Only partial message sent with SMTP - python

I have an SMTP setup where I am sending emails to an email address as well as a text to an email address like this. Though the problem is the email receives the full message, which is "Phase monitor, system off" but the phone just receives "Phase monitor, system o". I've sent longer messages and it received them so I don't think it is a length issue. Any ideas why the text is different? Code below.
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
emails = ["me#gmail.com", "my_number#tmomail.net"]
server = smtplib.SMTP('smtp.office365.com', 587)
server.ehlo()
server.starttls()
server.ehlo()
server.login("username", "password")
for email in emails:
msg = MIMEMultipart()
msg['From'] = 'me#work.com'
msg['To'] = email
msg['Subject'] = 'Chiller Alarm'
body = "Phase monitor, system off"
msg.attach(MIMEText(body))
server.sendmail("me#work.com", email, msg.as_string())
server.quit()
Oddly enough, I just added 8 f's to "off" so it became "offffffff" and it sent with 6 f's. So it there's that?
Answer? When I added \n to the end of the message it sent correctly. I have no clue what is going on with this but at least it is working.

Related

Python sending email with either plain text or html, but not both

I am experimenting with sending emails using Python. I have run into a problem where I cannot send plain text and html in the body, only one or the other. If I attach both parts, only the HTML shows up, and if I comment out the HTML part, then the plain text shows up.
I'm not sure why the email can't contain both. The code looks like this:
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
username = 'email_address'
password = 'password'
def send_mail(text, subject, from_email, to_emails):
assert isinstance(to_emails, list)
msg = MIMEMultipart('alternative')
msg['From'] = from_email
msg['To'] = ', '.join(to_emails)
msg['Subject'] = subject
txt_part = MIMEText(text, 'plain')
msg.attach(txt_part)
html_part = MIMEText("<h1>This is working</h1>", 'html')
msg.attach(html_part)
msg_str = msg.as_string()
with smtplib.SMTP(host='smtp.gmail.com', port=587) as server:
server.ehlo()
server.starttls()
server.login(username, password)
server.sendmail(from_email, to_emails, msg_str)
server.quit()
I actually believe according to 7.2 The Multipart Content-Type what you coded is correct and the email client chooses whichever it believes is "best" according to its capabilities, which generally is the HTML version . Using 'mixed' causes both versions to be displayed serially (assuming the capability exists). I have observed in Microsoft Outlook that the text version becomes an attachment.
To see both serially:
Instead of:
msg = MIMEMultipart('alternative')
use:
msg = MIMEMultipart('mixed')
The server.ehlo() command is superfluous.

How to send emails programmatically and hide the sender address?

I would like to send mail notifications to my customers via python. The problem is the sender mail account needs to be hidden. Just to be clear - this is not for phishing or spamming, only personal use!
I used smtplib and setup a new 'noreply' account in gmail, but even when providing an alias to the message, the 'mail from:' header contains my actual mail.
import smtplib
from email.mime.text import MIMEText
from email.utils import *
email_sender = 'noreply%%#gmail.com'
email_receiver = 'example%%%#gmail.com'
subject = 'Python!'
msg = MIMEText('This is the body of the message.')
msg['To'] = formataddr(('Recipient', 'example%%%#gmail.com'))
msg['From'] = formataddr(('Author', 'author#example.com'))
msg['Subject'] = 'Simple test message'
connection = smtplib.SMTP('smtp.gmail.com', 587)
connection.starttls()
connection.login(email_sender, 'password')
connection.sendmail(msg['From'], email_receiver, msg.as_string())
connection.quit()
I get the mail in to my inbox as expected but when clicking 'more details' the original sender address appears.
The first argument to sendmail is the envelope sender, and should be just the email terminus, not a formatted address; so passing in msg['From'] there is doubly wrong (one, because you don't want to show it; and two, because you are passing in the entire From: header with display name and all).

Send email via python in c++

my question is whether I can send an email via python in a c++ program.
That is my actual python script.
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
# From
fromaddr = "...#gmail.com"
# To
toaddr = "..."
msg = MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = toaddr
# subject
msg['Subject'] = "..."
# Text
body = "..."
msg.attach(MIMEText(body, 'plain'))
#smtplib import
import smtplib
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.ehlo()
server.login("username", "password")
text = msg.as_string()
#send email
server.sendmail(fromaddr, toaddr, text)
My plan ist it, that I will open python and import the script via the commandline in the programm.
Is there a better way to do it?
The problem is that c++ open via system("python") the commandline, but now I have to write import mail.py in the command line.
Can I do this automaticly with an other order? I will open python, import mail and quit with one order. Is that possible?
Thank You!
Here is the program for an email.
smtpserver = smtplib.SMTP("smtp.gmail.com",587)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo()
smtpserver.login(email, password)
smtpserver.sendmail(email, recipient, text)
print 'Message Sent!'
smtpserver.close()
The variables: email is your email address, password is the password to your email, recipient is the receiver of the email, and text is the text to send.

