I have a long dictionary which looks like this:
name = 'Barack.'
name_last = 'Obama!'
street_name = "President Streeet?"
list_of_slot_names = {'name':name, 'name_last':name_last, 'street_name':street_name}
I want to remove the punctation for every slot (name, name_last,...).
I could do it this way:
name = name.translate(str.maketrans('', '', string.punctuation))
name_last = name_last.translate(str.maketrans('', '', string.punctuation))
street_name = street_name.translate(str.maketrans('', '', string.punctuation))
Do you know a shorter (more compact) way to write this?
Result:
>>> print(name, name_last, street_name)
>>> Barack Obama President Streeet
Use a loop / dictionary comprehension
{k: v.translate(str.maketrans('', '', string.punctuation)) for k, v in list_of_slot_names.items()}
You can either assign this back to list_of_slot_names if you want to overwrite existing values or assign to a new variable
You can also then print via
print(*list_of_slot_names.values())
name = 'Barack.'
name_last = 'Obama!'
empty_slot = None
street_name = "President Streeet?"
print([str_.strip('.?!') for str_ in (name, name_last, empty_slot, street_name) if str_ is not None])
-> Barack Obama President Streeet
Unless you also want to remove them from the middle. Then do this
import re
name = 'Barack.'
name_last = 'Obama!'
empty_slot = None
street_name = "President Streeet?"
print([re.sub('[.?!]+',"",str_) for str_ in (name, name_last, empty_slot, street_name) if str_ is not None])
import re, string
s = 'hell:o? wor!d.'
clean = re.sub(rf"[{string.punctuation}]", "", s)
print(clean)
output
hello world
Related
I need it to extract the word that starts with a capital letter, if and only if, this word is preceded by the beginning of the sentence or by one of these options (?:,and|and|her friends|,or |or |,)
import re
match_names = ""
input_sense = "Susan gave some cosmetic gifts to her friends Lisa, Veronica and Katy, but only Katy thanked her"
#I concatenate a series of characters that probably nobody uses so that it searches at the beginning
input_sense = "rlt99ll" + input_sense
if match := re.findall(r"(?:rlt99ll|,and|and|her friends|,or |or |,)\s*([A-Z].*?\b)", input_sense):
match_names = match
print("match names: ")
print(match_names)
input_sense = input_sense.replace("rlt99ll", "") #I add this aux-string only for the pattern
n = 0
print("match_auxs : ")
for name in match_names:
match_aux = match_names
for m in match_aux:
if (m == name):
match_aux[n] = ""
n += 1
n = 0
print(match_aux)
I need that output lists:
match names:
['Susan', 'Lisa', 'Veronica', 'Katy']
match_auxs :
['','Lisa', 'Veronica', 'Katy']
['Susan', '', 'Veronica', 'Katy']
['Susan', 'Lisa', '', 'Katy']
['Susan', 'Lisa', 'Veronica', '']
But I get this ( and it's wrong)...
match names:
['Susan', 'Lisa', 'Veronica', 'Katy']
match_auxs :
['', 'Lisa', 'Veronica', 'Katy']
['', '', 'Veronica', 'Katy']
['', '', '', 'Katy']
['', '', '', '']
As said in the comments, assigning a list to another variable doesn't create a copy of it. Along with this, your code can be simplified by using functions like enumerate:
import re
match_names = ""
input_sense = "Susan gave some cosmetic gifts to her friends Lisa, Veronica and Katy, but only Katy thanked her"
#I concatenate a series of characters that probably nobody uses so that it searches at the beginning
input_sense = "rlt99ll" + input_sense
if match_names := re.findall(r"(?:rlt99ll|,and|and|her friends|,or |or |,)\s*([A-Z].*?\b)", input_sense):
print(f"match names: {match_names}")
input_sense = input_sense.replace("rlt99ll", "") #I add this aux-string only for the pattern
n = 0
print("match_auxs: ")
for index, name in enumerate(match_names):
match_aux = match_names.copy()
match_aux[index] = ""
n = 0
print(match_aux)
If you don't want to use copy on the list (for speed), this code will also work:
import re
match_names = ""
input_sense = "Susan gave some cosmetic gifts to her friends Lisa, Veronica and Katy, but only Katy thanked her"
#I concatenate a series of characters that probably nobody uses so that it searches at the beginning
input_sense = "rlt99ll" + input_sense
if match_names := re.findall(r"(?:rlt99ll|,and|and|her friends|,or |or |,)\s*([A-Z].*?\b)", input_sense):
print(f"match names: {match_names}")
input_sense = input_sense.replace("rlt99ll", "") #I add this aux-string only for the pattern
n = 0
print("match_auxs: ")
prev = ""
for index, name in enumerate(match_names):
if index > 0:
match_names[index - 1] = prev
prev = match_names[index]
match_names[index] = ""
print(match_names)
match_names[-1] = prev
I have txt file like this;
name lastname 17 189cm
How do I get it to be like this?
