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Selenium: Unable to locate element by class and id

Trying to scrape a website, I created a loop and was able to locate all the elements. My problem is, that the next button id changes on every page. So I can not use the id as a locator.
This is the next button on page 1:
<a rel="nofollow" id="f_c7" href="#" class="nextLink jasty-link"></a>
And this is the next button on page 2:
<a rel="nofollow" id="f_c9" href="#" class="nextLink jasty-link"></a>
Idea:
next_button = browser.find_elements_by_class_name("nextLink jasty-link")
next_button.click
I get this error message:
Message: no such element: Unable to locate element
The problem here might be that there are two next buttons on the page.
So I tried to create a list but the list is empty.
next_buttons = browser.find_elements_by_class_name("nextLink jasty-link")
print(next_buttons)
Any idea on how to solve my problem? Would really appreciate it.
This is the website:
https://fazarchiv.faz.net/faz-portal/faz-archiv?q=Kryptow%C3%A4hrungen&source=&max=10&sort=&offset=0&_ts=1657629187558#hitlist

There are two issues in my opinion:
Depending from where you try to access the site there is a cookie banner that will get the click, so you may have to accept it first:
browser.find_element_by_class_name('cb-enable').click()
To locate a single element, one of the both next buttons, it doeas not matter, use browser.find_element() instead of browser.find_elements().
Selecting your element by multiple class names use xpath:
next_button = browser.find_element(By.XPATH, '//a[contains(#class, "nextLink jasty-link")]')
or css selectors:
next_button = browser.find_element(By.CSS_SELECTOR, '.nextLink.jasty-link')
Note: To avoid DeprecationWarning: find_element_by_* commands are deprecated. Please use find_element() import in addition from selenium.webdriver.common.by import By

You can't get elements by multiple class names. So, you can use find_elements_by_css_selector instead.
next_buttons = browser.find_elements_by_css_selector(".nextLink.jasty-link")
print(next_buttons)
You can then loop through the list and click the buttons:
next_buttons = browser.find_elements_by_css_selector(".nextLink.jasty-link")
for button in next_buttons:
button.click()

Try below xPath
//a[contains(#class, 'step jasty-link')]/following-sibling::a

How to find an element with respect to its parent element with Selenium and Python

I am trying to scrape a website, but I need to search for an element whose parent is like this:
//div[#title="parent"]
People are talking about getting an element from its child. Is there a way to reverse it and find the child from its parent?
I want the /span with #title = "child" whose parent is //div[#title = "Search results."]

You can try to use
//div[parent::div[#title="parent"]]
or simply
//div[#title="parent"]/div
In Python code you can also use
parent = driver.find_element(By.XPATH, '//div[#title="parent"]')
child = parent.find_element(By.XPATH, './div')

To locate the child element:
<span title="child"...>
within it's parent:
<div title="Search results."...>
you can use either of the following Locator Strategies:
Using css_selector:
element = driver.find_element(By.CSS_SELECTOR, "div[title='Search results.'] span[title='child']")
Using xpath:
element = driver.find_element(By.XPATH, "//div[#title='Search results.']//span[#title='child']")

Retrieving aria-label value using Selenium's find function

I have the xpath of an element on a website but I'm trying to get the aria-label value of that element.
# NO SUCCESS: print(WebDriverWait(browser, 20).until(EC.visibility_of_element_located((By.XPATH, "element_xpath_you_found"))).get_attribute("aria-label"))
# NO SUCCESS: first_rev = browser.find_element(By.xpath, "/html/body/span/g-lightbox/div[2]/div[3]/span/div/div/div/div[2]/div[1]/div/div[2]/div[1]/div[1]/div[3]/div[1]/g-review-stars/span")
first_rev = browser.find_element_by_xpath("/html/body/span/g-lightbox/div[2]/div[3]/span/div/div/div/div[2]/div[1]/div/div[2]/div[1]/div[1]/div[3]/div[1]/g-review-stars/span").click()
aria_label = first_rev.find_element_by_css_selector('span').get_attribute("aria-label")
print(aria_label)
On the browser, I inspect the element and get this html:
<span class="fTKmHE99XE4__star fTKmHE99XE4__star-s" aria-label="Rated 3.0 out of 5," style=""><span style="width:42px"></span></span>
However, can the problem be that this element is inside a pop-up on the page? Page source doesn't show any html for any element in the pop-up.

click() doesn't have return value, which means it returns None, which make first_rev None, split it to two actions. You also don't need the first_rev.find_element, you are actually getting its child element
first_rev = browser.find_element_by_xpath("/html/body/span/g-lightbox/div[2]/div[3]/span/div/div/div/div[2]/div[1]/div/div[2]/div[1]/div[1]/div[3]/div[1]/g-review-stars/span")
first_rev.click()
aria_label = first_rev.get_attribute("aria-label")
print(aria_label)

How to click on the element with Selenium Python

I'm trying to click a the element with text as I don't have the telephone on this website.
So I find the element with inspect. here is the element in html:
<span class="toggle-link link_has-no-phone" role="button">I don't have a telephone number</span>
In my nonfunctional code i wrote this:
r = driver.find_element_by_xpath("//*[#id='root']/div/div[2]/div/main/div/div/div/form/div[3]/div/div[2]/div/span")
r.click
The button is never clicked and nothing happens i get no error and i can't click it any help would be appreciated.

You can use css selector below to get span:
r = driver.find_element_by_css_selector(".link_has-no-phone")
r.click()

r = driver.find_element_by_xpath("//*[#id='root']/div/div[2]/div/main/div/div/div/form/div[3]/div/div[2]/div/span")
r.click()
You just forgot the parenthesis

To click on the element with text as I don't have a telephone number you can use either of the Locator Strategies:
css_selector:
driver.find_element_by_css_selector("span.toggle-link.link_has-no-phone").click()
xpath:
driver.find_element_by_xpath("//span[#class='toggle-link link_has-no-phone']").click()

Getting search bar ID for selenium

Trying to get the search bar ID from this website: http://www.pexels.com
browser = webdriver.Chrome(executable_path="C:\\Users\\James\\Documents\\PythonScripts\\chromedriver.exe")
url = "https://www.pexels.com"
browser.get(url)
browser.maximize_window()
search_bar = browser.find_element_by_id("//input[#id='search__input']")
search_bar.send_keys("sky")
search_button.click()
However this isn't correct and I'm not sure how to get the search to work. First time using selenium so all help is appreciated!

There's no id attribute in the tag you are searching for. You may use css selectors instead. Here's a sample snippet:
search_bar = driver.find_element_by_css_selector("input[placeholder='Search for free photos…']");
search_bar.send_keys("sky")
search_bar.send_keys(Keys.RETURN)
Above snippet will insert 'sky' in the search bar and hit enter button.

Locating Elements gives an explanation on how to locate elements with Selenium.
The element you want to select, looks like this in the DOM:
<input required="required" autofocus="" class="search__input" type="search" placeholder="Search for free photos…" name="s">
Since there is no id specified you can't use find_element_by_id.
For me this worked:
search_bar = driver.find_element_by_xpath('/html/body/header[2]/div/section/form/input')
search_bar.send_keys("sky")
search_bar.send_keys(Keys.RETURN)
for the selection you can also use the class name:
search_bar = driver.find_element_by_class_name("search__input")
or the name tag:
search_bar = driver.find_element_by_name('s')
However, locating elements by names is probably not a good idea if there are more elements with the same name (link)
BTW if you are unsure about the xpath, the google Chrome inspection tool lets you copy the xpath from the document: