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How to click the follow button on Instagram?

I am trying to click the follow button on Instagram using Python Selenium
https://www.instagram.com/luvly_zuby/?hl=en
I've tried the bellow code but it's not working.
#click follow
follow = driver.find_element_by_partial_link_text("Follo")
ActionChains(driver).move_to_element(follow).click().perform()

You can click on the element by using simple selenium click by finding the element using its text in the xpath and then using explicit wait on the element.
You can do it like:
follow_button = WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.XPATH, "//button[text()='Follow']")))
follow_button.click()
You need to add the following imports:
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

This should work for you. Pass the WebElement to click(element) method.
from selenium import webdriver
driver = webdriver.Chrome()
driver.get('testUrl')
follow = driver.find_element(By.XPATH, '//button[contains(text(),'Follow')]')
webdriver.ActionChains(driver).move_to_element(follow).click(follow).perform()

Try to find the element using this css selector a.BY3EC > button and wait using .element_to_be_clickable:
follow = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, 'a.BY3EC > button')))
follow.click()
Following import:
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

Python Selenium element is not visible [duplicate]

I am trying to enter username and password in the following website:
https://www.thegreatcoursesplus.com/sign-in
driver = webdriver.Chrome()
driver.get('https://www.TheGreatCoursesPlus.com/sign-in')
driver.find_element_by_xpath('//h1[#class="sign-in-input"]').click()
This gave following exception:
selenium.common.exceptions.ElementNotVisibleException: Message: element not visible
Then I tried to use java script:
driver.execute_script("document.getElementsByClassName('sign-in-input')[0].click()")
cmd = "document.getElementsByClassName('label-focus')[0].value = 'abc#abc.com'"
driver.execute_script(cmd)
There are no errors but no text is sent to "Email Address" field.
Can someone please guide me on the correct way to enter email address, password and then click "Sign-in".

This error message...
selenium.common.exceptions.ElementNotVisibleException: Message: element not visible
...implies that the desired element was not visible within the HTML DOM while the WebDriver instance was trying to find it.
ElementNotVisibleException
ElementNotVisibleException is thrown when an element is present on the DOM Tree, but it is not visible, and so is not able to be interacted with.
Reason
One possitive take away from ElementNotVisibleException is the fact that the WebElement is present within the HTML and this exception is commonly encountered when trying to click() or read an attribute of an element that is hidden from view.
Solution
As ElementNotVisibleException ensures that the WebElement is present within the HTML so the solution ahead would be two folds as per the next steps as detailed below:
If you next step is to read any attribute of the desired element, then you need to induce WebDriverWait in-conjunction with expected_conditions clause set to visibility_of_element_located as follows:
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
my_value = WebDriverWait(driver, 10).until(EC.visibility_of_element_located((By.XPATH, "element_xpath"))).get_attribute("innerHTML")
If you next step is to invoke click() on the desired element, then you need to induce WebDriverWait in-conjunction with expected_conditions clause set to element_to_be_clickable as follows:
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "element_xpath"))).click()
This usecase
The xpath you constructed as //h1[#class="sign-in-input"] doesn't match any node. We need to create unique xpath to locate the elements representing Email Address, Password and Sign In button inducing WebDriverWait. The below code block will help you to achieve the same:
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
options = Options()
options.add_argument("start-maximized")
options.add_argument("disable-infobars")
options.add_argument("--disable-extensions")
driver = webdriver.Chrome(chrome_options=options, executable_path="C:\\Utility\\BrowserDrivers\\chromedriver.exe")
driver.get('https://www.TheGreatCoursesPlus.com/sign-in')
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//div[#id='modal']//input[#name='email']"))).send_keys("abc#abc.com")
driver.find_element_by_xpath("//div[#id='modal']//input[#name='password']").send_keys("password")
driver.find_element_by_xpath("//div[#id='modal']//button[#class='color-site sign-in-button']").click()

for username use :
driver.find_element_by_xpath("//input(#type='email')").click()
driver.find_element_by_xpath("//input(#type='email')").send_keys( "username" )
for password use :
driver.find_element_by_xpath("//input(#type='password')").click()
driver.find_element_by_xpath("//input(#type='password')").send_keys( "password" )

There are two problems:
The first one is timing, it takes some time for the form to appear. You you can use explicit wait to solve it.
The second one is that the field id in <input> tag, not <h1> tag, and there are many fields that matches this xpath. I suggest you locate the form holding the fields and use it to locate each field
For the timing issue you can use explicit wait
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome()
driver.get('https://www.TheGreatCoursesPlus.com/sign-in')
form = WebDriverWait(driver, 10).until(EC.visibility_of_element_located((By.XPATH, '//div[#class="modal-body"]//form')))
form.find_element_by_name('email').send_keys(email)
form.find_element_by_name('password').send_keys(password)
form.find_element_by_name('sign-in-button').click()

How to fix "SyntaxError: Failed to execute 'evaluate' on 'Document':"?

I am trying to copy the xpath of an element, but it keeps saying that the xpath is incorrect
Here is the code I have done:
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://www.bol.com/nl/v/bananago-nl/1067588/")
x = driver.find_element_by_xpath("//*[#id=js_overview']/ul/li[2]/div/div[2]/p/text()[2]")
print(x)
The element I am trying to copy is the text that says "12 beoordelingen". Let me know if you need any more information

You are missing the initial single quote in 'js_overview'.

