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How to rewrite thid XML file?

I trying to rewrite this xml file containing this XML code:
<?xml version="1.0" encoding="UTF-8"?>
<BrowserAutomationStudioProject>
<ModelList>
<Model>
<Name>token</Name>
<Description ru="token" en="token"/>
<Value>5660191076:AAEY8RI3hXcI3dEvjWAj7p2e7DdxOMNjPfk8</Value>
</Model>
<Defaults/>
<Model>
<Name>chat_id</Name>
<Value>5578940124</Value>
</Model>
<Defaults/>
</ModelList>
</BrowserAutomationStudioProject>
My python code:
import xml.etree.ElementTree as ET
tree = ET.parse('Actual.xml')
root = tree.getroot()
for model in root.findall('Model'):
name = model.find('Name').text
if name == 'token':
model.find('Value').text = '123456789:ABCDEFGHIJKLMNOPQRSTUVWXYZ'
if name == 'chat_id':
model.find('Value').text = '1234567890'
tree.write('xml_file.xml')
It works but I get the same file:
<?xml version="1.0" encoding="UTF-8"?>
<BrowserAutomationStudioProject>
<ModelList>
<Model>
<Name>token</Name>
<Description ru="token" en="token"/>
<Value>5660191076:AAEY8RI3hXcI3dEvjWAj7p2e7DdxOMNjPfk8</Value>
</Model>
<Defaults/>
<Model>
<Name>chat_id</Name>
<Value>5578940124</Value>
</Model>
<Defaults/>
</ModelList>
</BrowserAutomationStudioProject>
What's wrong with my code?
Even ChatGPT can't help me haha
I even tried to print it but it doesn't work
What I should do?
Please help me.

As described in the documentation, Element.findall() finds only elements with a tag which are direct children of the current element.. You need to force ET to selects all subelements, on all levels beneath the current element by using //.
Since <Model> is not a direct child of root (it's a grandchild, or something to that effect :)), root.findall('Model') finds nothing. So to get ET to find it, you need to modify that to
root.findall('.//Model')
and it should work.

You could also use for model in root.findall('ModelList/Model').

If you know the order of the xml tag you can do something like pop() the values from a list by iterate through the tree:
import xml.etree.ElementTree as ET
tree = ET.parse('Actual.xml')
root = tree.getroot()
input_value = ['1234567890','123456789:ABCDEFGHIJKLMNOPQRSTUVWXYZ']
for elem in root.iter():
if elem.tag == "Value":
elem.text = input_value.pop()
print(elem.tag, elem.text)
tree.write('xml_file.xml')
Output:
<?xml version="1.0"?>
<BrowserAutomationStudioProject>
<ModelList>
<Model>
<Name>token</Name>
<Description ru="token" en="token" />
<Value>123456789:ABCDEFGHIJKLMNOPQRSTUVWXYZ</Value>
</Model>
<Defaults />
<Model>
<Name>chat_id</Name>
<Value>1234567890</Value>
</Model>
<Defaults />
</ModelList>
</BrowserAutomationStudioProject>

How to load xml file with specifc paragraph by xml in Python?

I have a xml file and its structure like that,
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<book>
<toc> <tocdiv pagenum="564">
<title>9thmemo</title>
<tocdiv pagenum="588">
<title>b</title>
</tocdiv>
</tocdiv></toc>
<chapter><title>9thmemo</title>
<para>...</para>
<para>...</para></chapter>
<chapter>...</chapter>
<chapter>...</chapter>
</book>
There are several chapters in the <book>...</book>, and each chapter has a title, I only want to read all content of this chapter,"9thmemo"(not others)
I tried to read by following code:
from xml.dom import minidom
filename = "result.xml"
file = minidom.parse(filename)
chapters = file.getElementsByTagName('chapter')
for i in range(10):
print(chapters[i])
I only get the address of each chapter...
if I add some sub-element like chapters[i].title, it shows cannot find this attribute

I only want to read all content of this chapter,"9thmemo"(not others)
The problem with the code is that it does not try to locate the specific 'chapter' while the answer code uses xpath in order to locate it.
Try the below
import xml.etree.ElementTree as ET
xml = '''<?xml version="1.0" encoding="UTF-8"?>
<book>
<toc>
<tocdiv pagenum="564">
<title>9thmemo</title>
<tocdiv pagenum="588">
<title>b</title>
</tocdiv>
</tocdiv>
</toc>
<chapter>
<title>9thmemo</title>
<para>A</para>
<para>B</para>
</chapter>
<chapter>...</chapter>
<chapter>...</chapter>
</book>'''
root = ET.fromstring(xml)
chapter = root.find('.//chapter/[title="9thmemo"]')
para_data = ','.join(p.text for p in chapter.findall('para'))
print(para_data)
output
A,B

How to replace xml lines using 'if statements' in python?

