I build a website using Django and I need to add functionality to edit every peace of every page blocks on a site. I found Wagtail and read the docs about how to integrate it and thought of the way to integrate it via django views, like this (main is an app name):
main/pages.py:
...
class IndexPage(Page):
header_title = models.CharField(...)
header_subtitle = models.CharField(...)
...
main/views.py:
...
def view_index(request):
pages = Page.objects.all()
page = pages.filter(...) # somehow filter index page
return render(
request,
'index.html',
context={'page': page.specific},
content_type='text/html')
...
Is it good way to use Wagtail pages and integrate it into existing Django views this way? Could any surprises be found along the way?
Finally decided to use a StreamField. StreamField could be used to build a Page, like this:
main/pages.py:
class IndexPage(Page):
content = StreamField([
('title', blocks.CharBlock()),
('subtitle', blocks.CharBlock()),
...
])
IndexPage is a Model in Django terms (so we have a simple DB table) & content is stored like a list of JSON's. This two things gave our team an understanding to use it the way we want. To use it in a Django view this code could be used:
main/views.py:
...
def index_view(request):
page = IndexPage.objects.all().first()
return {
'content': unify(page.content),
}
unify - a special method to create a dict from content, because a content is an array where a title live inside content[0], subtitle - inside content[1], etc... Indices could be randomly rearranged, that's why unify is important to use. After unify have applied we can use a content in a template via attribute {{ content.title }}, {{ content.subtitle }}, etc...
Related
I have created a Custom view in Admin Panel with this code in admin.py. I want the sometemplate.html template to have the information in the same UI format just like when I click on another model in the admin panel, and that information needs to be a combination of rows from multiple models. So, the data is displayed in this custom view will have all the entries from multiple models with valid = False
How can I do that in my custom view of Django admin?
class DummyModelAdmin(admin.ModelAdmin):
model = DummyModel
def my_custom_view(self,request):
# return HttpResponse('Admin Custom View')
context = dict(
)
return TemplateResponse(request, "webapp/sometemplate.html", context)
def get_urls(self):
view_name = '{}_{}_changelist'.format(
self.model._meta.app_label, self.model._meta.model_name)
return [
path('my_admin_path/', self.my_custom_view, name=view_name),
]
admin.site.register(DummyModel, DummyModelAdmin)
sometemplate.html code:
{% extends "admin/base_site.html" %}
{% block content %}
{% endblock %}
You could try and use django-polymorphic where you define one common base model, in their example Project, that is inherited by the models ArtProject and ResearchProject, and a queryset of the base model contains instances of the base model and all models that inherit from it. Example from the docs:
>>> Project.objects.all()
[ <Project: id 1, topic "Department Party">,
<ArtProject: id 2, topic "Painting with Tim", artist "T. Turner">,
<ResearchProject: id 3, topic "Swallow Aerodynamics", supervisor "Dr. >Winter"> ]
It also provides some useful model admin classes to display parent and child models in one list view. A lot of the django admin functionalities are preserved.
If you don't need any of that, you are probably better off writing the view on your own. Django admin is useful to bring some data fast to the screen, but it can get very complicated when you try to get around the default way of doing things.
Im trying to use Django Suit's form includes to add a button to the list display of all my subscribers in the admin. In the documentation it says to add this to your admin.py file in the right app.
class SubscriberAdmin(admin.ModelAdmin):
list_display = ('email', 'date')
readonly_fields = ('email', 'date')
def has_add_permission(self, request):
return False
suit_form_includes = (
('admin/suit_includes/suit_csv.html', 'top'),
)
However this only appears when clicking into an instance of an object, and doesn't show up on the admin page that shows the entire list of objects in the database. Is there a way to do this with Django Suit ? I had trouble finding anything on google.
suit form include template:
<button class="btn btn-info">Export to File</button>
Admin instance display (Where its appearing):
Admin list display (Where I want it to appear):
What's doing django-suit, here, is that it is including your HTML snippet in the change_form that is displayed for your model, the change_form being where you can modify your model and save the changes into the database.
Where you want it to appear is the "change_list", aka the place where you can see all of your instances of that model in your database.
To add it your html snippet, you should extend your change_list.html with your own snippet : More info on expanding templates in the official documentation
Good luck !
There is a common case I encounter, where I can't find a way to split apps.
The case is when a info of two models is related and needs to be in the same template
An example speaks 1000 words: (2 models - pages + comments).
# models.py
class Page(models.Model):
title = models.CharField()
content = models.TextField()
class Comment(models.Model):
page = models.ForeignKey('Page')
content = models.TextField()
# url.py
...
url(r'^page/(?P<page_pk>\d+)/$', views.ViewPage, name='page-view-no-comments'),
url(r'^comment/(?P<comment_pk>\d+)/$', views.ViewComment, name='comment-view'),
url(r'^page-with-comments/(?P<page_pk>\d+)/$', views.ViewPageWithComments, name='page-view-with-comments'),
...
