python get changed (non-default) cli arguments? - python

Given an argument parser with n arguments, where I change the default value of only a small subset every run from the command line, is there a clean way of extracting a dict/namespace of all the non-default k,v arguments?
parser = argparse.ArgumentParser()
parser.add_argument("--a",type=str,default='a')
parser.add_argument("--b",type=str,default='b')
parser.add_argument("--c",type=str,default='c')
parser.add_argument("--d",type=str,default='d')
And
python run.py --a "e"
I would like to have
def main():
parser = argparse.ArgumentParser()
parser.add_argument("--a",type=str,default='a')
parser.add_argument("--b",type=str,default='b')
parser.add_argument("--c",type=str,default='c')
parser.add_argument("--d",type=str,default='d')
non_default = parse_non_default(parser) # non_default = {'a':'e'}

You could lookup the parser and compare which values differenciate:
import argparse
def main():
parser = argparse.ArgumentParser()
parser.add_argument("--a", type=str, default='a')
parser.add_argument("--b", type=str, default='b')
parser.add_argument("--c", type=str, default='c')
parser.add_argument("--d", type=str, default='d')
parser.add_argument("--n", type=int, default=999)
args = parser.parse_args(['--a', 'e']) # Test CLI arguments!
non_default = {
opt.dest: getattr(args, opt.dest)
for opt in parser._option_string_actions.values()
if hasattr(args, opt.dest) and opt.default != getattr(args, opt.dest)
}
print(non_default)
main()
Out:
{'a': 'e'}

Related

argparse - how to pass argument from args into function?

import argparse
from queries import most_common_cities
parser = argparse.ArgumentParser(description='A script that does operations with database data and returns values')
parser.add_argument('-c', '--most_common_cities',
nargs=1,
type=positive_int,
help='Specify how many common cities.')
args = parser.parse_args()
if args.most_common_cities:
result = most_common_cities(n) # "n" should be an arg passed by user
print(result)
How could I pass arguments from CLI to my function arg?
When someone use command:
python argp.py --most_common_cities 5
It should return 5 most common cities.
Remove nargs=1, then args.most_common_cities will be the actual value passed in.
nargs=1 wraps it in a list.
parser.add_argument('-c', '--most_common_cities',
type=int,
help='Specify how many common cities.')
args = parser.parse_args(['-c', '5'])
n = args.most_common_cities
print(n)
print(type(n))
# 5
# <class 'int'>
I started your script with following command:
python3 test.py --most_common_cities 5
You can access the arguments with:
import argparse
parser = argparse.ArgumentParser(description='A script that does operations with database data and returns values')
parser.add_argument('-c', '--most_common_cities',
nargs=1,
type=int,
help='Specify how many common cities.')
args = parser.parse_args()
arguments = vars(parser.parse_args())
print(arguments) #{'most_common_cities': [5]}
#then you can access the value with:
arguments['most_common_cities']

How to run a python script inside a python script

I have a Python script script1 that have multiple arguments which could be simplified as:
def add_vars(var1, var2, var3, var4, var5):
sum = var1+var2+var3+var4+var5
return sum
if __name__ == '__main__':
parser = argparse.ArgumentParser(formatter_class=argparse.RawTextHelpFormatter, description="""
simple addition
""")
parser.add_argument('var1', type=float, help='var1')
parser.add_argument('-var2', type=float, default=20, help='var2')
parser.add_argument('-var3', type=float, default=30, help='var3')
parser.add_argument('-var4', type=float, default=40, help='var4')
parser.add_argument('-var5', type=float, default=50, help='var5')
args = parser.parse_args()
print(args)
ss = add_vars(args.var1, args.var2, args.var3, args.var4, args.var5)
print('sum=', ss)
in which only arg1 is required and arg2-arg5 are optional.
I would like to call this script in another Python script with arg1, arg3 just like in the terminal:
script1.py 1 -var3 4
Does anyone know how to do this? I have tried os.execl but without luck.
EDIT: I'd say using subprocess wouldn't be a "better" way but this is a way you could do it?
from subprocess import check_output
out = check_output(["python", "script1.py", "1", "-var3", "4"])
print(out.decode("utf-8"))
Output:
Namespace(var1=1.0, var2=20, var3=4.0, var4=40, var5=50)
sum= 115.0
<empty line>
Original:
script1.py:
def add_vars(var1, var2=20, var3=30, var4=40, var5=50):
sum = var1+var2+var3+var4+var5
return sum
if __name__ == '__main__':
parser = argparse.ArgumentParser(formatter_class=argparse.RawTextHelpFormatter,
description="""simple addition""")
parser.add_argument('var1', type=float, help='var1')
parser.add_argument('-var2', type=float, default=20, help='var2')
parser.add_argument('-var3', type=float, default=30, help='var3')
parser.add_argument('-var4', type=float, default=40, help='var4')
parser.add_argument('-var5', type=float, default=50, help='var5')
args = parser.parse_args()
print(args)
ss = add_vars(args.var1, args.var2, args.var3, args.var4, args.var5)
print('sum=', ss)
script2.py:
import script1
print(script1.add_vars(1, var3=4))
var2=20, var3=30, var4=40, var5=50 sets the default values for the function (just like for argparse)
if __name__=='__main__'
resists your program functions to be called in other program
so you can do something like this in in other program
from script1.py import add_vars
and since you have given arg 1 and 3 default vals in the function you with other arguments so you have to be careful while passing other args , while you are in the other file
add_vars(arg1,arg3)
if you would have simply call script1.py then this would have not executed
if you have further question do add a comment i'll do make my best to answer your query
if you want to change vals of arg1 and arg3
add_vars(arg1=29,arg3=8)
you can specify them ,
so that their default value is overrided

