I've tried to use find_element_by_class_name and link text and both result in NoSuchElement Exception. I'm just trying to click this Join waitlist button for https://v2.waitwhile.com/l/fostersbarbershop/list-view - Any assistance is greatly appreciated.
from selenium import webdriver
import time
PATH = "C:\Python\Pycharm\attempt\Drivers\chromedriver.exe"
driver = webdriver.Chrome(PATH)
driver.get("https://v2.waitwhile.com/l/fostersbarbershop/list-view")
join = False
while not join:
try:
joinButton = driver.find_element_by_class_name("disabled")
print("Button isnt ready yet.")
time.sleep(2)
driver.refresh()
except:
joinButton = driver.find_element_by_class_name("public-submit-btn")
print("Join")
joinButton.click()
join = True
It seems you have synchronization issue.
Induce WebDriverWait() and wait for element_to_be_clickable() for following ID locator
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.ID, "join-waitlist"))).click()
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.ID, "ww-name"))).send_keys("TestUser")
You need to import below libraries.
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
browser snapshot
The page your trying to automate is angular. Typically what happens in script-based pages is you download the source, the page load event is classed as complete, then some JS scripts run to get/update the page content. Those scripts (which can take seconds to complete) update the DOM with the page you see.
In contrast selenium can only recognise the page is loaded - Selenium will be attempting to find those elements at this readystate-point and is unaware of any running scripts.
You will need to wait for your element to be ready before you proceed.
Easy solution is to add an implicit wait to your script.
An implicit wait will ignore the nosuchelement exception until the timeout has been reached.
See here for more information on waits.
This is the line of code to add:
driver.implicitly_wait(10)
Just adjust the time based on what you need.
You only need it once.
This is the code that works for me:
driver = webdriver.Chrome()
driver.get("https://v2.waitwhile.com/l/fostersbarbershop/list-view")
driver.implicitly_wait(10)
join = False
while not join:
try:
joinButton = driver.find_element_by_class_name("disabled")
print("Button isnt ready yet.")
time.sleep(2)
driver.refresh()
except:
joinButton = driver.find_element_by_class_name("public-submit-btn")
print("Join")
joinButton.click()
join = True
This is the end state:
This page has a total of 790 products and I write selenium code to automatically click on the product load button until it will finish loading all 790 products. Unfortunately, my code is not working and getting an error. here is my full code:
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
import time
driver = webdriver.Chrome()
driver.maximize_window()
url ='https://www.billigvvs.dk/maerker/grohe/produkter?min_price=1'
driver.get(url)
time.sleep(5)
#accept cookies
try:
driver.find_element_by_xpath("//button[#class='coi-banner__accept']").click()
except:
pass
print('cookies not accepted')
# Wait 20 seconds for page to load.
timeout = 20
try:
WebDriverWait(driver, timeout).until(EC.visibility_of_element_located((By.XPATH, "//a[#class='productbox__info__name']")))
except TimeoutException:
print("Timed out waiting for page to load")
browser.quit()
#my page load button not working. I want to load all 790 product in this page
products_load_button = driver.find_element_by_xpath("//div[#class='filterlist__button']").click()
The error that I am getting:
Message: no such element: Unable to locate element: {"method":"xpath","selector":"//div[#class='filterlist__button']"}
(Session info: chrome=87.0.4280.88)
The error message saying Unable to locate element but see the picture which saying I am selecting the right element.
You are missing an extra space at the end, try with this:
products_load_button = driver.find_element_by_xpath("//div[#class='filterlist__button ']").click()
when you work with selectors is always a good practice to copy and paste directly from the page, that will save a lot of headaches in the future.
Edit:
The while loop to check if all the elements are loaded looks similar to this:
progress_bar_text = driver.find_element_by_css("div.filterlist__pagination__text").text
# From here you could extract the total items and the loaded items
# Note: I am doing this because I don't have access to the page, probably
# there is a better way to found out if the items are loaded taking
# taking a look into the attributes of the progressBar
total_items = int(progress_bar_text.split()[4])
loaded_items = int(progress_bar_text.split()[1])
while loaded_items < total_items:
# Click the product load button until the products are loaded
product_load_button.click()
# Get the progress bar text and updates the loaded_items count
progress_bar_text = driver.find_element_by_css("div.filterlist__pagination__text").text
loaded_items = int(progress_bar_text.split()[1])
This is a very simple example and does not consider a lot of scenarios that you will need to handle to make it stable, some of them are:
The elements might disappear or reload after you click the products_load_button. For this I'll recommend that you take a look to explicit waits in selenium docs.
