>3:
print("Game Over")
break()
import random
print("\tWelcome to 'Guess My Number'!")
print("\nI'm thinking of a number between 1 and 100.")
print("Try to guess it in as few attempts as possible.\n")
# set the initial values
the_number = random.randint(1, 100)
guess = int(input("Take a guess: "))
tries = 1
while tries < 8:
if guess == the_number:
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")
break
elif guess > the_number:
print("Lower...")
else:
print("Higher...")
guess = int(input("Take a guess: "))
tries += 1
if tries == 8:
print("You failed to guess my number")
input("\n\nPress the enter key to exit.")
You can also do it this way
Related
I'm having issues with this random number guessing game. There are 2 issues: The first issue has to do with the counting of how many tries you have left. it should give you 3 changes but after the 2nd one it goes into my replay_input section where I am asking the user if they want to play again.
import random
# guess the # game
guess = input("Enter in your numerical guess. ")
random_number = random.randint(0, 10)
print(random_number) # used to display the # drawn to check if code works
number_of_guess_left = 3
# this is the main loop where the user gets 3 chances to guess the correct number
while number_of_guess_left > 0:
if guess != random_number:
number_of_guess_left -= 1
print(f"The number {guess} was an incorrect guess. and you have {number_of_guess_left} guesses left ")
guess = input("Enter in your numerical guess. ")
elif number_of_guess_left == 0:
print("You lose! You have no more chances left.")
else:
print("You Win! ")
break
The second part has to do with the replay input, I can't seem to get it to loop back to the beginning to restart the game.
replay_input = input("Yes or No ").lower()
if replay_input == "yes":
guess = input("Enter in your numerical guess. ")
The break statement exits a while loop. The code in the loop executes once, hits break at the end, and moves on to execute the code after the loop.
You can have the player replay the game by wrapping it in a function which I've called play_game below. The while True loop at the end (which is outside of play_game) will loop until it encounters a break statement. The player plays a game once every loop. The looping stops when they enter anything other than "yes" at the replay prompt which will make it hit the break statement.
import random
def play_game():
# guess the # game
guess = input("Enter in your numerical guess. ")
random_number = random.randint(0, 10)
print(random_number) # used to display the # drawn to check if code works
number_of_guess_left = 3
# this is the main loop where the user gets 3 chances to guess the correct number
while number_of_guess_left > 0:
if guess != random_number:
number_of_guess_left -= 1
print(f"The number {guess} was an incorrect guess. and you have {number_of_guess_left} guesses left ")
guess = input("Enter in your numerical guess. ")
elif number_of_guess_left == 0:
print("You lose! You have no more chances left.")
else:
print("You Win! ")
while True:
play_game()
replay_input = input("Yes or No ").lower()
if replay_input != "yes":
break
Please focus on the basics first before posting the questions here. Try to debug with tools like https://thonny.org/. However, I updated your code, just check.
import random
# guess the # game
random_number = random.randint(0, 10)
print(random_number)
# don't forget to convert to int
guess = int(input("Enter in your numerical guess. "))
number_of_guess_left = 3
# this is the main loop where the user gets 3 chances to guess the correct number
while number_of_guess_left > 0:
number_of_guess_left -= 1
if guess == random_number:
print("You Win! ")
break
else:
if number_of_guess_left == 0:
print("You lose! You have no more chances left.")
break
else:
print(f"The number {guess} was an incorrect guess. and you have {number_of_guess_left} guesses left ")
guess = int(input("Enter in your numerical guess. "))
I need help changing the range and showing the user what the range is so they know if they are closer or not. I have given the description I have been given. On what I need to do . I have given the code that I have come up wit so far. Let me know if you need anything else from me.
Step 6 – Guiding the user with the range of values to select between
Add functionality so that when displaying the guess prompt it will display the current range
to guess between based on the user’s guesses accounting for values that are too high and too
low. It will start out by stating What is your guess between 1 and 100, inclusive?, but as
the user guesses the range will become smaller and smaller based on the value being higher
or lower than what the user guessed, e.g., What is your guess between 15 and 32,
inclusive? The example output below should help clarify.
