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counttonum = 1
countnum = input("[•] Provide A Number :")
while counttonum < countnum:
print("[", counttonum, "] : Number = ", counttonum)
counttonum +=1
I was trying to make a counting tool that counts up to the provided number from the “input()” function.
For example:
providedNumberFromInput = 5
output = 1
2
3
4
5
And it’ll stop if the provided number is reached. Please help me.
You are very close to solution. Problem is that input() returns value as string so you will need to convert it. And also if you want to include entered number use <= instead of <
while counttonum <= int(countnum):
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Need some help here
num = [(1,4,5,30,33,41,52),(2,10,11,29,30,36,47),(3,15,25,37,38,58,59)]
if the last 6 digits are located to return the first digit.
example if finds 10,11,29,30,36,47 return 2
You can use next similair to user's approach:
num = [(1,4,5,30,33,41,52),(2,10,11,29,30,36,47),(3,15,25,37,38,58,59)]
to_find = [10,11,29,30,36,47]
print(next(n for n, *nums in num if nums == to_find))
2
You can use next with a conditional generator expression:
num = [(1,4,5,30,33,41,52),(2,10,11,29,30,36,47),(3,15,25,37,38,58,59)]
search = 11
next(first for first, *rest in num if search in rest)
# 2
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def thing():
_list = [1,1,5,6,8,3,4,6,10,23,5,12,67,3,25,2,6,5,4,3,2,1]
_list1 = [str(i) for i<=5 in lista]
return " ".join(_list1)
print(thing()))
I am new to this type of list managment, I am trying to put in _list1 only integers that are less then 5
so like the name of your function, it's created to calculate the sum of integers.
So basically, if your n=0 then your program will return 0 as result.
If not (else), it gonna give you a result of the calculation in return.
And here you want to print the interger sum of 451 which will give you the result of n % 10 + integer_sum(int(n / 10))
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Write a shell (text-based) program, called sum_num.py, that asks the user for a semicolon (;) separated list of numbers, and calculated the total. See the example below.
a = str(raw_input("Enter semicolon separated list of integers:"))
b = a.split(";")
c = (a[0:])
print("the total is " + sum(c))
PS C:\Users\ssiva\Desktop> python sum_num.py
Enter semicolon separated list of integers: 3;10;4;23;211;3
The total is 254
This code will convert into integers and sum them
a=input()
b=a.split(';')
sum=0
for num in b:
sum+=int(num)
print(sum)
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In my program, I wish to make the input to be words and not integers, and the inputted words are put into an array. The following variables are already declared.When I run my test data, numbers are accepted into the array.
i=o
for i in range (carers):
nm=input("Enter name")
carernm.append[nm]
You could use isdigit to check if your string contains digits
Example 1
print( all( not c.isdigit() for c in "String doesn't contain any numbers." ) )
True
Example 2
print( all( not c.isdigit() for c in "String 2 doesn't contain any numbers." ) )
False