# views.py
def ViewPage(request, page_pk):
page = get_object_or_404(Page, pk=page_pk)
return render(request, 'view_page.html', {'page':page,})
def ViewComment(request, comment_pk):
comment = get_object_or_404(Comment, pk=comment_pk)
return render(request, 'view_comment.html', {'comment':comment})
def ViewPageWithComments(request, page_pk):
page = get_object_or_404(Page, pk=page_pk)
page_comments = Comment.objects.filter(page=page)
return render(request, 'view_page.html', {'page':page,'page_comments':page_comments'})
In this situation, splitting to Page app and Comment app is problematic, because they share a view (ViewPageWithComments) and url.
My options are:
1) Create an Ajax call to comments, which has crawling problems although Google might have fixed it lately.
2) Create a method of page that calls a method in the comments app that returns html with the comments content. If the method needs more arguments I also need to write a custom filter tag.
3) Decide not to split...
Am I missing something and there's another option? When would you prefer (1) vs (2) ?
Note - I created a very simple example to keep the problem general.
You don't need to split anything, you have the pages, and comments have a foreign key to that so you can just iterate over the pages comments
{% for page in pages %}
{% for comment in page.comment_set.all %}
{% endfor}
{% endfor %}
If you want to be able to use the same template for a version of this page without comments you can just wrap the comment for loop in an {% if show_comments %} statement
I am running a Django website and I want to be able to upload a file through my admin panel and then have visitors to the main site be able to download it. I am running my site using Django-nonrel, Django FileTransfers and Google App Engine. I believe the upload functionality is working correctly as I am able to see the file in my App Engine Blob Storage. What I can't seem to figure out is how to present a download link to the specified file on the public website. I have pasted the relevant classes below:
I have an app called Calendar, that has the following model:
class CalendarEvent (models.Model):
start = models.DateTimeField(auto_now=False, auto_now_add=False)
end = models.DateTimeField(auto_now=False, auto_now_add=False)
title = models.CharField(max_length=500)
description = models.TextField()
file = models.FileField(upload_to='uploads/%Y/%m/%d/%H/%M/%S/')
Here is the view:
def calendar(request):
events = CalendarEvent.objects.exclude(start__lt=datetime.datetime.now()).order_by('start')
return render_to_response('home/calendar.html',{'events': events},context_instance=RequestContext(request))
def download_handler(request, pk):
upload = get_object_or_404(CalendarEvent, pk=pk)
return serve_file(request, upload.file, save_as=True)
Here is my admin:
class calendarAdmin(admin.ModelAdmin):
list_display = ('title','start','end')
admin.site.register(CalendarEvent, calendarAdmin)
Finally, here is the relevant part of my template:
{% for e in events %}
{% url Calendar.views.download_handler pk=e.pk as fallback_url %}
Download
{% endfor %}
{% firstof e.file|public_download_url fallback_url %} is just returning blank, i'm not sure where I am going wrong.
The GAE blob store does not support public download according to the documentation here, so if you use the default backend for public download urls, it returns None. So my guess is that e.file|public_download_url always return None. You could verify that.
Then I think your template is wrong. You're trying to access e.views.download_handler where it should be Calendar.views.download_handler if your app is named Calendar.
I think the sample on the django-filetransfers page is error prone because the variable used in the template loop has the same name as the sample app: "upload".
If this doesn't fix it, could you post your urls.py from Calendar app. It could be that the template's url method is not able to resolve the url for Calendar.views.download_handler if there is no mapping in urlpatterns.
You should have something like
urlpatterns = patterns('Calendar.views',
...
(r'^download/(?P<pk>.+)$', 'download_handler'),
...
)
in this file.
I don't see anything special, eg
Download File
should work, or just use e.file.url directly?
I haven't deployed on Google App Engine myself, but this appears to be what django-filetransfers was designed for:
http://www.allbuttonspressed.com/projects/django-filetransfers#handling-downloads
edit: I believe I've answered this in the other question you posted, then: Trouble downlaoding file using Django FileTransfers
I think easiest way is to write a view since this file blob cannot be retrieved directly to write a function which is such:
def file_transfer(req, calendar_event_id):
try:
ce = CalendarEvent.objects.get(calendar_event_id)
except CalendarEvent.DoesNotExist:
raise Http404()
file = ce.file (Write Google appengine specfic routine to pull file)
return HttpResponse(file, media_type='file content type')
Hook it up on urls.py
How can I create a widget on the site, such as login forms, dynamic menu (items taken from the database), site statistics?
I know that you can render a template that will extend out of a base template. And in the base template you can create these widgets.
But I do not know how to move the logic from the base template to my code. For example, the selection data for the block. Such actions certainly can be done in the template, but it would be a poor method in my opinion.
Sorry for my bad English. If you can not understand, I'll try to rephrase.
You would use a python library called WTForms. It helps you write code for creating forms and other widgets backed by database which you can render using jinja2 templates.
class YourForm(Form):
your_field1 = TextField()
....
your_fieldn = SubmitField()
#app.route('/')
def view():
form=YourForm()
return render_template('your.html', form=form)
In your.html
<form >
{{ form.your_field1 }}
....
{{ form.your_fieldn }}
</form>
Check out this flask pattern for form validation and rendering to know more about it.
Edit: To create global variables available to all templates,there are two ways:
You can use global dict of jinja environment.
This is the code:
app.jinja_env.globals.update({'variable':1})
You can use ContextProcessor. Code:
#app.context_processor
def inject_variable():
return dict(variable=1)
Now you can access variable in any template of your app.