I am currently working on a project where my goal is to get the game scores for each NCAA mens basketball game. In order to do this, I need to use the python package sportsreference. I need to use two dataframes, one called df which has the game date and one called box_index (shown below) which has the unique link of each game. I need to get the date column replaced by the unique link of each game. These unique links start with the date (formatted exactly as in the date column of df), which makes it easier to do this with regex or the .contains(). I keep getting a Keyerror: 0 error. Can someone help me figure out what is wrong with my logic below?
from sportsreference.ncaab.schedule import Schedule
def get_team_schedule(name):
combined =Schedule(name).dataframe
box_index = combined["boxscore_index"]
box = box_index.to_frame()
#print(box)
for i in range(len(df)):
for j in range(len(box)):
if box.loc[i,"boxscore_index"].contains(df.loc[i, "date"]):
df.loc[i,"date"] = box.loc[i,"boxscore_index"]
get_team_schedule("Virginia")
It seems like "box" and "df" are pandas data frame, and since you are iterating through all the rows, it may be more efficient to use iterrows (instead of searching by index with ".loc")
for i, row_df in df.iterrows():
for j, row_box in box.iterrows():
if row_box["boxscore_index"].contains(row_df["date"]):
df.at[i, 'date'] = row_box["boxscore_index"]
the ".at" function will overwrite the value at a given cell
Just fyi, iterrows is more efficient than .loc., however itertuples is about 10x faster, and zip about 100xs.
The Keyerror: 0 error is saying you can't get that row at index 0, because there is no index value of 0 using box.loc[i,"boxscore_index"] (the index values are the dates, for example '2020-12-22-14-virginia'). You could use .iloc. though, like box.iloc[i]["boxscore_index"]. You'd have to convert all the .loc to that.
Like the other post said though, I wouldn't go that path. I actually wouldn't even use iterrows here. I would put the box_index into a list, then iterarte through that. Then use pandas to filter your df dataframe. I'm sort of making some assumptions of what df looks like, so if this doesn't work, or not what you looking to do, please share some sample rows of df:
from sportsreference.ncaab.schedule import Schedule
def get_team_schedule(name):
combined = Schedule(name).dataframe
box_index_list = list(combined["boxscore_index"])
for box_index in box_index_list:
temp_game_data = df[df["date"] == boxscore_index]
print(box_index)
print(temp_game_data,'\n')
get_team_schedule("Virginia")
Related
I have the following for loop for a dataframe
# this is my data
df=yf.download('AAPL', period='max', interval='1d' )
vwap15 = []
for i in range(0,len(df)-1):
if(i>=15):
vwap15.append(sum(df["Close"][i-15:i]*df["Volume"][i-15:i])/sum(df["Volume"][i-15:i]))
else:
vwap15.append(None)
When I created the above for loop it generated a list.
I actually want to have it as a dataframe that I can join to my original dataframe df
any insights would be appreciated
thanks
Maybe you mean something like (right after the loop):
df["vwap15"] = vwap15
Note that you will need to fix your for loop like so (otherwise lengths will not match):
for i in range(len(df)):
Maybe you want to have a look at currently available packages for Technical Analysis indicators in Python with Pandas.
Also, try to use NaN instead of None and consider using the Pandas .rolling method when computing indicators over a time window.
I'm not entirely sure why I am getting this error as I have a very simple dataframe that I am currently working with. Here is a sample of the dataframe (the date column is the index):
date
News
2021-02-01
This is a news headline. This is a news summary.
2021-02-02
This is another headline. This is another summary
So basically, all I am trying to do is loop through the dataframe one row at a time and pull the News item, use the Sentiment Intensity Analyzer on it and store the compound value into a separate list (which I am appending to an empty list). However, when I run the loop, it gives me this error:
Length of values (5085) does not match the length of index (2675)
Here is a sample of the code that I have so far:
sia = SentimentIntensityAnalyzer()
news_sentiment_list = []
for i in range (0, (df_news.shape[0]-1)):
n = df_news.iloc[i][0]
news_sentiment_list.append(sia.polarity_scores(n)['compound'])
df['News Sentiment'] = news_sentiment_list
I've tried the loop statement a number of different ways using the FOR loop, and I always return that error. I am honestly lost at this point =(
edit: The shape of the dataframe is: (5087, 1)
The target dataframe is df whereas you loop on df_news, the indexes are probably not the same. You might need to merge the dataframes before doing so.
Moreover, there is an easier approach to your problem that would avoid having to loop on it. Assuming your dataframe df_news holds the column News (as shown on your table), you can add a column to this dataframe simply by doing:
sia = SentimentIntensityAnalyzer()
df_news['News Sentiment'] = df_news['News'].apply(lambda x: sia.polarity_scores(x)['compound'])
A general rule when using pandas is to avoid as much as possible using for-loops, except when you have a very specific edge case panda's built-in methods will be sufficient.
