Import and insert word in sequence in Python - python

I want to import and insert word in sequence and NOT RANDOMLY, each registration attempt uses a single username and stop until the registration is completed. Then logout and begin a new registration with the next username in the list if the REGISTRATION is FAILED, and skip if the REGISTRATION is SUCCEDED.
I'm really confused because I have no clue. I've tried this code but it chooses randomly and I have no idea how to use the "for loop"
import random
Copy = driver.find_element_by_xpath('XPATH')
Copy.click()
names = [
"Noah" ,"Liam" ,"William" ,"Anthony"
]
idx = random.randint(0, len(names) - 1)
print(f"Picked name: {names[idx]}")
Copy.send_keys(names[idx])
How can I make it choose the next word in sequence and NOT RANDOMLY
Any Help Please


I am going to assume that you are happy with what the code does, with exception that the names it picks are random. This narrows everything down to one line, and namely the one that picks names randomly:
idx = random.randint(0, len(names) - 1)
Simple enough, you want "the next word in sequence and NOT RANDOMLY":
https://docs.python.org/3/tutorial/datastructures.html#more-on-lists
If you take a look at the link I've provided, you can see that lists have a pop() method, returning and removing some element from the list. We want the first one so we will provide 0 as the argument for the pop method.
We modify the line to look something like this
name = names.pop(0)
Now you still want to have the for-loop that will loop over all of the actions including name picking so you encapsulate all of the code in a for-loop:
names = [
"Noah" ,"Liam" ,"William" ,"Anthony"
]
for i in range(len(names)):
# ...
Copy = driver.find_element_by_xpath('XPATH')
Copy.click()
name = names.pop(0)
print(f"Picked name: {name}")
Copy.send_keys(name)
# ...
You might notice that the names list is not inside the for-loop. That is because we don't want to reassign the list every time we try to use a new name.
If you're completely unsure how for-loops work or how to implement one yourself, you should probably start by reading about how they work.
https://docs.python.org/3/tutorial/controlflow.html?highlight=loop#for-statements
Last but not least you can see some # ... comments in my example indicating where the logic will probably go for the other part of your question: "Then logout and begin a new registration with the next username in the list if the REGISTRATION is FAILED, and skip if the REGISTRATION is SUCCEDED." I don't think we I can help you with that since there is simply not enough context or examples in your question.
Refer to this guide explaining how to ask a well formulated question so we can help you more next time.

Related

I do not understand why this function reverses the string

This function requests a string input and reverses it. For some reason, I just cannot wrap my head around the logic behind it.
def reverse(s):
new = ""
for i in s:
print(new)
new = i + new
return new
oldStr = input("String?")
newStr = reverse(oldStr)
print(newStr)
print(reverse("good bye"))
A friend suggested I print the variable new in the string which I added and it helped a little, but I just don't understand it.

It looks to me as if you are in a stage where you want to learn how to debug small programs.
For questions on StackOverflow, you want to provide a minimal reproducible example. What does that mean in your case?
"repoducible" means that you should not depend on user input. Replace user input by hardcoded values.
"minimal" means that you don't call the function twice. Once is enough.
For that reason, I'll not walk you through your original program, but through this one instead:
def reverse(s):
new = ""
for i in s:
print(new)
new = i + new
return new
print(reverse("abcdef"))
I'll use a free program called PyCharm Community Edition. You set a breakpoint where you want to understand how things work. Since you don't understand the reverse() method, put it right at the beginning of that method. You do that by clicking between the line number and the text:
Even if your code has no bug, go to the Run/Debug menu:
Execution will stop at the breakpoint and you'll now be able to see all the variables and step through your code line by line.
Look at all the variables after each single line. Compare the values to what you think the values should be. If there is a mismatch, it's likely a misunderstanding on your side, not by Python. Do that a few times and it'll be obvious why and how the string is reversed.

Let analysis it:
Iteration 1:
new = 'A', i = g
Perform new = i + new : new = gA
Iteration 2:
new = gA, i = o
Perform new = i + new: new = ogA
.
.
.
This happens because we add new i before we add the existing string from previous iteration.

the key is in "new = i + new" note that new is the previous iteration character and is in the right side of the current character, this cause the string to reverse

How to iterate over 2D list to find user specified element, then delete all rows that do not contain stated element

