Related
I am using mplot3d from the mpl_toolkits library. When displaying the 3D surface on the figure I'm realized the axis were not positioned as I wished they would.
Let me show, I have added to the following screenshot the position of each axis:
Is there a way to change the position of the axes in order to get this result:
Here's the working code:
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
ax = Axes3D(plt.figure())
def f(x,y) :
return -x**2 - y**2
X = np.arange(-1, 1, 0.02)
Y = np.arange(-1, 1, 0.02)
X, Y = np.meshgrid(X, Y)
Z = f(X, Y)
ax.plot_surface(X, Y, Z, alpha=0.5)
# Hide axes ticks
ax.set_xticks([-1,1])
ax.set_yticks([-1,1])
ax.set_zticks([-2,0])
ax.set_yticklabels([-1,1],rotation=-15, va='center', ha='right')
plt.show()
I have tried using xaxis.set_ticks_position('left') statement, but it doesn't work.
No documented methods, but with some hacking ideas from https://stackoverflow.com/a/15048653/1149007 you can.
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = ax = fig.add_subplot(111, projection='3d')
ax.view_init(30, 30)
def f(x,y) :
return -x**2 - y**2
X = np.arange(-1, 1, 0.02)
Y = np.arange(-1, 1, 0.02)
X, Y = np.meshgrid(X, Y)
Z = f(X, Y)
ax.plot_surface(X, Y, Z, alpha=0.5)
# Hide axes ticks
ax.set_xticks([-1,1])
ax.set_yticks([-1,1])
ax.set_zticks([-2,0])
ax.xaxis._axinfo['juggled'] = (0,0,0)
ax.yaxis._axinfo['juggled'] = (1,1,1)
ax.zaxis._axinfo['juggled'] = (2,2,2)
plt.show()
I can no idea of the meaning of the third number in triples. If set zeros nothing changes in the figure. So should look in the code for further tuning.
You can also look at related question Changing position of vertical (z) axis of 3D plot (Matplotlib)? with low level hacking of _PLANES property.
Something changed, code blow doesn't work, all axis hide...
ax.xaxis._axinfo['juggled'] = (0,0,0)
ax.yaxis._axinfo['juggled'] = (1,1,1)
ax.zaxis._axinfo['juggled'] = (2,2,2)
I suggest using the plot function to create a graph
I have a sequence of line plots for two variables (x,y) for a number of different values of a variable z. I would normally add the line plots with legends like this:
import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(111)
# suppose mydata is a list of tuples containing (xs, ys, z)
# where xs and ys are lists of x's and y's and z is a number.
legns = []
for(xs,ys,z) in mydata:
pl = ax.plot(xs,ys,color = (z,0,0))
legns.append("z = %f"%(z))
ax.legends(legns)
plt.show()
But I have too many graphs and the legends will cover the graph. I'd rather have a colorbar indicating the value of z corresponding to the color. I can't find anything like that in the galery and all my attempts do deal with the colorbar failed. Apparently I must create a collection of plots before trying to add a colorbar.
Is there an easy way to do this? Thanks.
EDIT (clarification):
I wanted to do something like this:
import matplotlib.pyplot as plt
import matplotlib.cm as cm
fig = plt.figure()
ax = fig.add_subplot(111)
mycmap = cm.hot
# suppose mydata is a list of tuples containing (xs, ys, z)
# where xs and ys are lists of x's and y's and z is a number between 0 and 1
plots = []
for(xs,ys,z) in mydata:
pl = ax.plot(xs,ys,color = mycmap(z))
plots.append(pl)
fig.colorbar(plots)
plt.show()
But this won't work according to the Matplotlib reference because a list of plots is not a "mappable", whatever this means.
I've created an alternative plot function using LineCollection:
def myplot(ax,xs,ys,zs, cmap):
plot = lc([zip(x,y) for (x,y) in zip(xs,ys)], cmap = cmap)
plot.set_array(array(zs))
x0,x1 = amin(xs),amax(xs)
y0,y1 = amin(ys),amax(ys)
ax.add_collection(plot)
ax.set_xlim(x0,x1)
ax.set_ylim(y0,y1)
return plot
xs and ys are lists of lists of x and y coordinates and zs is a list of the different conditions to colorize each line. It feels a bit like a cludge though... I thought that there would be a more neat way to do this. I like the flexibility of the plt.plot() function.
