Django version 3.1.3 form not saving to model - python

I am following this tutorial
I have gone back and written the code to match exactly. I have another form that works called category_add which is exactly the same as this form. But for the life of me I cannot figure out why bookmark_add doesn't update the database with the form entries.
Models.py
from django.db import models
from django.contrib.auth.models import User
class Category(models.Model):
title = models.CharField(max_length=255)
description = models.TextField(blank=True, null=True)
created_by = models.ForeignKey(User, related_name='categories', on_delete=models.CASCADE)
created_at = models.DateTimeField(auto_now_add=True)
class Meta:
verbose_name_plural = 'Categories'
def __str__(self):
return self.title
class Bookmark(models.Model):
category = models.ForeignKey(Category, related_name='bookmarks', on_delete=models.CASCADE)
title = models.CharField(max_length=255)
description = models.TextField(blank=True, null=True)
url = models.CharField(max_length=255, blank=True)
created_by = models.ForeignKey(User, related_name='bookmarks', on_delete=models.CASCADE)
created_at = models.DateTimeField(auto_now_add=True)
def __str__(self):
return self.title
View.py
from django.shortcuts import render, redirect
from django.contrib.auth.decorators import login_required
from .forms import BookmarkForm
#login_required
def bookmark_add(request, category_id):
if request.method == 'POST':
form = BookmarkForm(request.POST)
if form.is_valid():
bookmark = form.save(commit=False)
bookmark.created_by = request.user
bookmark.category_id = category_id
bookmark.save()
return redirect('category', category_id=category_id)
else:
form = BookmarkForm()
context = {
'form': form
}
return render(request, 'bookmark/bookmark_add.html', context)
Forms.py
from django.forms import ModelForm
from .models import Bookmark
class BookmarkForm(ModelForm):
class Meta:
model = Bookmark
fields = ['title', 'description', 'url']
Urls.py
path('', dashboard, name='dashboard'),
path('categories/', categories, name='categories'),
path('categories/add/', category_add, name='category_add'),
path('categories/<int:category_id>/', category, name='category'),
path('categories/<int:category_id>/add_bookmark', bookmark_add, name='bookmark_add')
]
bookmark_add.html
{% extends 'core/base.html' %}
{% block content %}
<div class="container">
<h1 class="title">Add link</h1>
<form method="post" action=".">
{% csrf_token %}
{{ form.as_p }}
<button type="submit" class="button is-primary">Submit</button>
</form>
</div>
{% endblock %}

Solved this!
This was a dumb issue and an oversight on my end. Thanks to the content creator on youtube. I just needed to append "/" to the url path for add_bookmark.
Problem:
path('categories/<int:category_id>/add_bookmark', bookmark_add, name='bookmark_add')
The Fix:
path('categories/<int:category_id>/add_bookmark/', bookmark_add, name='bookmark_add')

Related

Django: How do I assign a button to take info and save()

