I am trying to build an website which renders some books and the corresponding pages. I want to make possible to access a page like this:
path('/<str:book_pk>-<int:book_page>/', views.TestClass.as_view(), name='book-test')
I want a user to access it very simple, something like: mysite.com/5-12/ - which redirects him to the book nr 5 at page 12. The problem is that when I access this page from the website itself, using href, the real path becomes:
mysite.com/%2F5-13/
If I want to write in the browser, the following path: myste.com/5-13/, it throws me 404 page not found, because the real path is mysite.com/%2F5-13/ . This is pretty obvious, but my question is:
How can I stick to my initial path, and make it possible to be accessed via myste.com/5-13/? For some reason, Django URL Patterns, adds an extra %2F string at the beginning. Can somebody explain me why, and how to solve this issue?
I much appreciate your time and effort! Thank you so much!
You don't have to include / at the beginning of the url, simply:
path('<str:book_pk>-<int:book_page>/', views.TestClass.as_view(), name='book-test')
/ is encoded automatically as %2F in urls (read the full list here)
Related
Sorry if this is not a valid question, i personally feel it kind of boarders on the edge.
Assuming the website involved has given full permission
How could I download the ENTIRE contents (html) of that website using a python data scraper. By entire contents I refer to not only the current page you are on, but any other directory that branches off of that main website. Eg.
Using the link:
https://www.dogs.com
could I pull info from:
https://www.dogs.com/about-us
and any other directory attached to the "https://www.dogs.com/"
(I have no idea is dogs.com is a real website or not, just an example)
I have already made a scraper that will pull info from a certain link (nothing further than that), but I want to further improve it so I dont have to have heaps of links. I understand I can use an API but if this is possible I would rather this. Cheers!
while there is scrapy to do it professionally, you can use requests to get the url data, and bs4 to parse the html and look into it. it's also easier to do for a beginner i guess.
anyhow you go, you need to have a starting point, then you just follow the link's in the page, and then link's within those pages.
you might need to check if the url is linking to another website or is still in the targeted website. find the pages one by one and scrape them.
Is there a way of grabbing a subset of the URL in Django views.py?
I have tried request.build_absolute_uri() but that captures slightly more than I want.
E.G.
If the URL was http://127.0.0.1:8000/jobs/new I would like to get http://127.0.0.1:8000/
Instead I end up getting the entire URL, with the page names.
I am wondering if there is a rootURL function in Django or something similar maybe?
This question has a few approaches which are:
Using request.get_host(),
Go back home
Using href='/',
Go back home
Or Using the root url defined in your url conf.
url(r'^mah_root/$', 'someapp.views.mah_view', name='mah_view'),
Then in your template:
Go back home
I've had a weird issue that's been stumping me for days, and I really need to get it working tonight. I wrote an app in Python on Google App Engine (I'm assuming this is relevant to the issue), and whenever I include a link with the tag, the link on the live site is prepended with my own site's URL.
For example, if I placed a link in the home page html to, say, YouTube, like so:
Clicky here
...then on the live website, it'll be a link to www.mysitedomain.com/www.youtube.com
Needless to say, I get a 404 every time. I hope this is a simple issue to resolve, I'm really on a time crunch tonight. Thank you for any and all help!
Put http:// before your link, otherwise it is taken as a relative link.
Clicky here
This question already has answers here:
How can you tell if a site has been made with Django?
(7 answers)
Closed last year.
I actually have some questions (real childish).
1) If I know that a website has been developed using django , can we determine from the html source code (by right clicking and choosing "view page source ") , if that website has been developed using django?
2) If I have an HTML code for website written in HTML , and I just want to present it like that using django , how can present this HTML code using django?
3) For what kind of websites , should django be used or are used for ? I mean pure static page , blogs , or a simple google like .
Thanks in advance
Here are a few things you could use to determine if a web app was written in Django. None of these are foolproof by any means, but they could be indicators.
Try http://site.com/admin/ and see if it says "Django site admin" at the top.
Inspect all of the HTML source code of every form you can find on the site, and see if any contain an input tag with name='csrfmiddlewaretoken'. csrfmiddlewaretoken is Django's CSRF token identifier. Other web frameworks may use this same name, but Django is the predominant user of it.
Find information about the site owner and/or developer from a "Contact" page, Google their usernames/emails as well as the word "Django," such as "emailname#gmail.com django". If you see posts or questions about Django, this could possibly mean they use it often.
If all else fails, simply contact the site owner and ask them.
No, the source depends completely on the person who developed it, and there are no necessary "hints" that it was written in Django.
You should at least try the Django tutorial at https://www.djangoproject.com/, you'll learn the basics of setting up a Django application, and you'll answer your own question.
Django is pretty general purpose, a bit overkill for static pages. Anything else can be done in Django, the same way it can be done in Ruby on Rails or other Web frameworks.
Well, what you should do is to test the website behaviour in an unusal stiatuation, for example forcing it to return 404 or 500 error message, which developers often forget to customize.
If you for example go to http://www.galaxyzoo.org/ and then try to determine backend just by looking at HTML, you'll fail.
If, however, you try to access a page 'blablablabla' i.e. http://www.galaxyzoo.org/blablablabla then you'll see 404 message. If you paste the entrie text into google, you'll most likely get hits to Ruby On Rails... :)
Django leaves no trace on the html source unless you specifically do. If you only want a static site, django is overkill. Though if you really want to, have a look at django flatpages.
You could possibly try www.domainname.com/admin. Some people leave their admin at that url and you can see the login page.
If they left the login page as default, the title tag will say Login | Django site admin or something like that.
For example: http://www.snowbird.com/admin/ (no affiliation)
No.
Yes. See direct_to_template
See djangosites.org
I need to know the full url for the current page from within a Mako template file in Pylons.
The url will be using in an iframe contained within the page so it needs to be known when the page is being generated rather than after the page hits the server or from the environment. (Not sure if I am communicating that last bit properly)
Not sure if this is the Pylons way of doing things but ${request.url} seems to work for me.
I think you can use h.url_for('', qualified=True) to get the full URL.
Make sure you have imported url_for in your helper file: from routes.util import helpers as h
Have a look at http://pylonshq.com/docs/en/0.9.7/thirdparty/routes/#routes.util.url_for