Concatenate random element from list with user input in Python - python

I'm writing a code that allows a user to enter a city they have been to. After the user inputs it, I want my code to return a randomly generated remark about the city from my list. However, whenever I run the code, it concatenates the user input with a random letter, which is not my intention of the code.
import random
message = "Type your city here: "
#Comments to concatenate with user input
comments = [f"what a lovely {}", f"I always wanted to visit {}", "I hope you enjoyed your trip to {}"]
#While loop for user input
while True:
message = input(message)
for elem in comments:
message += random.choice(elem)
if message == "quit":
break

I assume this is what your looking for?
import random
#Comments to concatenate with user input
comments = ["what a lovely ", "I always wanted to visit ", "I hope you enjoyed your trip to "]
#While loop for user input
message = None
while message != "quit":
message = input("Type your city here: ")
print(random.choice(comments)+message)

I recommend coding a function that takes the city as input then at the end returns the list. Like this
def random_quote(city):
comments = [f"what a lovely ", f"I always wanted to visit ", "I hope you
enjoyed your trip to "]
comment = random.choice(comments)
return comment + city

random.choice() accepts a list (take a look at the docs), Don't iterate over your comments variable, pass it to random.choice() and don't forget to replace {} with the city:
city = input('Please enter a city')
comment = random.choice(comments)
comment.replace('{}', city)
print(comment)

You do not need a for loop inside your while. You should always avoid while True as it is an opening for bugs. Having a break inside a loop usually marks bad programming.
You should probably read a bit about what f-string is before using it, you also don't seem to know what random.choice does since you put it into the for which gave it the messages, which it randomly took a character out of.
import random
def main():
prompt = "Type your city here: "
# Comments to concatenate with user input
comments = ["what a lovely ", "I always wanted to visit ", "I hope you enjoyed your trip to "]
usr_input = input(prompt)
# While loop for user input
while usr_input != 'quit':
message = random.choice(comments) + usr_input
usr_input = input(prompt)
if __name__ == '__main__':
main()

Related

having trouble implementing the right word to a url link

i have a program that asks users which department they want to choose from, i made the question into a while loop that would keep asking the same question until they put a valid response in. and whenever they wanted to break the loop they would type the word "exit". once they type in a valid response it would add ask another question in another function that would ask for the class your want info on based on the department you're in, it would then lead it to a website where i can get the information i need. the issue im facing is that it doesn't take the valid response that was typed in, it would instead implement the word "exit" which was used to break out of the loop as it was the last input. i want it to take the input before that and not "EXIT"
here is the code
def get_departments():
umd_departments = requests.get("https://api.umd.io/v0/courses/departments")
umd_departments_list = umd_departments.json()
umd_departments_list2 = json.dumps(umd_departments_list, indent=1)
department_storage = [department['dept_id'] for department in umd_departments_list]#comprehensive for loop to put the department ID into a list
print(department_storage)
while True:
dept = input('what department are you in right now: ')
dept = dept.upper()
if dept == 'EXIT':
break
if dept not in department_storage:
print("not approriate response")
else:
try:
department_url = requests.get(f"https://api.umd.io/v0/courses?dept_id={dept}")
specific_major =department_url.json()
keep_keys = ["course_id"]
courses = [{k: json_dict[k] for k in keep_keys}
for json_dict in specific_major]
print(courses)
except Exception as e:
print(e)
return courses,dept
def get_classes(courses):
classes = [course['course_id'] for course in courses]
print(classes)
course_select = input('what class would you like to select').upper()
if course_select not in classes:
raise ValueError(" class does not exist")
else:
driver = webdriver.Chrome(ChromeDriverManager().install())
url = f"https://app.testudo.umd.edu/soc/202008/{dept}"
driver.get(url)
section_container = driver.find_element_by_id(f"{course_select}")
section_container.find_element_by_xpath(".//a[#class='toggle-sections-link']").click()# it would click on the show section button on the site that would reveal the sections
sleep(1)
section_info = section_container.find_element_by_xpath(".//div[#class='sections sixteen colgrid']").text
return section_info
let's say for example in the get departments function i type in INST and its considered a valid response, it would then ask for which class i want to choose from that department. it would then create a url that would get me the info i need like this:
https://app.testudo.umd.edu/soc/202008/INST
however i get this:
https://app.testudo.umd.edu/soc/202008/EXIT
the latter doesn't produce anything as it doesn't exist and it causes errors. is there a way to make it so that it doesn't make the "EXIT" input stored into a valuable and instead takes the valid response before it? greatly appreciated if anyone could help.
Looks like you just need another variable
userInput = input('what department are you in right now: ')
userInput = userInput.upper()
if userInput == 'EXIT':
break
else:
dept = userInput