(I know this is an old question but...) Colorbars require a matplotlib.cm.ScalarMappable, plt.plot produces lines which are not scalar mappable, therefore, in order to make a colorbar, we are going to need to make a scalar mappable.
Ok. So the constructor of a ScalarMappable takes a cmap and a norm instance. (norms scale data to the range 0-1, cmaps you have already worked with and take a number between 0-1 and returns a color). So in your case:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.normalize(min=0, max=1))
plt.colorbar(sm)
Because your data is in the range 0-1 already, you can simplify the sm creation to:
sm = plt.cm.ScalarMappable(cmap=my_cmap)
EDIT: For matplotlib v1.2 or greater the code becomes:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.normalize(vmin=0, vmax=1))
# fake up the array of the scalar mappable. Urgh...
sm._A = []
plt.colorbar(sm)
EDIT: For matplotlib v1.3 or greater the code becomes:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.Normalize(vmin=0, vmax=1))
# fake up the array of the scalar mappable. Urgh...
sm._A = []
plt.colorbar(sm)
EDIT: For matplotlib v3.1 or greater simplifies to:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.Normalize(vmin=0, vmax=1))
plt.colorbar(sm)
Here's one way to do it while still using plt.plot(). Basically, you make a throw-away plot and get the colorbar from there.
import matplotlib as mpl
import matplotlib.pyplot as plt
min, max = (-40, 30)
step = 10
# Setting up a colormap that's a simple transtion
mymap = mpl.colors.LinearSegmentedColormap.from_list('mycolors',['blue','red'])
# Using contourf to provide my colorbar info, then clearing the figure
Z = [[0,0],[0,0]]
levels = range(min,max+step,step)
CS3 = plt.contourf(Z, levels, cmap=mymap)
plt.clf()
# Plotting what I actually want
X=[[1,2],[1,2],[1,2],[1,2]]
Y=[[1,2],[1,3],[1,4],[1,5]]
Z=[-40,-20,0,30]
for x,y,z in zip(X,Y,Z):
# setting rgb color based on z normalized to my range
r = (float(z)-min)/(max-min)
g = 0
b = 1-r
plt.plot(x,y,color=(r,g,b))
plt.colorbar(CS3) # using the colorbar info I got from contourf
plt.show()
It's a little wasteful, but convenient. It's also not very wasteful if you make multiple plots as you can call plt.colorbar() without regenerating the info for it.
Here is a slightly simplied example inspired by the top answer given by Boris and Hooked (Thanks for the great idea!):
1. Discrete colorbar
Discrete colorbar is more involved, because colormap generated by mpl.cm.get_cmap() is not a mappable image needed as a colorbar() argument. A dummie mappable needs to generated as shown below:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1, n_lines + 1)
cmap = mpl.cm.get_cmap('jet', n_lines)
fig, ax = plt.subplots(dpi=100)
# Make dummie mappable
dummie_cax = ax.scatter(c, c, c=c, cmap=cmap)
# Clear axis
ax.cla()
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap(i))
fig.colorbar(dummie_cax, ticks=c)
plt.show();
This will produce a plot with a discrete colorbar:
2. Continuous colorbar
Continuous colorbar is less involved, as mpl.cm.ScalarMappable() allows us to obtain an "image" for colorbar().
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1, n_lines + 1)
norm = mpl.colors.Normalize(vmin=c.min(), vmax=c.max())
cmap = mpl.cm.ScalarMappable(norm=norm, cmap=mpl.cm.jet)
cmap.set_array([])
fig, ax = plt.subplots(dpi=100)
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap.to_rgba(i + 1))
fig.colorbar(cmap, ticks=c)
plt.show();
This will produce a plot with a continuous colorbar:
[Side note] In this example, I personally don't know why cmap.set_array([]) is necessary (otherwise we'd get error messages). If someone understand the principles under the hood, please comment :)
As other answers here do try to use dummy plots, which is not really good style, here is a generic code for a
Discrete colorbar
A discrete colorbar is produced in the same way a continuous colorbar is created, just with a different Normalization. In this case a BoundaryNorm should be used.