I am trying to iterate over a 2D list to find an element that matches the user input. When a match is found, all rows of the list that do not contain that element will be removed from the list. The idea is that I can keep applying filters until i am left with what the user wants to see but I am coming unstuck at the first hurdle.
def catlistfun():
for cat in appdata:
if cat[1] not in catlist:
catlist.append(cat[1])
Above is a part of my program that I have used to access the list successfully. When I try the program below it runs but no rows appear to delete.
def categorymenu():
print(catlist)
catchoice = input('Enter Chosen Category: ')
for cats in appdata:
if catchoice != cats[1]:
del cats
I understand the way I am trying to achieve this may be quite basic but i am fairly new to python and would like to stick to something close to this if possible. Thanks
Edit: Example
appdata = [a,b,c,d,e,f],[a,t,e,g,h,y],[r,y,i,a,d,c]
catchoice = t
for cat in appdata:
if catchoice != cat[1]:
del cat
print(appdata)
output: [a,t,e,g,h,y]
The above is the output I am looking for but at the moment the output is
output: [a,b,c,d,e,f],[a,t,e,g,h,y],[r,y,i,a,d,c]

If I understood correctly, you are looking for this:
[row for row in appdata if catchoice in row]
Please provide example input and example output to eliminate ambiguity in interpretation.

Is there a way to remove items from various lists based on conditional statements?

I am writing a program that will act as a photography idea-generator for New York photographers. The way it works now is quite simple, the code is utilizing the random.choice function to randomly pull items from lists, then the code prints them out in a way that forms a sentence in English as an end result.
My issue is I need to add some logic to this, as some results would not make sense for a photographer to do (at least in my opinion). In this example I am trying to remove 'Bracketed (HDR)' from the technique_list, IF "Portrait" happens to be randomly chosen when python chooses the theme item.
I have a feeling I am mis-using the .remove function within the conditional if statement. Is there a better way to do this? I have attached the pertinent parts of the code for examination.
I have tried technique_list.remove('Bracketed (HDR)') , as well as
del technique_list[0] , both as the response part of the if statement.
import random
print ("You should try taking a...")
#pool of items that the program will randomly choose..
theme_list = ['Cityscape','Peoplescape','Port-Scape', 'Portrait']
technique_list = ['Bracketed (HDR)','Wide Angle', 'Zoom','Long
Exposure','Fast Shutter','Daytime Long Expo','Timelapse']
#what we need here are conditional IF statements, that manipulate items
from various lists
#this bit of code determines the theme of a photo idea
theme_var = random.choice(theme_list)
for theme in theme_var:
if theme == 'Portrait':
technique_list.remove('Bracketed (HDR)')
print("",theme_var)
#this bit of code determines the technique of a photo idea
technique_var = random.choice(technique_list)
print("", technique_var)
print("picture, from")
#this line of code determines the location of a photo idea
location_var = random.choice(location_list)
print("", location_var)
This still remains one of the possible results of the code:
You should try taking a...
Portrait
Bracketed (HDR)
picture, from
34th Street
during
Sunrise
and then give it a
Black & White
edit in Lightroom!
[Finished in 0.2
As I said earlier, Portrait and Bracketed (HDR) should never be part of the same result, it doesn't make sense for this situation.

The issue (I think) is because you are iterating over the randomly chosen result not the list itself, you don't need the for loop that is.
theme_var = random.choice(theme_list)
if theme_var == 'Portrait':
technique_list.remove('Bracketed (HDR)')
print("",theme_var)
#this bit of code determines the technique of a photo idea
technique_var = random.choice(technique_list)
print("", technique_var)
print("picture, from")
#rest of the code
Should do it

I'd go with a dictionary of inappropriate techniques, a list comprehension, and top it off with an f-string:
import random
#pool of items that the program will randomly choose..
theme_list = ['Cityscape','Peoplescape','Port-Scape', 'Portrait']
technique_list = ['Bracketed (HDR)','Wide Angle', 'Zoom','Long Exposure','Fast
Shutter','Daytime Long Expo','Timelapse']
location_list = ['34th Street']
# dictionary of inappropriate techniques for given theme
d_inappropes = {'Cityscape': [],
'Port-Scape': [],
'Portrait': ['Bracketed (HDR)'],
'Peoplescape': ['Long Exposure', 'Timelapse', 'Daytime Long Expo']}
#this bit of code determines the theme of a photo idea
theme_var = random.choice(theme_list)
#this bit of code determines the technique of a photo idea
# list comprehension generates a new list with the inappropriate techniques removed,
# without affecting the original list
technique_var = random.choice([ti for ti in technique_list if ti not in d_inappropes[theme_var]])
#this line of code determines the location of a photo idea
location_var = random.choice(location_list)
# use f-stirngs to put the whole output in a single line to keep it managable
print(f"You should try taking a \n {theme_var} {technique_var} picture, \n from
{location_var}.")

if I may add and give more explanation to the answers
You want to delete "bracked (HDR)" IF potrait is selected. Don't use .remove as it will delete "bracked (HDR)" permanently and prevent other theme to use that technique. you can use dictionary of inappropriate technique as kingfischer suggested for that
random.choice outputted a single value from your list. you should not use for-loop with it as for-loop will iterate over the character/alphabets in the value outputted by random.choice
if I may give a feedback, the indentations in your code snippet are quite jumbled. Some lines that should have indentation, don't have it. I don't know.. maybe it is unintended and the problem is with my browser. if it was so, sorry!

