I'd like to create a CSV from a TXT file. I have a text file with lines (300 lines+) separated by backslashes. I'd like each line to be a separate row, and each backslash to be a separate new column.
The text file looks like:
example 1\example 2\example 3\example 4
test 1\test 2\test 3\test 4
I'd like the CSV to look like:
Example 1
Example 2
Example 3
Example 4
Test 1
Test 2
Test 3
Test 4
So far I have:
import csv
with open('Report.txt') as report:
report_txt = report.read()
with open('Report.csv','w',newline='') as csvfile:
writer = csv.writer(csvfile)
writer.writerow(report_txt)
I know I need to use \ as a delimiter, but I'm not sure how. Thanks for any help!
Define your delimiter like this (escape the \):
reader = csv.reader(open("Report.csv"), delimiter="\\")
Code:
import csv
with open('Report.txt') as report:
reader = csv.reader(report, delimiter="\\")
with open('Report_output.csv', 'w', newline='') as csvfile:
writer = csv.writer(csvfile)
for line in reader:
writer.writerow(line)
First you got to split the string based on the delimeter. You can achieve this by using the split operator or regex.
import csv
with open('file.txt', 'r') as in_file:
stripped = (line.strip() for line in in_file)
lines = (line.split("\\") for line in stripped if line)
Then pretty much write it to the csv.
with open('report.csv', 'w') as out_file:
writer = csv.writer(out_file)
writer.writerows(lines)
Tweak your code accordingly. The concept is pretty much the same. Note the double backslash is to account for the escape character.
If you are just trying to convert that text into CSV, you can just replace every "\" character with ";" and you'll have a valid CSV file.
Else, if you want to do something with the parsed data before reexporting to CSV, you can read the file line by line and use the split() Method with "\", then rejoin and write line by line, like here:
with open('in.txt') as input_file:
with open('out.csv','a') as output_file:
txt_line = input_file.readline()
while txt_line:
cells = txt_line.split("\\")
# Do something with each cell...
csv_line = ";".join(cells)
output_file.write(csv_line)
txt_line = input_file.readline()
Related
I need code that can read a .txt file and output the data inside into a CSV file. The .txt file would have data in this form:
Jeff/Terry/01-10-2020/1-2
+Tom/02-10-2020
-Jeff/03-10-2020
And I need to write the data into a CSV file where the string is split and separated every time it encounters a "/". So the CSV file would look something like this:
Column A
Column B
Column C
Column D
Jeff
Terry
01-10-2020
1-2
+Tom
02-10-2020
-Jeff
03-10-2020
Furthermore I would also need code to write this CSV file data back into another .txt file in the same format, with the "/" separating the data of the cells.
I currently have this:
import csv
with open ("data.txt", "r") as in_file:
stripped = (line.strip() for line in in_file)
lines = (line.split("/") for line in stripped if line
open ("data.csv", "w") as out_file:
writer = csv.writer(out_file)
writer.writerow(('first', 'second'))
writer.writerows(lines)
Currently it is nowhere near the functionality that I need, and it is also giving me syntax errors on the "o" of open on the 4th last line, open ("data.csv", "w") as out_file:.
There are a few grammatical errors here.
Line 4 has missing closing parenthesis: lines = (line.split("/") for line in stripped if line).
Line 5 should start with with: with open("data.csv", "w") as out_file:.
Also, it's better to place the 5th line outside the with block on line 2.
Lines 6 through 8 should have one indent, not two.
Try the following (see the documentation):
import csv
with open("data.txt", "r", newline='') as in_file:
lines = list(csv.reader(in_file, delimiter="/"))
with open("data.csv", "w", newline='') as out_file:
writer = csv.writer(out_file, delimiter="/")
writer.writerow(('first', 'second'))
writer.writerows(lines)
I am trying to convert a txt file into a csv file in Python. The current format of the txt file are several strings separated by spaces. I would like to write each string into one cell in the csv file.
The txt file has got following structure:
UserID Desktop Display (Version) (Server/Port handle), Date
UserID Desktop Display (Version) (Server/Port handle), Date
etc.
My approach would be following:
with open('licfile.txt', "r+") as in_file:
stripped = (line.strip() for line in in_file)
lines = (line.split(" ") for line in stripped if line)
with open('licfile.csv', 'w') as out_file:
writer = csv.writer(out_file)
writer.writerow(('user', 'desktop', 'display', 'version', 'server', 'handle', 'date'))
writer.writerows(lines)
Unfortunately this is not working as expected. I do get following ValueError: I/O operation on closed file. Additionally only the intended row headers are shown in one cell in the csv file.
Any tips on how to proceed? Many thanks in advance.
how about
with open('licfile.txt', 'r') as in_file, open('licfile.csv', 'w') as out_file:
for line in in_file:
if line.strip():
out_file.write(line.strip().replace(' ', ',') + '\n')
and for the german Excel enthusiasts...
...
...
...
... .replace(' ', ';') + '\n')
:)
You can also use the built in csv module to accomplish this easily:
import csv
with open('licfile.txt', 'r') as in_file, open('licfile.csv', 'w') as out_file:
reader = csv.reader(in_file, delimiter=" ")
writer = csv.writer(out_file, lineterminator='\n')
writer.writerows(reader)
I used lineterminator='\n' argument here as the default is \r\n and it ends up giving you an extra line of return per row in most cases.
