Scenerio:
Parse the PDF Bank statement and transform into clean and formatted csv file.
What I've tried:
I manage to parse the pdf file(tabular format) using camelot library but failed to produce the desired result in sense of formatting.
Code:
import camelot
import pandas as pd
tables = camelot.read_pdf('test.pdf', pages = '3')
for i, table in enumerate(tables):
print(f'table_id:{i}')
print(f'page:{table.page}')
print(f'coordinates:{table._bbox}')
tables = camelot.read_pdf('test.pdf', flavor='stream', pages = '3')
columns = df.iloc[0]
df.columns = columns
df = df.drop(0)
df.head()
for c in df.select_dtypes('object').columns:
df[c] = df[c].str.replace('$', '')
df[c] = df[c].str.replace('-', '')
def convert_to_float(num):
try:
return float(num.replace(',',''))
except:
return 0
for col in ['Deposits', 'Withdrawals', 'Balance']:
df[col] = df[col].map(convert_to_float)
My_Result:
Desired_Output:
The logic I came up with is to move those rows up i guess n-1 if date column is NaN i don't know if this logic is right or not.Can anyone help me to sort out this properly?
I tried pandas groupby and aggregation functions but it only merging the whole data and removing NaN and duplicate dates which is not suitable because every entry is necessary.
Using Transform -
df.loc[~df.Date.isna(), 'group'] = 1
g = df.group.fillna(0).cumsum()
df['Description'] = df.groupby(g)['Description'].transform(' '.join)
new_df = df.loc[~df['Date'].isna()]
Related
I'm trying to loop through a series of tickers cleaning the associated dataframes then combining the individual ticker dataframes into one large dataframe with columns named for each ticker. The following code enables me to loop through unique tickers and name the columns of each ticker's dataframe after the specific ticker:
import pandas as pd
def clean_func(tkr,f1):
f1['Date'] = pd.to_datetime(f1['Date'])
f1.index = f1['Date']
keep = ['Col1','Col2']
f2 = f1[keep]
f2.columns = [tkr+'Col1',tkr+'Col2']
return f2
tkrs = ['tkr1','tkr2','tkr3']
for tkr in tkrs:
df1 = pd.read_csv(f'C:\\path\\{tkr}.csv')
df2 = clean_func(tkr,df1)
However, I don't know how to create a master dataframe where I add each new ticker to the master dataframe. With that in mind, I'd like to align each new ticker's data using the datetime index. So, if tkr1 has data for 6/25/22, 6/26/22, 6/27/22, and tkr2 has data for 6/26/22, and 6/27/22, the combined dataframe would show all three dates but would produce a NaN for ticker 2 on 6/25/22 since there is no data for that ticker on that date.
When not in a loop looking to append each successive ticker to a larger dataframe (as per above), the following code does what I'd like. But it doesn't work when looping and adding new ticker data for each successive loop (or I don't know how to make it work in the confines of a loop).
combined = pd.concat((df1, df2, df3,...,dfn), axis=1)
Many thanks in advance.
You should only create the master DataFrame after the loop. Appending to the master DataFrame in each iteration via pandas.concat is slow since you are creating a new DataFrame every time.
Instead, read each ticker DataFrame, clean it, and append it to a list which store every ticker DataFrames. After the loop create the master DataFrame with all the Dataframes using pandas.concat:
import pandas as pd
def clean_func(tkr,f1):
f1['Date'] = pd.to_datetime(f1['Date'])
f1.index = f1['Date']
keep = ['Col1','Col2']
f2 = f1[keep]
f2.columns = [tkr+'Col1',tkr+'Col2']
return f2
tkrs = ['tkr1','tkr2','tkr3']
dfs_list = []
for tkr in tkrs:
df1 = pd.read_csv(f'C:\\path\\{tkr}.csv')
df2 = clean_func(tkr,df1)
dfs_list.append(df2)
master_df = pd.concat(dfs_list, axis=1)
As a suggestion here is a cleaner way of defining your clean_func using DataFrame.set_index and DataFrame.add_prefix.
def clean_func(tkr, f1):
f1['Date'] = pd.to_datetime(f1['Date'])
f2 = f1.set_index('Date')[['Col1','Col2']].add_prefix(tkr)
return f2
Or if you want, you can parse the Date column as datetime and set it as index directly in the pd.read_csv call by specifying index_col and parse_dates parameters (honestly, I'm not sure if those two parameters will play well together, and I'm too lazy to test it, but you can try ;)).
import pandas as pd
def clean_func(tkr,f1):
f2 = f1[['Col1','Col2']].add_prefix(tkr)
return f2
tkrs = ['tkr1','tkr2','tkr3']
dfs_list = []
for tkr in tkrs:
df1 = pd.read_csv(f'C:\\path\\{tkr}.csv', index_col='Date', parse_dates=['Date'])
df2 = clean_func(tkr,df1)
dfs_list.append(df2)
master_df = pd.concat(dfs_list, axis=1)
Before the loop create an empty df with:
combined = pd.DataFrame()
Then within the loop (after loading df1 - see code above):
combined = pd.concat((combined, clean_func(tkr, df1)), axis=1)
If you get:
TypeError: concat() got multiple values for argument 'axis'
Make sure your parentheses are correct per above.
