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How to Extract the Information from XML Soap Response?

We have a requirement to get the data from a SOAP XML Response.
Below is the associated XML file
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<GetResultResponse xmlns="http://www.relatics.com/">
<GetResultResult>
<Report ReportName="RFC" GeneratedOn="2022-12-22" EnvironmentID="XXXX" EnvironmentName="Systematic Assurance – an XXX Solution" EnvironmentURL="https://XXXX.relaticsonline.com/" WorkspaceID="XXXXX" WorkspaceName="P - ADL Program Management - XXX" TargetDevice="Pc" ReportField="" xmlns="">
<Change_module>
<applied_individual_change_request Change_Request="TestKZIreport" RFC_GUID="XXXXX">
<code RFC_Code="VtW-0101" />
<progress RFC_Progress="agreed" />
<applied_individual_project_organisation Organisation="XXXX" />
<applied__individual_discipline Discipline="Highways" />
<specification Specification="Context of Documents">
<code Specification_Code="1.1.1a" />
</specification>
<applied_individual_workpackage Workpackage="Enabling work">
<code Workpackage_Code="WP-01" />
</applied_individual_workpackage>
<physical_object Physical_Object="Train Station">
<code Physical_Object_Code="TFO-0001" />
</physical_object>
<person approver="XXX" />
<applied_individual_change_consequence_qualification Consequence_Value="10 days">
<applied_conceptual_change_consequence_aspect Consequence_Aspect="Schedule" />
</applied_individual_change_consequence_qualification>
<document Document_Name="WI 300 Design.pdf">
<code Document_Code="DOC-0002" />
</document>
<answer_status BR_Status="no" />
<applied_individual_business_rule Business_Rule="Change Review compliance">
<code BR_Code="BR-006" />
</applied_individual_business_rule>
<applied_individual_change_consequence_qualification Consequence_Value="XXX">
<applied_conceptual_change_consequence_aspect Consequence_Aspect="Finance" />
</applied_individual_change_consequence_qualification>
</applied_individual_change_request>
</Change_module>
</Report>
</GetResultResult>
</GetResultResponse>
</soap:Body>
</soap:Envelope>
i need all the tag values after Change_module.i tried some online help in Stack overflow but it didn't work.
I never worked with XML documents before and here is the sample code i
tried from Stack Overflow.
import xml.etree.ElementTree as ET
import pandas as pd
import numpy as np
tree = ET.parse("Relatics_XML.xml")
root = tree.getroot()
print(root.tag)
print(root.attrib)
namespaces = {"soap": "http://www.w3.org/2003/05/soap-envelope/",
"xsi": "http://www.w3.org/2001/XMLSchema-instance",
"xsd": "http://www.w3.org/2001/XMLSchema/",
'a': 'http://www.relatics.com/',}
names = tree.findall('./soap:Body''/a:GetResultResponse''/a:GetResultResult', namespaces)
print(names)
for name in names:
print(name.text)
i tried different methods like find and findall and also inside the method i try to pass different values but all its printing is null.
I'm not sure how to get the values out of tags.