Is there a way for the button to do the following? : When user press the button it takes the user.username of the current user and automatically fill up a form of BookInstance from models.py and save it to the database.
From models.py :
class BookInstance(models.Model):
id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
book = models.ForeignKey("Book", on_delete=models.RESTRICT, null=True)
imprint = models.CharField(max_length=200, blank=True, null=True)
due_back = models.DateField(blank=True, null=True)
borrower = models.ForeignKey(
User, on_delete=models.SET_NULL, blank=True, null=True)
LOAN_STATUS = (
('m', 'Maintenance'),
('o', 'On Loan'),
('a', 'Available'),
('r', 'Reserved')
)
status = models.CharField(
max_length=1, choices=LOAN_STATUS, blank=True, default='a')
class Meta:
ordering = ['due_back']
def __str__(self):
return f'{self.id} - {self.book.title}'
def get_absolute_url(self):
return reverse("catalog:book_list")
class Book(models.Model):
title = models.CharField(max_length=50)
author = models.ForeignKey(
'Author', on_delete=models.SET_NULL, null=True)
summary = models.TextField(
max_length=500, help_text="Enter brief description")
isbn = models.CharField('ISBN', max_length=13, unique=True)
genre = models.ManyToManyField(Genre, help_text="Select genre")
language = models.ForeignKey(
"Language", on_delete=models.SET_NULL, null=True)
def __str__(self):
return self.title
def get_absolute_url(self):
return reverse("catalog:book_detail", kwargs={"pk": self.pk})
This is my from my views.py :
def borrowBook(request, pk):
context = {
'book_instance': BookInstance.objects.all()
}
success_url = reverse_lazy('catalog:index')
if request.method == "POST":
form = BorrowForm(request.POST or None)
if form.is_valid():
book_instance.id = BookInstance.objects.get(pk=pk)
book_instance.book = BookInstance.objects.get(book=book)
book_instance.borrower = request.user
book_instance.status = 'o'
book_borrowed_count = BookInstance.objects.filter(
owner=request.user).count()
if book_borrowed_count < 4:
book_instance = form.save(commit=False)
book_instance.save()
else:
print("Maximum limit reached!")
return redirect('catalog:index')
return render(request, 'catalog/book_detail.html', {'form': form})
here's from my BorrowForm from forms.py :
class BorrowForm(forms.ModelForm):
class Meta:
model = BookInstance
fields = '__all__'
here's my from my urls.py :
path("book_list/book/<int:pk>/borrow", views.borrowBook, name="borrowBook"),
I also tried using a CBV here:
class BorrowBookView(PermissionRequiredMixin, CreateView):
permission_required = 'login'
model = BookInstance
fields = '__all__'
template_name = 'catalog/borrow_form.html'
success_url = reverse_lazy('catalog:index')
def post(self, request, *args, **kwargs):
book_instance.id = BookInstance.objects.get(pk=pk)
book_instance.book = BookInstance.objects.get(book=book)
book_instance.borrower = request.user
book_instance.status = 'o'
book_instance = form.save(commit=False)
book_instance.save()
CBV path from urls.py :
path("book_list/book/<int:pk>/borrow/",
views.BorrowBookView.as_view(), name="book_borrow"),
Here's how I implemented the button using suggestions from here:
<form action="#" method="post">
{% csrf_token %}
<button
type="submit"
class="btn btn-dark flex-shrink-0 "
value="{{ book.id }}">Borrow
</button>
but when I pressed it doesn't seem to save anything to the database and just popup errors, though I may implemented the button or the function from my is views wrong. Thanks and appreciate for any help provided.
You do not need a Django form for this. Forms are usually used for when you want to create objects or edit its fields (like in the admin page). While here an user is not editing nor creating an object (book), but borrowing one.
So basically, we just need to list all available book instances (status='a'), and have a button to "borrow" it. The borrow action is to update status to 'r' or 'o' and have the borrower updated to the current user which is guaranteed to exist inside the request object by LoginRequiredMixin
views.py
from django.contrib.auth.mixins import LoginRequiredMixin
from django.views import View
from django.contrib import messages
from django.urls import reverse
from django.http import HttpResponseRedirect
from django.shortcuts import get_object_or_404
from .models import BookInstance
class BorrowBook(LoginRequiredMixin, View):
def get(self, request, *args, **kwargs):
book_id = kwargs['pk']
available_books = BookInstance.objects.filter(book__pk=book_id, status='a')
return render(request, 'borrow_book.html', {'available_books': available_books})
def post(self, request, *args , **kwargs):
book_instance_id = request.POST['id']
obj = get_object_or_404(BookInstance, id=book_instance_id)
obj.status = 'r'
obj.borrower = request.user
# Maybe also update due_back data
# obj.due_back = ...
obj.save()
messages.success(request, "Your book is reserved.")
# I used the redirection to the same template
# But you probably want to send the user somewhere else
return HttpResponseRedirect(reverse('core:borrow-book', kwargs={'pk': 1}))
borrow_book.html
{% extends 'base.html' %}
{% block content %}
{% if messages %}
<ul class="messages">
{% for message in messages %}
<li{% if message.tags %} class="{{ message.tags }}"{% endif %}>{{ message }}</li>
{% endfor %}
</ul>
{% endif %}
{% for instance in available_books %}
<form action="{% url 'core:borrow-book' instance.book.id %}" method="POST">
{% csrf_token %}
<input type="hidden" name="id" value="{{instance.id}}">
<p>{{instance.book}}</p>
<p>{{instance.book.language.name}}</p>
<input type="submit" value="Borrow this book.">
</form>
{% endfor %}
{% endblock content %}
urls.py
from django.urls import path
from core import views
app_name = 'core'
urlpatterns = [
path("book_list/book/<int:pk>/borrow/", views.BorrowBook.as_view(), name="borrow-book"),
]

