python self generating figure - python

I would like to create figures using matplotlib for example, based on matrix data. The matrix has 3 dimensions, x and y are size of a layer and n is the number of layers of my matrix.
I would like to display each layer separatly using an imshow for each layer. The matrix is loaded from a file, and before loading it I don't know the size of the matrix.
How can I automate figure generation ? It is always the same thing, but usually I'm doing it statically:
If I have 3 layer I'm doing it by hand :
import matplotlib.pyplot as plt
fig1 = plt.figure()
# my plots
fig2 = plt.figure()
# my plots
fig3 = plt.figure()
# my plots
But if I don't knowthe number of figure I cannot do it this way. I would like to create it using a loop:
for i in range(n):
figi = plt.figure()
But in doing this way I'm overwriting figi every time of course! How can I do to conserve all of my figures ?
Thanks for your help

Related

How to print multiple plots together in python?

I am trying to print about 42 plots in 7 rows, 6 columns, but the printed output in jupyter notebook, shows all the plots one under the other. I want them in (7,6) format for comparison. I am using matplotlib.subplot2grid() function.
Note: I do not get any error, and my code works, however the plots are one under the other, vs being in a grid/ matrix form.
Here is my code:
def draw_umap(n_neighbors=15, min_dist=0.1, n_components=2, metric='euclidean', title=''):
fit = umap.UMAP(
n_neighbors=n_neighbors,
min_dist=min_dist,
n_components=n_components,
metric=metric
)
u = fit.fit_transform(df);
plots = []
plt.figure(0)
fig = plt.figure()
fig.set_figheight(10)
fig.set_figwidth(10)
for i in range(7):
for j in range(6):
plt.subplot2grid((7,6), (i,j), rowspan=7, colspan=6)
plt.scatter(u[:,0], u[:,1], c= df.iloc[:,0])
plt.title(title, fontsize=8)
n=range(7)
d=range(6)
for n in n_neighbors:
for d in dist:
draw_umap(n_neighbors=n, min_dist=d, title="n_neighbors={}".format(n) + " min_dist={}".format(d))
I did refer to this post to get the plots in a grid and followed the code.
I also referred to this post, and modified my code for size of the fig.
Is there a better way to do this using Seaborn?
What am I missing here? Please help!
Both questions that you have linked contain solutions that seem more complicated than necessary. Note that subplot2grid is useful only if you want to create subplots of varying sizes which I understand is not your case. Also note that according to the docs Using GridSpec, as demonstrated in GridSpec demo is generally preferred, and I would also recommend this function only if you want to create subplots of varying sizes.
The simple way to create a grid of equal-sized subplots is to use plt.subplots which returns an array of Axes through which you can loop to plot your data as shown in this answer. That solution should work fine in your case seeing as you are plotting 42 plots in a grid of 7 by 6. But the problem is that in many cases you may find yourself not needing all the Axes of the grid, so you will end up with some empty frames in your figure.
Therefore, I suggest using a more general solution that works in any situation by first creating an empty figure and then adding each Axes with fig.add_subplot as shown in the following example:
import numpy as np # v 1.19.2
import matplotlib.pyplot as plt # v 3.3.4
# Create sample dataset
rng = np.random.default_rng(seed=1) # random number generator
nvars = 8
nobs = 50
xs = rng.uniform(size=(nvars, nobs))
ys = rng.normal(size=(nvars, nobs))
# Create figure with appropriate space between subplots
fig = plt.figure(figsize=(10, 8))
fig.subplots_adjust(hspace=0.4, wspace=0.3)
# Plot data by looping through arrays of variables and list of colors
colors = plt.get_cmap('tab10').colors
for idx, x, y, color in zip(range(len(xs)), xs, ys, colors):
ax = fig.add_subplot(3, 3, idx+1)
ax.scatter(x, y, color=color)
This could be done in seaborn as well, but I would need to see what your dataset looks like to provide a solution relevant to your case.
You can find a more elaborate example of this approach in the second solution in this answer.

Is there a way in python using matplotlib to create a figure with subplots of subplots?