Using xml.etree.ElementTree make life easier.
documentation in here
It can parsing tag attribute or innerText.
import xml.etree.ElementTree as ET
xml = """\
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<GetResultResponse xmlns="http://www.relatics.com/">
<GetResultResult>
<Report ReportName="RFC" GeneratedOn="2022-12-22" EnvironmentID="XXXX" EnvironmentName="Systematic Assurance – an XXX Solution" EnvironmentURL="https://XXXX.relaticsonline.com/" WorkspaceID="XXXXX" WorkspaceName="P - ADL Program Management - XXX" TargetDevice="Pc" ReportField=""
xmlns="">
<Change_module>
<applied_individual_change_request Change_Request="TestKZIreport" RFC_GUID="XXXXX">
<code RFC_Code="VtW-0101" />
<progress RFC_Progress="agreed" />
<applied_individual_project_organisation Organisation="XXXX" />
<applied__individual_discipline Discipline="Highways" />
<specification Specification="Context of Documents">
<code Specification_Code="1.1.1a" />
</specification>
<applied_individual_workpackage Workpackage="Enabling work">
<code Workpackage_Code="WP-01" />
</applied_individual_workpackage>
<physical_object Physical_Object="Train Station">
<code Physical_Object_Code="TFO-0001" />
</physical_object>
<person approver="XXX" />
<applied_individual_change_consequence_qualification Consequence_Value="10 days">
<applied_conceptual_change_consequence_aspect Consequence_Aspect="Schedule" />
</applied_individual_change_consequence_qualification>
<document Document_Name="WI 300 Design.pdf">
<code Document_Code="DOC-0002" />
</document>
<answer_status BR_Status="no" />
<applied_individual_business_rule Business_Rule="Change Review compliance">
<code BR_Code="BR-006" />
</applied_individual_business_rule>
<applied_individual_change_consequence_qualification Consequence_Value="XXX">
<applied_conceptual_change_consequence_aspect Consequence_Aspect="Finance" />
</applied_individual_change_consequence_qualification>
</applied_individual_change_request>
</Change_module>
</Report>
</GetResultResult>
</GetResultResponse>
</soap:Body>
</soap:Envelope>
"""
root = ET.fromstring(xml)
print("RFC_Code: " + str(root.find(".//code[#RFC_Code]").attrib))
print("RFC_Progress: " + str(root.find(".//progress[#RFC_Progress]").attrib))
print("specification: " + str(root.find(".//specification[#Specification]").attrib))
print("Specification_Code: " + str(root.find(".//code[#Specification_Code]").attrib))
print("Workpackage_Code: " + str(root.find(".//code[#Workpackage_Code]").attrib))
print("Document_Code: " + str(root.find(".//code[#Document_Code]").attrib))
Result
$ python get-data.py
RFC_Code: {'RFC_Code': 'VtW-0101'}
RFC_Progress: {'RFC_Progress': 'agreed'}
specification: {'Specification': 'Context of Documents'}
Specification_Code: {'Specification_Code': '1.1.1a'}
Workpackage_Code: {'Workpackage_Code': 'WP-01'}
Document_Code: {'Document_Code': 'DOC-0002'}
If you using xml file open, using this code
with open('data.xml', 'r') as xml_file:
root = ET.parse(xml_file)

How do you properly fetch from this nested XML?

I have the following XML:
<?xml version="1.0" encoding="UTF-8"?>
<data>
<columns>
<Leftover index="5">Leftover</Leftover>
<NODE5 index="6"></NODE5>
<NODE6 index="7"></NODE6>
<NODE8 index="9"></NODE8>
<Nomenk__Nr_ index="2">Nomenk.
Nr.</Nomenk__Nr_>
<Year index="8">2020</Year>
<Name index="1">Name</Name>
<Value_code index="3">Value code</Value_code>
</columns>
<records>
<record index="1">
<Leftover>Leftover</Leftover>
<NODE5>Test1</NODE5>
<NODE6>Test2</NODE6>
<NODE8>Test3</NODE8>
<Nomenk__Nr_></Nomenk__Nr_>
<Name></Name>
<Value_code></Value_code>
</record>
... (it repeats itself with different values and the index value increments)
My code is:
import lxml
import lxml.etree as et
xml = open('C:\outputfile.xml', 'rb')
xml_content = xml.read()
tree = et.fromstring(xml_content)
for bad in tree.xpath("//records[#index=\'*\']/NODE5"):
bad.getparent().remove(bad) # here I grab the parent of the element to call the remove directly on it
result = (et.tostring(tree, pretty_print=True, xml_declaration=True))
f = open( 'outputxml.xml', 'w' )
f.write( str(result) )
f.close()
What I need to do is to remove the NODE5, NODE6, NODE8. I tried using a wildcard and then specifying one of the nodes (see line 6) but that seems to not have worked... I'm also getting a syntax error right after the loop on the first character but the code executes.
My problem is also that the encoding by lxml is set to ASCII afterwards when the file is "exported".
UPDATE
I am getting this error on line 8:
return = ...
^
SyntaxError: invalid syntax
I took some code from https://stackoverflow.com/a/7981894/1987598

