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How to read excel cell values as a list?

When I tried to read data from excel file (excell sheet screenshot attached), I get values as strings. But i need python datatype when i read excel file data.
#read excel file
dataframe1 = pd.read_excel('Data.xlsx')
Below code line give me list of string that makes sense.
#read mega_links column
mega_linkss = dataframe1.iloc[:,7].tolist()
for link in mega_linkss:
print(link, ' ',type(link))
break
OUTPUT:
"['https://mega.nz/folder/KXICCZrS#dJT2bqTh3eK_xbbMPuNglQ']" <class 'str'>
As you can see class is 'str'
To get class as 'list', i tried following code.
# when i used list function to convert string in list.
for link in mega_linkss:
print(list(link))
break
OUTPUT:
['[', "'", 'h', 't', 't', 'p', 's', ':', '/', '/', 'm', 'e', 'g', 'a', '.', 'n', 'z', '/', 'f', 'o', 'l', 'd', 'e', 'r', '/', 'K', 'X', 'I', 'C', 'C', 'Z', 'r', 'S', '#', 'd', 'J', 'T', '2', 'b', 'q', 'T', 'h', '3', 'e', 'K', '_', 'x', 'b', 'b', 'M', 'P', 'u', 'N', 'g', 'l', 'Q', "'", ']']
I need output like this.
OUTPUT:
['https://mega.nz/folder/KXICCZrS#dJT2bqTh3eK_xbbMPuNglQ'] <class 'list'>
Excell Sheet Screenshot is attached.
Code Screenshot is attached for a better understanding of what I need.
Thanks
[enter image description here](https://i.stack.imgur.com/yLsK8.jpg)
I need output like this.
OUTPUT:
['https://mega.nz/folder/KXICCZrS#dJT2bqTh3eK_xbbMPuNglQ'] <class 'list'>

The value in your excel file is a string "['https...']". It is a string representation of a list, so if you wanted to convert it to a list, you could use eval(string) or ast.literal_eval(string).
eval is considered unsafe, and ast.literal_eval is a safer alternative, part of a built-in ast module.
For example, ast.literal_eval("[1,2,3]") = [1, 2, 3]. Likewise, ast.literal_eval(link) will return a list version of your link, which according to your excel table will be a list with a single string in it.

How can I reference a string (e.g. 'A') to the index of a larger list (e.g. ['A', 'B', 'C', 'D', ...])?

I have been racking my brain and scouring the internet for some hours now, please help.
Effectively I am trying to create a self-contained function (in python) for producing a caesar cipher. I have a list - 'cache' - of all letters A-Z.
def caesarcipher(text, s):
global rawmessage #imports a string input - the 'raw message' which is to be encrypted.
result = ''
cache = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O',
'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
Is it possible to analyze the string input (the 'rawmessage') and attribute each letter to its subsequent index position in the list 'cache'? e.g. if the input was 'AAA' then the console would recognise it as [0,0,0] in the list 'cache'. Or if the input was 'ABC' then the console would recognise it as [0,1,2] in the list 'cache'.
Thank you to anyone who makes the effort to help me out here.

Use a list comprehension:
positions = [cache.index(letter) for letter in rawmessage if letter in cache]

You can with a list comprehension. Also you can get the letter from string.
import string
print([string.ascii_uppercase.index(c) for c in "AAA"])
# [0, 0, 0]
print([string.ascii_uppercase.index(c) for c in "ABC"])
# [0, 1, 2]

result = []
for i in list(rawmessage):
result.append(cache.index(i))

Python: How to replace string elements using an array of tuples?

I'm trying to replace the characters of the reversed alphabet with those of the alphabet. This is what I've got:
alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
rev_alphabet = alphabet[::-1]
sample = "wrw blf hvv ozhg mrtsg'h vkrhlwv?"
def f(alph, rev_alph):
return (alph, rev_alph)
char_list_of_tups = list(map(f, alphabet, rev_alphabet))
for alph, rev_alph in char_list_of_tups:
sample = sample.replace(rev_alph, alph)
print(sample)
expected output: did you see last night's episode?
actual output: wrw you svv ozst nrtst's vprsowv?
I understand that I'm printing the last "replacement" of the whole iteration. How can I avoid this without appending it to a list and then running into problems with the spacing of the words?