Hi I'm new to xml files in general, but I am trying to replace specific lines in a xml file using 'if statements' in python 3.6. I've been looking at suggestions to use ElementTree, but none of the posts online quite fit the problem I have, so here I am.
My file is as followed:
<?xml version="1.0" encoding="UTF-8"?>
-<StructureDefinition xmlns="http://hl7.org/fhir">
<url value="http://example.org/fhir/StructureDefinition/MyObservation"/>
<name value="MyObservation"/>
<status value="draft"/>
<fhirVersion value="3.0.1"/>
<kind value="resource"/>
<abstract value="false"/>
<type value="Observation"/>
<baseDefinition value="http://hl7.org/fhir/StructureDefinition/Observation"/>
<derivation value="constraint"/>
</StructureDefinition>
I want to replace
url value="http://example.org/fhir/StructureDefinition/MyObservation"/
to something like
url value="http://example.org/fhir/StructureDefinition/NewObservation"/
by using conditional statements - because these are repeated multiple times in other files.
I have tried for-looping through the xml find to find the exact string match (which I've succeeded), but I wasn't able to delete, or replace the line (probably having to do with the fact that this isn't a .txt file).
Any help is greatly appreciated!

Your sample file contains a "-"-token in ln 3 that may be overlooked when copy/pasting in order to find a solution.
Input File
<?xml version="1.0" encoding="UTF-8"?>
<StructureDefinition xmlns="http://hl7.org/fhir">
<url value="http://example.org/fhir/StructureDefinition/MyObservation"/>
<name value="MyObservation"/>
<status value="draft"/>
<fhirVersion value="3.0.1"/>
<kind value="resource"/>
<abstract value="false"/>
<type value="Observation"/>
<baseDefinition value="http://hl7.org/fhir/StructureDefinition/Observation"/>
<derivation value="constraint"/>
</StructureDefinition>
Script
from xml.dom.minidom import parse # use minidom for this task
dom = parse('june.xml') #read in your file
search = "http://example.org/fhir/StructureDefinition/MyObservation" #set search value
replace = "http://example.org/fhir/StructureDefinition/NewObservation" #set replace value
res = dom.getElementsByTagName('url') #iterate over url tags
for element in res:
if element.getAttribute('value') == search: #in case of match
element.setAttribute('value', replace) #replace
with open('june_updated.xml', 'w') as f:
f.write(dom.toxml()) #update the dom, save as new xml file
Output file
<?xml version="1.0" ?><StructureDefinition xmlns="http://hl7.org/fhir">
<url value="http://example.org/fhir/StructureDefinition/NewObservation"/>
<name value="MyObservation"/>
<status value="draft"/>
<fhirVersion value="3.0.1"/>
<kind value="resource"/>
<abstract value="false"/>
<type value="Observation"/>
<baseDefinition value="http://hl7.org/fhir/StructureDefinition/Observation"/>
<derivation value="constraint"/>
</StructureDefinition>

XPath with LXML Element

I am trying to parse an XML document using lxml etree. The XML doc I am parsing looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<metadata xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.openarchives.org/OAI/2.0/">\t
<codeBook version="2.5" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="ddi:codebook:2_5" xsi:schemaLocation="ddi:codebook:2_5 http://www.ddialliance.org/Specification/DDI-Codebook/2.5/XMLSchema/codebook.xsd">
<docDscr>
<citation>
<titlStmt>
<titl>Test Title</titl>
</titlStmt>
<prodStmt>
<prodDate/>
</prodStmt>
</citation>
</docDscr>
<stdyDscr>
<citation>
<titlStmt>
<titl>Test Title 2</titl>
<IDNo agency="UKDA">101</IDNo>
</titlStmt>
<rspStmt>
<AuthEnty>TestAuthEntry</AuthEnty>
</rspStmt>
<prodStmt>
<copyright>Yes</copyright>
</prodStmt>
<distStmt/>
<verStmt>
<version date="">1</version>
</verStmt>
</citation>
<stdyInfo>
<subject>
<keyword>2009</keyword>
<keyword>2010</keyword>
<topcClas>CLASS</topcClas>
<topcClas>ffdsf</topcClas>
</subject>
<abstract>This is an abstract piece of text.</abstract>
<sumDscr>
<timePrd event="single">2020</timePrd>
<nation>UK</nation>
<anlyUnit>Test</anlyUnit>
<universe>test</universe>
<universe>hello</universe>
<dataKind>fdsfdsf</dataKind>
</sumDscr>
</stdyInfo>
<method>
<dataColl>
<timeMeth>test timemeth</timeMeth>
<dataCollector>test data collector</dataCollector>
<sampProc>test sampprocess</sampProc>
<deviat>test deviat</deviat>
<collMode>test collMode</collMode>
<sources/>
</dataColl>
</method>
<dataAccs>
<setAvail>
<accsPlac>Test accsPlac</accsPlac>
</setAvail>
<useStmt>
<restrctn>NONE</restrctn>
</useStmt>
</dataAccs>
<othrStdyMat>
<relPubl>122</relPubl>
<relPubl>12332</relPubl>
</othrStdyMat>
</stdyDscr>
</codeBook>
</metadata>
I wrote the following code to try and process it:
from lxml import etree
import pdb
f = open('/vagrant/out2.xml', 'r')
xml_str = f.read()
xml_doc = etree.fromstring(xml_str)
f.close()
From what I understand from the lxml xpath docs, I should be able to get the text from a specific element as follows:
xml_doc.xpath('/metadata/codeBook/docDscr/citation/titlStmt/titl/text()')
However, when I run this it returns an empty array.
The only xpath I can get to return something is using a wildcard:
xml_doc.xpath('*')
Which returns [<Element {ddi:codebook:2_5}codeBook at 0x7f8da8a413f8>].
I've read through the docs and I'm not understanding what is going wrong with this. Any help is appreciated.

