Python mocking the right class/import - python

I am trying to implement unittests for my python program. The problem is, that my program is using several imported classes, which I would like to replace by a mocked object/class to verify single functions/methods.
I do not get any errors with my mocked class. But it appears that the mock itself didn't replace the object I wanted to replace.
This is basically my structure:
First the class I want to mock. Might look like that:
class ToMock():
def getSomething(self):
return "something"
The class I want to test looks like this:
from x.y import ToMock
class ClassToTest():
def __init__(self):
self.obj = ToMock()
def returnStuff():
return self.obj.getSomething()
As you can imagine, I want to test the returnStuff method. Therfore I want to mock .getSomething, or better said the whole ToMock object.
The unittest should therefore test the ClassToTest with the mocked ToMock class. I tried several mock.patch variants, but I couldn't get it to run/test properly.
import unittest
from unittest import mock
from a.b import ClassToTest
class TestObject(unittest.TestCase):
def setUp(self):
with mock.patch('x.y.ToMock') as mock_obj:
mock_obj.return_value.getSomething().return_value="mocked return value"
self.test_class = ClassToTest()
result = self.test_class.returnStuff() # This should return now 'mocked return value', I guess?
mock_obj.return_value.getSomething.assert_called_once_with("")
The problem I face is, that the self.test_class.returnStuff() is not "calling" the mocked object, but imports the real class etc. and therefore I am running into timeouts, or similar stuff.
I am sure, that I provide the wrong path for the object which should be mocked. Perhaps someone can hint me into the right direction.
Thanks
-GreNait

The issue is that you are not patching in the correct place. You are patching where the object is defined as opposed to where it is looked up.
a.py
-> Defines ToMock
b.py
-> from a import ToMock
-> some_function/class instantiates ToMock
In your code shown you are patching a.ToMock however you should be patching b.ToMock. That is why it is not running your mock object when testing. You can read more about where to patch here.

Related

python unittest.mock.patch strange behaviour

I use unittest in my testing. I import a class in yhab.main package as...
from yhab.blah import SomeClass
def some_func():
some_instance = SomeClass()
return some_instance.method()
yhab.blah.SomeClass is defined as...
class SomeClass:
def method(self):
return 'hello'
And then I write a test like this...
#mock.patch('yhab.blah.SomeClass')
def test_mock_of_blah_someclass(mock_some_class):
assert some_func() != 'hello'
the invocation of method() calls the real instance, not a mock.
But if I do this...
#mock.patch('yhab.main.SomeClass')
def test_mock_of_main_someclass(mock_some_class):
assert some_func() != 'hello'
the invocation of method() calls the mock, not the real instance and the test passes.
Why is that?
I was thinking that python must make some sort of copy of the class definition when an import happens, but I wrote a test that proves that to not be the case.
The docs say the following, which kind of eludes to this, but it doesn't really say it outright, and IMO doesn't really explain it, especially for a python newb...
Patching a class replaces the class with a MagicMock instance. If the
class is instantiated in the code under test then it will be the
return_value of the mock that will be used.
Do the docs need to be updated to be clear?
After you import SomeClass from yhab.blah, it ends up in the yhab.main namespace, not in the yhab.blah namespace.
Try to use #mock.patch('yhab.main.SomeClass') instead of #mock.patch('yhab.blah.SomeClass').

Unittest and mocks, how to reset them?

I am testing a class that needs a mock in the constructor, so I usually do this:
class TestActionManager(unittest.TestCase):
#patch('actionlib.SimpleActionClient', return_value=create_autospec(actionlib.SimpleActionClient))
def setUp(self, mock1):
self.action_manager = ActionManager()
Then in this class I add all the tests. So the first one is working fine
def test_1(self):
self.action_manager.f()
self.action_manager.f.assert_called_once()
But if I add another test and run both
def test_2(self):
self.action_manager.f()
self.action_manager.f.assert_called_once()
It says f has been called twice. I was expecting setUp to create a new ActionManager (and hence create a new mock) before starting every test, but it is clearly not happening, since the mock is somehow shared. Also I tried to do
def tearDown(self):
del self.action_manager
But it does not fix the problem.
I have read something related in
Python Testing - Reset all mocks?
where the solution is to use a different library (something that I would like to avoid)
and in Any way to reset a mocked method to its original state? - Python Mock - mock 1.0b1 where it is using different classes to do it.
Is there any possibility to reset the mock in the same class before or after every test?
BTW, this is a unittest question, not a pytest question.
Anyways,
I believe what you're looking for is reset_mock
Here's, in general, how it works:
def test_1(self):
f = MagicMock() # or whatever you're mocking
f()
f.assert_called_once()
f.reset_mock()
f()
f.assert_called_once()
The result will be PASSED
If you want to automate, then you store the mocked thing inside setUp, and in tearDown you call the mocked thing's .reset_mock() method.
def setUp(self, mock1):
self.mock1 = mock1
# ... do other things ...
def tearDown(self):
self.mock1.reset_mock()

