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Why this Syntax Error on Python 3.8 for Mac [closed]

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Closed 2 years ago.
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Check out the screenshot and help this newb with why i'm getting this syntax error with the for loop even though im following the right syntax.
The code :
elif choice == 'AVERAGE':
import statistics
lst = []
n = int(input('Enter number of values to calculate mean of: ')
for i in range(0,n):
ele=int(input())
lst.append(ele)
The Error : Invalid Syntax for the ':' after 'range(0,n)'

You are spacing the items inside the for loop with double Tab, the indentation should be either 4 spaces or a single tab.
And you are missing a parenthesis closing in the n input line
See the modified code below.
elif choice == 'AVERAGE':
import statistics
lst = []
n = int(input('Enter number of values to calculate mean of: '))
for i in range(0,n):
ele=int(input())
lst.append(ele)

Print error in while loop in python [closed]

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Closed 5 years ago.
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Helli I'm a beginner programmer and I'm getting a print syntax error and I don't know why....
def Input_Q_bounds (lower,upper):
delta_x = .1
#since there are 100 iterations
J=np.zeros(101)
for i in range(101) :
Q=(i*delta_x)+(delta_x/2)
if lower <=(Q_i)<= upper :
Q_i =1
else :
Q_i=0
#now fill the matrix
J[i]=(Q+(9.5*(J[i-1])))/10.5
while (i==1):
J_analytical = Q*(np.exp(upper-10)+(np.exp(lower-10))
print(J_analytical)
break
Here's the error:
File "<ipython-input-135-25106d5ec500>", line 19
print(J_analytical)
^
SyntaxError: invalid syntax

Your parentheses in the line above are not balanced - you have four open parens and only three closing parens.

In the line before
print(J_analytical)
the brackets do not match!
J_analytical = Q*(np.exp(upper-10)+(np.exp(lower-10))
^
# change it to:
J_analytical = Q*(np.exp(upper-10)+(np.exp(lower-10)))
^

list access e[-1] is fine but e[1] is not in Python [closed]

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Closed 8 years ago.
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In Python, I defined
string = ("car-automobile, gem-jewel, journey-voyage, boy-lad, coast-shore, "
"asylum-madhouse, magician-wizard, midday-noon, furnacestove, food-fruit, "
"bird-cock, bird-crane, tool-implement, brother-monk, ladbrother, "
"crane-implement, journey-car, monk-oracle, cemetery-woodland, foodrooster, "
"coast-hill, forest-graveyard, shore-woodland, monk-slave, coast-forest, "
"lad-wizard, chord-smile, glass-magician, rooster-voyage, "
"noon-string".split(', '))
test = [i.split('-') for i in string]
and the following code causes error:
[e[1] for e in test]
Traceback (most recent call last):
File "<pyshell#136>", line 1, in <module>
[e[1] for e in test]
IndexError: list index out of range
but following code works
[e[-1] for e in test]
Why is this so?

You have a few values with no - in them:
>>> [e for e in string if not '-' in e]
['furnacestove', 'ladbrother', 'foodrooster']
which when split results in a one-element list; there is only e[0], no e[1]. e[-1] gives you the last element always, even if there is only 1.

Why does Python regex with literal words not match, but \w+ does? [closed]

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Closed 8 years ago.
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I tried to write a regular expression that looks like it would work, but I had to replace some of the literal strings with word patterns and I want to understand why.
Here's the example:
import re
text = " 1 p2 2.26347691E+12 optvl 9.05369210E+04 ctha 6.00000000E+01"
p1 = re.compile(r"\s+(\d+)\s+p2\s+([\d\.\+\-E]+)\s+optv1\s+([\d\.\+\-E]+)\s+ctha\s+([\d\.\+\-E]+)")
m1 = p1.findall(text)
print m1
p2 = re.compile(r"\s+(\d+)\s+p2\s+([\d\.\+\-E]+)\s+\w+\s+([\d\.\+\-E]+)\s+\w+\s+([\d\.\+\-E]+)")
m2 = p2.findall(text)
print m2
Here's the output:
[]
[('1', '2.26347691E+12', '9.05369210E+04', '6.00000000E+01')]
Thanks for any insight!
Edit: yep, it's a typo - the old l vs 1

There is a typo in the first version with words, should be l instead of 1:
p1 = re.compile(r"\s+(\d+)\s+p2\s+([\d\.\+\-E]+)\s+optvl\s+([\d\.\+\-E]+)\s+ctha\s+([\d\.\+\-E]+)")
^

How to convert tuple to int? [closed]

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Closed 9 years ago.
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This is the code I am trying to run :
line = "123456789"
p = 2
print line[p,p+2]
And I get the error - TypeError: string indices must be integers, not tuple. How can I use line[ , ] with variables. Any help is appreciated.

You want to use colons for slicing.
line = "123456789"
p = 2
print line[p:p+2]
That works fine.
Output:
34

line = "123456789"
p = 2
print line[p,p+2] # this is incorrect slice notation
the correct form is:
print line[p:p+2] # with a colon
look here for info on strings and string slicing