Recursion with defined functions for simple text-based Python program

I'm writing my first program - it's an idiom generator, which combines individual elements from lists of random verbs, nouns, and pronouns (that I have entered) in Madlibs style and generates a humorous expression. This is a simplified version of my source code:
baseFunction = True
def mainFunction() :
import random
quest = input("Which language do you want it in? Type 'French' or 'English'. ")
if quest == "French" or "french":
verb =
#list of verbs I have manually entered
noun =
#list of nouns I have manually entered
pronoun =
#list of pronouns I have manually entered
morenouns =
#list of nouns I have manually entered
phrase = random.choice(verb) + random.choice(noun) + random.choice(pronoun) + random.choice(morenouns)
print(phrase)
print("Now, give it some meaning and use in the world!")
elif quest == "English" or "english":
verb =
#another list of verbs I have manually entered
noun =
#another list of nouns I have manually entered
pronoun =
#another list of pronouns I have manually entered
morenouns =
#another list of nouns I have manually entered
phrase = random.choice(verb) + random.choice(noun) + random.choice(pronoun) + random.choice(morenouns)
print(phrase)
print("Now, invent some meaning for it and use it in the world!")
f8 = input("Do you want to make another one? Say 'yes' if you do. ")
if f8 == "yes" or "Yes":
mainFunction()
else:
print("Thanks for playing!")
else:
print("Didn't quite catch that. Try again! (say yes!)")
mainFunction()
def malif() :
ques = input("Want to hear a funny idiom? Say 'yes' or 'no'. ")
if ques == "yes" or "Yes":
mainFunction()
elif ques == "no" or "No":
print("Wrong answer. Try again! (say yes)")
malif()
else:
print("Didn't quite catch that. Say 'yes' or 'no'.")
while baseFunction :
malif()
mainFunction()
Essentially, I am asking the user whether they want to make an idiom, offering them a choice of language, generating the expression for them, and then asking them if they want to repeat the process. When I run the script in PyCharm, it runs the two functions in order (meaning, malif() first and then mainFunction(), as I have it at the end) but it does not pay any attention to my input (ex. if I say 'no' it runs the mainFunction anyway and will always do it in French even if I say 'English').
I used some of the tips discussed in this entry (Python - How to make program go back to the top of the code instead of closing). I think the problem lies calling the functions in their own definitions (ex. calling malif() if I answer 'no' to input 'ques', which is defined in malif() ). Yet, I have followed the tips discussed in the question that I linked and it is still not working the way that I want it to. Am I doing something wrong in formatting the code (ex. in terms of indentation) or if it is not obvious what I am doing wrong, is there a way for me to loop functions back to the beginning that was not suggested in the original question?
Thanks!
First some tips when you work with strings as input. Python will make the difference between caps and non-caps letter, thus a good way to deal with strings is to lower() them first (or upper(), ...):
Example:
ques = input("Enter Yes or No: ")
ques = ques.lower()
if ques == "yes":
# do something
elif ques == "no":
# do something else
else:
# raise error
Now I feel like your code is build in a funny way. A good habit is to separate the import from the functions, from the main program. The 2 first will be imported if the module (file) is imported, while the last one will be played when the file is executed. To do so, you can use this:
# -*- coding: utf-8 -*-
"""
docstring of the module
"""
# Imports
import random
import os
# Functions
def f():
return "Hello world"
# Main program
if __name__ == '__main__':
# Calling the function, taking the inputs and so on
In the main program, it's rather useful to deal with the possibility that an exception is raised. Moreover, if you use the cmd to display your program, the cmd will close immediately when an error is raised. This syntax is quite useful:
if __name__ == '__main__':
try:
# Do stuff
except:
import sys
print (sys.exc_info()[0])
import traceback
print (traceback.format_exc())
os.system("pause") # for windows, else easy way is to have an empty input to freeze the cmd
Now your code. I would rework it this way:
# -*- coding: utf-8 -*-
"""
Docstring
"""
# Imports
import random
import os
# Functions
def build_a_phrase(language) :
if language == "french":
verb = ["vendre", "atterir", "attaquer", "jeter"]
#list of verbs I have manually entered
noun = ["arbre", "poisson", "chien"]
#list of nouns I have manually entered
pronoun = ["un", "les"]
#list of pronouns I have manually entered
morenouns = ["chat", "oiseau"]
#list of nouns I have manually entered
choices = [random.choice(verb), random.choice(noun), random.choice(pronoun), random.choice(morenouns)]
phrase = " ".join(choices) # Add a space between the words
return phrase
elif language == "english":
verb = ["...", "...", "..."]
#another list of verbs I have manually entered
noun = ["...", "...", "..."]
#another list of nouns I have manually entered
pronoun = ["...", "...", "..."]
#another list of pronouns I have manually entered
morenouns = ["...", "...", "..."]
#another list of nouns I have manually entered
choices = [random.choice(verb), random.choice(noun), random.choice(pronoun), random.choice(morenouns)]
phrase = " ".join(choices) # Add a space between the words
return phrase
if __name__ == '__main__':
try:
# Parameters
available_language = ["french", "english"]
available_answers = ["yes", "no"]
# Safety implementation of an input
quest = ""
i = 0
while quest.lower() not in available_answers:
quest = input("Want to hear a funny idiom? Say 'yes' or 'no'. ")
i += 1
if i == 2: # number of tries
break
if quest.lower() == "no":
print ("I'm sure you meant yes.")
language = ""
i = 0
while language.lower() not in available_language:
language = input("Which language do you want it in? Type 'French' or 'English'.\n")
i += 1
if i == 2: # number of tries
break
while True:
sentence = build_a_phrase(language)
print (sentence)
print ("Now, give it some meaning and use in the world!")
f8 = ""
i = 0
while f8.lower() not in available_answers:
f8 = input("Do you want to make another one? Say 'yes' if you do. ")
i += 1
if i == 2: # number of tries
break
if f8.lower() == "no":
print("Thanks for playing!")
break
except:
import sys
print (sys.exc_info()[0])
import traceback
print (traceback.format_exc())
os.system("pause")
Hope you'll get a few good tricks from this answer, and some good habits :)
Not complete yet, when the input is wrong, an Error should be raised rather than waiting for the error resulting in the wrong input (i.e. a raise statement should be placed instead of the breaks)