With the code above, you can skip the original step:
df2 = clean_func(tkr,df1)
Since it is embedded in the concat function. Alternatively, you could keep the df2 step and use:
combined = pd.concat((combined,df2), axis=1)
Just make sure the dataframes are encapsulated by parentheses within the concat function.
Same answer as GC123 but here is a full example which mimics reading from separate files and concatenating them
import pandas as pd
import io
fake_file_1 = io.StringIO("""
fruit,store,quantity,unit_price
apple,fancy-grocers,2,9.25
pear,fancy-grocers,3,100
banana,fancy-grocers,1,256
""")
fake_file_2 = io.StringIO("""
fruit,store,quantity,unit_price
banana,bargain-grocers,667,0.01
apple,bargain-grocers,170,0.15
pear,bargain-grocers,281,0.45
""")
fake_files = [fake_file_1,fake_file_2]
combined = pd.DataFrame()
for fake_file in fake_files:
df = pd.read_csv(fake_file)
df = df.set_index('fruit')
combined = pd.concat((combined, df), axis=1)
print(combined)
Output
This method is slightly more efficient:
combined = []
for fake_file in fake_files:
combined.append(pd.read_csv(fake_file).set_index('fruit'))
combined = pd.concat(combined, axis=1)
print(combined)
Output:
store quantity unit_price store quantity unit_price
fruit
apple fancy-grocers 2 9.25 bargain-grocers 170 0.15
pear fancy-grocers 3 100.00 bargain-grocers 281 0.45
banana fancy-grocers 1 256.00 bargain-grocers 667 0.01
I'm trying to achieve this kind of transformation with Pandas.
I made this code but unfortunately it doesn't give the result I'm searching for.
CODE :
import pandas as pd
df = pd.read_csv('file.csv', delimiter=';')
df = df.count().reset_index().T.reset_index()
df.columns = df.iloc[0]
df = df[1:]
df
RESULT :
Do you have any proposition ? Any help will be appreciated.
First create columns for test nonOK and then use named aggregatoin for count, sum column Values and for count Trues values use sum again, last sum both columns:
df = (df.assign(NumberOfTest1 = df['Test one'].eq('nonOK'),
NumberOfTest2 = df['Test two'].eq('nonOK'))
.groupby('Category', as_index=False)
.agg(NumberOfID = ('ID','size'),
Values = ('Values','sum'),
NumberOfTest1 = ('NumberOfTest1','sum'),
NumberOfTest2 = ('NumberOfTest2','sum'))
.assign(TotalTest = lambda x: x['NumberOfTest1'] + x['NumberOfTest2']))
I have a large dataframe of urls and a smaller 2nd dataframe that contains columns of strings which I want to use to merge the two dataframes together. Data from the 2nd df will be used to populate the larger 1st df.
The matching strings can contain * wildcards (and more then one) but the order of the grouping still matters; so "path/*path2" would match with "exsample.com/eg_path/extrapath2.html but not exsample.com/eg_path2/path/test.html. How can I use the strings in the 2nd dataframe to merge the two dataframes together. There can be more then one matching string in the 2nd dataframe.
import pandas as pd
urls = {'url':['https://stackoverflow.com/questions/56318782/','https://www.google.com/','https://en.wikipedia.org/wiki/Python_(programming_language)','https://stackoverflow.com/questions/'],
'hits':[1000,500,300,7]}
metadata = {'group':['group1','group2'],
'matching_string_1':['google','wikipedia*Python_'],
'matching_string_2':['stackoverflow*questions*56318782','']}
result = {'url':['https://stackoverflow.com/questions/56318782/','https://www.google.com/','https://en.wikipedia.org/wiki/Python_(programming_language)','https://stackoverflow.com/questions/'],
'hits':[1000,500,300,7],
'group':['group2','group1','group1','']}
df1 = pd.DataFrame(urls)
df2 = pd.DataFrame(metadata)
what_I_am_after = pd.DataFrame(result)
Not very robust but gives the correct answer for my example.