Python 2.7 mock a void method of a class

I am trying to use unittests.mock to mock a void method call of an object.
My package is like below
common
baseupgradehandler.py
baseupgradehandler.py
class BaseUpgradeHandler(object):
def __init__(self, upgrade_config, upgrade_state, system_config, pre_step, main_step, post_step):
...
# Method call to be supressed
def start(self, service_manifest, upgrade_bundle):
# type: (service_version_pb2.ServiceManifest, str) -> ()
...
In my test code I am trying to mock the call to start() like below as explained in the documentation.
from workflow.upgradeworkflow import UpgradeWorkflow
from common.serviceregistry import ServiceRegistry
# The above imports are at the start of the test file
...
with patch('common.baseupgradehandler.BaseUpgradeHandler') as handler_mock: # type: Mock
handler_mock.return_value.start.return_value = ''
wf = UpgradeWorkflow(ServiceRegistry(self.service_bundle, config, sys_config, state),
config,
state,
sys_config)
BaseUpgradeHandler object is returned by get_upgrade_handler() method of ServiceRegistry. When I am executing the above code in test I am seeing the BaseUpgradeHandler.start() is still getting called.
Can someone let me know how can I mock the call to a start() so that the method is not called?
EDIT
If I change my patching code like below it is working as expected and BaseUpgradeHandler is getting mocked and start is not getting called.
with patch('common.baseupgradehandler.BaseUpgradeHandler') as handler_mock: # type: Mock
handler_mock.return_value.start.return_value = ''
with patch('common.serviceregistry.ServiceRegistry') as serviceregistry_mock: # type: Mock
serviceregistry_mock.return_value.get_upgrade_handler.return_value = handler_mock
wf = UpgradeWorkflow(ServiceRegistry(self.service_bundle, config, sys_config, state), config, state, sys_config)
wf.start()
Can someone explain me why do I have to patch ServiceRegistry as well?
The code you provided is not enough to see the part that causes the issue. We'd need to see the module serviceregistry to be sure but I'd take an educated guess:
You have a file a.py (aka baseupgradehandler) like this:
class A:
def method(self):
print("It's real!")
And a file b.py (aka serviceregistry) like this:
from a import A
class B:
def get_A(self):
return A()
In your test files you do this:
import unittest
from unittest.mock import patch
from b import B
from a import A
GAME OVER!
The B module right now has already got its reference to the original A class. When, afterwards, you patch('a.A') only the reference in the a module is changed, but patch has no way to know that B has its own reference to the original A.
You can fix this in three ways:
patch the method: this will modify the existing class so all references to that class will be automatically patched
patch b.A too:
with patch('a.A') as h_a, patch('b.A') as h_b:
h_a.return_value.method.return_value = ''
h_b.return_value.method.return_value = ''
Avoid importing the modules before patching (probably not feasible or a good idea):
import unittest
from unittest.mock import patch
class MyTest(unittest.TestCase):
def test_one(self):
with patch('a.A') as h:
h.return_value.method.return_value = ''
from b import B
B().get_A().method()
I have been using unittest.mocks for a while, and I have been re-inventing the wheel sometimes. I decided to make mockito part of my project and now things look way better. Any kind of mock verification is really simple, if you can, I definitively encourage you to make mockito part of your libraries. This library has a good documentation and so far it has been easier than unittest.mock IMHO.