name lastname, 17, 189cm
Using str.strip and str.split:
>>> my_string = 'name lastname 17 189cm'
>>> s = list(map(str.strip, my_string.split()))
>>> ', '.join([' '.join(s[:2]), *s[2:] ])
'name lastname, 17, 189cm'
You can use regex to replace multiple spaces (or tabs) with a comma:
import re
text = 'name lastname 17 189cm'
re.sub(r'\s\s+|\t', ', ', text)
text = 'name lastname 17 189cm'
out = ', '.join(text.rsplit(maxsplit=2)) # if sep is not provided then any consecutive whitespace is a separator
print(out) # name lastname, 17, 189cm
You could use re.sub:
import re
s = "name lastname 17 189cm"
re.sub("[ ]{2,}",", ", s)
PS: for the first problem you proposed, I had the following solution:
s = "name lastname 17 189cm"
s[::-1].replace(" ",",", 2)[::-1]
text="Brand.*/Smart Planet.#/Color.*/Yellow.#/Type.*/Sandwich Maker.#/Power Source.*/Electrical."
I have this kind of string. I am facing the problem which splits it to 2 lists. Output will be approximately like this :
name = ['Brand','Color','Type','Power Source']
value = ['Smart Plane','Yellow','Sandwich Maker','Electrical']
Is there any solution for this.
name = []
value = []
text = text.split('.#/')
for i in text:
i = i.split('.*/')
name.append(i[0])
value.append(i[1])
This is one approach using re.split and list slicing.
Ex:
import re
text="Brand.*/Smart Planet.#/Color.*/Yellow.#/Type.*/Sandwich Maker.#/Power Source.*/Electrical."
data = [i for i in re.split("[^A-Za-z\s]+", text) if i]
name = data[::2]
value = data[1::2]
print(name)
print(value)
Output:
['Brand', 'Color', 'Type', 'Power Source']
['Smart Planet', 'Yellow', 'Sandwich Maker', 'Electrical']
You can use regex to split the text, and populate the lists in a loop.
Using regex you protect your code from invalid input.
import re
name, value = [], []
for ele in re.split(r'\.#\/', text):
k, v = ele.split('.*/')
name.append(k)
value.append(v)
>>> print(name, val)
['Brand', 'Color', 'Type', 'Power Source'] ['Smart Planet', 'Yellow', 'Sandwich Maker', 'Electrical.']
text="Brand.*/Smart Planet.#/Color.*/Yellow.#/Type.*/Sandwich Maker.#/Power Source.*/Electrical."
name=[]
value=[]
word=''
for i in range(len(text)):
temp=i
if text[i]!='.' and text[i]!='/' and text[i]!='*' and text[i]!='#':
word=word+''.join(text[i])
elif temp+1<len(text) and temp+2<=len(text):
if text[i]=='.' and text[temp+1]=='*' and text[temp+2]=='/':
name.append(word)
word=''
elif text[i]=='.' and text[temp+1]=='#' and text[temp+2]=='/':
value.append(word)
word=''
else:
value.append(word)
print(name)
print(value)
this will be work...
There are four keywords: title, blog, tags, state
Excess keyword occurrences are being removed from their respective matches.
