This question already has an answer here:
Python 3 integer division [duplicate]
(1 answer)
Closed 2 years ago.
if I use integer type cast conversion technique then it doesn't work for large numbers like 12630717197566440063
I got wrong answer in some cases like below in python 3
a =12630717197566440063;
print(a)
temp = a/10
print(int(temp))
Then I am getting 1263071719756644096 as a answer instead of 1263071719756644006
You can use the // (floor division) operator:
temp = a//10
print(temp)
Related
This question already has answers here:
Limiting floats to two decimal points
(35 answers)
how to format float number in python? [duplicate]
(3 answers)
variable number of digit in format string
(3 answers)
Closed 1 year ago.
I'm reading this textbook called "Practical Statistics for Data Scientists" and this :.3f keeps getting used in almost every f-string. What does :.3f mean? My guess is it has something to do with floating point numbers.
Example:
{house_lm_factor.intercept_:.3f}
This is show you how many number are printing:
>>> import math
>>> flt = math.pi
>>> f'{flt:.3f}'
'3.142'
>>> f'{flt:.5f}'
'3.14159'
>>> f'{flt:.10f}'
'3.1415926536'
This question already has answers here:
Converting bitstring to 32-bit signed integer yields wrong result
(3 answers)
Closed 2 years ago.
Is there a way to force python to treat a number based upon its sign?
E.g. 0xFFFFFFFF = -1 instead of 4294967295?
You can use ctypes.c_int32 for a signed 32 bit integer:
import ctypes
wrapped = ctypes.c_int32(0xFFFFFFFF)
print(wrapped) # c_int(-1)
print(wrapped.value) # -1
This question already has answers here:
Round to 5 (or other number) in Python
(21 answers)
How do I round to the nearest 0.5?
(10 answers)
Closed 2 years ago.
I got this number 1.12412 and I want to round it to 1.12415 or 1.12410 (muliple of 5 in last decimal)
If using the Round(X,4) function I get 1.1241 (4 decimals).
Is there a function that can make that happen?
Thanks!
There is an answer in stack but using c# not python
My way to do that is to specify rounding unit first and then simple trick as below:
import numpy as np
rounding_unit = 0.00005
np.round(1.12412/rounding_unit) * rounding_unit
You may:
Multiply your number by 2
Use Round(X,4)
Divide the result by 2
profit!!!
This question already has answers here:
How to suppress scientific notation when printing float values?
(16 answers)
Closed 4 years ago.
How to suppress scientific notation from a float value in python. Here I tried the following code but it's not working
r_val[v].append('%.2f' % val.get("closing_balance"))
Thanks in advance
Using format(x, '.#f')
consider this snippet:
x = 0.000000235
print(x)
2.35e-07
print (format(x, '.9f'))
0.000000235
Or, to go closer to your question:
y = -1.06267582739e-11 # note I changed '+' to '-' since '+' is is just represented as a regular float
print(y)
-1.06267582739e-11
print(format(y,'.22f'))
-0.0000000000106267582739
This question already has answers here:
Round a floating-point number down to the nearest integer?
(12 answers)
Closed 7 years ago.
Is there any way to convert a floating point number in Python to an integer except math.floor()?
I have already tried math.floor(), but I am getting an error says:
Cannot import math
Any other way?
Use the int() function
print int(5.3) # "5"
For more info
You can:
Use int(3.14)
import math then math.floor(3.14) or math.ceil(3.14) (depending on which way you want to round) (you said this doesn't work but I'll leave it for reference)
x = x - x % 1 or x -= x % 1