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.colors
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1., n_lines + 1)
cmap = plt.get_cmap("jet", len(c))
norm = matplotlib.colors.BoundaryNorm(np.arange(len(c)+1)+0.5,len(c))
sm = plt.cm.ScalarMappable(norm=norm, cmap=cmap)
sm.set_array([]) # this line may be ommitted for matplotlib >= 3.1
fig, ax = plt.subplots(dpi=100)
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap(i))
fig.colorbar(sm, ticks=c)
plt.show()
I am trying to animate a pcolormesh in matplotlib. I have seen many of the examples using the package animation, most of them using a 1D plot routine, and some of them with imshow().
First, I wan to use the FuncAnimation routine. My problem is, first, that I do not know if I can initialize the plot
fig,ax = plt.subplots()
quad = ax.pcolormesh(X,Y,Z)
I have tried a few simple lines:
fig,ax = plt.subplots()
quad = ax.pcolormesh([])
def init():
quad.set_array([])
return quad,
def animate(ktime):
quad.set_array(X,Y,np.sin(Z)+ktime)
return quad,
anim = animation.FuncAnimation(fig,animate,init_func=init,frames=Ntime,interval=200,blit=True)
plt.show()
By the way, How do I set labels into and animated plot? Can I animate the title, if it is showing a number that changes in time?
Thanks
The problem was that I was wrongly using set_array() routine. It is very important to note that you must pass a 1D array to this routine. To do so, regarding that color, pcolormesh and so on usually plots multidimensional arrays, you should use .ravel() .
One more important thing: In order to animate different plots at the same time, the blitz option at animate.FuncAnimation must be False (See section "Animating selected plot elements" of this link).
Here I post the code that simple program with various subplots:
import matplotlib.pyplot as plt
import numpy as np
import matplotlib.gridspec as gridspec
import matplotlib.animation as animation
y, x = np.meshgrid(np.linspace(-10, 10,100), np.linspace(-10, 10,100))
z = np.sin(x)*np.sin(x)+np.sin(y)*np.sin(y)
v = np.linspace(-10, 10,100)
t = np.sin(v)*np.sin(v)
tt = np.cos(v)*np.cos(v)
###########
fig = plt.figure(figsize=(16, 8),facecolor='white')
gs = gridspec.GridSpec(5, 2)
ax1 = plt.subplot(gs[0,0])
line, = ax1.plot([],[],'b-.',linewidth=2)
ax1.set_xlim(-10,10)
ax1.set_ylim(0,1)
ax1.set_xlabel('time')
ax1.set_ylabel('amplitude')
ax1.set_title('Oscillationsssss')
time_text = ax1.text(0.02, 0.95, '', transform=ax1.transAxes)
#############################
ax2 = plt.subplot(gs[1:3,0])
quad1 = ax2.pcolormesh(x,y,z,shading='gouraud')
ax2.set_xlabel('time')
ax2.set_ylabel('amplitude')
cb2 = fig.colorbar(quad1,ax=ax2)
#########################
ax3 = plt.subplot(gs[3:,0])
quad2 = ax3.pcolormesh(x, y, z,shading='gouraud')
ax3.set_xlabel('time')
ax3.set_ylabel('amplitude')
cb3 = fig.colorbar(quad2,ax=ax3)
############################
ax4 = plt.subplot(gs[:,1])
line2, = ax4.plot(v,tt,'b',linewidth=2)
ax4.set_xlim(-10,10)
ax4.set_ylim(0,1)
def init():
line.set_data([],[])
line2.set_data([],[])
quad1.set_array([])
return line,line2,quad1
def animate(iter):
t = np.sin(2*v-iter/(2*np.pi))*np.sin(2*v-iter/(2*np.pi))
tt = np.cos(2*v-iter/(2*np.pi))*np.cos(2*v-iter/(2*np.pi))
z = np.sin(x-iter/(2*np.pi))*np.sin(x-iter/(2*np.pi))+np.sin(y)*np.sin(y)
line.set_data(v,t)
quad1.set_array(z.ravel())
line2.set_data(v,tt)
return line,line2,quad1
gs.tight_layout(fig)
anim = animation.FuncAnimation(fig,animate,frames=100,interval=50,blit=False,repeat=False)
plt.show()
print 'Finished!!'