EXAMPLE
----------------
What is your guess between 1 and 44 inclusive? 2
Your guess was too low. Guess again.
import random
import sys
def main():
print("Assignment 6 BY enter name.")
welcome()
play()
#Part 1
def welcome():
print("Welcome to the guessing game. I have selected a number between 1 and 100 inclusive. ")
print("Your goal is to guess it in as few guesses as possible. Let’s get started.")
print("\n")
def play():
''' Plays a guessing game'''
number = int(random.randrange(1,10))
guess = int(input("What is your guess between 1 and 10 inclusive ?: "))
number_of_guess = 0
while guess != number :
(number)
#Quit
if guess == -999:
print("Thanks for Playing")
sys.exit(0)
#Guessing
if guess < number:
if guess < number:
guess = int(input("Your guess was too low. Guess Again: "))
number_of_guess += 1
elif guess not in range(1,11):
print("Invalid guess – out of range. Guess doesn’t count. : ")
guess = int(input("Guess Again: "))
else:
guess = input("Soemthing went wrong guess again: ")
if guess > number:
if guess > number:
guess = int(input("Your guess was too high. Guess Again: "))
number_of_guess += 1
elif guess not in range(1,11):
print("Invalid guess – out of range. Guess doesn’t count. : ")
guess = int(input("Guess Again: "))
else:
guess = input("Soemthing went wrong guess again: ")
#Winner
if guess == number :
number_of_guess += 1
print("Congratulations you won in " + str(number_of_guess) + " tries!")
again()
def again():
''' Prompts users if they want to go again'''
redo = input("Do you want to play again (Y or N)?: ")
if redo.upper() == "Y":
print("OK. Let’s play again.")
play()
elif redo.upper() == "N":
print("OK. Have a good day.")
sys.exit(0)
else:
print("I’m sorry, I do not understand that answer.")
again()
main()
What you'll need is a place to hold the user's lowest and highest guess. Then you'd use those for the range checks, instead of the hardcoded 1 and 11. With each guess, if it's a valid one, you then would compare it to the lowest and highest values, and if it's lower than the lowest then it sets the lowest value to the guess, and if it's higher than the highest it'll set the highest value to the guess. Lastly you'll need to update the input() string to display the lowest and highest guesses instead of a hardcoded '1' and '10'.
You need to simplify a lot your code. Like there is about 6 different places where you ask a new value, there sould be only one, also don't call method recursivly (call again() in again()) and such call between again>play>again.
Use an outer while loop to run games, and inside it an inner while loop for the game, and most important keep track of lower_bound and upper_bound
import random
import sys
def main():
print("Assignment 6 BY enter name.")
welcome()
redo = "Y"
while redo.upper() == "Y":
print("Let’s play")
play()
redo = input("Do you want to play again (Y or N)?: ")
def welcome():
print("Welcome to the guessing game. I have selected a number between 1 and 100 inclusive. ")
print("Your goal is to guess it in as few guesses as possible. Let’s get started.\n")
def play():
lower_bound, upper_bound = 0, 100
number = int(random.randrange(lower_bound, upper_bound))
print(number)
guess = -1
number_of_guess = 0
while guess != number:
guess = int(input(f"What is your guess between {lower_bound} and {upper_bound - 1} inclusive ?: "))
if guess == -999:
print("Thanks for Playing")
sys.exit(0)
elif guess not in list(range(lower_bound, upper_bound)):
print("You're outside the range")
continue
number_of_guess += 1
if guess < number:
print("Your guess was too low")
lower_bound = guess
elif guess > number:
print("Your guess was too high")
upper_bound = guess
print("Congratulations you won in", number_of_guess, "tries!")
For a class assignment, I'm trying to make a number guessing game in which the user decides the answer and the number of guesses and then guesses the number within those limited number of turns. I'm supposed to use a while loop with an and operator, and can't use break. However, my issue is that I'm not sure how to format the program so that when the maximum number of turns is reached the program doesn't print hints (higher/lower), but rather only tells you you've lost/what the answer was. It doesn't work specifically if I choose to make the max number of guesses 1. Instead of just printing " You lose; the number was __", it also prints a hint as well. This is my best attempt that comes close to doing everything that this program is supposed to do. What am I doing wrong?
answer = int(input("What should the answer be? "))
guesses = int(input("How many guesses? "))
guess_count = 0
guess = int(input("Guess a number: "))
guess_count += 1
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
while guess != answer and guess_count < guesses:
guess = int(input("Guess a number: "))
guess_count += 1
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
if guess_count >= guesses and guess != answer:
print("You lose; the number was " + str(answer) + ".")
if guess == answer:
print("You win!")