What I need to do is to remove the NODE5, NODE6, NODE8.
below
import xml.etree.ElementTree as ET
xml = '''<?xml version="1.0" encoding="UTF-8"?>
<data>
<columns>
<Leftover index="5">Leftover</Leftover>
<NODE5 index="6" />
<NODE6 index="7" />
<NODE8 index="9" />
<Nomenk__Nr_ index="2">Nomenk.
Nr.</Nomenk__Nr_>
<Year index="8">2020</Year>
<Name index="1">Name</Name>
<Value_code index="3">Value code</Value_code>
</columns>
<records>
<record index="1">
<Leftover>Leftover</Leftover>
<NODE5>Test1</NODE5>
<NODE6>Test2</NODE6>
<NODE8>Test3</NODE8>
<Nomenk__Nr_ />
<Name />
<Value_code />
</record>
<record index="21">
<Leftover>Leftover</Leftover>
<NODE5>Test11</NODE5>
<NODE6>Test21</NODE6>
<NODE8>Test39</NODE8>
<Nomenk__Nr_ />
<Name />
<Value_code />
</record>
</records>
</data>'''
root = ET.fromstring(xml)
col = root.find('./columns')
for x in ['5','6','8']:
nodes_to_remove = col.findall('./NODE{}'.format(x))
for node in nodes_to_remove:
col.remove(node)
records = root.find('./records')
records_lst = records.findall('./record'.format(x))
for r in records_lst:
for x in ['5','6','8']:
nodes_to_remove = r.findall('./NODE{}'.format(x))
for node in nodes_to_remove:
r.remove(node)
ET.dump(root)
output
<data>
<columns>
<Leftover index="5">Leftover</Leftover>
<Nomenk__Nr_ index="2">Nomenk.
Nr.</Nomenk__Nr_>
<Year index="8">2020</Year>
<Name index="1">Name</Name>
<Value_code index="3">Value code</Value_code>
</columns>
<records>
<record index="1">
<Leftover>Leftover</Leftover>
<Nomenk__Nr_ />
<Name />
<Value_code />
</record>
<record index="2">
<Leftover>Leftover</Leftover>
<Nomenk__Nr_ />
<Name />
<Value_code />
</record>
</records>
</data>

Parsing XML with namespace into dictionary

I'm having a hard time following the xml.etree.ElementTree documentation with regard to parsing an XML document with a namespace and nested tags.
To begin, the xml tree I am trying to parse looks like:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ROOT-MAIN xmlns="http://fakeurl.com/page">
<Alarm> <--- I dont care about these types of objects
<Node>
<location>Texas></location>
<name>John</name>
</Node>
</Alarm>
<Alarm> <--- I care about these types of objects
<CreateTime>01/01/2011</CreateTime>
<Story>
<Node>
<Name>Ethan</name
<Address category="residential>
<address>1421 Morning SE</address>
</address>
</Node>
</Story>
<Build>
<Action category="build_value_1">Build was successful</Action>
</Build>
<OtherData type="string" meaning="favoriteTVShow">Purple</OtherData>
<OtherData type="string" meaning="favoriteColor">Seinfeld</OtherData>
</Alarm>
</ROOT-MAIN>
I am trying to build an array of dictionaries that have a similar structure to the second < Alarm > object. When parsing this XML file, I do the following:
import xml.etree.ElementTree as ET
tree = ET.parse('data/'+filename)
root = tree.getroot()
namespace= '{http://fakeurl.com/page}'
for alarm in tree.findall(namespace+'Alarm'):
for elem in alarm.iter():
try:
creation_time = elem.find(namespace+'CreateTime')
for story in elem.findall(namespace+'Story'):
for node in story.findall(namespace+'Node'):
for Address in node.findall(namespace+'Address'):
address = Address.find(namespace+'address').text
for build in elem.findall(namespace+'Build'):
category= build.find(namespace+'Action').attrib
action = build.find(namespace+'Action').text
for otherdata in elem.findall(namespace+'OtherData'):
#not sure how to get the 'meaning' attribute value as well as the text value for these <OtherData> tags
except:
pass
Right I'm just trying to get values for:
< address >
< Action > (attribute value and text value)
< OtherData > (attribute value and text value)
I'm sort of able to do this with for loops within for-loops but I was hoping for a cleaner, xpath solution which I haven't figured out how to do with a namespace.
Any suggestions would be much appreciated.