How to use a function's if statement to use info from another function?

So I'm designing a sign-in AI, and I want it to work so that the admin name is Shawn. Here is my issue:
The program starts with the interface -
def interface():
username = input('Hello traveler, what is your name? ')
lowerUsername = username.lower()
print()
print()
if lowerUsername == 'megan':
print()
print('So you are the one Shawn has told me so much about? You are looking beautiful today my dear ☺️🌷')
elif lowerUsername == 'shawn':
OfficialSignInEdit()
So you can see at the end that if the user inputs that their name is 'shawn' at sign-in, it calls on the OfficialSignInEdit function, which is the admin sign in. It looks like this:
def OfficialSignInEdit():
print()
if PossInputs('perio', 'What street did you grow up on?: ') == correct:
print()
print('Greetings Master Shawn, it is a pleasure to see you again πŸ™‚')
else:
print()
res1 = input('Incorrect password, try again? (Yes/No)')
lowres1 = res1.lower()
if lowres1 == 'yes':
print()
print()
OfficialSignIn()
elif lowres1 == 'no':
print()
print()
interface()
So I have pinpointed the source of my issue to be right here in this particular line:
if PossInputs('perio', 'What street did you grow up on?: ') == correct:
print()
print('Greetings Master Shawn, it is a pleasure to see you again πŸ™‚')
this (just for your reference) is the PossInputs function:
def PossInputs(x, y):
term = x
question = input(y)
lowQuestion = question.lower()
words = lowQuestion.split()
if term in words:
print()
print (correct)
else:
print()
print (incorrect)
So what I want to happen is, when 'shawn' is entered as a name, the program will jump to the OfficialSignInEdit Function, and ask the question 'What street did you grow up on?'. Then IF the user enters the answer 'perio', the program will print 'correct', and then print the message 'Greetings Master Shawn, it is a pleasure to see you again'. I tried to say that IF PossInputs == correct (and I did define correct = 'correct', and incorrect = 'incorrect' outside all functions) then this would happen, but instead it prints 'correct', and then 'Incorrect password, try again? (Yes/No)', so how can I make a conditional statement that says that if the user answers 'perio', then it will print the welcome message?
Just for thoroughness sake, I also tried
if PossInputs('perio', 'What street did you grow up on?: ') == True
also without success...
anyways anything you can give me is extremely appreciated, if you have any questions or you would like to to clarify something about the written code, I would be more than happy to get back with you as soon as I can.
Thanks!