New to python, trying to take a csv and get the country that has the max number of gold medals. I can get the country name as a type Index but need a string value for the submission.
csv has rows of countries as the indices, and columns with stats.
ind = DataFrame.index.get_loc(index_result) doesn't work because it doesn't have a valid key.
If I run dataframe.loc[ind], it returns the entire row.
df = read_csv('csv', index_col=0,skiprows=1)
for loop to get the most gold medals:
mostMedals= iterator
getIndex = (df[df['medals' == mostMedals]).index #check the column medals
#for mostMedals cell to see what country won that many
ind = dataframe.index.get_loc[getIndex] #doesn't like the key
What I'm going for is to get the index position of the getIndex so I can run something like dataframe.index[getIndex] and that will give me the string I need but I can't figure out how to get that index position integer.
Expanding on my comments above, this is how I would approach it. There may be better/other ways, pandas is a pretty enormous library with lots of neat functionality that I don't know yet, either!
df = read_csv('csv', index_col=0,skiprows=1)
max_medals = df['medals'].max()
countries = list(df.where(df['medals'] == max_medals).dropna().index)
Unpacking that expression, the where method returns a frame based on df that matches the condition expressed. dropna() tells us to remove any rows that are NaN values, and index returns the remaining row index. Finally, I wrap that all in list, which isn't strictly necessary but I prefer working with simple built-in types unless I have a greater need.
I'm a beginner in panda and python, trying to learn it.
I would like to iterate over panda rows, to apply simple coded logic.
Instead of fancy mapping functions, I just want simple coded logic.
So then I can easily adapt it later for other coded logic rules as well.
In my dataframe dc,
I like to check if column AgeUnkown == 1 (or >0 )
And if so it should move the value of column Age to AgeUnknown.
And then make Age equal to 0.0
I tried various combinations of my below code but it won't work.
# using a row reference #########
for index, row in dc.iterrows():
r = row['AgeUnknown']
if (r>0):
w = dc.at[index,'Age']
dc.at[index,'AgeUnknown']=w
dc.at[index,'Age']=0
Another attempt
for index in dc.index:
r = dc.at[index,'AgeUnknown'].[0] # also tried .sum here
if (r>0):
w= dc.at[index,'Age']
dc.at[index,'AgeUnknown']=w
dc.at[index,'Age']=0
Also tried
if(dc[index,'Age']>0 #wasnt allowed either
Why isn't this working as far as I understood a dataframe should be able to be addressed like above.
I realize you requested a solution involving iterating the df, but I thought I'd provide one that I think is more traditional.
A non-iterating solution to your problem is something like this- 1) get all the indexes that meet your criteria 2) set those indexes of the df to what you want.
# indexes where column AgeUnknown is >0
inds = dc[dc['AgeUnknown'] > 0].index.tolist()
# change the indexes of AgeUnknown to to the Age column
dc.loc[inds, 'AgeUnknown'] = dc.loc[inds, 'Age']
# change the Age to 0 at those indexes
dc.loc[inds, 'Age'] = 0
Say I construct a dataframe with pandas, having multi-indexed columns:
mi = pd.MultiIndex.from_product([['trial_1', 'trial_2', 'trial_3'], ['motor_neuron','afferent_neuron','interneuron'], ['time','voltage','calcium']])
ind = np.arange(1,11)
df = pd.DataFrame(np.random.randn(10,27),index=ind, columns=mi)
Link to image of output dataframe
Say I want only the voltage data from trial 1. I know that the following code fails, because the indices are not sorted lexically:
idx = pd.IndexSlice
df.loc[:,idx['trial_1',:,'voltage']]
As explained in another post, the solution is to sort the dataframe's indices, which works as expected:
dfSorted = df.sortlevel(axis=1)
dfSorted.loc[:,idx['trial_1',:,'voltage']]
I understand why this is necessary. However, say I want to add a new column:
dfSorted.loc[:,('trial_1','interneuron','scaledTime')] = 100 * dfSorted.loc[:,('trial_1','interneuron','time')]
Now dfSorted is not sorted anymore, since the new column was tacked onto the end, rather than snuggled into order. Again, I have to call sortlevel before selecting multiple columns.
I feel this makes for repetitive, bug-prone code, especially when adding lots of columns to the much bigger dataframe in my own project. Is there a (preferably clean-looking) way of inserting new columns in lexical order without having to call sortlevel over and over again?
One approach would be to use filter which does a text filter on the column names:
In [117]: df['trial_1'].filter(like='voltage')
Out[117]:
motor_neuron afferent_neuron interneuron
voltage voltage voltage
1 -0.548699 0.986121 -1.339783
2 -1.320589 -0.509410 -0.529686