To get the Text 12 beoordelingen you need to induce WebDriverWait and element_to_be_clickable() to get the element and then
Induce JavaScripts Exceutor execute_script() and get the lastChild textContent .
Try below code.
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://www.bol.com/nl/v/bananago-nl/1067588/")
element=WebDriverWait(driver,20).until(EC.element_to_be_clickable((By.XPATH,"//div[#id='js_overview']//div[#class='media__body']/p")))
print(driver.execute_script('return arguments[0].lastChild.textContent;', element))

Selenium Can't find element when using find_element through Python

Keep getting unable to locate element error message.
The first find element by xpath was fine, but the second one is giving me a hard time.
Here is my code:
import XLUtils
from selenium import webdriver
driver=webdriver.Chrome(executable_path="C:\Chrome_Driver\Chromedriver.exe")
driver.get("https://www.canada.ca/en/revenue-agency/services/e-services/e-services-businesses/payroll-deductions-online-calculator.html")
driver.find_element_by_xpath('/html/body/main/div[1]/div[7]/p/a[1]').click()
driver.find_element_by_xpath('//*[#id="welcome_button_next"]').click()

You'll need to wait a bit for the Next button to appear.
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
wait = WebDriverWait(driver, 10)
e = wait.until(
EC.presence_of_element_located((By.XPATH, '//*[#id="welcome_button_next"]'))
)
e.click()

To click on the element with text as Next you need to induce WebDriverWait for the element to be clickable and you can use either of the following solutions:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input.btn.btn-primary#welcome_button_next"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#class='btn btn-primary' and #id="welcome_button_next"]"))).click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

WebDriverWait on finding element by CSS Selector

I want to retrieve the price of the flight of this webpage using Python 3: https://www.google.es/flights?lite=0#flt=/m/0h3tv./m/04jpl.2018-12-17;c:EUR;e:1;a:FR;sd:1;t:f;tt:o
At first I got an error which after many hours I realized was due to the fact that I wasn't giving the webdriver enough time to load all elements. So to ensure that it had enough time I added a time.sleep like so:
time.sleep(1)
This made it work! However, I've read and was advised to not use this solution and to use WebDriverWait instead. So after many hours and several tutorials im stuck trying to pinpoint the exact CSS class the WebDriverWait should wait for.
The closest I think I've got is:
WebDriverWait(d, 1).until(EC.presence_of_element_located((By.CSS_SELECTOR, ".flt-subhead1.gws-flights-results__price.gws-flights-results__cheapest-price")))
Any ideas on what I'm missing on?

You could use a css attribute = value selector to target, or if that value is dynamic you can use a css selector combination to positional match.
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome()
driver.get("https://www.google.es/flights?lite=0#flt=/m/0h3tv./m/04jpl.2018-12-17;c:EUR;e:1;a:FR;sd:1;t:f;tt:o")
#element = WebDriverWait(driver, 5).until(EC.presence_of_element_located((By.CSS_SELECTOR , '[jstcache="9322"]')))
element = WebDriverWait(driver, 5).until(EC.presence_of_element_located((By.CSS_SELECTOR , '.flt-subhead1.gws-flights-results__price.gws-flights-results__cheapest-price span + jsl')))
print(element.text)
#driver.quit()
No results case:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
driver = webdriver.Chrome()
url ="https://www.google.es/flights?lite=0#flt=/m/0h3tv./m/04jpl.2018-12-17;c:EUR;e:1;a:FR;sd:1;t:f;tt:o" #"https://www.google.es/flights?lite=0#flt=/m/0h3tv./m/04jpl.2018-11-28;c:EUR;e:1;a:FR;sd:1;t:f;tt:o"
driver.get(url)
try:
status = WebDriverWait(driver, 5).until(EC.presence_of_element_located((By.CSS_SELECTOR , 'p[role=status')))
print(status.text)
except TimeoutException as e:
element = WebDriverWait(driver, 5).until(EC.presence_of_element_located((By.CSS_SELECTOR , '.flt-subhead1.gws-flights-results__price.gws-flights-results__cheapest-price span + jsl')))
print(element.text)
#driver.quit()

I may be wrong but I think you are trying to get the price of the flight trip.
If my assumption is correct, take a look at my approach. I find the Search Results list, then all the Itinerary inside the Search Results list, loop over and get all the price information. This is the best approach I can come up with and avoiding all the dynamic attributes
from selenium.webdriver import Chrome
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
wait = 20
driver = Chrome()
driver.get("https://www.google.es/flights?lite=0#flt=/m/0h3tv./m/04jpl.2018-12-17;c:EUR;e:1;a:FR;sd:1;t:f;tt:o")
# Get the Search Result List
search_results= WebDriverWait(driver, wait).until(EC.presence_of_element_located((By.CSS_SELECTOR , 'ol[class="gws-flights-results__result-list"]')))
# loop through all the Itinerary
for result in search_results.find_elements_by_css_selector('div[class*="gws-flights-results__collapsed-itinerary"]'):
price = result.find_element_by_css_selector('div[class="gws-flights-results__itinerary-price"]')
print(price.text)
Output
€18