I am working with the bot-auth sample and after having the user logged in I need to be able to interact with the user, in my case I would like to start with an echo. I can't find a way to end the dialog and for the bot to start answering the user. Could you guide me with an example or ideas? Thanks
I wouldn't need to show the token, so at this point it would be enough for me to finish here and start interacting with the user
main_dialog.py
async def login_step(self, step_context: WaterfallStepContext) -> DialogTurnResult:
# Get the token from the previous step. Note that we could also have gotten the
# token directly from the prompt itself. There is an example of this in the next method.
if step_context.result:
await step_context.context.send_activity("You are now logged in.")
return await step_context.prompt(
ConfirmPrompt.__name__,
PromptOptions(
prompt=MessageFactory.text("Would you like to view your token?")
),
)
await step_context.context.send_activity(
"Login was not successful please try again."
)
return await step_context.end_dialog()
I could achieve my goal, which was once finished the login of the user to start, e.g, using a echo_bot or qna_bot. The problem is that I couldn't get out of the login-show token dialog loop. The solution "I found" is to create a user_state.create_property() in main_dialog.py and access properties defined get(turn_context) in dialog_bot.py. With this I was able to leave the dialogue.
Related
#events.register(events.NewMessage(chats='tubot'))
async def mi_handler(event):
client = event.client
if 'A big' in event.raw_text:
async for message in client.iter_messages('tubot', limit=1, from_user='tubot'):
await message.click(0)
url = event.message.buttons[0][0].url
print(url)
await event.client.send_message('mybot', url.split('=')[1])
This code does something to me that had never happened to me before:
The code should do is: when the message appears in the ¨tubot¨, it should press the button and unlock the url, then a part of that url will send it to my bot called ¨mybot¨.
BUT:
when the message arrives in ´tubot´ the code click on the button and unlock the url, but it does not forward it to ´mybot´.
however when that message with the button already unlocked I manually forward it to "tubot" the code does forward it perfectly to ´mybot´
I have tried the following:
1- await asyncio.sleep(0.2) put an await between clicking on the button and reading the url and nothing didn't work.
2- even separate the code into two parts, one that clicks the button and another that forwards and nothing did not work
3- I made a group I put the code to click on the 'tubot' message and forward it to the group and another code that reads the message in that group with the button already unlocked and forwards the url to 'mybot' and nothing did not work. Even in the group, if I forward the message with the unlocked button, it reads me the url perfectly and it forwards me perfectly to 'mybot' but if it does the code doesn't work
So I'm getting an issue here where I'm trying to make a status check command to check if a user is online, offline, idle, or dnd, if they are on mobile or desktop, and maybe even their custom status. However, my main problem is seeing if a user is online/offline or whatever. It seems to always return 'offline' even though I know I'm not offline. Here's my code (currently its just printing to console to see)
#client.command(name="status")
async def status(ctx, user: discord.Member=None):
if not user:
user = ctx.message.author
print(user)
print(user.raw_status)
However when I initiate this command it always returns 'offline', and I haven't been able to figure out why. I've tried: user.status, user.raw_status, user.desktop_status, and just in case it was being weird or I didn't understand it, mobile_status (I'm on desktop.) If anyone has a fix to this please let me know, thanks!
If you haven't added intents to your bot, then you cannot deal with user statuses in a server. Head to "https://discord.com/developers/applications//bot" and under "Privileged Gateway Intents" tick "PRESENCE INTENT" and "SERVER MEMBERS INTENT". This will allow the bot to request presence data from users in the server.
In your bot's code, add
from discord import Intents
client = commands.Bot(command_prefix=YOUR_PREFIX, intents = Intents.all())
I want to write a simple slack bot, which responds a given string to # mentions, however I am not able to make the official documentation code to work.
I gave all OAuth permission to the bot and have the following code:
from slack import RTMClient
#RTMClient.run_on(event="message")
def gravity_bot(**payload):
data = payload['data']
print(data.get('text'))
try:
rtm_client = RTMClient(
token="my_token_auth_code",
connect_method='rtm.start'
)
print("Bot is up and running!")
rtm_client.start()
except Exception as err:
print(err)
I think the connection is established, as the "Bot is up and running" message appears, however on the slack channel to bot seems to be offline, also I am not able to get any response in the terminal, not for direct messages, not for channel messages even after inviting the bot to given channels.