Here (collecting a subset of the elements you mentioned -- add more code to collect rest of elements)
import xml.etree.ElementTree as ET
import re
xmlstring = '''<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<root xmlns="http://fakeurl.com/page">
<Alarm>
<Node>
<location>Texas></location>
<name>John</name>
</Node>
</Alarm>
<Alarm>
<CreateTime>01/01/2011</CreateTime>
<Story>
<Node>
<Name>Ethan</Name>
<Address category="residential">
<address>1421 Morning SE</address>
</Address>
</Node>
</Story>
<Build>
<Action category="build_value_1">Build was successful</Action>
</Build>
<OtherData type="string" meaning="favoriteTVShow">Purple</OtherData>
<OtherData type="string" meaning="favoriteColor">Seinfeld</OtherData>
</Alarm>
</root>'''
xmlstring = re.sub(' xmlns="[^"]+"', '', xmlstring, count=1)
root = ET.fromstring(xmlstring)
alarms = root.findall('Alarm')
alarms_list = []
for alarm in alarms:
create_time = alarm.find('CreateTime')
if create_time is not None:
entry = {'create_time': create_time.text}
alarms_list.append(entry)
actions = alarm.findall('Build/Action')
if actions:
entry['builds'] = []
for action in actions:
entry['builds'].append({'category': action.attrib['category'], 'status': action.text})
print(alarms_list)

copy xml node and children to new xml file

I have the following code that loops over a set of records and moves each record to a new file:
import os
import xml.etree.cElementTree as ET
for filename in os.listdir('modemuze'):
if filename.endswith('.xml'):
original_tree = ET.ElementTree(file='modemuze/'+filename)
root = original_tree.getroot()
for child in root[2]:
if child.tag == "{http://www.openarchives.org/OAI/2.0/}record":
new_tree = ET.ElementTree(file='test.xml')
new_root = new_tree.getroot()
new_root.append(child)
the file which contains the records i want to move has to following structure:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<OAI-PMH xsi:schemaLocation="http://www.openarchives.org/OAI/2.0/ http://www.openarchives.org/OAI/2.0/OAI-PMH.xsd" xmlns="http://www.openarchives.org/OAI/2.0/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<responseDate>2018-02-14T12:15:11.241+02:00</responseDate>
<request verb="ListRecords">147.102.11.65:9000/fashionedmfp/oai</request>
<ListRecords>
<record>
<header>
<identifier>oai:fashionedmfp:8c549bcd078e2ce84a265d318547c5f8e8bf0cd0</identifier>
<datestamp>2016-06-27</datestamp>
</header>
<metadata>
<rdf:RDF xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:edm="http://www.europeana.eu/schemas/edm/" xmlns:foaf="http://xmlns.com/foaf/0.1/" xmlns:edmfp="http://www.europeanafashion.eu/edmfp/" xmlns:rdaGr2="http://rdvocab.info/ElementsGr2/" xmlns:ore="http://www.openarchives.org/ore/terms/" xmlns:dcterms="http://purl.org/dc/terms/" xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#" xmlns:mrel="http://id.loc.gov/vocabulary/relators/" xmlns:owl="http://www.w3.org/2002/07/owl#" xmlns:wgs84="http://www.w3.org/2003/01/geo/wgs84_pos#" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:crm="http://www.cidoc-crm.org/rdfs/cidoc_crm_v5.0.2_english_label.rdfs#" xmlns:gr="http://www.heppnetz.de/ontologies/goodrelations/v1#" xmlns:xalan="http://xml.apache.org/xalan" xmlns:skos="http://www.w3.org/2004/02/skos/core#">
<edm:ProvidedCHO rdf:about="localID/europeana-fashion/10918x1y95563">
<dcterms:created>circa 1855-1874</dcterms:created>
<dcterms:issued>1875</dcterms:issued>
<dcterms:issued>1875</dcterms:issued>
<dcterms:medium>katoen</dcterms:medium>
<dcterms:provenance>schenking</dcterms:provenance>
<dcterms:provenance>1958</dcterms:provenance>
<dcterms:spatial>
<edm:Place>
<skos:prefLabel>Nederland</skos:prefLabel>
</edm:Place>
</dcterms:spatial>
<dcterms:creator>
<edm:Agent/>
</dcterms:creator>
<dc:creator>
<edm:Agent/>
</dc:creator>
<dc:description>Jurk (kind) van wit piqué, gegarneerd met broderie en soustache</dc:description>
<dc:identifier>0061211</dc:identifier>
<dc:title>jurken</dc:title>
<dc:title>kinderkleding</dc:title>
<edm:type>IMAGE</edm:type>
<edmfp:localType>jurken</edmfp:localType>
<edmfp:localType>kinderkleding</edmfp:localType>
<edmfp:technique>piqué-weefsel</edmfp:technique>
</edm:ProvidedCHO>
<ore:Aggregation rdf:about="localID/europeana-fashion/Aggregation_10918x1y95563">
<edm:aggregatedCHO rdf:resource="localID/europeana-fashion/10918x1y95563"/>
<edm:dataProvider>
<edm:Agent>
<skos:prefLabel>Gemeentemuseum Den Haag</skos:prefLabel>
</edm:Agent>
</edm:dataProvider>
<edm:hasView>
<edm:WebResource rdf:about="http://images.gemeentemuseum.nl/br/0061211.jpg"/>
</edm:hasView>
<edm:isShownBy>
<edm:WebResource rdf:about="http://images.gemeentemuseum.nl/br/0061211.jpg"/>
</edm:isShownBy>
<edm:provider>
<edm:Agent rdf:about="http://www.europeanafashion.eu/">
<skos:prefLabel>Europeana Fashion</skos:prefLabel>
</edm:Agent>
</edm:provider>
<edm:rights rdf:resource="http://www.europeana.eu/rights/rr-f/"/>
</ore:Aggregation>
</rdf:RDF>
</metadata>
</record>
</ListRecords>
</OAI-PMH>
and the file i want to place the records in has the following structure:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ListRecords>
</ListRecords>
but when i run this code my test.xml file contains no records..
Why is this happening?
I am totally new to XML and python so if i missed something or something is unclear please let me know so i can clarify or add it.
I am doing this is python 2.7
All help and suggestions are very much appreciated!