Is possible that the progress bar could disappear/hide after the load is complete.
I've created a script in python to scrape the content populated upon initiating a serach in the search box in google map. My script can generate results by pressing that search button. Now I wish to keep parsing the results by pressing the next button (located at the bottom left) until there is none.
Site address
I'm using this motels in new jersey keyword as search.
I've tried with:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome()
driver.get("https://www.google.com/maps/search/")
wait = WebDriverWait(driver, 10)
wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR, "input#searchboxinput"))).send_keys("motels in new jersey")
wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button#searchbox-searchbutton"))).click()
while True:
for item in wait.until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, ".section-result-content"))):
name = WebDriverWait(item,10).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "h3[class='section-result-title'] > span"))).text
print(name)
try:
next_page = wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR,"button[jsaction$='.nextPage'] > span")))
driver.execute_script("arguments[0].click();",next_page)
except TimeoutException: break
driver.quit()
The above script gives me the same results (from first page) several times no matter how far it goes clicking on that next button.
How can I get the accurate results from next pages?
Here is the logic that should work.
There is a server error (application issue) occurring when navigating through the list, so are waiting for the page to load the information and then check if server error displayed, if not then continue with population of the results.
driver.get("https://www.google.com/maps/search/")
wait = WebDriverWait(driver, 10)
wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR, "input#searchboxinput"))).send_keys("motels in new jersey")
wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button#searchbox-searchbutton"))).click()
while True:
# wait until the information is loaded
wait.until_not(EC.presence_of_element_located((By.XPATH, "//div[#id='searchbox'][contains(#class,'loading')]")))
# check if there is any server error
if len(driver.find_elements_by_xpath("//div[#class='snackbar-message'][contains(.,'error')]"))>0:
# print the error message
print(driver.find_element_by_xpath("//div[#class='snackbar-message'][contains(.,'error')]").text)
# exit the loop
break
for item in wait.until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, ".section-result-content"))):
name = WebDriverWait(item,10).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "h3[class='section-result-title'] > span"))).text
print(name)
try:
next_page = wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR,"button[jsaction$='.nextPage'] > span")))
driver.execute_script("arguments[0].click();",next_page)
except TimeoutException: break
Being in a while True loop, your script does not wait for the next page to be rendered before searching for the name. The locators input#searchboxinput and button#searchbox-searchbutton are still active when the next page is loading. Thus your script will output the same names from the same page for as many iterations as will run before the next page is loaded.
I recommend a wait condition for the page loading, such as the presence of the spinner animation in the top left where the X button usually is. This should pause the execution until the next page is loaded. The div with id searchbox has a show-loading class appear only while that spinner is active. You can use that to determine if the page is still loading.
I am trying to scrape data from the Sunshine List website (http://www.sunshinelist.ca/) using the Selenium package but I get the following error mentioned below. From several other related posts I understand that I need to use the WebDriverWait to explicitly ask the driver to wait/refresh but I am unable to identify where and how I should call the function.
Screenshot of Error
StaleElementReferenceException: Message: The element reference
of (tr class="even") stale: either the element is no longer attached to the DOM or the
page has been refreshed
import numpy as np
import pandas as pd
import requests
import time
from bs4 import BeautifulSoup
from selenium import webdriver
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.firefox.firefox_binary import FirefoxBinary
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
from selenium.common.exceptions import StaleElementReferenceException
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
ffx_bin = FirefoxBinary(r'C:\Users\BhagatM\AppData\Local\Mozilla Firefox\firefox.exe')
ffx_caps = DesiredCapabilities.FIREFOX
ffx_caps['marionette'] = True
driver = webdriver.Firefox(capabilities=ffx_caps,firefox_binary=ffx_bin)
driver.get("http://www.sunshinelist.ca/")
driver.maximize_window()
tablewotags1=[]
while True:
divs = driver.find_element_by_id('datatable-disclosures')
divs1=divs.find_elements_by_tag_name('tbody')
for d1 in divs1:
div2=d1.find_elements_by_tag_name('tr')
for d2 in div2:
tablewotags1.append(d2.text)
try:
driver.find_element_by_link_text('Next →').click()
except NoSuchElementException:
break
year1=tablewotags1[0::10]
name1=tablewotags1[3::10]
position1=tablewotags1[4::10]
employer1=tablewotags1[1::10]
df1=pd.DataFrame({'Year':year1,'Name':name1,'Position':position1,'Employer':employer1})
df1.to_csv('Sunshine List-1.csv', index=False)
If your problem is to click the "Next" button, you can do that with the xpath:
driver = webdriver.Firefox(executable_path=r'/pathTo/geckodriver')
driver.get("http://www.sunshinelist.ca/")
wait = WebDriverWait(driver, 20)
el=wait.until(EC.presence_of_element_located((By.XPATH,"//ul[#class='pagination']/li[#class='next']/a[#href='#' and text()='Next → ']")))
el.click()
For each click on the "Next" button -- you should find that button and click on it.
