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Python get multiple specific keys and values from list of dictionaries

I have the following data:
data={
"locations": [
{
"id": "27871f2d-101c-449e-87ad-36a663b144fe",
"switch_id": 20,
"switch_port": 16,
"vlan_id": 101,
},
{
"id": "94b1d7a2-7ff2-4ba3-8259-5eb7ddd09fe1",
"switch_id": 6,
"switch_port": 24,
"vlan_id": 203,
},
]
}
And what I want to do is extract 'id' and 'vlan_id' into a new dictionary with a list of sub dictionaries, like this:
new_data={
"connections": [
{
"id": "27871f2d-101c-449e-87ad-36a663b144fe",
"vlan_id": 101,
},
{
"id": "94b1d7a2-7ff2-4ba3-8259-5eb7ddd09fe1",
"vlan_id": 203,
},
]
}
My initial thoughts were as a dictionary comprehension like this:
new_data = {"connections": [some code here]}
But not sure of the some code bit yet.

Try:
new_data = {"connections": [{'id': d['id'], 'vlan_id': d['vlan_id']} for d in data['locations']]}
{'connections': [{'id': '27871f2d-101c-449e-87ad-36a663b144fe', 'vlan_id': 101}, {'id': '94b1d7a2-7ff2-4ba3-8259-5eb7ddd09fe1', 'vlan_id': 203}]}

You can create the new_data variable accesing the first dictionary data like this:
new_data={
"connections": [
{
"id": data['locations'][0]['id'],
"vlan_id": data['locations'][0]['vlan_id'],
},
{
"id": data['locations'][1]['id'],
"vlan_id": data['locations'][1]['vlan_id'],
},
]
}
edit:
You can get a more dynamic approach by reading every object in the list with a forloop like this:
new_data={
"connections": []
}
for object in data['locations']:
new_dict = {
"id": object["id"],
"vlan_id": object["vlan_id"]
}
new_data['connections'].append(new_dict)

Following Marc's answer here, you could modify it to
new_data = {}
for i in range(len(data['locations'])):
if "connections" not in new_data.keys():
new_data['connections'] = [{"id": data['locations'][i]['id'],"vlan_id": data['locations'][i]['vlan_id']}]
else:
new_data['connections'].append({"id": data['locations'][i]['id'],"vlan_id": data['locations'][i]['vlan_id']})

The Answers here are good but you can make the code more dynamic
keys_to_extract = ['id', 'vlan_id']
locations = data['locations']
connections = { key: val for key, val in locations.items() if key in keys_to_extract }
new_data = {'connections': connections}
Now you can change the keys you need on the fly

How to get the values of dictionary python?

I have the below python dictionary stored as dictPython
{
"paging": {"count": 10, "start": 0, "links": []},
"elements": [
{
"organizationalTarget~": {
"vanityName": "vv",
"localizedName": "ViV",
"name": {
"localized": {"en_US": "ViV"},
"preferredLocale": {"country": "US", "language": "en"},
},
"primaryOrganizationType": "NONE",
"locations": [],
"id": 109,
},
"role": "ADMINISTRATOR",
},
],
}
I need to get the values of vanityName, localizedName and also the values from name->localized and name->preferredLocale.
I tried dictPython.keys() and it returned dict_keys(['paging', 'elements']).
Also I tried dictPython.values() and it returned me what is inside of the parenthesis({}).
I need to get [vv, ViV, ViV, US, en]

I am writing this in a form of answer, so I can get to explain it better without the comments characters limit
a dict in python is an efficient key/value structure or data type
for example dict_ = {'key1': 'val1', 'key2': 'val2'} to fetch key1 we can do it in 2 different ways
dict_.get(key1) this returns the value of the key in this case val1, this method has its advantage, that if the key1 is wrong or not found it returns None so no exceptions are raised. You can do dict_.get(key1, 'returning this string if the key is not found')
dict_['key1'] doing the same .get(...) but will raise a KeyError if the key is not found
So to answer your question after this introduction,
a dict can be thought of as nested dictionaries and/or objects inside of one another
to get your values you can do the following
# Fetch base dictionary to make code more readable
base_dict = dict_["elements"][0]["organizationalTarget~"]
# fetch name_dict following the same approach as above code
name_dict = base_dict["name"]
localized_dict = name_dict["localized"]
preferred_locale_dict = name_dict ["preferredLocale"]
so now we fetch all of the wanted data in their corresponding locations from your given dictionary, now to print the results, we can do the following
results_arr = []
for key1, key2 in zip(localized_dict, preferredLocale_dict):
results_arr.append(localized_dict.get(key1))
results_arr.append(preferred_locale_dict.get(key2))
print(results_arr)