You need to take the default namespace into account so instead of
xml_doc.xpath('/metadata/codeBook/docDscr/citation/titlStmt/titl/text()')
use
xml_doc.xpath.xpath(
'/oai:metadata/ddi:codeBook/ddi:docDscr/ddi:citation/ddi:titlStmt/ddi:titl/text()',
namespaces={
'oai': 'http://www.openarchives.org/OAI/2.0/',
'ddi': 'ddi:codebook:2_5'
}
)

Element Tree doesn't load a Google Earth-exported KML

I have a problem related to a Google Earth exported KML, as it doesn't seem to work well with Element Tree. I don't have a clue where the problem might lie, so I will explain how I do everything.
Here is the relevant code:
kmlFile = open( filePath, 'r' ).read( -1 ) # read the whole file as text
kmlFile = kmlFile.replace( 'gx:', 'gx' ) # we need this as otherwise the Element Tree parser
# will give an error
kmlData = ET.fromstring( kmlFile )
document = kmlData.find( 'Document' )
With this code, ET (Element Tree object) creates an Element object accessible via variable kmlData. It points to the root element ('kml' tag). However, when I run a search for the sub-element 'Document', it returns None. Although the 'Document' tag is present in the KML file!
Are there any other discrepancies between KMLs and XMLs apart from the 'gx: smth' tags? I have searched through the KML files I am dealing with and found nothing suspicious. Here is a simplified structure of an KML file the program is supposed to deal with:
<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://earth.google.com/kml/2.2">
<Document>
<name>UK.kmz</name>
<Style id="sh_blu-blank">
<IconStyle>
<scale>1.3</scale>
<Icon>
<href>http://maps.google.com/mapfiles/kml/paddle/blu-blank.png</href>
</Icon>
<hotSpot x="32" y="1" xunits="pixels" yunits="pixels"/>
</IconStyle>
<ListStyle>
<ItemIcon>
<href>http://maps.google.com/mapfiles/kml/paddle/blu-blank-lv.png</href>
</ItemIcon>
</ListStyle>
</Style>
[other style tags...]
<Folder>
<name>UK</name>
<Placemark>
<name>1262 Crossness Pumping Station</name>
<LookAt>
<longitude>0.1329926667038817</longitude>
<latitude>51.50303535104574</latitude>
<altitude>0</altitude>
<range>4246.539753518848</range>
<tilt>0</tilt>
<heading>-4.295161152207489</heading>
<altitudeMode>relativeToGround</altitudeMode>
<gx:altitudeMode>relativeToSeaFloor</gx:altitudeMode>
</LookAt>
<styleUrl>#msn_blu-blank15000</styleUrl>
<Point>
<coordinates>0.1389579668507301,51.50888923518947,0</coordinates>
</Point>
</Placemark>
[other placemark tags...]
</Folder>
</Document>
</kml>
Do you have an idea why I can't access any sub-elements of 'kml'? By the way, Python version is 2.7.

The KML document is in the http://earth.google.com/kml/2.2 namespace, as indicated by
<kml xmlns="http://earth.google.com/kml/2.2">
This means that the name of the Document element is in fact {http://earth.google.com/kml/2.2}Document.
Instead of this:
document = kmlData.find('Document')
you need this:
document = kmlData.find('{http://earth.google.com/kml/2.2}Document')
However, there is a problem with the XML file. There is an element called gx:altitudeMode. The gx bit is a namespace prefix. Such a prefix needs to be declared, but the declaration is missing.
You have worked around the problem by simply replacing gx: with gx. But the proper way to do this would be to add the namespace declaration. Based on https://developers.google.com/kml/documentation/altitudemode, I take it that gx is associated with the http://www.google.com/kml/ext/2.2 namespace. So for the document to be well-formed, the root element start tag should read
<kml xmlns="http://earth.google.com/kml/2.2" xmlns:gx="http://www.google.com/kml/ext/2.2">
Now the document can be parsed:
In [1]: from xml.etree import ElementTree as ET
In [2]: kmlData = ET.parse("kml2.xml")
In [3]: document = kmlData.find('{http://earth.google.com/kml/2.2}Document')
In [4]: document
Out[4]: <Element '{http://earth.google.com/kml/2.2}Document' at 0x1895810>
In [5]: