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Print a calendar starting from today's date

I want to print a calendar of the current month but starting from today's date in python. Is there any way I can do this?
Only thing I thought to try was :
import calendar
y = int(input("Input the year : "))
m = int(input("Input the month : "))
d = int (input("Input the day: "))
print(calendar.month(y, m, d))
which in retrospect is a dumb idea because all it did was :
but considering my 3 day experience in python it seemed dumb enough to work.
I want the end result to look something like this:
Essentially,I want the calendar to show only the remaining days of the month,instead of the whole month.

The calender method returns a string. You can use conventual string manipulation methods to modify the string before printing - f.e. regex replacement:
import calendar
import re
y = 2020
m = 5
d = 15
h = calendar.month(y, m, 3) # 3 is the width of the date column, not the day-date
print(h)
print()
# replace all numbers before your day, take care of either spaces or following \n
for day in range(d):
# replace numbers at the start of a line
pattern = rf"\n{day} "
h = re.sub(pattern, "\n " if day < 10 else "\n ", h)
# replace numbers in the middle of a line
pattern = rf" {day} "
h = re.sub(pattern, " " if day < 10 else " ", h)
# replace numbers at the end of a line
pattern = rf" {day}\n"
h = re.sub(pattern, " \n" if day < 10 else " \n", h)
print(h)
Output:
May 2020
Mon Tue Wed Thu Fri Sat Sun
1 2 3
4 5 6 7 8 9 10
11 12 13 14 15 16 17
18 19 20 21 22 23 24
25 26 27 28 29 30 31
# after replacement
May 2020
Mon Tue Wed Thu Fri Sat Sun
15 16 17
18 19 20 21 22 23 24
25 26 27 28 29 30 31

How can i convert this string to integers & other strings in Python

I got this string...
String = '-268 14 7 19 - Fri Aug 3 12:32:08 2018\n'
I want to get the first 4 numbers (-268, 14, 7, 19) in integer-variables and Fri Aug 3 12:32:08 in another string-variable.
Is that possible?

Using basic python
string = '-268 14 7 19 - Fri Aug 3 12:32:08 2018\n'
vals, date = string.strip().split(' - ')
int_vals = [int(v) for v in vals.split()]
print(int_vals) # [-268, 14, 7, 19]
print(date) # Fri Aug 3 12:32:08 2018
Using regex
import re
match = re.search(r'([-\d]+) ([-\d]+) ([-\d]+) ([-\d]+)[ -]*(.*)', string)
date = match.group(5)
int_vals = [int(v) for v in match.groups()[:4]] # same results

Use str.split
Ex:
String = '-268 14 7 19 - Fri Aug 3 12:32:08 2018\n'
first, second = String.split(" - ")
first = tuple(int(i) for i in first.split())
print(first)
print(second)
Output:
(-268, 14, 7, 19)
Fri Aug 3 12:32:08 2018

Use split and map for it:
left, date = String.split(' - ')
numbers = list(map(int, left.split()))
print(numbers, date)

How to error check list index out of range

I have a read.log file that will have lines such as...
10.2.177.170 Tue Jun 19 03:30:55 CDT 2018
10.2.177.170 Tue Jun 19 03:31:03 CDT 2018
10.2.177.170 Tue Jun 19 03:31:04 CDT 2018
10.2.177.170 Tue Jun 19 03:32:04 CDT 2018
10.2.177.170 Tue Jun 19 03:33:04 CDT 2018
My code will read the 3rd to last line and combine strings. So the normal output would be:
2018:19:03:32:04
My problem is, if there are only 4 or less lines of data such as
10.1.177.170 Tue Jun 19 03:30:55 CDT 2018
10.1.177.170 Tue Jun 19 03:31:03 CDT 2018
10.1.177.170 Tue Jun 19 03:31:04 CDT 2018
10.1.177.170 Tue Jun 19 03:32:04 CDT 2018
I get an error
x1 = line.split()[0]
IndexError: list index out of range
How can I error check this or keep it from happening? I have been trying to check how many lines there are in the log and if less than 5, print a notice. Are there better options?
def run():
f = open('read.log', 'r')
lnumber = dict()
for num,line in enumerate(f,1):
x1 = line.split()[0]
log_day = line.split()[3]
log_time = line.split()[4]
log_year = line.split()[6]
if x1 in lnumber:
lnumber[x1].append((log_year + ":" + log_day + ":" + log_time))
else:
lnumber[x1] = [(num,log_time)]
if x1 in lnumber and len(lnumber.get(x1,None)) > 2:
# if there are less than 3 lines in document, this will fail
line_time = (lnumber[x1][-3].__str__())
print(line_time)
else:
print('nothing')
f.close
run()