I'm trying to display a figure that contains 3 plots, and each of the plots is a plot of (8,1)-shaped subplots.
Essentially, I want one big figure with three sections each containing (8,1)-shaped subplots.
I'm looking for a way to do this without having to manually set all the proportions and spacings. The reason I'm doing this is to visualize an 8-channel neural signal compared to three other pre-defined signals, each signal being 8 channels.
If it makes any sense this way, I'm trying for something like this (ficticious code):
fig, ax = plt.subplots(n_figures = 3, n_rows = 8, n_cols = 1)
ax[figure_i, row_j, col_k].imshow(image)
Is there a way to do this?
Here is an example of what I am talking about. Ideally it would three subplots, and in each of the subplots there is a set of subplots of shape 8x1. I understand how to plot this all out by going through all the margins and setting the proportions, but I'm wondering if there's a simpler way to do this without having to go through all the additional code and settings as described in the above example code I've written.
You can create this kind of figure by first creating a subplot grid with the appropriate layout using the plt.subplots() function and then looping through the array of axes to plot the data, like in this example:
import numpy as np # v 1.19.2
import matplotlib.pyplot as plt # v 3.3.2
# Create sample signal data as a 1-D list of arrays representing 3x8 channels
signal_names = ['X1', 'X2', 'X3']
nsignals = len(signal_names) # ncols of the subplot grid
nchannels = 8 # nrows of the subplot grid
nsubplots = nsignals*nchannels
x = np.linspace(0, 14*np.pi, 100)
y_signals = nsubplots*[np.cos(x)]
# Set subplots width and height
subp_w = 10/nsignals # 10 corresponds the figure width in inches
subp_h = 0.25*subp_w
# Create figure and subplot grid with the appropriate layout and dimensions
fig, axs = plt.subplots(nchannels, nsignals, sharex=True, sharey=True,
figsize=(nsignals*subp_w, nchannels*subp_h))
# Optionally adjust the space between the subplots: this can also be done by
# adding 'gridspec_kw=dict(wspace=0.1, hspace=0.3)' to the above function
# fig.subplots_adjust(wspace=0.1, hspace=0.3)
# Loop through axes to create plots: note that the list of axes is transposed
# in this example to plot the signals one after the other column-wise, as
# indicated by the colors representing the channels
colors = nsignals*plt.get_cmap('tab10').colors[:nchannels]
for idx, ax in enumerate(axs.T.flat):
ax.plot(x, y_signals[idx], c=colors[idx])
if ax.is_first_row():
ax.set_title(signal_names[idx//nchannels], pad=15, fontsize=14)
plt.show()

Matplotlib 3D Waterfall Plot with Colored Heights

I'm trying to visualise a dataset in 3D which consists of a time series (along y) of x-z data, using Python and Matplotlib.
I'd like to create a plot like the one below (which was made in Python: http://austringer.net/wp/index.php/2011/05/20/plotting-a-dolphin-biosonar-click-train/), but where the colour varies with Z - i.e. so the intensity is shown by a colormap as well as the peak height, for clarity.
An example showing the colormap in Z is (apparently made using MATLAB):
This effect can be created using the waterfall plot option in MATLAB, but I understand there is no direct equivalent of this in Python.
I have also tried using the plot_surface option in Python (below), which works ok, but I'd like to 'force' the lines running over the surface to only be in the x direction (i.e. making it look more like a stacked time series than a surface). Is this possible?
Any help or advice greatly welcomed. Thanks.
I have generated a function that replicates the matlab waterfall behaviour in matplotlib, but I don't think it is the best solution when it comes to performance.
I started from two examples in matplotlib documentation: multicolor lines and multiple lines in 3d plot. From these examples, I only saw possible to draw lines whose color varies following a given colormap according to its z value following the example, which is reshaping the input array to draw the line by segments of 2 points and setting the color of the segment to the z mean value between the 2 points.
Thus, given the input matrixes n,m matrixes X,Y and Z, the function loops over the smallest dimension between n,m to plot each line like in the example, by 2 points segments, where the reshaping to plot by segments is done reshaping the array with the same code as the example.
def waterfall_plot(fig,ax,X,Y,Z):
'''
Make a waterfall plot
Input:
fig,ax : matplotlib figure and axes to populate
Z : n,m numpy array. Must be a 2d array even if only one line should be plotted
X,Y : n,m array
'''
# Set normalization to the same values for all plots
norm = plt.Normalize(Z.min().min(), Z.max().max())
# Check sizes to loop always over the smallest dimension
n,m = Z.shape
if n>m:
X=X.T; Y=Y.T; Z=Z.T
m,n = n,m
for j in range(n):
# reshape the X,Z into pairs
points = np.array([X[j,:], Z[j,:]]).T.reshape(-1, 1, 2)
segments = np.concatenate([points[:-1], points[1:]], axis=1)
lc = LineCollection(segments, cmap='plasma', norm=norm)
# Set the values used for colormapping
lc.set_array((Z[j,1:]+Z[j,:-1])/2)
lc.set_linewidth(2) # set linewidth a little larger to see properly the colormap variation
line = ax.add_collection3d(lc,zs=(Y[j,1:]+Y[j,:-1])/2, zdir='y') # add line to axes
fig.colorbar(lc) # add colorbar, as the normalization is the same for all, it doesent matter which of the lc objects we use
Therefore, plots looking like matlab waterfall can be easily generated with the same input matrixes as a matplotlib surface plot:
import numpy as np; import matplotlib.pyplot as plt
from matplotlib.collections import LineCollection
from mpl_toolkits.mplot3d import Axes3D
# Generate data
x = np.linspace(-2,2, 500)
y = np.linspace(-2,2, 40)
X,Y = np.meshgrid(x,y)
Z = np.sin(X**2+Y**2)
# Generate waterfall plot
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
waterfall_plot(fig,ax,X,Y,Z)
ax.set_xlabel('X') ; ax.set_xlim3d(-2,2)
ax.set_ylabel('Y') ; ax.set_ylim3d(-2,2)
ax.set_zlabel('Z') ; ax.set_zlim3d(-1,1)
The function assumes that when generating the meshgrid, the x array is the longest, and by default the lines have fixed y, and its the x coordinate what varies. However, if the size of the y dimension is larger, the matrixes are transposed, generating the lines with fixed x. Thus, generating the meshgrid with the sizes inverted (len(x)=40 and len(y)=500) yields:
with a pandas dataframe with the x axis as the first column and each spectra as another column
offset=0
for c in s.columns[1:]:
plt.plot(s.wavelength,s[c]+offset)
offset+=.25
plt.xlim([1325,1375])