Or do something like this:
max_attemps = 10
while True:
next = self.driver.find_element_by_css_selector(".next>a")
if next is not None:
break
else:
time.sleep(0.5)
max_attemps -= 1
if max_attemps == 0:
self.fail("Cannot find element.")
And after this code does click action.
PS: Also try to add just time.sleep(x) after fiding element and then do click action.
Try this code below.
When the element is no longer attached to the DOM and the StaleElementReferenceException is invoked, search for the element again to reference the element.
Please do note I checked with Chrome:
try:
driver.find_element_by_css_selector('div[id="datatable-disclosures_wrapper"] li[class="next"]>a').click()
except StaleElementReferenceException:
driver.find_element_by_css_selector('div[id="datatable-disclosures_wrapper"] li[class="next"]>a').click()
except NoSuchElementException:
break
>>>Stale Exceptions can be handled using **StaleElementReferenceException** to continue to execute the for loop. When you try to get the element by any find_element method in a for loop.
from selenium.common import exceptions
and customize your code of for loop as:
for loop starts:
try:
driver.find_elements_by_id("data") //method to find element
//your code
except exceptions.StaleElementReferenceException:
pass
When you raise the StaleElementException that means that somthing changed in the site, but not in the list you have. So the trick is to refresh that list every time, inside the loop like this:
while True:
driver.implicitly_wait(4)
for d1 in driver.find_element_by_id('datatable-disclosures').find_element_by_tag_name('tbody').find_elements_by_tag_name('tr'):
tablewotags1.append(d1.text)
try:
driver.switch_to.default_content()
driver.find_element_by_xpath('//*[#id="datatable-disclosures_wrapper"]/div[2]/div[2]/div/ul/li[7]/a').click()
except NoSuchElementException:
print('Don\'t be so cryptic about error messages, they are good\n
...Script broke clicking next') #jk aside put some info there
break
Hope this help you, cheers.
Edit:
So I went to the said website, the layout is pretty straight forward, but the structure repeats itself like four times. So when you go about crawling the site like that something is bound to change.
So I’ve edited the code to only scrap one tbody tree. This tree comes from the first datatable-disclousure. And added some waits.
I want to scrape all the data of a page implemented by a infinite scroll. The following python code works.
for i in range(100):
driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
time.sleep(5)
This means every time I scroll down to the bottom, I need to wait 5 seconds, which is generally enough for the page to finish loading the newly generated contents. But, this may not be time efficient. The page may finish loading the new contents within 5 seconds. How can I detect whether the page finished loading the new contents every time I scroll down? If I can detect this, I can scroll down again to see more contents once I know the page finished loading. This is more time efficient.
The webdriver will wait for a page to load by default via .get() method.
As you may be looking for some specific element as #user227215 said, you should use WebDriverWait to wait for an element located in your page:
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.common.exceptions import TimeoutException
browser = webdriver.Firefox()
browser.get("url")
delay = 3 # seconds
try:
myElem = WebDriverWait(browser, delay).until(EC.presence_of_element_located((By.ID, 'IdOfMyElement')))
print "Page is ready!"
except TimeoutException:
print "Loading took too much time!"
I have used it for checking alerts. You can use any other type methods to find the locator.
EDIT 1:
I should mention that the webdriver will wait for a page to load by default. It does not wait for loading inside frames or for ajax requests. It means when you use .get('url'), your browser will wait until the page is completely loaded and then go to the next command in the code. But when you are posting an ajax request, webdriver does not wait and it's your responsibility to wait an appropriate amount of time for the page or a part of page to load; so there is a module named expected_conditions.
Trying to pass find_element_by_id to the constructor for presence_of_element_located (as shown in the accepted answer) caused NoSuchElementException to be raised. I had to use the syntax in fragles' comment:
from selenium import webdriver
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
driver = webdriver.Firefox()
driver.get('url')
timeout = 5
try:
element_present = EC.presence_of_element_located((By.ID, 'element_id'))
WebDriverWait(driver, timeout).until(element_present)
except TimeoutException:
print "Timed out waiting for page to load"
This matches the example in the documentation. Here is a link to the documentation for By.