f.readlines() gives you a list of lines in a file. So, you could try reading in all the lines in a file:
f = open('firewall.log', 'r')
lines = f.readlines()
And exiting if there are 4 or less lines:
if len(lines) <= 4:
f.close()
print("4 or less lines in file")
exit()
That IndexError you're getting is because you're calling split() on a line with nothing on it. I would suggest doing something like if not line: continue to avoid that case.

Python - Parsing a text file into a csv file

I have a text file that is output from a command that I ran with Netmiko to retrieve data from a Cisco WLC of things that are causing interference on our WiFi network. I stripped out just what I needed from the original 600k lines of code down to a couple thousand lines like this:
AP Name.......................................... 010-HIGH-FL4-AP04
Microwave Oven 11 10 -59 Mon Dec 18 08:21:23 2017
WiMax Mobile 11 0 -84 Fri Dec 15 17:09:45 2017
WiMax Fixed 11 0 -68 Tue Dec 12 09:29:30 2017
AP Name.......................................... 010-2nd-AP04
Microwave Oven 11 10 -61 Sat Dec 16 11:20:36 2017
WiMax Fixed 11 0 -78 Mon Dec 11 12:33:10 2017
AP Name.......................................... 139-FL1-AP03
Microwave Oven 6 18 -51 Fri Dec 15 12:26:56 2017
AP Name.......................................... 010-HIGH-FL3-AP04
Microwave Oven 11 10 -55 Mon Dec 18 07:51:23 2017
WiMax Mobile 11 0 -83 Wed Dec 13 16:16:26 2017
The goal is to end up with a csv file that strips out the 'AP Name ...' and puts what left on the same line as the rest of the information in the next line. The problem is some have two lines below the AP name and some have 1 or none. I have been at it for 8 hours and cannot find the best way to make this happen.
This is the latest version of code that I was trying to use, any suggestions for making this work? I just want something I can load up in excel and create a report with:
with open(outfile_name, 'w') as out_file:
with open('wlc-interference_raw.txt', 'r')as in_file:
#Variables
_ap_name = ''
_temp = ''
_flag = False
for i in in_file:
if 'AP Name' in i:
#write whatever was put in the temp file to disk because new ap now
#add another temp variable in case an ap has more than 1 interferer and check if new AP name
out_file.write(_temp)
out_file.write('\n')
#print(_temp)
_ap_name = i.lstrip('AP Name.......................................... ')
_ap_name = _ap_name.rstrip('\n')
_temp = _ap_name
#print(_temp)
elif '----' in i:
pass
elif 'Class Type' in i:
pass
else:
line_split = i.split()
for x in line_split:
_temp += ','
_temp += x
_temp += '\n'