There is an ugly detail you need to take care when using QuadMesh.set_array(). If you intantiate your QuadMesh with X, Y and C you can update the values C by using set_array(). But set_array does not support the same input as the constructor. Reading the source reveals that you need to pass a 1d-array and what is even more puzzling is that depending on the shading setting you might need to cut of your array C.
Edit: There is even a very old bug report about the confusing array size for shading='flat'.
That means:
Using QuadMesh.set_array() with shading = 'flat'
'flat' is default value for shading.
# preperation
import numpy as np
import matplotlib.pyplot as plt
plt.ion()
y = np.linspace(-10, 10, num=1000)
x = np.linspace(-10, 10, num=1000)
X, Y = np.meshgrid(x, y)
C = np.ones((1000, 1000)) * float('nan')
# intantiate empty plot (values = nan)
pcmesh = plt.pcolormesh(X, Y, C, vmin=-100, vmax=100, shading='flat')
# generate some new data
C = X * Y
# necessary for shading='flat'
C = C[:-1, :-1]
# ravel() converts C to a 1d-array
pcmesh.set_array(C.ravel())
# redraw to update plot with new data
plt.draw()
Looks like:
Note that if you omit C = C[:-1, :-1] your will get this broken graphic:
Using QuadMesh.set_array() with shading = 'gouraud'
# preperation (same as for 'flat')
import numpy as np
import matplotlib.pyplot as plt
plt.ion()
y = np.linspace(-10, 10, num=1000)
x = np.linspace(-10, 10, num=1000)
X, Y = np.meshgrid(x, y)
C = np.ones((1000, 1000)) * float('nan')
# intantiate empty plot (values = nan)
pcmesh = plt.pcolormesh(X, Y, C, vmin=-100, vmax=100, shading='gouraud')
# generate some new data
C = X * Y
# here no cut of of last row/column!
# ravel() converts C to a 1d-array
pcmesh.set_array(C.ravel())
# redraw to update plot with new data
plt.draw()
If you cut off the last row/column with shade='gouraud' you will get:
ValueError: total size of new array must be unchanged
I am not sure why your quad = ax.pcolormesh(X,Y,Z) function is giving an error. Can you post the error?
Below is what I would do to create a simple animation using pcolormesh:
import matplotlib.pyplot as plt
import numpy as np
y, x = np.meshgrid(np.linspace(-3, 3,100), np.linspace(-3, 3,100))
z = np.sin(x**2+y**2)
z = z[:-1, :-1]
ax = plt.subplot(111)
quad = plt.pcolormesh(x, y, z)
plt.colorbar()
plt.ion()
plt.show()
for phase in np.linspace(0,10*np.pi,200):
z = np.sin(np.sqrt(x**2+y**2) + phase)
z = z[:-1, :-1]
quad.set_array(z.ravel())
plt.title('Phase: %.2f'%phase)
plt.draw()
plt.ioff()
plt.show()
One of the frames:
Does this help? If not, maybe you can clarify the question.
There is another answer presented here that looks simpler thus better (IMHO)
Here is a copy & paste of the alternative solution :
import matplotlib.pylab as plt
from matplotlib import animation
fig = plt.figure()
plt.hold(True)
#We need to prime the pump, so to speak and create a quadmesh for plt to work with
plt.pcolormesh(X[0:1], Y[0:1], C[0:1])
anim = animation.FuncAnimation(fig, animate, frames = range(2,155), blit = False)
plt.show()
plt.hold(False)
def animate( self, i):
plt.title('Ray: %.2f'%i)
#This is where new data is inserted into the plot.
plt.pcolormesh(X[i-2:i], Y[i-2:i], C[i-2:i])
Is there a function in matplotlib similar to MATLAB's line extensions?
I am basically looking for a way to extend a line segment to a plot. My current plot looks like this.
After looking at another question and applying the formula, I was able to get it to here, but it still looks messy.
Does anyone have the magic formula here?