Find below 3 methods:
readyState
Checking page readyState (not reliable):
def page_has_loaded(self):
self.log.info("Checking if {} page is loaded.".format(self.driver.current_url))
page_state = self.driver.execute_script('return document.readyState;')
return page_state == 'complete'
The wait_for helper function is good, but unfortunately click_through_to_new_page is open to the race condition where we manage to execute the script in the old page, before the browser has started processing the click, and page_has_loaded just returns true straight away.
id
Comparing new page ids with the old one:
def page_has_loaded_id(self):
self.log.info("Checking if {} page is loaded.".format(self.driver.current_url))
try:
new_page = browser.find_element_by_tag_name('html')
return new_page.id != old_page.id
except NoSuchElementException:
return False
It's possible that comparing ids is not as effective as waiting for stale reference exceptions.
staleness_of
Using staleness_of method:
#contextlib.contextmanager
def wait_for_page_load(self, timeout=10):
self.log.debug("Waiting for page to load at {}.".format(self.driver.current_url))
old_page = self.find_element_by_tag_name('html')
yield
WebDriverWait(self, timeout).until(staleness_of(old_page))
For more details, check Harry's blog.
As mentioned in the answer from David Cullen, I've always seen recommendations to use a line like the following one:
element_present = EC.presence_of_element_located((By.ID, 'element_id'))
WebDriverWait(driver, timeout).until(element_present)
It was difficult for me to find somewhere all the possible locators that can be used with the By, so I thought it would be useful to provide the list here.
According to Web Scraping with Python by Ryan Mitchell:
ID
Used in the example; finds elements by their HTML id attribute
CLASS_NAME
Used to find elements by their HTML class attribute. Why is this
function CLASS_NAME not simply CLASS? Using the form object.CLASS
would create problems for Selenium's Java library, where .class is a
reserved method. In order to keep the Selenium syntax consistent
between different languages, CLASS_NAME was used instead.
CSS_SELECTOR
Finds elements by their class, id, or tag name, using the #idName,
.className, tagName convention.
LINK_TEXT
Finds HTML tags by the text they contain. For example, a link that
says "Next" can be selected using (By.LINK_TEXT, "Next").
PARTIAL_LINK_TEXT
Similar to LINK_TEXT, but matches on a partial string.
NAME
Finds HTML tags by their name attribute. This is handy for HTML forms.
TAG_NAME
Finds HTML tags by their tag name.
XPATH
Uses an XPath expression ... to select matching elements.
From selenium/webdriver/support/wait.py
driver = ...
from selenium.webdriver.support.wait import WebDriverWait
element = WebDriverWait(driver, 10).until(
lambda x: x.find_element_by_id("someId"))
On a side note, instead of scrolling down 100 times, you can check if there are no more modifications to the DOM (we are in the case of the bottom of the page being AJAX lazy-loaded)
def scrollDown(driver, value):
driver.execute_script("window.scrollBy(0,"+str(value)+")")
# Scroll down the page
def scrollDownAllTheWay(driver):
old_page = driver.page_source
while True:
logging.debug("Scrolling loop")
for i in range(2):
scrollDown(driver, 500)
time.sleep(2)
new_page = driver.page_source
if new_page != old_page:
old_page = new_page
else:
break
return True
Have you tried driver.implicitly_wait. It is like a setting for the driver, so you only call it once in the session and it basically tells the driver to wait the given amount of time until each command can be executed.
driver = webdriver.Chrome()
driver.implicitly_wait(10)
So if you set a wait time of 10 seconds it will execute the command as soon as possible, waiting 10 seconds before it gives up. I've used this in similar scroll-down scenarios so I don't see why it wouldn't work in your case. Hope this is helpful.
To be able to fix this answer, I have to add new text. Be sure to use a lower case 'w' in implicitly_wait.
Here I did it using a rather simple form:
from selenium import webdriver
browser = webdriver.Firefox()
browser.get("url")
searchTxt=''
while not searchTxt:
try:
searchTxt=browser.find_element_by_name('NAME OF ELEMENT')
searchTxt.send_keys("USERNAME")
except:continue
Solution for ajax pages that continuously load data. The previews methods stated do not work. What we can do instead is grab the page dom and hash it and compare old and new hash values together over a delta time.
import time
from selenium import webdriver
def page_has_loaded(driver, sleep_time = 2):
'''
Waits for page to completely load by comparing current page hash values.