Django 'x' object has no attribute 'get_form'

I have a generic DetailView and I'm trying to do a form for the comment of an user after I display the details of the model but I keep getting the error 'ProductFeedbackView' object has no attribute 'get_form'.
I don't know if the templates have any problem because the error is in the view when I try to get the form into a variable.
Here is comment's model:
class Comment(models.Model):
service = models.ForeignKey(Product, on_delete=models.CASCADE, blank=True, null=True, related_name='comments')
author = models.ForeignKey(User, on_delete=models.CASCADE, blank=True, null=True,)
content = models.CharField(max_length=200, null=False, blank=True)
...
def get_absolute_url(self):
return reverse('product-feedback', kwargs={'pk': self.pk})
Comment's form:
class CommentForm(forms.ModelForm):
content = forms.CharField()
class Meta:
model = Comment
fields = ['content']
View:
class ProductFeedbackView(DetailView):
model = Product
template_name = 'services/product-feedback.html'
form_class = CommentForm
def get_success_url(self):
return reverse('product-feedback', kwargs={'pk': self.object.id})
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
context['form'] = CommentForm(initial={'content': self.object})
return context
def post(self, request, *args, **kwargs):
self.object = self.get_object()
form = self.get_form()
if form.is_valid():
return self.form_valid(form)
else:
return self.form_invalid(form)
def form_valid(self, form):
form.instance.author = self.request.user
form.save()
return super().form_valid(form)
urls's:
...
path('feedback/<int:pk>/', ProductFeedbackView.as_view(), name='product-feedback'),
Template:
Details
Feedback
<p>{{ product.author }}</p>
<h1>{{ product.title }}</h1>
<p>{{ product.description }}</p>
{% if user.is_authenticated %}
<form method="POST">
<label for="comment">Type comment</label>
{{ form.as_p }} {% csrf_token %} <input type="submit" value="Post">
</form>
{% else %}
...
{% endif %}
{% for comment in comment.service.all %}
<p>{{ comment.author }}</p>
<p>{{ comment.content }}</p>
{% endfor %}
Product model:
class Product(models.Model):
author = models.ForeignKey(User, default=None, on_delete=models.CASCADE)
title = models.CharField(max_length=120, unique=True)
category = models.ForeignKey(Category, default=None, on_delete=models.PROTECT)
description = models.CharField(max_length=300, blank=True, null=True)
...
views = models.IntegerField(default=0)
featured = models.BooleanField(default=False)
date_posted = models.DateTimeField(default=timezone.now)
def get_absolute_url(self):
return reverse('product-detail', kwargs={'pk': self.pk})
You need to inherit the form view mixing like so:
from django.views.generic.edit import FormMixin
class ProductFeedbackView(DetailView, FormMixin):
...
As per django classy class based views guide:
https://ccbv.co.uk/projects/Django/4.1/django.views.generic.edit/FormView/
However, mixing a detail view and an edit view probably doesn't match the usual djagno-esque methodology.
Youre likely better off having a detail view and an edit view (FormView) respectively and using the built in behaviour of django.
Just add an edit button to your detail page which is a reverse to the form view :)
If you need more help, just ping a comment.

How can I solve ValueError in django. Exception Value: ModelForm has no model class specified