What about:
dic = {
"paging": {"count": 10, "start": 0, "links": []},
"elements": [
{
"organizationalTarget~": {
"vanityName": "vv",
"localizedName": "ViV",
"name": {
"localized": {"en_US": "ViV"},
"preferredLocale": {"country": "US", "language": "en"},
},
"primaryOrganizationType": "NONE",
"locations": [],
"id": 109,
},
"role": "ADMINISTRATOR",
},
],
}
base = dic["elements"][0]["organizationalTarget~"]
c = base["name"]["localized"]
d = base["name"]["preferredLocale"]
output = [base["vanityName"], base["localizedName"]]
output.extend([c[key] for key in c])
output.extend([d[key] for key in d])
print(output)
outputs:
['vv', 'ViV', 'ViV', 'US', 'en']

So something like this?
[[x['organizationalTarget~']['vanityName'],
x['organizationalTarget~']['localizedName'],
x['organizationalTarget~']['name']['localized']['en_US'],
x['organizationalTarget~']['name']['preferredLocale']['country'],
x['organizationalTarget~']['name']['preferredLocale']['language'],
] for x in s['elements']]

How can I fetch specific information for a dictionary thats in an api

So I am writing a code that can give me certain information. The url https://api.brawlhalla.com/player/28472387/ranked?api_key=MY_API_KEY
provides information about my profile. When print it in text I get
{
"name": "Twitter: ufrz_",
"brawlhalla_id": 28472387,
"rating": 2093,
"peak_rating": 2110,
"tier": "Diamond",
"wins": 140,
"games": 257,
"region": "US-E",
"global_rank": 0,
"region_rank": 0,
"legends": [
{
"legend_id": 3,
"legend_name_key": "bodvar",
"rating": 870,
"peak_rating": 870,
"tier": "Tin 4",
"wins": 2,
"games": 4
},
{
"legend_id": 4,
"legend_name_key": "cassidy",
"rating": 968,
"peak_rating": 968,
"tier": "Bronze 2",
"wins": 0,
"games": 0
},
{
"legend_id": 5,
"legend_name_key": "orion",
"rating": 1131,
"peak_rating": 1131,
"tier": "Silver 1",
"wins": 1,
"games": 3
},
(not the full page.)
Here is the code I used to fetch this
import requests
url = "https://api.brawlhalla.com/player/28472387/ranked?api_key= MY_API_KEY"
r = requests.get(url)
print(r.text)
Now for example how would I go about fetching my rating and not the actual word but the number "2093" I tried someway but they didn't work. I am using bs4 and request and new to both so I really don't know how I would get this.
(Just want to say sorry for poorly worded question I don't really know how word my issue so my apologies in advance)

First of all, you have to convert your result to a json object:
data = r.json()
Then, you can request using data['rating']
For your question :
how would I go about getting the ranking for the legend_key_name "bodvar" how could I specifically get that legends ranking.
for legend in data['legends']:
if legend['legend_name_key'] == "bovdar"
print(legend['rating'])
return legend['rating']
or using a function :
def getLegendByName(data, legendName):
for legend in data['legends']:
if legend['legend_name_key'] == legendName:
return legend
return None
legendName = "bodvar"
data = r.json()
legend = getLegendByName(data, legendName)
if legend is not None:
legendRating = legend['rating']
else
print("There is no legend that exists with this name"

Json to Python converting

I have this sample json data, and need to grab only the MAC addresses so I can convert the mac to a list of manufacturers later.
[
{
"aps": {
"00:20:90:B3:16:25": {
"ssid": "",
"encryption": "Open",
"hidden": 1,
"channel": 11,
"signal": -23,
"wps": 0,
"last_seen": 1594356454,
"clients": []
},
"06:AA:A0:84:7F:D8": {
"ssid": "",
"encryption": "Open",
"hidden": 1,
"channel": 6,
"signal": -75,
"wps": 0,
"last_seen": 1594356452,
"clients": []
},
"1E:51:A4:D4:B7:29": {
"ssid": "",
"encryption": "WPA Mixed PSK (CCMP TKIP)",
"hidden": 1,
"channel": 11,
"signal": -63,
"wps": 0,
"last_seen": 1594356448,
"clients": []
}
}
}
]
This is my python program so far, but im not sure how to isolate the MAC address
import json
f = open('recon_data.json',)
data = json.load(f)
print(data["aps"])
f.close()
I get an error every time I run the program weather im asking for aps or ssid information
Traceback (most recent call last):
File "recon.py", line 12, in
print(data["ssid"])
TypeError: list indices must be integers or slices, not str

This is because the data you're loading is a list. Try data[0]["aps"]
As for getting all the mac addresses they are the keys in that dict so you can just use list on that inner dict to get all the keys:
import json
with open('recon_data.json') as f
data = json.load(f)
print(list(data[0]['aps']))
This will print a list of all the MAC addresses
['00:20:90:B3:16:25', '06:AA:A0:84:7F:D8', '1E:51:A4:D4:B7:29']

Index JSON searches python

I have the next JSON that I get from a URL:
[{
"id": 1,
"version": 23,
"external_id": "2312",
"url": "https://example.com/432",
"type": "typeA",
"date": "2",
"notes": "notes",
"title": "title",
"abstract": "dsadasdas",
"details": "something",
"accuracy": 0,
"reliability": 0,
"severity": 12,
"thing": "32132",
"other": [
"aaaaaaaaaaaaaaaaaa",
"bbbbbbbbbbbbbb",
"cccccccccccccccc",
"dddddddddddddd",
"eeeeeeeeee"
],
"nana": 8
},
{
"id": 2,
"version": 23,
"external_id": "2312",
"url": "https://example.com/432",
"type": "typeA",
"date": "2",
"notes": "notes",
"title": "title",
"abstract": "dsadasdas",
"details": "something",
"accuracy": 0,
"reliability": 0,
"severity": 12,
"thing": "32132",
"other": [
"aaaaaaaaaaaaaaaaaa",
"bbbbbbbbbbbbbb",
"cccccccccccccccc",
"dddddddddddddd",
"eeeeeeeeee"
],
"nana": 8
}]
My code:
import json
import urllib2
data = json.load(urllib2.urlopen('http://someurl/path/to/json'))
print data
I want to know how to access to the part "abstract" of the object that has "id" equal to 2 for example. The part "id" is unique so I can use id to index my searchs.
Thanks!

Here's one way to do it. You can create a generator via a generator expression, call next to iterate that generator once, and get back the desired object.
item = next((item for item in data if item['id'] == 2), None)
if item:
print item['abstract']
See also Python: get a dict from a list based on something inside the dict
EDIT : If you'd like access to all elements of the list that have a given key value (for example, id == 2) you can do one of two things. You can either create a list via comprehension (as shown in the other answer), or you can alter my solution:
my_gen = (item for item in data if item['id'] == 2)
for item in my_gen:
print item
In the loop, item will iterate over those items in your list which satisfy the given condition (here, id == 2).

You can use list comprehention to filter:
import json
j = """[{"id":1,"version":23,"external_id":"2312","url":"https://example.com/432","type":"typeA","date":"2","notes":"notes","title":"title","abstract":"dsadasdas","details":"something","accuracy":0,"reliability":0,"severity":12,"thing":"32132","other":["aaaaaaaaaaaaaaaaaa","bbbbbbbbbbbbbb","cccccccccccccccc","dddddddddddddd","eeeeeeeeee"],"nana":8},{"id":2,"version":23,"external_id":"2312","url":"https://example.com/432","type":"typeA","date":"2","notes":"notes","title":"title","abstract":"dsadasdas","details":"something","accuracy":0,"reliability":0,"severity":12,"thing":"32132","other":["aaaaaaaaaaaaaaaaaa","bbbbbbbbbbbbbb","cccccccccccccccc","dddddddddddddd","eeeeeeeeee"],"nana":8}]"""
dicto = json.loads(j)
results = [x for x in dicto if "id" in x and x["id"]==2]
And then you can print the 'abstract' values like so:
for result in results:
if "abstract" in result:
print result["abstract"]

import urllib2
import json
data = json.load(urllib2.urlopen('http://someurl/path/to/json'))
your_id = raw_input('enter the id')
for each in data:
if each['id'] == your_id:
print each['abstract']
In the above code data is list and each is a dict you can easily access the dict object.