I'm working on a school assignment and it works (so far) but I don't understand why I had to put the second if statement after else in the tester function for that if p condition (Xavier) to work.
I need someone to explain why I couldn't use the if before else in this case.
The same condition. It actually needs to test if the user input contains an uppercase X. I have searched online but just can't figure out which method to use.
def tester(p, givenstring = "Too short"):
result=len(p)
if result>=10:
print(p)
else:
print(givenstring)
if p == "Is Xavier here?": # if p == "X" doesn't work.
print("X is spotted!")
def main():
while True:
prompt=input("Write something (quit ends): ")
if prompt=="quit":
break
else:
tester(prompt)
if __name__ == "__main__":
main()
def tester(p, givenstring = "Too short"):
result=len(p)
if result>=10:
print(p)
else:
print(givenstring)
#Comments should be created using hash(#) not (//) >> //if p == "X" doesn't work.
if p == "Is Xavier here?": # this is doing an exact match of the string and not finding 'X'
print("X is spotted!")
def tester(p, givenstring = "Too short"):
result=len(p)
if result>=10:
print(p)
else:
print(givenstring)
if 'X' in p: # this will return True if 'X' is present in p
print("X is spotted!")
def main():
while True:
prompt=input("Write something (quit ends): ")
if prompt=="quit":
break
else:
tester(prompt)
main()
Write something (quit ends): This is captain x-merica
This is captain x-merica
Write something (quit ends): This is captain X-merica
This is captain X-merica
X is spotted!
Write something (quit ends): quit
Related
Ok I have a code that's basically this....
def create():
#long list of print statements
m_commands()
def get_desc():
#print statement
m_commands()
def m_commands():
while close != True:
input = input(str(">>>"))
If inp == "close" or "quit":
close = True
If inp == "create":
create()
If inp == "describe":
get_desc()
m_commands()
I need to call m_commands() in create() and get_desc() to continue continuity. Is this possible. Sorry in advance, I don't know how to put code in a spoiler thingy. Thanks!
def create():
#long list of print statements
print("hello")
m_commands()
def get_desc():
#print statement
print("world")
m_commands()
def m_commands():
close=False
while close != True:
inp = input(str(">>>"))
if inp == "close" or "quit":
close = True
if inp == "create":
create()
if inp == "describe":
get_desc()
m_commands()
This is working for me though.
This is my first project, I used a lot of resources from others with the same project and this is what I have come up with. I am using Jupyter notebook. I am not getting any more error messages in my code, but for some reason I can't get it to run? Also, any advice or improvements in my code would also be appreciated.
I've tried to just call the tic_tac_toe() command but nothing comes up and I'm not sure why.
def tic_tac_toe():
brd = [None] + list(range(1,10))
end = False
winner = ((1,2,3),(4,5,6),(7,8,9),(1,4,7),(2,5,8),(3,6,9),(1,5,9), (3,5,7))
from IPython.display import clear_output
def show_board():
print(brd[1]+'|'+brd[2]+'|'+brd[3])
print(brd[4]+'|'+brd[5]+'|'+brd[6])
print(brd[7]+'|'+brd[8]+'|'+brd[9])
print()
def player_input():
marker = ''
while marker != 'x' and marker != 'o':
marker = input('Do you want to be x or o?: ')
player1 = marker
if player1 == 'x':
player2 ='o'
else:
player2 = 'x'
player_markers = [player1,player2]
def choose_number():
while True:
try:
val = int(input())
if val in brd:
return val
else:
print('\n Please choose another number')
except ValueError:
print('\n Please choose another number')
def game_over():
for a, b, c in winner:
if brd[a] == brd[b] == brd[c]:
print("{0} wins!\n".format(board[a]))
print("Congrats\n")
return True
if 9 == sum((pos == 'x' or pos == 'o') for pos in board):
print("The game ends in a tie\n")
return True
for player in 'x' or 'o' * 9:
draw()
if is_game_over():
break
print("{0} pick your move".format(player))
brd[choose_number()] = player
print()
while True:
tac_tac_toe()
if input("Play again (y/n)\n") != "y":
break
I'm not sure why it is not running normally.
There's a couple things wrong with your code here. Your indentation for one. Also wondering why your functions are all in another function. You also create a bunch of functions but never call most of them. And have some functions that do not seem to exist. There are also a lot of logic errors here and there.