Example:
blog: blog state title tags and returns state title tags and instead of
blog state title tags and
The sub function should be matching .+ after it sees blog:, so I don't know why it treats blog as an exception to .+
Regex:
re.sub(r'((^|\n|\s|\b)(title|blog|tags|state)(\:\s).+(\n|$))', matcher, a)
Code:
def n15():
import re
a = """blog: blog: fooblog
state: private
title: this is atitle bun
and text"""
kwargs = {}
def matcher(string):
v = string.group(1).replace(string.group(2), '').replace(string.group(3), '').replace(string.group(4), '').replace(string.group(5), '')
if string.group(3) == 'title':
kwargs['title'] = v
elif string.group(3) == 'blog':
kwargs['blog_url'] = v
elif string.group(3) == 'tags':
kwargs['comma_separated_tags'] = v
elif string.group(3) == 'state':
kwargs['post_state'] = v
return ''
a = re.sub(r'((^|\n|\s|\b)(title|blog|tags|state)(\:\s).+(\n|$))', matcher, a)
a = a.replace('\n', '<br />')
a = a.replace('\r', '')
a = a.replace('"', r'\"')
a = '<p>' + a + '</p>'
kwargs['body'] = a
print kwargs
Output:
{'body': '<p>and text</p>', 'post_state': 'private', 'blog_url': 'foo', 'title': 'this is a bun'}
Edit:
Desired Output:
{'body': '<p>and text</p>', 'post_state': 'private', 'blog_url': 'fooblog', 'title': 'this is atitle bun'}
replace(string.group(3), '')
is replacing all occurrences of 'blog' with '' .
Rather than try to replace all the other parts of the matched string, which will be hard to get right, I suggest capture the string you actually want in the original match.
r'((^|\n|\s|\b)(title|blog|tags|state)(\:\s)(.+)(\n|$))'
which has () around the .+ to capture that part of the string, then
v = match.group(5)
at the start of matcher.
I know that you can use split() to split a user input into two, but how would you split input that consists of multiple variables ? For example:
User input:
Shawn=14:soccer#2991842
What I would like to do:
name = Shawn
age = 14
course = soccer
idnumber = 2991842
What's the best way to do such thing ?
str = 'Shawn=14:soccer#2991842'
keys = ['name', 'age', 'course', 'idnumber']
values = re.split('[=:#]', str)
print dict(zip(keys, values))
Out[114]: {'age': '14', 'course': 'soccer', 'idnumber': '2991842', 'name': 'Shawn'}
I think Regex will work best here:
>>> from re import split
>>> mystr = "Shawn=14:soccer#2991842"
>>> split("\W", mystr)
['Shawn', '14', 'soccer', '2991842']
>>> lst = split("\W", mystr)
>>> name = lst[0]
>>> name
'Shawn'
>>> age = lst[1]
>>> age
'14'
>>> course = lst[2]
>>> course
'soccer'
>>> idnumber = lst[3]
>>> idnumber
'2991842'
>>>
Also, the above is a step-by-step demonstration. You can actually just do:
name, age, course, idnumber = split("\W", mystr)
Here's how I would do it.
def splitStr(str):
temp = str.split(':')
temp_nameAge = temp[0].split('=')
temp_courseId = temp[1].split('#')
name = temp_nameAge[0]
age = int(temp_nameAge[1])
course = temp_courseId[0]
idnumber = int(temp_courseId[1])
print 'Name = %s, age = %i, course = %s, id_number = %i' % (name, age, course, idnumber)
Another thing you can do is use split like: string.split(":").
Then you can change the format to "name:age:course:number"
You could just keep splitting the splits...
text2split = "Shawn=14:soccer#2991842"
name = text2split.split('=')[0]
age = text2split.split('=')[1].split(':')[0]
course = text2split.split('=')[1].split(':')[1].split('#')[0]
idnumber = text2split.split('=')[1].split(':')[1].split('#')[1]
This isn't the most elegant way to do it, but it'll work so long as text2split always has the same delimeters.
If you are ok with storing them under dictionary keys, you could use named group references
import re
x='shawn=14:soccer#2991842'
re.match(r'(?P<name>.*?)=(?P<age>.*):(?P<course>.*?)#(?P<idnumber>.*)', x).groupdict()
{'idnumber': '2991842', 'course': 'soccer', 'age': '14', 'name': 'shawn