What about something like this?
answer = int(input("What should the answer be? "))
guesses = int(input("How many guesses? "))
guess_count = 1
guess_correct = False
while guess_correct is False:
if guess_count < guesses:
guess = int(input("Guess a number: "))
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
else: # answer == guess
print("You win!")
break
guess_count += 1
elif guess_count == guesses:
guess = int(input("Guess a number: "))
if guess != answer:
print("You lose; the number was " + str(answer) + ".")
if guess == answer:
print("You win!")
break
It's very similar to your program, but has a couple break statements in there. This tells Python to immediately stop execution of that loop and go to the next block of code (nothing in this case). In this way you don't have to wait for the program to evaluate the conditions you specify for your while loop before starting the next loop. If this helped solve your problem, it'd be great of you to click the checkmark by my post
So I'm learning python and I'm trying to code a simple guess my number game where you only have 5 guesses or the game ends. Im really having trouble with the while loop not recognising that the number has been guessed or the guess limit has been reached. Is there a better way of formatting my functions also. Thanks for any and all help, first time using this site.
# Guess my number
#
# The computer picks a random number between 1 and 100
# The player tries to guess it and the computer lets
# the player know if the guess is too high, too low
# or right on the money
import random
GUESS_LIMIT = 5
# functions
def display_instruct():
"""Display game instructions."""
print("\tWelcome to 'Guess My Number'!")
print("\nI'm thinking of a number between 1 and 100.")
print("Try to guess it in as few attempts as possible.")
print("\nHARDCORE mode - You have 5 tries to guess the number!\n")
def ask_number(question, low, high, step = 1):
"""Ask for a number within a range."""
response = None
while response not in range(low, high, step):
response = int(input(question))
return response
def guessing_loop():
the_number = random.randint(1, 100)
guess = ask_number("\nTake a guess:", 1, 100)
tries = 1
while guess != the_number or tries != GUESS_LIMIT:
if guess > the_number:
print("Lower...")
else:
print("Higher...")
guess = ask_number("Take a guess:", 1, 100)
tries += 1
if tries == GUESS_LIMIT:
print("\nOh no! You have run out of tries!")
print("Better luck next time!")
else:
print("\nYou guessed it! The number was", the_number)
print("And it only took you", tries, "tries!")
def main():
display_instruct()
guessing_loop()
# start the program
main()
input("\n\nPress the enter key to exit")
Your while condition will be true as long as you haven't hit the guess limit.
while guess != the_number or tries != GUESS_LIMIT:
You should join those conditions with and, not or. The way you have it now, the entire condition will be true because tries != GUESS_LIMIT is true, even if guess != the_number is false.
Or you can break your cycle explicitly with break statement. But previous answer is more correct in a sense you should really understand conditions you're setting for the loop.
My next task is modifying current code. In a previous exercise, I've written a basic application that covers a numbers guessing game. The code is as follows: -
# Guess My Number
#
# The computer picks a random number between 1 and 100
# The player tries to guess it and the computer lets
# the player know if the guess is too high, too low
# or right on the money
import random
print("\tWelcome to 'Guess My Number'!")
print("\nI'm thinking of a number between 1 and 100.")
print("Try to guess it in as few attempts as possible.\n")
# set the initial values
the_number = random.randint(1, 100)
guess = int(input("Take a guess: "))
tries = 1
# guessing loop
while guess != the_number:
if guess > the_number:
print("Lower...")
else:
print("Higher...")
guess = int(input("Take a guess: "))
tries += 1
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")
input("\n\nPress the enter key to exit.")
My task is to modify this so that there is a limited number of goes before a failure message is given to the user. Thus far, the chapter has covered "if, elif, else, for, loops, avoiding infinte loops." As such, I'd like to limit my response to these concepts only. For loops are covered next chapter.
What have I tried?
So far, I've tried amending the block in another while loop using 5 goes and the tries variable but it doesn't seem to work.
# guessing loop
while tries < 6:
guess = int(input("Take a guess: "))
if guess > the_number:
print("Lower...")
elif guess < the_number:
print("Higher...")
elif guess == the_number:
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")
break
tries += 1
input("You didn't do it in time!")
input("\n\nPress the enter key to exit.")
Any pointers or highlighting what I've missed would be appreciated plus any explanation as to what I'd missed. Teaching myself to think programatically is aslo proving tricky.
What doesn't work
When I run it, the loop conditions't don't appear to work. My idle feedback is as follows.
This means my question can be summarised as
Where is my looping logic broken?
>>> ================================ RESTART ================================
>>>
Welcome to 'Guess My Number'!
I'm thinking of a number between 1 and 100.
Try to guess it in as few attempts as possible.
Take a guess: 2
Take a guess: 5
Higher...
You didn't do it in time!
Press the enter key to exit.
The problem is that your break statement is not indented to be included in your elif:
elif guess == the_number:
print("You guessed it! The number was", the_number)
print("And it only took you", tries, "tries!\n")
break
Thus, the loop always stops after the first iteration. Indent the break to be included within the elif and it should work.
The break is not in the conditional.
Add a tab before it.