This is my code:
django.models. my model.py file
from django.db import models
class Product(models.Model):title = models.CharField(max_length=150)
description = models.TextField(blank=True, null=True)
price = models.DecimalField(decimal_places=2, max_digits=100000)
summary = models.TextField(blank=True, null=False)
featured = models.BooleanField(default=False)
forms.py That's my full form.py file
from django import forms
from .models import Product
class ProductForm(forms.ModelForm):
class Meta:
model = Product
fields = [
'title',
'description',
'price',
]
class RawProductForm(forms.ModelForm):
title = forms.CharField()
description = forms.CharField()
price = forms.DecimalField()
django.views my django.views file
from django.shortcuts import render
from .models import Product
from .forms import ProductForm, RawProductForm
def product_create_view(request):
my_form = RawProductForm()
if request.method == 'POST':
my_form = RawProductForm(request.POST)
if my_form.is_valid():
print(my_form.cleaned_data)
Product.objects.create(**my_form.cleaned_data)
else:
print(my_form.errors)
context = {'form': my_form}
return render(request, "products/product_create.html", context)
products_create.html this is my html file
{% extends 'base.html' %}
{% block content %}
<form action="." method="POST">
{% csrf_token %}
{{ form.as_p }}
<input type="submit" value="Save" />
</form>
{% endblock %}
In his code I'm trying to make a form but when I run python manage.py runserver at http://127.0.0.1:8000/create/ I'm getting ValueError
This is a screenshot of my full error messagae
You need to specify your model class in your form :
class RawProductForm(forms.ModelForm):
class Meta:
model = Product
fields = ["price","description" ,"title"]
view :
def product_create_view(request):
my_form = RawProductForm()
if request.method == 'POST':
my_form = RawProductForm(request.POST)
if my_form.is_valid():
print(my_form.cleaned_data)
Product.objects.create(**my_form.cleaned_data)
else:
print(my_form.errors)
context = {'form': my_form}
return render(request, "products/product_create.html", context)

Why is the inline formset not validating

I have two models with foreign key relation
models.py
from django.db import models
# Create your models here.
class Project(models.Model):
STATUSES = (
('Ongoing', 'Ongoing'),
('Completed', 'Completed')
)
YEARS = (
(2019, 2019),
(2020, 2020),
(2021, 2021),
(2022, 2022)
)
name = models.CharField(max_length=200)
client = models.CharField(max_length=100)
year = models.SmallIntegerField(choices=YEARS)
status = models.CharField(max_length=10, choices=STATUSES)
picture = models.ImageField(blank=True, null=True)
description = models.TextField(blank=True, null=True)
def __str__(self):
return self.name
class Photo(models.Model):
project = models.ForeignKey("Project", on_delete=models.CASCADE, related_name="images", blank=True, null=True)
image = models.ImageField()
description = models.CharField(max_length=100, blank=True, null=True)
slide = models.BooleanField(default=False)
I want photos and project to be created on the same form so I've used inline_formset_factory
forms.py
from django.forms import inlineformset_factory
from projects.models import Photo, Project
from django.forms import ModelForm
class ProjectModelForm(ModelForm):
class Meta:
model = Project
fields = (
'name',
'client',
'year',
'picture',
'status',
'description',
)
class PhotoModelForm(ModelForm):
class Meta:
model = Photo
fields = (
'image',
'slide',
'description'
)
PhotoFormset = inlineformset_factory(Project, Photo, form=PhotoModelForm, extra=1)
I used the generic CreateView
views.py
from django.contrib.auth.mixins import LoginRequiredMixin
from projects.forms import PhotoFormset, ProjectModelForm
from django.shortcuts import redirect, reverse, render
from django.views.generic import ListView, DetailView, CreateView, UpdateView, DeleteView
from .models import Photo, Project
# Create your views here.
class ProjectCreateView(LoginRequiredMixin, CreateView):
template_name = 'projects/project_create.html'
form_class = ProjectModelForm
def get_context_data(self, **kwargs):
context = super(ProjectCreateView, self).get_context_data(**kwargs)
context['photos_formset'] = PhotoFormset()
return context
def post(self, request, *args, **kwargs):
self.object = None
form_class = self.get_form_class()
form = self.get_form(form_class)
photo_formset = PhotoFormset(self.request.POST)
if form.is_valid() and photo_formset.is_valid():
return self.form_valid(form, photo_formset)
else:
return self.form_invalid(form, photo_formset)
def form_valid(self, form, photo_formset):
self.object = form.save(commit=False)
self.object.save()
print('valid')
photos = photo_formset.save(commit=False)
for photo in photos:
photo.project = self.object
photo.save()
return reverse('projects:projectspage')
def form_invalid(self, form, photo_formset):
if not photo_formset.is_valid():
print('invalid formset')
return self.render_to_response(
self.get_context_data(form=form, photos_formset=photo_formset)
)
def get_success_url(self):
return reverse('projects:projectspage')
this is the template
{% extends 'base.html' %}
{% load crispy_forms_filters %}
<!-- crispy_forms_tags -->
{% block content %}
<div class="container">
<h2>create new project</h2>
<form method="post">
{% csrf_token %}
{{ form|crispy }}
<h2 class="display-6 my-5">
Add photos
</h2>
{{ photos_formset.as_p }}
<input type="submit" value="Create" class="btn btn-primary">
</form>
</div>
{% endblock content %}
When I submit form_invalid is returned from the post method of the view
How do i get the inline_formset to validate or is there better way of doing it
I prefer to write those views as functions, seems more straightforward, try:
#login_required
def post_news(request):
if request.method == 'POST':
project_form = ProjectModelForm(request.POST, request.FILES)
photo_form = PhotoModelForm(request.POST, request.FILES)
picture = request.FILES['picture']
image = request.FILES['image']
if project_form.is_valid() and photo_form.is_valid():
project_instance = project_form.save(commit=False)
project_instance.picture = picture
project_instance.save()
photo_instance = project_form.save(commit=False)
photo_instance.project = project_instance
photo_instance.image = image
photo_instance.save()
return reverse('projects:projectspage')
else:
project_form = ProjectModelForm()
photo_form = PhotoModelForm()
return render(request, 'projects/project_create.html',
{'project_form': project_form, 'photo_form': photo_form})
You will have to account for a case when no picture for the project model is is provided I think. Just pop both forms into your template and this should work.