I think your best option is to read all lines of the file, then split into sections starting with AP Name. Then you can work on parsing each section.
Example
s = """AP Name.......................................... 010-HIGH-FL4-AP04
Microwave Oven 11 10 -59 Mon Dec 18 08:21:23 2017
WiMax Mobile 11 0 -84 Fri Dec 15 17:09:45 2017
WiMax Fixed 11 0 -68 Tue Dec 12 09:29:30 2017
AP Name.......................................... 010-2nd-AP04
Microwave Oven 11 10 -61 Sat Dec 16 11:20:36 2017
WiMax Fixed 11 0 -78 Mon Dec 11 12:33:10 2017
AP Name.......................................... 139-FL1-AP03
Microwave Oven 6 18 -51 Fri Dec 15 12:26:56 2017
AP Name.......................................... 010-HIGH-FL3-AP04
Microwave Oven 11 10 -55 Mon Dec 18 07:51:23 2017
WiMax Mobile 11 0 -83 Wed Dec 13 16:16:26 2017"""
import re
class AP:
"""
A class holding each section of the parsed file
"""
def __init__(self):
self.header = ""
self.content = []
sections = []
section = None
for line in s.split('\n'): # Or 'for line in file:'
# Starting new section
if line.startswith('AP Name'):
# If previously had a section, add to list
if section is not None:
sections.append(section)
section = AP()
section.header = line
else:
if section is not None:
section.content.append(line)
sections.append(section) # Add last section outside of loop
for section in sections:
ap_name = section.header.lstrip("AP Name.") # lstrip takes all the characters given, not a literal string
for line in section.content:
print(ap_name + ",", end="")
# You can extract the date separately, if needed
# Splitting on more than one space using a regex
line = ",".join(re.split(r'\s\s+', line))
print(line.rstrip(',')) # Remove trailing comma from imperfect split
Output
010-HIGH-FL4-AP04,Microwave Oven,11,10,-59,Mon Dec 18 08:21:23 2017
010-HIGH-FL4-AP04,WiMax Mobile,11,0,-84,Fri Dec 15 17:09:45 2017
010-HIGH-FL4-AP04,WiMax Fixed,11,0,-68,Tue Dec 12 09:29:30 2017
010-2nd-AP04,Microwave Oven,11,10,-61,Sat Dec 16 11:20:36 2017
010-2nd-AP04,WiMax Fixed,11,0,-78,Mon Dec 11 12:33:10 2017
139-FL1-AP03,Microwave Oven,6,18,-51,Fri Dec 15 12:26:56 2017
010-HIGH-FL3-AP04,Microwave Oven,11,10,-55,Mon Dec 18 07:51:23 2017
010-HIGH-FL3-AP04,WiMax Mobile,11,0,-83,Wed Dec 13 16:16:26 2017
Tip:
You don't need Python to write the CSV, you can output to a file using the command line
python script.py > output.csv

Python: Working out whitespace in date

I have a log file file.txt and it has the date format as '%b %_d %H:%M:%S'.
When the day of the month is between the 1st and 9th, it pads out the field with a space.
I'm just wondering if my code is the best way to check if this includes a space or not as I'm just trying to pull out the date/time from each line
file.txt
Sep 8 16:13:02 blah
Sep 8 16:14:02 blahblah
Sep 8 16:15:02 blablahblah
Code:
with open('file.txt','r') as f:
for line in f:
if int(line.split()[1]) < 10:
d = line.split()[0] + ' ' + line.split()[1] + ' ' + line.split()[2] #double space after [0]
else:
d = line.split()[0] + ' ' + line.split()[1] + ' ' + line.split()[2] #single space after [0]
print d

If you want your output field to be padded with spaces, you can use python string formatting spec.
>>> for line in 'Sep 8 16:13:02 blah', 'Sep 12 16:13:02 blah':
>>> print('{0} {1:>2} {2}'.format(*line.split()))
Sep 8 16:13:02
Sep 12 16:13:02
{1:>2} means that field 1 should be right aligned and at least 2 characters wide. Missing characters will be padded with spaces.
In python 3.6+ you can also use f-strings to make it more self-explanatory.
>>> for line in 'Sep 8 16:13:02 blah', 'Sep 12 16:13:02 blah blah blah':
>>> month, date, time, *rest = line.split()
>>> print(f'date: {month} {date:>2} {time}\ncomment: {" ".join(rest)}')
date: Sep 8 16:13:02
comment: blah
date: Sep 12 16:13:02
comment: blah blah blah

Based on the comment by jedwards:
from datetime import datetime
f = '''Sep 8 16:13:02 blah
Sep 8 16:14:02 blahblah
Sep 8 16:15:02 blablahblah'''.splitlines()
for line in f:
d = datetime.strptime(line[:15], '%b %d %H:%M:%S')
print(d)
Output:
1900-09-08 16:13:02
1900-09-08 16:14:02
1900-09-08 16:15:02