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Shuffle a copy of a list [duplicate]

This question already has an answer here:
How to properly copy a list in python
(1 answer)
Closed 2 years ago.
It seems that the copy of a list is shuffled too?
So if I do for 2 lists:
data = examples
np.random.shuffle(examples)
then the list data is also shuffled? Why?

Python doesn't create copies of objects when it thinks they're not needed.
In your case you can use built-in copy module:
import copy
data = copy.deepcopy(examples)
np.random.shuffle(examples)

You have to do examples = np.copy(data) because otherwise the two variables will reference the same position in memory meaning they both change.

Generating Variable Name Dynamically In Python 3 [duplicate]

This question already has answers here:
How do I create variable variables?
(17 answers)
Closed 3 years ago.
I'm porting some Python 2 code to Python 3
I know this code snippet is bad practice, but I am looking for a way replace the exec() calls. I basically get "None" back, as predicted by the migration documents. I tried eval() but I get syntax error messages.
What are the alternatives dynamically generating variable names?
value = "test"
for field in ['overviewSynopsis', 'callsToAction_productLevel']:
exec(field +'_value = ""')
exec(field +'_value = value')
print(exec(field + "_value"))

Use a dictionary instead. You can map a key name to a value.

Possible to convert string to a named variable or alternative? [duplicate]

This question already has answers here:
How do I create variable variables?
(17 answers)
How can I create multiple variables from a list of strings? [duplicate]
(2 answers)
generating variable names on fly in python [duplicate]
(6 answers)
Closed 3 years ago.
I have a ticker and I want to check a specific list of tickers to see if the ticker is found. If it is found, it will replace it.
The new tickers come from another data source and therefore do not know which specific list of tickers to check. In order to find that list, I can pass the lists name as a string but upon iterating the code (naturally) recognizes this as string as opposed to a list to iterate.
Is there a way to have the code/function recognize that the string is actually a specific list to be checked? In reading other questions, I know this may not be possible...in that case what is an alternative?
list_1=['A','B']
list_2=['C','D']
old_ticker='A'
new_ticker='E'
assigned_list='list_1'
def replace_ticker(old_ticker,new_ticker,list):
for ticker in list:
if new_ticker in list:
return
else:
list.append(new_ticker)
list.remove(old_ticker)
replace_ticker(old_ticker,new_ticker,assigned_list)

You key the needed lists by name in a dictionary:
ticker_directory = {
"list_1": list_1,
"list_2": list_2
}
Now you can accept the name and get the desired list as ticker_directory[assigned_list].

list_1=['A','B']
list_2=['C','D']
lists = {
'list_1':list_1,
'list_2':list_2
}
old_ticker='A'
new_ticker='E'
assigned_list='list_1'
def replace_ticker(old_ticker,new_ticker,list_name):
if old_ticker not in lists[list_name]:
return
else:
lists[list_name].append(new_ticker)
lists[list_name].remove(old_ticker)
replace_ticker(old_ticker,new_ticker,assigned_list)
print(lists[assigned_list])
This is the complete program from what i perceived.
#prune already answered this, I have just given the whole solution

There are at least two possibilities:
1 As noted in comments kind of overkill but possible:
Use eval() to evaluate string as python expressions more in the link:
https://thepythonguru.com/python-builtin-functions/eval/
For example:
list_name = 'list_1'
eval('{}.append(new_ticker)'.format(list_name))
2 Second
Using locals() a dictionary of locally scoped variables similiar to the other answers but without the need of creating the dict by hand which also requires the knowledge of all variables names.
list_name = 'list_1'
locals()[list_name].append(new_ticker)

(Python) Can I store the functions themselves, but not their value, in a list [duplicate]

This question already has answers here:
Python Argument Binders
(7 answers)
Closed 8 months ago.
As you can see from the code below, I'm adding a series of functions to a list.
The result is that each function gets ran and the returned value is added to the list.
foo_list = []
foo_list.append(bar.func1(100))
foo_list.append(bar.func2([7,7,7,9]))
foo_list.append(bar.func3(r'C:\Users\user\desktop\output'))
What I would like to know is, is it possible to have the function stored in the list and then ran when it is iterated upon in a for loop?

Yeah just use lambda:
foo_list = []
foo_list.append(lambda: bar.func1(100))
foo_list.append(lambda: bar.func2([7,7,7,9]))
foo_list.append(lambda: bar.func3(r'C:\Users\user\desktop\output'))
for foo in foo_list:
print(foo())

How do I organize a map In Python [duplicate]

This question already has answers here:
How do I sort a dictionary by value?
(34 answers)
Closed 6 years ago.
I am new to python and I am just beginning to learn the syntax. I would like to create a map (like in java but I understand that they may be called something else in python) so I would assume the code might look something like this
map = {}
map.append("somestring": 12)
map.append("anotherstring": 10)
map.append("yetanotherstring": 15)
'''
then organize the map by the numbers from largest to smallest
so if I were to then run through the map with a for loop it would
print
"yetanotherString" : 15
"somestring" : 12
"anotherstring" : 10
'''
I am clueless In almost every step of this process from declaring a "map" to organizing it by the ints. Though organizing it by the ints is my biggest problem.

They're called dictionaries!
Try like this:
pythonDict = {}
pythonDict['somestring'] = 12
See more in http://learnpythonthehardway.org/book/ex39.html
To learn more about iterating through the dictionary see https://docs.python.org/2/library/itertools.html