Have a go to write your own as I don't think this exists in matplotlib. This is a start, you could improve by adding the semiinfinite etc
import matplotlib.pylab as plt
import numpy as np
def extended(ax, x, y, **args):
xlim = ax.get_xlim()
ylim = ax.get_ylim()
x_ext = np.linspace(xlim[0], xlim[1], 100)
p = np.polyfit(x, y , deg=1)
y_ext = np.poly1d(p)(x_ext)
ax.plot(x_ext, y_ext, **args)
ax.set_xlim(xlim)
ax.set_ylim(ylim)
return ax
ax = plt.subplot(111)
ax.scatter(np.linspace(0, 1, 100), np.random.random(100))
x_short = np.linspace(0.2, 0.7)
y_short = 0.2* x_short
ax = extended(ax, x_short, y_short, color="r", lw=2, label="extended")
ax.plot(x_short, y_short, color="g", lw=4, label="short")
ax.legend()
plt.show()
I just realised you have some red dots on your plots, are those important? Anyway the main point I think you solution so far is missing is to set the plot limits to those that existed before otherwise, as you have found, they get extended.
New in matplotlib 3.3
There is now an axline method to easily extend arbitrary lines:
Adds an infinitely long straight line. The line can be defined either by two points xy1 and xy2
plt.axline(xy1=(0, 1), xy2=(1, 0.5), color='r')
or defined by one point xy1 and a slope.
plt.axline(xy1=(0, 1), slope=-0.5, color='r')
Sample data for reference:
import numpy as np
import matplotlib.pyplot as plt
x, y = np.random.default_rng(123).random((2, 100)) * 2 - 1
m, b = -0.5, 1
plt.scatter(x, y, c=np.where(y > m*x + b, 'r', 'k'))
I have a sequence of line plots for two variables (x,y) for a number of different values of a variable z. I would normally add the line plots with legends like this:
import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(111)
# suppose mydata is a list of tuples containing (xs, ys, z)
# where xs and ys are lists of x's and y's and z is a number.
legns = []
for(xs,ys,z) in mydata:
pl = ax.plot(xs,ys,color = (z,0,0))
legns.append("z = %f"%(z))
ax.legends(legns)
plt.show()
But I have too many graphs and the legends will cover the graph. I'd rather have a colorbar indicating the value of z corresponding to the color. I can't find anything like that in the galery and all my attempts do deal with the colorbar failed. Apparently I must create a collection of plots before trying to add a colorbar.
Is there an easy way to do this? Thanks.
EDIT (clarification):
I wanted to do something like this:
import matplotlib.pyplot as plt
import matplotlib.cm as cm
fig = plt.figure()
ax = fig.add_subplot(111)
mycmap = cm.hot
# suppose mydata is a list of tuples containing (xs, ys, z)
# where xs and ys are lists of x's and y's and z is a number between 0 and 1
plots = []
for(xs,ys,z) in mydata:
pl = ax.plot(xs,ys,color = mycmap(z))
plots.append(pl)
fig.colorbar(plots)
plt.show()
But this won't work according to the Matplotlib reference because a list of plots is not a "mappable", whatever this means.
I've created an alternative plot function using LineCollection:
def myplot(ax,xs,ys,zs, cmap):
plot = lc([zip(x,y) for (x,y) in zip(xs,ys)], cmap = cmap)
plot.set_array(array(zs))
x0,x1 = amin(xs),amax(xs)
y0,y1 = amin(ys),amax(ys)
ax.add_collection(plot)
ax.set_xlim(x0,x1)
ax.set_ylim(y0,y1)
return plot
xs and ys are lists of lists of x and y coordinates and zs is a list of the different conditions to colorize each line. It feels a bit like a cludge though... I thought that there would be a more neat way to do this. I like the flexibility of the plt.plot() function.
(I know this is an old question but...) Colorbars require a matplotlib.cm.ScalarMappable, plt.plot produces lines which are not scalar mappable, therefore, in order to make a colorbar, we are going to need to make a scalar mappable.
