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I'm trying to create a game of last man standing in python, but when you input a number it outputs the negative version of the correct answer? Also, when i enter anything other than 1, 2, or 3, I get the error: ValueError: could not convert string to float: '(anything other than the numbers)'
any help is appreciated. Thanks!
import random
num = random.randrange(20, 30)
print ("The number is " + str(num) + ", take either one, two or three away from it!")
take = float(input("input either 1, 2 or 3: "))
newnum = take - num
if take == 1:
print(newnum)
elif take == 2:
print(newnum)
elif take == 3:
print(newnum)
else:
print("please enter either 1, 2 or 3!")
You could just use a while loop to make sure the user only inputs 1,2 or 3.
import random
num = random.randrange(20, 30)
print ("The number is " + str(num) + ", take either one, two or three away from it!")
take = None
while take not in {1,2,3}: #{} faster than ()
take = int(input("input either 1, 2 or 3: "))
print("please enter either 1, 2 or 3!")
print(num-take)
Also as the above code shows, you need to use num-take instead of vice-versa.
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(I am pretty new to python)
Hey guys, so I was trying to code a simple python program which finds the HCF of two numbers, but I am getting an error when the two numbers are co-prime and the actual HCF is not showing for the two numbers
(Ex: The HCF for 12 and 24 should be 12 but python is showing 4
Here is the code, can any of you guys help me?
factors = []
print("Enter first number")
num1 = int(input())
print("Enter second number")
num2 = int(input())
if num1 < num2:
lesser = num1
else:
lesser = num2
for i in range(2, lesser + 2):
if num1 % i == 0 and num2 % i == 0:
factors.append(i)
if not factors:
print(num1, "and", num2, "are co-prime numbers, so they don't have any common factors")
str_factors = ', '.join(map(str, factors))
hcf = max(str_factors)
print(hcf)
You are turning factors into a comma separated string and using max on the string. It's giving you the max of the string lexicographically. You need to use max on the factors variable.
Say for a string '2, 12, 42, 13' max will return '4' because it loops through all characters in a string
Fix this line and it should produce you expected output
hcf = max(factors)
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I wrote this code snippet:
lowestNumber = int(input("\nWhat would you like your lowest number to be?"))
highestNumber = int(input("What would you like your highest number to be?"))
number = random.randint(lowestNumber, highestNumber)
tries = 0
while tries < 10:
guess = int(input(f'\nEnter a number between', lowestNumber))
if guess == number:
print("You guessed correctly! The number was", number)
break
elif guess < number:
print("Too low!")
elif guess > number:
print("Too high!")
tries += 1
SyntaxError: bad input on line 22 in main.py.
Line 22 was guess = int(input(f'\nEnter a number between', lowestNumber)).
I searched it up on google and got nothing, I pasted it into OpenAI's code fixing and it also didn't help.
How can I fix this error?
When you wrote
guess = int(input(f'\nEnter a number between', lowestNumber))
it passed both the string and lowestNumber into the input function. However, you probably wanted to write something like Enter a number between (lowestNumber) and (highestNumber). To do this, you would have to write
guess = int(input(f'\nEnter a number between {lowestNumber} and {highestNumber}. '))
In my example, it passes in one object, the string, which contains lowestNumber and highestNumber in it. In your example, it passes in two objects, the string and lowestNumber.
The formatting you did in the input functions works in print statements, so the print statements are correct, but the input function is not.
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def factorial(n):
if(n == 1):
fact = 1
return fact
else:
fact = a * factorial(n - 1)
return fact
a = int(input("Enter a number to find its factorial: ")
if (a > 0):
print("The factorial of", a, "is:", fact)
else:
print("Enter a positive value to find its factorial")
In the above code it tells me that - NameError name 'fact' is not defined .
Lines starting from a = int... should be outside your function. Once that is done all you need is to add fact = factorial(a).
Find the correct logic below.
def recur_factorial(n):
if n == 1:
return n
else:
return n*recur_factorial(n-1)
num = 7
# check if the number is negative
if num < 0:
print("Sorry, factorial does not exist for negative numbers")
elif num == 0:
print("The factorial of 0 is 1")
else:
print("The factorial of", num, "is", recur_factorial(num))
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I am trying to not accept the username if it is not between 3 and 9 characters.
print (""+winner+", please input your first name, maximum of 10 characters.")
winnername = str(input())
length = (int(len(winnername)))
if 3 > length > 10:
loop5 = 1
while loop5 == 1:
print ("name is too short")
winnername = input()
length = len(winnername)
if (length) <3 and (length) <10:
break
print ("name accept")
I would expect it to loop and ask the user for another input if the provided input doesn't meet the requirements outlined in the above text.
if 3 > length > 10: is checking to make sure that length is LESS than 3 and Greater than 10, which is impossible.
Therefore the check should be if 2 < length < 10: (this will be true for lengths 3 to 9)
Let me fix your code, elegant and clean:
while True:
# I don't know if `winner` is defined
firstname = input(""+winner+", please input your first name, maximum of 10 characters.")
if 3 < len(firstname) < 10:
break
print("name is too short or too long")
print('name accepted')
The problem is 3 > length > 10 will never be executed because 3 will never be greater > than 10
Regarding your first sentence, as far as I can see form the code you are actually trying to allow maximum number of characters to be 10, not 9.
Below is a possible solution for what you're trying to achieve. The below script will keep asking user until name length is within allowed range.
print ("'+winner+', please input your first name, maximum of 10 characters.")
while True:
winnername = str(input())
if(len(winnername) < 3):
print("Name is too short")
elif(len(winnername) > 10):
print("Name is too long")
else:
break
print ("Name accepted")
You may also consider to perform some validation of winnername first (do not allow spaces or any other special characters).
winner = "Mustermann"
# Build a string called "prompt"
prompt = winner + ", please input your first name, between 3 and and 10 characters."
loopLimit = 5 # Make this a variable, so it's easy to change later
loop = 0 # Start at zero
winnername = "" # Set it less than three to start, so the while loop will pick it up
# Put the while loop here, and use it as the length check
# Use an or to explicitely join them
while True: # Set an infinite loop
loop += 1 # Increment the loop here.
# Add the string to the input command. The "input" will use the prompt
# You don't need the "str()", since input is always a string
winnername = input(prompt)
length = len(winnername)
# Separate the checks, to give a better error message
if (length < 3):
print ("Name is too short!") # Loop will continue
elif (length > 10):
print("Name is too long!") # Loop will continue
else: # This means name is OK. So finish
print("Name accepted!")
break # Will end the loop, and the script, since no code follows the loop
if loop >= loopLimit:
# Raise an error to kill the script
raise RuntimeError("You have reached the allowed number of tries for entering you name!")
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I am trying to make a random number guessing game but I cant get the if statement to check if the users input is = to the random number
import random
realNumber = random.randint(1, 50)
print(realNumber)
myNumber = print(input("Guess the number from 1 to 50: "))
if int(myNumber) == realNumber:
print("You win")
else:
print("Nope guess again")
The unintended behavior of your program is due to this line:
myNumber = print(input("Guess the number from 1 to 50: "))
Here, you are trying to assign myNumber to the return value of the print statement (Which is None) and not the value obtained from the input() statement. To fix this, simply remove the print() around the input.
myNumber = input("Guess the number from 1 to 50: ")
Hope this helped!
You don't need the print statement around input.
import random
realNumber = random.randint(1, 50)
print(realNumber)
myNumber = input("Guess the number from 1 to 50: ")
if int(myNumber) == realNumber:
print("You win")
else:
print("Nope guess again")
Note that this code will not work if the user enters something besides an integer, because the int() call will not cast correctly