Python- Insert new values into 'nested' list?

What I'm trying to do isn't a huge problem in php, but I can't find much assistance for Python.
In simple terms, from a list which produces output as follows:
{"marketId":"1.130856098","totalAvailable":null,"isMarketDataDelayed":null,"lastMatchTime":null,"betDelay":0,"version":2576584033,"complete":true,"runnersVoidable":false,"totalMatched":null,"status":"OPEN","bspReconciled":false,"crossMatching":false,"inplay":false,"numberOfWinners":1,"numberOfRunners":10,"numberOfActiveRunners":8,"runners":[{"status":"ACTIVE","ex":{"tradedVolume":[],"availableToBack":[{"price":2.8,"size":34.16},{"price":2.76,"size":200},{"price":2.5,"size":237.85}],"availableToLay":[{"price":2.94,"size":6.03},{"price":2.96,"size":10.82},{"price":3,"size":33.45}]},"sp":{"nearPrice":null,"farPrice":null,"backStakeTaken":[],"layLiabilityTaken":[],"actualSP":null},"adjustmentFactor":null,"removalDate":null,"lastPriceTraded":null,"handicap":0,"totalMatched":null,"selectionId":12832765}...
All I want to do is add in an extra field, containing the 'runner name' in the data set below, into each of the 'runners' sub lists from the initial data set, based on selection_id=selectionId.
So initially I iterate through the full dataset, and then create a separate list to get the runner name from the runner id (I should point out that runnerId===selectionId===selection_id, no idea why there are multiple names are used), this works fine and the code is shown below:
for market_book in market_books:
market_catalogues = trading.betting.list_market_catalogue(
market_projection=["RUNNER_DESCRIPTION", "RUNNER_METADATA", "COMPETITION", "EVENT", "EVENT_TYPE", "MARKET_DESCRIPTION", "MARKET_START_TIME"],
filter=betfairlightweight.filters.market_filter(
market_ids=[market_book.market_id],
),
max_results=100)
data = []
for market_catalogue in market_catalogues:
for runner in market_catalogue.runners:
data.append(
(runner.selection_id, runner.runner_name)
)
So as you can see I have the data in data[], but what I need to do is add it to the initial data set, based on the selection_id.
I'm more comfortable with Php or Javascript, so apologies if this seems a bit simplistic, but the code snippets I've found on-line only seem to assist with very simple Python lists and nothing 'nested' (to me the structure seems similar to a nested array).
As per the request below, here is the full list:
{"marketId":"1.130856098","totalAvailable":null,"isMarketDataDelayed":null,"lastMatchTime":null,"betDelay":0,"version":2576584033,"complete":true,"runnersVoidable":false,"totalMatched":null,"status":"OPEN","bspReconciled":false,"crossMatching":false,"inplay":false,"numberOfWinners":1,"numberOfRunners":10,"numberOfActiveRunners":8,"runners":[{"status":"ACTIVE","ex":{"tradedVolume":[],"availableToBack":[{"price":2.8,"size":34.16},{"price":2.76,"size":200},{"price":2.5,"size":237.85}],"availableToLay":[{"price":2.94,"size":6.03},{"price":2.96,"size":10.82},{"price":3,"size":33.45}]},"sp":{"nearPrice":null,"farPrice":null,"backStakeTaken":[],"layLiabilityTaken":[],"actualSP":null},"adjustmentFactor":null,"removalDate":null,"lastPriceTraded":null,"handicap":0,"totalMatched":null,"selectionId":12832765},{"status":"ACTIVE","ex":{"tradedVolume":[],"availableToBack":[{"price":20,"size":3},{"price":19.5,"size":26.36},{"price":19,"size":2}],"availableToLay":[{"price":21,"size":13},{"price":22,"size":2},{"price":23,"size":2}]},"sp":{"nearPrice":null,"farPrice":null,"backStakeTaken":[],"layLiabilityTaken":[],"actualSP":null},"adjustmentFactor":null,"removalDate":null,"lastPriceTraded":null,"handicap":0,"totalMatched":null,"selectionId":12832767},{"status":"ACTIVE","ex":{"tradedVolume":[],"availableToBack":[{"price":11,"size":9.75},{"price":10.5,"size":3},{"price":10,"size":28.18}],"availableToLay":[{"price":11.5,"size":12},{"price":13.5,"size":2},{"price":14,"size":7.75}]},"sp":{"nearPrice":null,"farPrice":null,"backStakeTaken":[],"layLiabilityTaken":[],"actualSP":null},"adjustmentFactor":null,"removalDate":null,"lastPriceTraded":null,"handicap":0,"totalMatched":null,"selectionId":12832766},{"status":"ACTIVE","ex":{"tradedVolume":[],"availableToBack":[{"price":48,"size":2},{"price":46,"size":5},{"price":42,"size":5}],"availableToLay":[{"price":60,"size":7},{"price":70,"size":5},{"price":75,"size":10}]},"sp":{"nearPrice":null,"farPrice":null,"backStakeTaken":[],"layLiabilityTaken":[],"actualSP":null},"adjustmentFactor":null,"removalDate":null,"lastPriceTraded":null,"handicap":0,"totalMatched":null,"selectionId":12832769},{"status":"ACTIVE","ex":{"tradedVolume":[],"availableToBack":[{"price":18.5,"size":28.94},{"price":18,"size":5},{"price":17.5,"size":3}],"availableToLay":[{"price":21,"size":20},{"price":23,"size":2},{"price":24,"size":2}]},"sp":{"nearPrice":null,"farPrice":null,"backStakeTaken":[],"layLiabilityTaken":[],"actualSP":null},"adjustmentFactor":null,"removalDate":null,"lastPriceTraded":null,"handicap":0,"totalMatched":null,"selectionId":12832768},{"status":"ACTIVE","ex":{"tradedVolume":[],"availableToBack":[{"price":4.3,"size":9},{"price":4.2,"size":257.98},{"price":4.1,"size":51.1}],"availableToLay":[{"price":4.4,"size":20.97},{"price":4.5,"size":30},{"price":4.6,"size":16}]},"sp":{"nearPrice":null,"farPrice":null,"backStakeTaken":[],"layLiabilityTaken":[],"actualSP":null},"adjustmentFactor":null,"removalDate":null,"lastPriceTraded":null,"handicap":0,"totalMatched":null,"selectionId":12832771},{"status":"ACTIVE","ex":{"tradedVolume":[],"availableToBack":[{"price":24,"size":6.75},{"price":23,"size":2},{"price":22,"size":2}],"availableToLay":[{"price":26,"size":2},{"price":27,"size":2},{"price":28,"size":2}]},"sp":{"nearPrice":null,"farPrice":null,"backStakeTaken":[],"layLiabilityTaken":[],"actualSP":null},"adjustmentFactor":null,"removalDate":null,"lastPriceTraded":null,"handicap":0,"totalMatched":null,"selectionId":12832770},{"status":"ACTIVE","ex":{"tradedVolume":[],"availableToBack":[{"price":5.7,"size":149.33},{"price":5.5,"size":29.41},{"price":5.4,"size":5}],"availableToLay":[{"price":6,"size":85},{"price":6.6,"size":5},{"price":6.8,"size":5}]},"sp":{"nearPrice":null,"farPrice":null,"backStakeTaken":[],"layLiabilityTaken":[],"actualSP":null},"adjustmentFactor":null,"removalDate":null,"lastPriceTraded":null,"handicap":0,"totalMatched":null,"selectionId":10064909}],"publishTime":1551612312125,"priceLadderDefinition":{"type":"CLASSIC"},"keyLineDescription":null,"marketDefinition":{"bspMarket":false,"turnInPlayEnabled":false,"persistenceEnabled":false,"marketBaseRate":5,"eventId":"28180290","eventTypeId":"2378961","numberOfWinners":1,"bettingType":"ODDS","marketType":"NONSPORT","marketTime":"2019-03-29T00:00:00.000Z","suspendTime":"2019-03-29T00:00:00.000Z","bspReconciled":false,"complete":true,"inPlay":false,"crossMatching":false,"runnersVoidable":false,"numberOfActiveRunners":8,"betDelay":0,"status":"OPEN","runners":[{"status":"ACTIVE","sortPriority":1,"id":10064909},{"status":"ACTIVE","sortPriority":2,"id":12832765},{"status":"ACTIVE","sortPriority":3,"id":12832766},{"status":"ACTIVE","sortPriority":4,"id":12832767},{"status":"ACTIVE","sortPriority":5,"id":12832768},{"status":"ACTIVE","sortPriority":6,"id":12832770},{"status":"ACTIVE","sortPriority":7,"id":12832769},{"status":"ACTIVE","sortPriority":8,"id":12832771},{"status":"LOSER","sortPriority":9,"id":10317013},{"status":"LOSER","sortPriority":10,"id":10317010}],"regulators":["MR_INT"],"countryCode":"GB","discountAllowed":true,"timezone":"Europe\/London","openDate":"2019-03-29T00:00:00.000Z","version":2576584033,"priceLadderDefinition":{"type":"CLASSIC"}}}