Sorry couldn't let this one go.. I figured it out and here are the steps:
Create a "Classic" app in Slack (this is the only way to get the appropriate scopes), just click this link: https://api.slack.com/apps?new_classic_app=1
From the "Add features and functionality" tab click on "bots":
Click the "Add Legacy Bot User" button (this will add the "rtm.stream" scope that you need, but that you cannot add manually)
From the basic information page, install your app in a workspace
From the OAuth & Permissions page, copy the "Bot User OAuth Access Token" (the bottom one)
Run the following code (slightly modified version of the code in the docs)
from slack_sdk.rtm import RTMClient
# This event runs when the connection is established and shows some connection info
#RTMClient.run_on(event="open")
def show_start(**payload):
print(payload)
#RTMClient.run_on(event="message")
def say_hello(**payload):
print(payload)
data = payload['data']
web_client = payload['web_client']
if 'Hello' in data['text']:
channel_id = data['channel']
thread_ts = data['ts']
user = data['user']
web_client.chat_postMessage(
channel=channel_id,
text=f"Hi <#{user}>!",
thread_ts=thread_ts
)
if __name__ == "__main__":
slack_token = "<YOUR TOKEN HERE>"
rtm_client = RTMClient(token=slack_token)
rtm_client.start()
Previous answer:
Hmm, this is tricky one... According to the docs this only works for "classic" Slack apps, so that might be the first pointer. It explicitly says that you should not upgrade your app. Furthermore, you'll need to set the right permissions (god knows which ones) by selecting the "bot" scope.
Honestly, I haven't been able to get this running. Looks like Slack is getting rid of this connection method, so you might have more luck looking into the "Events API". I know it's not the ideal solution because its not as real-time, but it looks better documented and it will stay around for a while. Another approach could be polling. Its not sexy but it works...
My guess is that your problem is that there is not a valid connection, but there is no proper error handling in the Slack library. The message is printed before you actually connect, so that doesn't indicate anything.
Say, I have this tiny flask app if the user has a valid token when he posts something I give him something else. When he doesn't I want to silently drop his connection. How do I do that?
Here's some sample code to help you visualize what I want to do
#app.route("/do_action", methods=('POST',))
def do_action():
if request.form['TOKEN'] not in valid_tokens:
drop_connection() # how?
else:
return get_action_result()
To be clear, I don't want to throw an error or politely close the connection I want to just drop the user request, let him hit the timeout.
if you have logout method implemented in your application, You can direct the user to logout return redirect("url for logout")
I'm using python-telegram-bot (python-telegram-bot.org) to communicate with Telegram from Python3
I would like to update the last reply I sent.
Currently, the code below sends the message and then sends
another message 5 seconds later.
def echo(bot, update):
update.message.reply_text("Sorry, you're on your own, kiddo.")
time.sleep(5)
update.message.reply_text("Seriously, you're on your own, kiddo.")
I'd like to update the last message instead.
I tried
bot.editMessageText("Seriously, you're on your own, kiddo.",
chat_id=update.message.chat_id,
message_id=update.message.message_id)
which works in the examples to update replace an inline keyboard with a a message, but that crashes (and does not update the last message I sent as a bot).
I believe the order of your arguments in edit_message_text() is wrong. Check out the docs for that:
def echo(bot, update):
# Any send_* methods return the sent message object
msg = update.message.reply_text("Sorry, you're on your own, kiddo.")
time.sleep(5)
# you can explicitly enter the details
bot.edit_message_text(chat_id=update.message.chat_id,
message_id=msg.message_id,
text="Seriously, you're on your own, kiddo.")
# or use the shortcut (which pre-enters the chat_id and message_id behind)
msg.edit_text("Seriously, you're on your own, kiddo.")
The docs for the shortcut message.edit_text() is here.