Nested If Expression with user validation - repeating the prompt for user input

Thank you #Idor I am making some progress but I am not 100% there yet. Right now my code looks as following:
def easy_game(easy_text, parts_of_speech1):
replaced = []
easy_text = easy_text.split()
i = 0
for word in easy_text:
replacement = word_in_pos_easy(word, parts_of_speech1)
if replacement != None:
user_input = raw_input("Type in: " + replacement + " ")
word = word.replace(replacement, user_input)
while word != solutions[i]:
print "Sorry, you are wrong"
user_input = raw_input("Type in: " + replacement + " ")
print i
i = i + 1
print i
replaced.append(word)
else:
replaced.append(word)
replaced = " ".join(replaced)
print
#time.sleep(1)
print "Ok, lets see your results. Does it make sense?"
print
#time.sleep(1)
return replaced
print
#time.sleep(1)
print easy_game(easy_text, parts_of_speech1)
You can see I added the while loop. I also added an index and for troubleshooting I added print i to see what the program is doing. It still confuses me a bit or doesn't work as I would expect it. But being a newbie to programming my expectations are probably wrong. Here's what's happening:
When you enter the correct answer the program continues to question 2 and also increases i by 1
This works from beginning to end if you enter everything correctly
When you enter the wrong answer you are prompted to enter it again. Good!
However the user then gets stuck in this very question although i has been increased to the right value.
I don't really understand why the user would be stuck at this point when i has been increased, i.e. we would check at the right position in the list for the correct answer.
This is the full code of the game. I can successfully run it on my Mac but see the above behavior. Any thoughts on this by any chance? thanks in advance!
parts_of_speech1 = ["Word1", "Word2", "Word3", "Word4"]
# The following is the text for the easy text..
easy_text = "Python is a Word1 language that provides constructs intended to enable clear programs on both small and large scale. Python implementation was started in December Word2 by Guido von Rossum. The most simple Word3 in Python is Word4 and normally used at the beginning to tell Python to write 'Hello World' on the screen."
solutions = ["programming", "1989", "function", "print"]
# Checks if a word in parts_of_speech is a substring of the word passed in.
def word_in_pos_easy(word, parts_of_speech1):
for pos in parts_of_speech1:
if pos in word:
return pos
return None
# Plays a full game of mad_libs. A player is prompted to replace words in the easy text,
# which appear in parts_of_speech with their own words.
def easy_game(easy_text, parts_of_speech1):
replaced = []
easy_text = easy_text.split()
i = 0
for word in easy_text:
replacement = word_in_pos_easy(word, parts_of_speech1)
if replacement != None:
user_input = raw_input("Type in: " + replacement + " ")
word = word.replace(replacement, user_input)
while word != solutions[i]:
print "Sorry, you are wrong"
user_input = raw_input("Type in: " + replacement + " ")
print i
i = i + 1
print i
replaced.append(word)
else:
replaced.append(word)
replaced = " ".join(replaced)
print
#time.sleep(1)
print "Ok, lets see your results. Does it make sense?"
print
#time.sleep(1)
return replaced
print
#time.sleep(1)
print easy_game(easy_text, parts_of_speech1)
I am building out a quiz based on raw_input using several different list operations. I also want to validate the user input against a list before moving on to the next question in the quiz.
The function currently looks like this:
def play_game(ml_string, parts_of_speech):
replaced = []
ml_string = ml_string.split()
for word in ml_string:
replacement = word_in_pos(word, parts_of_speech)
if replacement != None:
user_input = raw_input("Type in a: " + replacement + " ")
word = word.replace(replacement, user_input)
if word != solution_list1[0]:
print "Sorry, you are wrong. Try again!"
replaced.append(word)
else:
replaced.append(word)
replaced = " ".join(replaced)
return replaced
In Line 9 I am checking against the List containing the solution words. Whereas the validation itself works the function just continues to the next question but I need it to repeat the question until getting the correct answer. I tried to reposition the different lines but simply can't get my head around it at this point in time. Where or how do I need to place the validation of the user input correctly to prompt the user for the same question again?
It seems to me that what you are looking for is a while loop.
Instead of:
if word != solution_list1[0]:
print "Sorry, you are wrong. Try again!"
Try:
while word != solution_list1[0]:
print "Sorry, you are wrong. Try again!"
user_input = raw_input("Type in a: " + replacement + " ") # ask the user again
word = word.replace(replacement, user_input)
This way the user will have to answer the question again (raw_input) until he gets it right.