Subparser function calls

How do I call the following functions below based on user input?
For example, if they type:
python test.py cmd1 -n hostname
it will call def cmd1 and pass the -n parameter (hostname) to function
import argparse
def cmd1(node):
print('cmd1')
def cmd1_option1():
print('cmd2')
def cmd1_option1(template):
print('cmd3')
parser = argparse.ArgumentParser()
subparsers = parser.add_subparsers(help='Functions')
command_1 = subparsers.add_parser('cmd1', help='...')
command_1.add_argument('-n', "--node", type=str, help='...')
command_2 = subparsers.add_parser('cmd2', help='...')
command_3 = subparsers.add_parser('cmd3', help='...')
command_3.add_argument('-t', "--template", type=int, help='...')
args = parser.parse_args()

How can I get an argument name from argparse?

This is my command line script
import argparse
parser = argparse.ArgumentParser('My command line app')
parser.add_argument('--start', type=start, metavar='HOST', dest='result', nargs='*', default='all', help='Start hosts')
parser.add_argument('--stop', type=stop, metavar='HOST', dest='result', nargs='*', default='all', help='Stop hosts')
parser.add_argument('--status', type=status, metavar='HOST', dest='result', nargs='*', default='all', help='Show hosts status')
args = parser.parse_args()
Currently I defined one function for each option, but I would like to wrap them in only one for these three options. Then I would need to know which argument was used. Is it possible with argparse?
Solution
At the end I took this way:
import argparse
def wrapper(command, hosts):
pass
parser = argparse.ArgumentParser('My script')
parser.add_argument('action', choices=['start', 'stop', 'status'], help='Action')
parser.add_argument('hosts', metavar='HOST', nargs='*', default='all')
args = parser.parse_args()
wrapper(args.action, args.hosts)
It sounds like the saner way to handle this would be the choices parameter:
commands = {'start': start, 'stop': stop, 'status': status}
parser = argparse.ArgumentParser('My command line app')
parser.add_argument('command', choices=commands.keys())
parser.add_argument('hosts', nargs='*', default=[])
args = parser.parse_args()
commands[args.command](*args.hosts)

python - argparse one argument instead of several others

For example I have options:
parser.add_argument('-b', action="store_true")
parser.add_argument('-c', action="store_true")
parser.add_argument('-d', action="store_true")
I want to enable all of them with synonym option "-a". Is it possible?
I think it is simplest to do this after parse_args():
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('-b', action="store_true")
parser.add_argument('-c', action="store_true")
parser.add_argument('-d', action="store_true")
parser.add_argument('-a', action="store_true")
args = parser.parse_args()
if args.a: args.b = args.c = args.d = True
Alternatively, you could do it with a custom action, but I think it is overkill:
import argparse
class AllAction(argparse.Action):
def __call__(self, parser, args, values, option_string = None):
# print '{n} {v} {o}'.format(n = args, v = values, o = option_string)
for param in ['a', 'b', 'c', 'd']:
setattr(args, param, True)
parser = argparse.ArgumentParser()
parser.add_argument('-b', action="store_true")
parser.add_argument('-c', action="store_true")
parser.add_argument('-d', action="store_true")
parser.add_argument('-a', action = AllAction, nargs = '?')
args = parser.parse_args()
print(args)

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