unittest blacklist namespace and fail any attempt to reference it

in the case of unit testing a wrapper library, testing the wrapper without depending/exercising the upstream library is a goal; In a known case, all calls to the upstream library can be mocked and that's what I've done, but I've been frustrated by changes to the wrapper that introduce more calls to the upstream library being missed by the mock tools;
How can I best fail any test that tries to use a given namespace?
My idea currently is to change all the unittest methods to have a monkey patch like
#unittest.mock.patch('wrapper_namespace.upsteam_namespace')
and reply the upstream library with a mock that can be asserted untouched; I'm hoping for an option that works globally, so that I
don't have to add a monkeypatch to every test method, though this level of granularity is acceptable; but also don't have to perform the assertion that the mock was never used in the test methods (or make a decorator to do all that either)
prohibits access to the upstream library from any part of the software
(e.g, Wrapper calls B calls Upstream, B's call to upstream might not be caught)
You don't have to patch every test method. You can easily patch over the class if you're using unittest, or just assign the module to whatever you want to patch over it with. Here's a workable example:
A fake lib in some_lib.py:
def some_lib_func():
raise ValueError("I've been called.")
def some_other_lib_func():
raise ValueError("I've been called.")
class SomeClass:
def __init__(self):
raise ValueError("I've been constructed.")
wrapper.py:
import some_lib
def wrapper1():
some_lib.some_lib_func()
def wrapper2():
some_lib.some_other_lib_func()
def wrapper3():
x = some_lib.SomeClass()
test.py:
from unittest.mock import patch, MagicMock
import unittest
import wrapper
# Alternative:
# wrapper.some_lib = MagicMock()
# Can patch an entire class
#patch('wrapper.some_lib', MagicMock())
class TestWrapper(unittest.TestCase):
def test_wrapper1(self):
wrapper.wrapper1()
def test_wrapper2(self):
wrapper.wrapper2()
def test_wrapper3(self):
wrapper.wrapper3()
if __name__ == "__main__":
unittest.main()
We would explode if the functions/classes in some_lib were called, but they aren't:
Matthews-MacBook-Pro:stackoverflow matt$ python test.py
...
----------------------------------------------------------------------
Ran 3 tests in 0.001s
OK
Feel free to comment out the patch and comment in wrapper.some_lib = MagicMock(). You'll get the same result in this toy example, but there is a major difference between the two approaches:
When using #patch('wrapper.some_lib', MagicMock()) the patch is only live for that Test Case class.
When using wrapper.some_lib = MagicMock(), however, that patch will stay live for the entire length of your python program, unless you save off the original module and patch it back manually at some point. Everything that is using the wrapper module will get the mocked version.
So you could so something like:
original_lib = wrapper.some_lib
wrapper.some_lib = MagicMock()
...
# call some test suite, every call to the wrapper module will be mocked out
...
wrapper.some_lib = original_lib
...
# call some other test suite that actually needs the real thing
...
HTH.
EDIT: Misread your question slightly, but you can inspect MagicMock objects to see if they've been called, and if so, fail the test. Or just patch over with something that fails when called (instead of MagicMock). I can provide code to do this if requested (just leave a comment), but hopefully the above can get you started. I think the crux of the question was really about the global patching. Cheers!

Mocking a function in another file and a class in a second other file

I'm noticing that the class methods are being mocked out properly, but the function is bypassing the mock and running the actual function.
from module1 import myClass
from module2 import my_function
import unittest
from mock import patch
class TestStuff(unittest.TestCase):
#patch('module2.my_function')
#patch('module1.myClass.my_method')
def test_my_function(self, mock_method, mock_function):
test_obj = myClass()
test_obj.my_method()
assert mock_method.called
my_function()
assert mock_function.called
if I print out my_function() and type(my_function) it will not show the mock, but the real function. Does it matter that I'm importing a class then mocking a method, but I'm importing the function directly?
I think I found the issue:
When I'm testing a function, and there's something I want to mock, I should not import it. Importing it causes it to get used, even if I've put the patch decorator.
I think this was general confusion about how mocking/testing works. What I wanted to do was to test a function without actually querying the database. Instead of mocking out the whole function, I could take the line that actually hits the db - query.all() - and make it it's own function, then mock that out.
from module1 import myClass
from module2 import my_function
import unittest
from mock import patch
class TestStuff(unittest.TestCase):
#patch('module2.db_query')
#patch('module1.myClass.my_method')
def test_my_function(self, mock_method, mock_db_query):
test_obj = myClass()
test_obj.my_method()
assert mock_method.called
my_function() # my_function calls db_query(), now mocked out
assert mock_db_query.called
If I had wanted to actually mock out the all of my_function, I could have just not imported it. At least that's how I'm understanding this at the moment.
I ran into a similar issue. Turns out I needed to give it the FULL path to my_function:
#patch('home.myuser.myprojects.mymodule.myfunc')

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