Your problem here is that you lose data as you perform each replacement; for a simple example, consider an input of "az". On the first replacement pass, you replace 'z' with 'a', and now have "aa". When you get to replacing 'a' with 'z', it becomes "zz", because you can't tell the difference between an already replaced character and one that's still unchanged.
For single character replacements, you want to use the str.translate method (and the not strictly required, but useful helper function, str.maketrans), to do character by character transliteration across the string in a single pass.
from string import ascii_lowercase # No need to define the alphabet; Python provides it
# You can use the original str form, no list needed
# Do this once up front, and reuse it for as many translate calls as you like
trans_map = str.maketrans(ascii_lowercase[::-1], ascii_lowercase)
sample = sample.translate(trans_map)

alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
# or
alphabet = [chr(97 + i) for i in range(0,26)]
sample = "wrw blf hvv ozhg mrtsg'h vkrhlwv?"
res = []
for ch in sample:
if ch in alphabet:
res.append(alphabet[-1 - alphabet.index(ch)])
else:
res.append(ch)
print("".join(res))

Another Way if you are ok with creating a new string instead.
alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
dictRev = dict(zip(alphabet, alphabet[::-1]))
sample = "wrw blf hvv ozhg mrtsg'h vkrhlwv?"
s1="".join([dictRev.get(char, char) for char in sample])
print(s1)
"did you see last night's episode?"

Python, why is my loop writing a blank space to the end of the list from text file

correctAnswers = ['A','C','A','A','D','B','C','A','C','B','A','D','C','A','D','C','B','B','D','A']
studentAnswers = []
correctList = []
file = open('forchapter7.txt','r')
student = file.readline()
student = student.rstrip('\n')
studentAnswers.append(student)
while student != '':
student = file.readline()
student = student.rstrip('\n')
studentAnswers.append(student)
print(studentAnswers)
print(correctAnswers)
file.close()
#displays this
['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', '']
['A', 'C', 'A', 'A', 'D', 'B', 'C', 'A', 'C', 'B', 'A', 'D', 'C', 'A', 'D', 'C', 'B', 'B', 'D', 'A']
my text file is a plain .txt file with the letters A-T going down and no space or new line after T, why is my loop writing the blank space?

When you read your final line, student == 'T', so the loop repeats itself. When you try to file.readline() after you have finished reading the entire file, it returns '' because there is nothing else to read. You are then adding this to your list.
Just add a check for empty string before adding to the list:
if student:
studentAnswers.append(student)
EDIT:
An alternative you could use is to read all the lines with file.readlines() and iterate over the list. This will not run the loop an extra time:
for student in file.readlines():
studentAnswers.append(student.rstrip('\n')
You can even use list comprehension this way:
studentAnswers = [student.rstrip('\n') for student in file.readlines()]
Note, however, that if the file does have an empty line these last two methods will need checks to prevent them from adding an empty entry to the list.

write list of tuples of lists to text file

My result data is in a list of tuples, which each have a list in them:
[(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H'], ['I', 'J', 'K', 'L', 'M', 'N']),
...
(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H'], ['I', 'J', 'K', 'L', 'M', 'N'])]
What's the best way to strip all the nesting and quotes and write A:N to a tab delimited file?

The quotes are not part of the string, they denote the string. You would not be able to remove them.
The csv module makes this taks pretty straightforward:
import csv, itertools
with open('file.csv', 'wb') as f:
writer = csv.writer(f, delimiter="\t")
writer.writerows(list(itertools.chain(*t)) for t in results)
This results in a file where each row corresponds to a tuple and a row contains the letters of both lists, separated by tabs.

Recursive is the natural way to solve this issue.
let target be your list [([A,B..]), ([A, B])]
def dump(target):
for obj in target:
if isinstance(obj,tuple) or isinstance(obj, list):
dump(obj)
else:
print(obj),
dump(target)
print()