import pandas as pd
urls = {'url':['https://stackoverflow.com/questions/56318782/','https://www.google.com/','https://en.wikipedia.org/wiki/Python_(programming_language)','https://stackoverflow.com/questions/'],
'hits':[1000,500,300,7]}
metadata = {'group':['group1','group2'],
'matching_string_1':['google','wikipedia*Python_'],
'matching_string_2':['stackoverflow*questions*56318782','']}
result = {'url':['https://stackoverflow.com/questions/56318782/','https://www.google.com/','https://en.wikipedia.org/wiki/Python_(programming_language)','https://stackoverflow.com/questions/'],
'hits':[1000,500,300,7],
'group':['group2','group1','group1','']}
df1 = pd.DataFrame(urls)
df2 = pd.DataFrame(metadata)
results = pd.DataFrame(columns=['url','hits','group'])
for index,row in df2.iterrows():
for x in row[1:]:
group = x.split('*')
rx = "".join([str(x)+".*" if len(x) > 0 else '' for x in group])
if rx == "":
continue
filter = df1['url'].str.contains(rx,na=False, regex=True)
if filter.any():
temp = df1[filter]
temp['group'] = row[0]
results = results.append(temp)
d3 = df1.merge(results,how='outer',on=['url','hits'])
I am trying to create a dictionary for year and month. Its a kind of macro which i can call over required no. of year and month. I am facing challenge while adding dynamic column in pyspark df
df = spark.createDataFrame([(1, "foo1",'2016-1-31'),(1, "test",'2016-1-31'), (2, "bar1",'2012-1-3'),(4, "foo2",'2011-1-11')], ("k", "v","date"))
w = Window().partitionBy().orderBy(col('date').desc())
df = df.withColumn("next_date",lag('date').over(w).cast(DateType()))
df = df.withColumn("next_name",lag('v').over(w))
df = df.withColumn("next_date",when(col("k") != lag(df.k).over(w),date_add(df.date,605)).otherwise(col('next_date')))
df = df.withColumn("next_name",when(col("k") != lag(df.k).over(w),"").otherwise(col('next_name')))
import copy
dict_of_YearMonth = {}
for yearmonth in [200901,200902,201605 .. etc]:
key_name = 'Snapshot_'+str(yearmonth)
dict_of_YearMonth[key_name].withColumn("test",yearmonth)
dict_of_YearMonth[key_name].withColumn("test_date",to_date(''+yearmonth[:4]+'-'+yearmonth[4:2]+'-1'+''))
# now i want to add a condition
if(dict_of_YearMonth[key_name].test_date >= dict_of_YearMonth[key_name].date) and (test_date <= next_date) then output snapshot_yearmonth /// i.e dataframe which satisfy this condition i am able to do it in pandas but facing challenge in pyspark
dict_of_YearMonth[key_name]
dict_of_YearMonth
Then i want to concatenate all the dataframe into single pyspark dataframe, i could do this in pandas as shown below but i need to do in pyspark
snapshots=pd.concat([dict_of_YearMonth['Snapshot_201104'],dict_of_YearMonth['Snapshot_201105']])
If is any other idea to generate dictionary of dynamic data frame with dynamic addition of columns and perform condition and generate year based data frame and merge them in single data frame. Any help would be appreciated.
I have tried below code is working fine
// Function to append all the dataframe using union
def unionAll(*dfs):
return reduce(DataFrame.unionAll, dfs)
// convert dates
def is_date(x):
try:
x= str(x)+str('01')
parse(x)
return datetime.datetime.strptime(x, '%Y%m%d').strftime("%Y-%m-%d")
except ValueError:
pass # if incorrect format, keep trying other format
dict_of_YearMonth = {}
for yearmonth in [200901,200910]:
key_name = 'Snapshot_'+str(yearmonth)
dict_of_YearMonth[key_name]=df
func = udf(lambda x: yearmonth, StringType())
dict_of_YearMonth[key_name] = df.withColumn("test",func(col('v')))
default_date = udf (lambda x : is_date(x))
dict_of_YearMonth[key_name] = dict_of_YearMonth[key_name].withColumn("test_date",default_date(col('test')).cast(DateType()))
dict_of_YearMonth
To add mutiple dataframes use below code:
final_df = unionAll(dict_of_YearMonth['Snapshot_200901'], dict_of_YearMonth['Snapshot_200910'])
In Excel, I have to separate the following value from one cell into two:
2016-12-12 (r=0.1)
2016-12-13* (r=0.7)
How do I do that in Python so that in the Excel file, dates and "r=#" will be in different cells? And also, is there a way to automatically remove the "*" sign?
This task is pretty straight forward if you use pandas:
Build a test file:
import pandas as pd
df_out = pd.DataFrame(
['2016-12-12 (r=0.1)', '2016-12-13* (r=0.7)'], columns=['data'])
df_out.to_excel('test.xlsx')
Code to convert string:
def convert_date(row):
return pd.Series([c.strip('*').strip('(').strip(')')
for c in row.split()])
Test code:
# read in test file
df_in = pd.read_excel('test.xlsx')
print(df_in)
# build a new dataframe
df_new = df_in['data'].apply(convert_date)
df_new.columns = ['date', 'r']
print(df_new)
# save the dataframe
df_new.to_excel('test2.xlsx')
Results:
data
0 2016-12-12 (r=0.1)
1 2016-12-13* (r=0.7)
date r
0 2016-12-12 r=0.1
1 2016-12-13 r=0.7