Having trouble parsing a txt file into a list full of zip codes in my zipcode lookup program

Hello everyone thanks for looking into my problem. What I am trying to do is write a "Structured" program in python that takes txt from a file and parses it into lists. Then after closing the file, I need to reference the user input (zipcode) in those lists and then print out the city and state according to the zipcode that they entered. My instructor is having us use structure by making several functions. I know there are probably lots of more efficient ways of doing this, but I must keep the structure thats in place.
EDIT
Here is my code(Current):
#-----------------------------------------------------------------------
# VARIABLE DEFINITIONS
eof = False
zipRecord = ""
zipFile = ""
zipCode = []
city = []
state = []
parsedList = []
#-----------------------------------------------------------------------
# CONSTANT DEFINITIONS
USERPROMPT = "\nEnter a zip code to find (Press Enter key alone to stop): "
#-----------------------------------------------------------------------
# FUNCTION DEFINITIONS
def startUp():
global zipFile
print "zipcode lookup program".upper()
zipFile = open("zipcodes.txt","r")
loadList()
def loadList():
while readRecord():
pass
processRecords()
def readRecord():
global eof, zipList, zipCode, city, state, parsedList
zipRecord = zipFile.readline()
if zipRecord == "":
eof = True
else:
parsedList = zipRecord.split(",")
zipCode.append(parsedList[0])
city.append(parsedList[1])
state.append(parsedList[2])
eof = False
return not eof
def processRecords():
userInput = raw_input(USERPROMPT)
if userInput:
print userInput
print zipCode
if userInput in zipCode:
index_ = zipcode.index(userInput)
print "The city is %s and the state is %s " % \
(city[index_], state[index_])
else:
print "\nThe zip code does not exist."
else:
print "Please enter a data"
def closeUp():
zipFile.close()
#-----------------------------------------------------------------------
# PROGRAM'S MAIN LOGIC
startUp()
closeUp()
raw_input("\nRun complete. Press the Enter key to exit.")
Here is a sample from the zipcode txt file:
00501,HOLTSVILLE,NY
I am definitely stuck at this point and would appreciate your help in this matter.
EDIT
Thanks for all the help everyone. I really do appreciate it. :)
why you fill the lists zipcode, city , state like that, i mean in each user entry we get the next line from the file
i think that you should do :
def loadList():
# Fill all the list first , make the readRecord() return eof (True or False).
while readRecord():
pass
# than process data (check for zip code) this will run it only one time
# but you can put it in a loop to repeat the action.
processRecords()
about your problem :
def processRecords():
userInput = raw_input(USERPROMPT)
# Check if a user has entered a text or not
if userInput:
# check the index from zipcode
if userInput in zipcode:
# the index of the zipcode in the zipcode list is the same
# to get related cities and states.
index_ = zipcode.index(userInput)
print "The city is %s and the state is %s " % \
(city[index_], state[index_])
else:
print "\nThe zip code does not exist."
else:
print "Please enter a data"
one of the beauties of Python is that it's interactive. if you take processRecords() out of loadList(), and then at the bottom of your program put:
if __name__ == '__main__':
processRecords()
Then, from the command prompt, type "python". You'll get the Python shell prompt, ">>>". There you type:
from zipcodes import * # this assumes your program is zipcodes.py
dir() # shows you what's defined
print zipCode # shows you what's in zipCode
that ought to help debugging.
Strings don't have an append method like lists do. What I think you're trying to do is append the strings zipCode, city, and state to parsedList. This is the code you'd use to do that:
parsedList.append(zipCode)
parsedList.append(city)
parsedList.append(state)
Or, even more compactly:
parsedList = [zipCode, city, state]
Let me know if you get another error message and I can offer more suggestions.

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