Try this instead:
# numpy is a package that has a lot of helpful functions and lets you manipulate
# numbers and arrays in many more useful ways than the standard Python list allows you to
import numpy as np
def show_board(brd):
print(brd[0]+'|'+brd[1]+'|'+brd[2])
print(brd[3]+'|'+brd[4]+'|'+brd[5])
print(brd[6]+'|'+brd[7]+'|'+brd[8])
print()
def player_input():
marker = ''
while marker != 'x' and marker != 'o':
marker = input('Do you want to be x or o?: ')
player1 = marker
if player1 == 'x':
player2 ='o'
else:
player2 = 'x'
player_markers = [player1,player2]
return player_markers
def choose_number(brd):
while True:
try:
val = int(input())
if brd[val-1] == "_":
return val
else:
print('\nNumber already taken. Please choose another number:')
except ValueError:
print('\nYou did not enter a number. Please enter a valid number:')
def is_game_over(winner, brd):
for a, b, c in winner:
if brd[a] != "_" and (brd[a] == brd[b] == brd[c]):
print("{} wins!\n".format(brd[a]))
print("Congrats\n")
return True
if 9 == sum((pos == 'x' or pos == 'o') for pos in brd):
print("The game ends in a tie\n")
return True
# I split this function in two because the "is_game_over" code was included here
# instead of being by itself.
def game_over(winner, brd, player_markers):
last = 0
# The first player is the one stored in "player_markers[0]"
player = player_markers[0]
# There are nine turns so that is what this is for. It has nothing to do with
# 'x' or 'o'. And one more turn is added for the "is_game_over" to work in
# case of a tie.
for i in range(10):
if is_game_over(winner, brd):
break
print()
print("{0} pick your move [1-9]:".format(player))
brd[choose_number(brd)-1] = player
show_board(brd)
# This is added to change from one player to another
# by checking who was the last one (look up ternary operators)
player = player_markers[1] if last==0 else player_markers[0]
last = 1 if last==0 else 0
def tic_tac_toe():
brd = ["_"] * 9
end = False
winner = ((1,2,3),(4,5,6),(7,8,9),(1,4,7),(2,5,8),(3,6,9),(1,5,9),(3,5,7))
winner = np.array([list(elem) for elem in winner]) - 1
player_markers = player_input()
show_board(brd)
game_over(winner, brd, player_markers)
while True:
tic_tac_toe()
if input("Play again (y/n)\n") != "y":
break
I keep getting a list index out of range exception when I check the length of the list a. The error pops up for either the if or elif part of the second if statement, depending on what the user inputs. I know that when the user input is split the list is created correctly because I print it out... So I'm a little lost about why I'm getting that error.
if __name__ == '__main__':
for line in sys.stdin:
s = line.strip()
if not s: break
if (str(s) is "quit") == True: quit()
elif (str(s) is "quit") == False:
a = s.split()
print(a)
if (len(a) == 2) == True: first(a)
elif (len(a) == 3) == True: first(a)
else: print("Invalid Input. Please Re-enter.")
The first method is: (The methods it calls in the if statement just print things out at the moment)
def first(self, a = list()):
word = a[0]
if word is ls:
ls(a[1])
elif word is format:
form(a[1]) # EDIT: was format
elif word is reconnect:
reconnect(a[1])
elif word is mkfile:
mkfile(a[1])
elif word is mkdir:
mkdir(a[1])
elif word is append:
append(a[1], a[2])
elif word is delfile:
delfile(a[1])
elif word is deldir:
deldir(a[1])
else:
print("Invalid Prompt. Please Re-enter.")
Other methods:
def reconnect(one = ""):
print("Reconnect")
def ls(one = ""):
print("list")
def mkfile(one = ""):
print("make file")
def mkdir(one = ""):
print("make drive")
def append(one = "", two = ""):
print("append")
def form(one = ""):
print("format")
def delfile(one = ""):
print("delete file")
def deldir(one = ""):
print("delete directory")
def quit():
print("quit")
sys.exit(0)
The problem seems to be the definition of first(). You invoke it as a function:
if (len(a) == 2) == True: first(a)
elif (len(a) == 3) == True: first(a)
But you define it as a method:
def first(self, a = list()):
The array of command and argument gets put into self and a is always an empty list which you attempt to index and fail. Also, you shouldn't use a mutable type like list() as a default value unless you're certain what you are doing. I suggest simply:
def first(a):
As far as your __main__ code goes, simplify:
if __name__ == '__main__':
for line in sys.stdin:
string = line.strip()
if not string:
break
if string == "quit":
quit()
tokens = string.split()
length = len(tokens)
if 2 <= length <= 3:
first(tokens)
else:
print("Invalid Input. Please Re-enter.")
Real issue:
To solve your error you have to remove the self parameter of the first function
def first(a=list())
Basically the self is only used for object orientation creating methods.
Function like yours can't use self otherwise you will passing the first parameter to self not to a which you want to.
My second issue I can point out is that, You are trying to compare using is between a string and a function.
def first(a = list()):
word = a[0]
if word is "ls":
ls(a[1])
elif word is "format":
format(a[1])
elif word is "reconnect":
reconnect(a[1])
elif word is "mkfile":
mkfile(a[1])
elif word is "mkdir":
mkdir(a[1])
elif word is "append":
append(a[1], a[2])
elif word is "delfile":
delfile(a[1])
elif word is "deldir":
deldir(a[1])
else:
print("Invalid Prompt. Please Re-enter.")