Plot multiple data on 3d scatter plot

I'm having trouble plotting multiple sets of data onto a single 3D scatter plot. What I'm doing is I have a system of three equations and I'm calculating the zeros of the equations using linalg. I'm then plotting each set of zeros I get onto a 3D plot. For one of my parameters, I'm changing it's value and observing how the zeros change from that. I'd like to plot all of the data sets on one 3D scatter plot so it'd be easy to compare how they differ but I keep getting one graph plotted for each data set. Can any of you figure out what I need to fix?
import numpy as np
from numpy import linalg
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
plt.close('all')
#Will be solving the following system of equations:
#sx-(b/r)z=0
#-x+ry+(s-b)z=0
#(1/r)x+y-z=0
r=50.0
b=17.0/4.0
s=[10.0,20.0,7.0,r/b]
color=['r','b','g','y']
markers=['s','o','^','d']
def system(s,b,r,color,m):
#first creates the matrix as an array so the parameters can be changed from outside
#and then coverts array into a matrix
u_arr=np.array([[s,0,-b/r],[-1,r,s-b],[1/r,1,-1]])
u_mat=np.matrix(u_arr)
U_mat=linalg.inv(u_mat)
#converts matrix into an array and then into a list to manipulate
x_zeros=np.array(U_mat[0]).reshape(-1).tolist()
y_zeros=np.array(U_mat[1]).reshape(-1).tolist()
z_zeros=np.array(U_mat[2]).reshape(-1).tolist()
zeros=[x_zeros,y_zeros,z_zeros]
coordinates=['x','y','z']
print('+'*70)
print('For s=%1.1f:' % s)
print('\n')
for i in range(3):
print('For the %s direction, the roots are: ' % coordinates[i])
for j in range(3):
print(zeros[i][j])
print('-'*50)
fig3d=plt.figure()
ax=Axes3D(fig3d)
ax.scatter(x_zeros,y_zeros,z_zeros,c=color,marker=m)
plt.title('Zeros for a Given System of Equations for s=%1.1f' % (s))
ax.set_xlabel('Zeros in x Direction')
ax.set_ylabel('Zeros in y Direction')
ax.set_zlabel('Zeros in z Direction')
plt.show()
for k in range(len(s)):
system(s[k],b,r,color[k],markers[k])
Thanks in advance for any help.
You are creating a new axes instance each time system() is called. Instead pass ax as an argument to system
def system(s,b,r,color,m, ax):
# ...
ax.scatter(x_zeros,y_zeros,z_zeros,c=color,marker=m)
Then create the axes instance before looping
fig3d=plt.figure()
ax=Axes3D(fig3d)
for k in range(len(s)):
system(s[k],b,r,color[k],markers[k], ax)
plt.show()
This was all plots are added to ax. You may then want to think about setting the axes labels etc outside of the system() function. Splitting it into two functions, one which sets the plot up and one which creates the required data and plots it.

How to plot a data cube in python

I was wondering if there's a way to plot a data cube in Python. I mean I have three coordinate for every point
x=part.points[:,0]
y=part.points[:,1]
z=part.points[:,2]
And for every point I have a scalar field t(x,y,z)
I would like to plot a 3D data cube showing the position of the point and for every point a color which is proportional to the scalar field t in that point.
I tried with histogramdd but it didn't work.
You can use matplotlib.
Here you have a working example (that moves!):
import random
from matplotlib import pyplot
from mpl_toolkits.mplot3d import Axes3D
mypoints = []
for _ in range(100):
mypoints.append([random.random(), #x
random.random(), #y
random.random(), #z
random.randint(10,100)]) #scalar
data = zip(*mypoints) # use list(zip(*mypoints)) with py3k
fig = pyplot.figure()
ax = fig.add_subplot(111, projection='3d')
ax.scatter(data[0], data[1], data[2], c=data[3])
pyplot.show()
You probably have to customize the relation of your scalar values with the corresponding colors.
Matplotlib has a very nice look but it can be slow drawing and moving these 3D drawings when you have many points. In these cases I used to use Gnuplot controlled by gnuplot.py. Gnuplot can also be used directly as a subprocess as shown here and here.
Another option is Dots plot, produced by MathGL. It is GPL plotting library. Add it don't need many memory if you save in bitmap format (PNG, JPEG, GIF and so on).

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