Python smtplib security

I was experimenting with an email python script and was wondering if when writing a python-based email script is it is less secure as opposed to when credentials are send over the internet when logging into a web page? In the following script, are the user and pass in the clear?
import smtplib
from email.mime.text import MIMEText
GMAIL_LOGIN = 'xxxxxx#gmail.com'
GMAIL_PASSWORD = 'amiexposed?'
def send_email(subject, message, from_addr=GMAIL_LOGIN, to_addr=GMAIL_LOGIN):
msg = MIMEText(message)
msg['Subject'] = 'Test message'
msg['From'] = from_addr
msg['To'] = to_addr
server = smtplib.SMTP('smtp.gmail.com',587)
server.ehlo()
server.starttls()
server.ehlo()
server.login(GMAIL_LOGIN,GMAIL_PASSWORD)
server.sendmail(from_addr, to_addr, msg.as_string())
server.close()
if __name__ == '__main__':
send_email('testing email script', 'This is a test message')
That would entirely depend how the TLS connection is set up. If you are requiring valid certificates (I believe if a certificate which is not trusted is encountered, your startTLS method will throw an exception (I'm not sure you should verify this)). But considering you are setting up TLS, and sending everything over the TLS connection, everything should be encrypted. This means neither your password, username or even your message and addressees will be sent in plain text.
So no, your username and password are not send clear.

Python: "subject" not shown when sending email using smtplib module

I am successfully able to send email using the smtplib module. But when the emial is sent, it does not include the subject in the email sent.
import smtplib
SERVER = <localhost>
FROM = <from-address>
TO = [<to-addres>]
SUBJECT = "Hello!"
message = "Test"
TEXT = "This message was sent with Python's smtplib."
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
How should I write "server.sendmail" to include the SUBJECT as well in the email sent.
If I use, server.sendmail(FROM, TO, message, SUBJECT), it gives error about "smtplib.SMTPSenderRefused"
Attach it as a header:
message = 'Subject: {}\n\n{}'.format(SUBJECT, TEXT)
and then:
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
Also consider using standard Python module email - it will help you a lot while composing emails. Using it would look like this:
from email.message import EmailMessage
msg = EmailMessage()
msg['Subject'] = SUBJECT
msg['From'] = FROM
msg['To'] = TO
msg.set_content(TEXT)
server.send_message(msg)
This will work with Gmail and Python 3.6+ using the new "EmailMessage" object:
import smtplib
from email.message import EmailMessage
msg = EmailMessage()
msg.set_content('This is my message')
msg['Subject'] = 'Subject'
msg['From'] = "me#gmail.com"
msg['To'] = "you#gmail.com"
# Send the message via our own SMTP server.
server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
server.login("me#gmail.com", "password")
server.send_message(msg)
server.quit()
try this:
import smtplib
from email.mime.multipart import MIMEMultipart
msg = MIMEMultipart()
msg['From'] = 'sender_address'
msg['To'] = 'reciver_address'
msg['Subject'] = 'your_subject'
server = smtplib.SMTP('localhost')
server.sendmail('from_addr','to_addr',msg.as_string())
You should probably modify your code to something like this:
from smtplib import SMTP as smtp
from email.mime.text import MIMEText as text
s = smtp(server)
s.login(<mail-user>, <mail-pass>)
m = text(message)
m['Subject'] = 'Hello!'
m['From'] = <from-address>
m['To'] = <to-address>
s.sendmail(<from-address>, <to-address>, m.as_string())
Obviously, the <> variables need to be actual string values, or valid variables, I just filled them in as place holders. This works for me when sending messages with subjects.
See the note at the bottom of smtplib's documentation:
In general, you will want to use the email package’s features to construct an email message, which you can then convert to a string and send via sendmail(); see email: Examples.
Here's the link to the examples section of email's documentation, which indeed shows the creation of a message with a subject line. https://docs.python.org/3/library/email.examples.html
It appears that smtplib doesn't support subject addition directly and expects the msg to already be formatted with a subject, etc. That's where the email module comes in.
import smtplib
# creates SMTP session
List item
s = smtplib.SMTP('smtp.gmail.com', 587)
# start TLS for security
s.starttls()
# Authentication
s.login("login mail ID", "password")
# message to be sent
SUBJECT = "Subject"
TEXT = "Message body"
message = 'Subject: {}\n\n{}'.format(SUBJECT, TEXT)
# sending the mail
s.sendmail("from", "to", message)
# terminating the session
s.quit()
I think you have to include it in the message:
import smtplib
message = """From: From Person <from#fromdomain.com>
To: To Person <to#todomain.com>
MIME-Version: 1.0
Content-type: text/html
Subject: SMTP HTML e-mail test
This is an e-mail message to be sent in HTML format
<b>This is HTML message.</b>
<h1>This is headline.</h1>
"""
try:
smtpObj = smtplib.SMTP('localhost')
smtpObj.sendmail(sender, receivers, message)
print "Successfully sent email"
except SMTPException:
print "Error: unable to send email"
code from: http://www.tutorialspoint.com/python/python_sending_email.htm
In case of wrapping it in a function, this should work as a template.
def send_email(login, password, destinations, subject, message):
server = smtplib.SMTP_SSL("smtp.gmail.com", 465)
server.login(login, password)
message = 'Subject: {}\n\n{}'.format(subject, message)
for destination in destinations:
print("Sending email to:", destination)
server.sendmail(login, destinations, message)
server.quit()
try this out :
from = "myemail#site.com"
to= "someemail#site.com"
subject = "Hello there!"
body = "Have a good day."
message = "Subject:" + subject + "\n" + body
server.sendmail(from, , message)
server.quit()

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