Extra
The is function on built in operations in Python. is compare the equity of the objects.
But this expression:
if (str(s) is "quit") == True:
Can be simpler like:
if str(s) == "quit":
Or:
if str(s) is "quit":
The == True is meaningless either == False you can use not more pythonicly.
I have a python program with an if statement. I want to add more choices to the if statement, how do I do it?
def start():
print ("A Wise man once said ...")
o1 = input("\n" +
"[L]ook to the poverty of Africa ... [T]HIS HAS YET TO BE WRITTEN")
if o1 == "L" or "l" or "Africa" or "1":
print ("\n" + "You decide only a radical solution is viable...")
else:
print ("THIS IS NOT WRITTEN YET")
def menu ():
print ("Menu\n")
print ("(1)Start")
print ("(2)Exit\n\n")
choice = (input('>>'))
if choice=="1":
start()
if choice=="2":
quit()
menu()
I am trying to make this option next:
o2 = input (
"\n" + "[D]ecide to take advantage ..., or T[H]IS HAS YET TO BE WRITTEN?"*)
How should I go about adding more options and choices so that I end up with a story?
There are a couple of good ways to do this, but I would make a class (lets call it "option_node") that uses dictionaries. The class would hold the text of the prompt, then a dictionary that mapped the text options to other option_nodes or a special option node that ends the dialog.
class option_node:
def __init__(self, prompt):
self.prompt = prompt
self.options = {}
def add_option(self, option_text, next_node):
self.options[option_text] = next_node
def print_prompt(self):
print(prompt)
def select_input(self):
for each in self.options:
print(each)
while(True)
user_input = input(">>")
if self.options.get(in):
return self.options.get(in)
def main():
nodes = []
nodes.append(option_node("Welcome"))
nodes.append(option_node("Stay Awhile"))
nodes.append(option_node("That's fine, I don't like you much either"))
nodes[0].add_option("Hello friend", nodes[1])
nodes[0].add_option("Hello enemy", nodes[2])
nodes[1].options = None
nodes[2].options = None
current_node = nodes[0]
while current_node.options is not None:
current_node.print_prompt()
current_node = current_node.select_input()
Hope this helps. I can elaborate more if you'd like
Add a new condition using elif (else if):
if ...
elif o1 == "D" or o1 == "H":
# your code here
else ...
By the way, you have a syntax error in your conditional statement. Correct it to this:
if o1 == "L" or o1 == "l" or o1 == "Africa" or o1 == "1":
If it makes it easier, look at it this way:
if (o1 == "L") or (o1 == "l") or (o1 == "Africa") or (o1 == "1"):
You should think about the order of operations in your statements. or has higher precedence than ==; additionally, the meaning of "L" or "l" is not what you think it is.
>>> if "L" or "l":
... print("foo")
...
foo
Curious, no? Try some of this stuff out for yourself at the interpreter.
I am a beginer python learner. I am trying to create a basic dictionary where random meaning of words will come and user have to input the correct word. I used the following method, but random doesn't work. I always get the first word first and when the last word finishes, I get infinite 'none' until I kill it. Using python 3.2
from random import choice
print("Welcome , let's get started")
input()
def word():
print('Humiliate')
a = input(':')
while a == 'abasement':
break
else:
word()
# --------------------------------------------------------- #
def word1():
print('Swelling')
a = input(':')
while a == 'billowing':
break
else:
word()
# ------------------------------------------------------------ #
wooo = [word(),word1()]
while 1==1:
print(choice(wooo))
is there any faster way of doing this and get real random? I tried classes but it seems harder than this. Also, is there any way I can make python not care about weather the input is capital letter or not?
To answer one part of your question ("is there any way I can make python not care about weather the input is capital letter or not?"): use some_string.lower():
>>> "foo".lower() == "foo"
True
>>> "FOO".lower() == "foo"
True
An this is to help you how you could improve the structure of your code:
import sys
from random import choice
WORDPAIRS = [('Humiliate', 'abasement'), ('Swelling', 'billowing')]
def ask():
pair = choice(WORDPAIRS)
while True:
answer = raw_input("%s: " % pair[0]).lower()
if answer == pair[1]:
print "well done!"
return
def main():
try:
while True:
ask()
except KeyboardInterrupt:
sys.exit(0)
if __name__ == "__main__":
main()
It works like that:
$ python lulu.py
Swelling: lol
Swelling: rofl
Swelling: billowing
well done!
Humiliate: rofl
Humiliate: Abasement
well done!
Swelling: BILLOWING
well done!
Humiliate: ^C
$
wooo = [word, word1]
while 1:
print(choice(wooo)())
But in any case it will print you None, cause both of your functions return nothing (None).