'''
def get_page_hash(driver):
'''
Returns html dom hash
'''
# can find element by either 'html' tag or by the html 'root' id
dom = driver.find_element_by_tag_name('html').get_attribute('innerHTML')
# dom = driver.find_element_by_id('root').get_attribute('innerHTML')
dom_hash = hash(dom.encode('utf-8'))
return dom_hash
page_hash = 'empty'
page_hash_new = ''
# comparing old and new page DOM hash together to verify the page is fully loaded
while page_hash != page_hash_new:
page_hash = get_page_hash(driver)
time.sleep(sleep_time)
page_hash_new = get_page_hash(driver)
print('<page_has_loaded> - page not loaded')
print('<page_has_loaded> - page loaded: {}'.format(driver.current_url))
How about putting WebDriverWait in While loop and catching the exceptions.
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
browser = webdriver.Firefox()
browser.get("url")
delay = 3 # seconds
while True:
try:
WebDriverWait(browser, delay).until(EC.presence_of_element_located(browser.find_element_by_id('IdOfMyElement')))
print "Page is ready!"
break # it will break from the loop once the specific element will be present.
except TimeoutException:
print "Loading took too much time!-Try again"
You can do that very simple by this function:
def page_is_loading(driver):
while True:
x = driver.execute_script("return document.readyState")
if x == "complete":
return True
else:
yield False
and when you want do something after page loading complete,you can use:
Driver = webdriver.Firefox(options=Options, executable_path='geckodriver.exe')
Driver.get("https://www.google.com/")
while not page_is_loading(Driver):
continue
Driver.execute_script("alert('page is loaded')")
use this in code :
from selenium import webdriver
driver = webdriver.Firefox() # or Chrome()
driver.implicitly_wait(10) # seconds
driver.get("http://www.......")
or you can use this code if you are looking for a specific tag :
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Firefox() #or Chrome()
driver.get("http://www.......")
try:
element = WebDriverWait(driver, 10).until(
EC.presence_of_element_located((By.ID, "tag_id"))
)
finally:
driver.quit()
Very good answers here. Quick example of wait for XPATH.
# wait for sizes to load - 2s timeout
try:
WebDriverWait(driver, 2).until(expected_conditions.presence_of_element_located(
(By.XPATH, "//div[#id='stockSizes']//a")))
except TimeoutException:
pass
I struggled a bit to get this working as that didn't worked for me as expected. anyone who is still struggling to get this working, may check this.
I want to wait for an element to be present on the webpage before proceeding with my manipulations.
we can use WebDriverWait(driver, 10, 1).until(), but the catch is until() expects a function which it can execute for a period of timeout provided(in our case its 10) for every 1 sec. so keeping it like below worked for me.
element_found = wait_for_element.until(lambda x: x.find_element_by_class_name("MY_ELEMENT_CLASS_NAME").is_displayed())
here is what until() do behind the scene
def until(self, method, message=''):
"""Calls the method provided with the driver as an argument until the \
return value is not False."""
screen = None
stacktrace = None
end_time = time.time() + self._timeout
while True:
try:
value = method(self._driver)
if value:
return value
except self._ignored_exceptions as exc:
screen = getattr(exc, 'screen', None)
stacktrace = getattr(exc, 'stacktrace', None)
time.sleep(self._poll)
if time.time() > end_time:
break
raise TimeoutException(message, screen, stacktrace)
If you are trying to scroll and find all items on a page. You can consider using the following. This is a combination of a few methods mentioned by others here. And it did the job for me:
while True:
try:
driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
driver.implicitly_wait(30)
time.sleep(4)
elem1 = WebDriverWait(driver, 30).until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, "element-name")))
len_elem_1 = len(elem1)
print(f"A list Length {len_elem_1}")
driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
driver.implicitly_wait(30)
time.sleep(4)
elem2 = WebDriverWait(driver, 30).until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, "element-name")))
len_elem_2 = len(elem2)
print(f"B list Length {len_elem_2}")
if len_elem_1 == len_elem_2:
print(f"final length = {len_elem_1}")
break
except TimeoutException:
print("Loading took too much time!")
selenium can't detect when the page is fully loaded or not, but javascript can. I suggest you try this.
from selenium.webdriver.support.ui import WebDriverWait
WebDriverWait(driver, 100).until(lambda driver: driver.execute_script('return document.readyState') == 'complete')
this will execute javascript code instead of using python, because javascript can detect when page is fully loaded, it will show 'complete'. This code means in 100 seconds, keep tryingn document.readyState until complete shows.
nono = driver.current_url
driver.find_element(By.XPATH,"//button[#value='Send']").click()
while driver.current_url == nono:
pass
print("page loaded.")