How to render view from differents applications in the same template?

I have two applications (blog and category). On the post list template I would like to get the category blog name and description.
I have tried to put the import category model in the blog view, but nothing show up. So I have made two views rendering the same template, but it does not work.
Blog models:
from django.db import models
from django.utils import timezone
from autoslug import AutoSlugField
from category.models import Category
class Post(models.Model):
author = models.ForeignKey('auth.User', on_delete=models.CASCADE)
category = models.ForeignKey(Category, on_delete=models.CASCADE,
default = '')
title = models.CharField(max_length=200)
...
class Meta:
verbose_name = "Post"
verbose_name_plural = "Posts"
ordering = ['created_date']
def publish(self):
self.published_date = timezone.now()
self.save()
def __str__(self):
return self.title
category models:
class Category(models.Model):
name = models.CharField(max_length=200)
slug = AutoSlugField(populate_from='name', default='')
parent = models.ForeignKey('self', blank=True, null=True, related_name='children', on_delete=models.CASCADE)
description = models.TextField(max_length=200)
class Meta:
unique_together = ('slug', 'parent',) # Enforcing that there can not be two
verbose_name_plural = "categories" # categories under a parent with same
# slug
def __str__(self): # __str__ method elaborated later in
full_path = [self.name] # post. use __unicode__ in place of
# __str__ if you are using python 2
k = self.parent
while k is not None:
full_path.append(k.name)
k = k.parent
return ' -> '.join(full_path[::-1])
Blog view:
def post_list(request):
posts = Post.objects.all()
cat_blog = Category.objects.get(pk=1)
context = {
'posts': posts,
'cat_blog': cat_blog
}
return render(request, 'blog/post_list.html', context)
Category view:
def cat_blog(request):
cat_blog = Category.objects.get(pk=1)
return render(request, 'blog/post_list.html', {'cat_blog': cat_blog})
post_list.html:
<div class="section-header text-center">
{% for category in cat_blog %}
<h1>{{ category.name }}</h1>
<p class="tag">{{ category.description }}</p>
{% endfor %}
</div>
<div class="row py-5">
{% for post in posts %}
// This part is fine
{% endfor%}
The post loop is fine. How can't I get the category name and description in my section header?
One URL gives one View gives one template.
You use the View to give context to the template to render.
def post_list(request):
posts = Post.objects.all()
cat_blog = Category.objects.get(pk=1)
context = {
'posts': posts,
'cat_blog': cat_blog
}
return render(request, 'blog/post_list.html', context)
Your url.py file should point to the post_list view.

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