There are also a few arguments you could use if say quoting is needed or a different delimiter is desired: https://docs.python.org/3/library/csv.html#csv-fmt-params
You are using comprehension with round brackets which will cause to create tuple object. Instead of that just use square bracket which will return list. see below example:
stripped = [line.strip() for line in in_file]
lines = [line.split(" ") for line in stripped if line]
licfile_df = pd.read_csv('licfile.txt',sep=",", header=None)
The problem is I have this text, csv file which is missing commas and I would like to insert it in order to run the file on LaTex and make a table. I have a MWE of a code from another problem which I ran and it did not work. Is it possible someone could guide me on how to change it.
I have used a Python code which provides a blank file, and another one which provides a blank document, and another which removes the spaces.
import fileinput
input_file = 'C:/Users/Light_Wisdom/Documents/Python Notes/test.txt'
output= open('out.txt','w+')
with open('out.txt', 'w+') as output:
for each_line in fileinput.input(input_file):
output.write("\n".join(x.strip() for x in each_line.split(',')))
text file contains more numbers but its like this
0 2.58612
0.00616025 2.20018
0.0123205 1.56186
0.0184807 0.371172
0.024641 0.327379
0.0308012 0.368863
0.0369615 0.322228
0.0431217 0.171899
Outcome
0.049282, -0.0635003
0.0554422, -0.110747
0.0616025, 0.0701394
0.0677627, 0.202381
0.073923, 0.241264
0.0800832, 0.193697
Renewed Attempt:
with open("CSV.txt","r") as file:
new = list(map(lambda x: ''.join(x.split()[0:1]+[","]+x.split()[0:2]),file.readlines()))
with open("New_CSV.txt","w+") as output:
for i in new:
output.writelines(i)
output.writelines("\n")
This can be using .split and .join by splitting the line into a list and then joining the list separated by commas. This enables us to handle several subsequent spaces in the file:
f1 = open(input_file, "r")
with open("out.txt", 'w') as f2:
for line in f1:
f2.write(",".join(line.split()) + "\n")
f1.close()
You can also use csv to handle the writing automatically:
import csv
f1 = open(input_file, "r")
with open("out.txt", 'w') as f2:
writer = csv.writer(f2)
for line in f1:
writer.writerow(line.split())
f1.close()
I'm trying to write to a CSV file with output that looks like this:
14897,40.50891,-81.03926,168.19999
but the CSV writer keeps writing the output with quotes at beginning and end
'14897,40.50891,-81.03926,168.19999'
When I print the line normally, the output is correct but I need to do line.split() or else the csv writer puts output as 1,4,8,9,7 etc...
But when I do line.split() the output is then
['14897,40.50891,-81.03926,168.19999']
Which is written as '14897,40.50891,-81.03926,168.19999'
How do I make the quotes go away? I already tried csv.QUOTE_NONE but doesn't work.
with open(results_csv, 'wb') as out_file:
writer = csv.writer(out_file, delimiter=',')
writer.writerow(["time", "lat", "lon", "alt"])
for f in file_directory):
for line in open(f):
print line
line = line.split()
writer.writerow(line)
with line.split(), you're not splitting according to commas but to blanks (spaces, linefeeds, tabs). Since there are none, you end up with only 1 item per row.
Since this item contains commas, csv module has to quote to make the difference with the actual separator (which is also comma). You would need line.strip().split(",") for it to work, but...
using csv to read your data would be a better idea to fix this:
replace that:
for line in open(some_file):
print line
line = line.split()
writer.writerow(line)
by:
with open(some_file) as f:
cr = csv.reader(f) # default separator is comma already
writer.writerows(cr)
You don't need to read the file manually. You can simply use csv reader.
Replace the inner for loop with:
# with ensures that the file handle is closed, after the execution of the code inside the block
with open(some_file) as file:
row = csv.reader(file) # read rows
writer.writerows(row) # write multiple rows at once
I have this input file:
one\tone
two\ttwo
three\tthree
With a tab between each word.
I am trying to save it in a csv file where each word ends up in its own cell. This is my code:
import csv
input = open('input.txt').read()
lines = input.split('\n')
with open('output.csv', 'w') as f:
writer = csv.writer(f)
for line in lines:
writer.writerow([line])
However, both words end up in the same cell:
How do I change the code so that each word ends up in its own cell?
Try this:
import csv
input = open('input.txt').read()
lines = input.split('\n')
with open('output.csv', 'w') as f:
writer = csv.writer(f)
for line in lines:
writer.writerow(line.split('\t'))
The writerow method in the CSV writer library takes a list of columns.
Currently, you are providing your whole string the value of the first column
writer.writerow([line])
Instead, try splitting the string by \t, thus creating a list of each individual word and provide that to the library instead.
writer.writerow(line.split("\t"))
You need to split the input lines into a list, so that csv.writer() will put them into seperate columns. Try:
with open('output.csv', 'w') as f:
writer = csv.writer(f)
for line in lines:
writer.writerow(line.split('\t'))