Ok. So the constructor of a ScalarMappable takes a cmap and a norm instance. (norms scale data to the range 0-1, cmaps you have already worked with and take a number between 0-1 and returns a color). So in your case:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.normalize(min=0, max=1))
plt.colorbar(sm)
Because your data is in the range 0-1 already, you can simplify the sm creation to:
sm = plt.cm.ScalarMappable(cmap=my_cmap)
EDIT: For matplotlib v1.2 or greater the code becomes:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.normalize(vmin=0, vmax=1))
# fake up the array of the scalar mappable. Urgh...
sm._A = []
plt.colorbar(sm)
EDIT: For matplotlib v1.3 or greater the code becomes:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.Normalize(vmin=0, vmax=1))
# fake up the array of the scalar mappable. Urgh...
sm._A = []
plt.colorbar(sm)
EDIT: For matplotlib v3.1 or greater simplifies to:
import matplotlib.pyplot as plt
sm = plt.cm.ScalarMappable(cmap=my_cmap, norm=plt.Normalize(vmin=0, vmax=1))
plt.colorbar(sm)
Here's one way to do it while still using plt.plot(). Basically, you make a throw-away plot and get the colorbar from there.
import matplotlib as mpl
import matplotlib.pyplot as plt
min, max = (-40, 30)
step = 10
# Setting up a colormap that's a simple transtion
mymap = mpl.colors.LinearSegmentedColormap.from_list('mycolors',['blue','red'])
# Using contourf to provide my colorbar info, then clearing the figure
Z = [[0,0],[0,0]]
levels = range(min,max+step,step)
CS3 = plt.contourf(Z, levels, cmap=mymap)
plt.clf()
# Plotting what I actually want
X=[[1,2],[1,2],[1,2],[1,2]]
Y=[[1,2],[1,3],[1,4],[1,5]]
Z=[-40,-20,0,30]
for x,y,z in zip(X,Y,Z):
# setting rgb color based on z normalized to my range
r = (float(z)-min)/(max-min)
g = 0
b = 1-r
plt.plot(x,y,color=(r,g,b))
plt.colorbar(CS3) # using the colorbar info I got from contourf
plt.show()
It's a little wasteful, but convenient. It's also not very wasteful if you make multiple plots as you can call plt.colorbar() without regenerating the info for it.
Here is a slightly simplied example inspired by the top answer given by Boris and Hooked (Thanks for the great idea!):
1. Discrete colorbar
Discrete colorbar is more involved, because colormap generated by mpl.cm.get_cmap() is not a mappable image needed as a colorbar() argument. A dummie mappable needs to generated as shown below:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1, n_lines + 1)
cmap = mpl.cm.get_cmap('jet', n_lines)
fig, ax = plt.subplots(dpi=100)
# Make dummie mappable
dummie_cax = ax.scatter(c, c, c=c, cmap=cmap)
# Clear axis
ax.cla()
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap(i))
fig.colorbar(dummie_cax, ticks=c)
plt.show();
This will produce a plot with a discrete colorbar:
2. Continuous colorbar
Continuous colorbar is less involved, as mpl.cm.ScalarMappable() allows us to obtain an "image" for colorbar().
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1, n_lines + 1)
norm = mpl.colors.Normalize(vmin=c.min(), vmax=c.max())
cmap = mpl.cm.ScalarMappable(norm=norm, cmap=mpl.cm.jet)
cmap.set_array([])
fig, ax = plt.subplots(dpi=100)
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap.to_rgba(i + 1))
fig.colorbar(cmap, ticks=c)
plt.show();
This will produce a plot with a continuous colorbar:
[Side note] In this example, I personally don't know why cmap.set_array([]) is necessary (otherwise we'd get error messages). If someone understand the principles under the hood, please comment :)
As other answers here do try to use dummy plots, which is not really good style, here is a generic code for a
Discrete colorbar
A discrete colorbar is produced in the same way a continuous colorbar is created, just with a different Normalization. In this case a BoundaryNorm should be used.
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.colors
n_lines = 5
x = np.linspace(0, 10, 100)
y = np.sin(x[:, None] + np.pi * np.linspace(0, 1, n_lines))
c = np.arange(1., n_lines + 1)
cmap = plt.get_cmap("jet", len(c))
norm = matplotlib.colors.BoundaryNorm(np.arange(len(c)+1)+0.5,len(c))
sm = plt.cm.ScalarMappable(norm=norm, cmap=cmap)
sm.set_array([]) # this line may be ommitted for matplotlib >= 3.1
fig, ax = plt.subplots(dpi=100)
for i, yi in enumerate(y.T):
ax.plot(x, yi, c=cmap(i))
fig.colorbar(sm, ticks=c)
plt.show()