i think i understand what you are trying to do now
first hold your data as a python object (you gave us a json object)
import json
my_data = json.loads(my_json_string)
for item in my_data['runners']:
item['selectionId'] = [item['selectionId'], my_name_here]
the thing is that my_data['runners'][i]['selectionId'] is a string, unless you want to concat the name and the id together, you should turn it into a list or even a dictionary
each item is a dicitonary so you can always also a new keys to it
item['new_key'] = my_value

So, essentially this works...with one exception...I can see from the print(...) in the loop that the attribute is updated, however what I can't seem to do is then see this update outside the loop.
mkt_runners = []
for market_catalogue in market_catalogues:
for r in market_catalogue.runners:
mkt_runners.append((r.selection_id, r.runner_name))
for market_book in market_books:
for runner in market_book.runners:
for x in mkt_runners:
if runner.selection_id in x:
setattr(runner, 'x', x[1])
print(market_book.market_id, runner.x, runner.selection_id)
print(market_book.json())
So the print(market_book.market_id.... displays as expected, but when I print the whole list it shows the un-updated version. I can't seem to find an obvious solution, which is odd, as it seems like a really simple thing (I tried messing around with indents, in case that was the problem, but it doesn't seem to be, its like its not refreshing the market_book list post update of the runners sub list)!

Python - Searching a dictionary for strings

Basically, I have a troubleshooting program, which, I want the user to enter their input. Then, I take this input and split the words into separate strings. After that, I want to create a dictionary from the contents of a .CSV file, with the key as recognisable keywords and the second column as solutions. Finally, I want to check if any of the strings from the split users input are in the dictionary key, print the solution.
However, the problem I am facing is that I can do what I have stated above, however, it loops through and if my input was 'My phone is wet', and 'wet' was a recognisable keyword, it would go through and say 'Not recognised', 'Not recognised', 'Not recognised', then finally it would print the solution. It says not recognised so many times because the strings 'My', 'phone' and 'is' are not recognised.
So how do I test if a users split input is in my dictionary without it outputting 'Not recognised' etc..
Sorry if this was unclear, I'm quite confused by the whole matter.
Code:
import csv, easygui as eg
KeywordsCSV = dict(csv.reader(open('Keywords and Solutions.csv')))
Problem = eg.enterbox('Please enter your problem: ', 'Troubleshooting').lower().split()
for Problems, Solutions in (KeywordsCSV.items()):
pass
Note, I have the pass there, because this is the part I need help on.
My CSV file consists of:
problemKeyword | solution
For example;
wet Put the phone in a bowl of rice.

Your code reads like some ugly code golf. Let's clean it up before we look at how to solve the problem
import easygui as eg
import csv
# # KeywordsCSV = dict(csv.reader(open('Keywords and Solutions.csv')))
# why are you nesting THREE function calls? That's awful. Don't do that.
# KeywordsCSV should be named something different, too. `problems` is probably fine.
with open("Keywords and Solutions.csv") as f:
reader = csv.reader(f)
problems = dict(reader)
problem = eg.enterbox('Please enter your problem: ', 'Troubleshooting').lower().split()
# this one's not bad, but I lowercased your `Problem` because capital-case
# words are idiomatically class names. Chaining this many functions together isn't
# ideal, but for this one-shot case it's not awful.
Let's break a second here and notice that I changed something on literally every line of your code. Take time to familiarize yourself with PEP8 when you can! It will drastically improve any code you write in Python.
Anyway, once you've got a problems dict, and a problem that should be a KEY in that dict, you can do:
if problem in problems:
solution = problems[problem]
or even using the default return of dict.get:
solution = problems.get(problem)
# if KeyError: solution is None
If you wanted to loop this, you could do something like:
while True:
problem = eg.enterbox(...) # as above
solution = problems.get(problem)
if solution is None:
# invalid problem, warn the user
else:
# display the solution? Do whatever it is you're doing with it and...
break

Just have a boolean and an if after the loop that only runs if none of the words in the sentence were recognized.

I think you might be able to use something like:
for word in Problem:
if KeywordsCSV.has_key(word):
KeywordsCSV.get(word)
or the list comprehension:
[KeywordsCSV.get(word) for word in Problem if KeywordsCSV.has_key(word)]

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