You need to write changes to the file.
Add to the code new_tree.write('test.xml')
As a result, the code should look like this
import os
import xml.etree.cElementTree as ET
for filename in os.listdir('modemuze'):
if filename.endswith('.xml'):
original_tree = ET.ElementTree(file='modemuze/'+filename)
root = original_tree.getroot()
for child in root[2]:
if child.tag == "{http://www.openarchives.org/OAI/2.0/}record":
new_tree = ET.ElementTree(file='test.xml')
new_root = new_tree.getroot()
new_root.append(child)
new_tree.write('test.xml')

how can I select all descendants of a certain element with ElementTree in Python 3.3?

This is the sample data.
input.xml
<root>
<entry id="1">
<headword>go</headword>
<example>I <hw>go</hw> to school.</example>
</entry>
</root>
I'd like to put node and its descendants into . That is,
output.xml
<root>
<entry id="1">
<headword>go</headword>
<examplegrp>
<example>I <hw>go</hw> to school.</example>
</examplegrp>
</entry>
</root>
My poor and incomplete script is:
import codecs
import xml.etree.ElementTree as ET
fin = codecs.open(r'input.xml', 'rb', encoding='utf-8')
data = ET.parse(fin)
root = data.getroot()
example = root.find('.//example')
for elem in example.iter():
---and then I don't know what to do---

Here's an example of how it can be done:
text = """
<root>
<entry id="1">
<headword>go</headword>
<example>I <hw>go</hw> to school.</example>
</entry>
</root>
"""
import lxml.etree
import StringIO
data = lxml.etree.parse(StringIO.StringIO(text))
root = data.getroot()
for entry in root.xpath('//example/ancestor::entry[1]'):
examplegrp = lxml.etree.SubElement(entry,"examplegrp")
nodes = [node for node in entry.xpath('./example')]
for node in nodes:
entry.remove(node)
examplegrp.append(node)
print lxml.etree.tostring(root,pretty_print=True)
which will output:
<root>
<entry id="1">
<headword>go</headword>
<examplegrp><example>I <hw>go</hw> to school.</example>
</examplegrp></entry>
</root>

http://docs.python.org/3/library/xml.dom.html?highlight=xml#node-objects
http://docs.python.org/3/library/xml.dom.html?highlight=xml#document-objects
You probably want to follow some paradigm of creating a Document Element and appending reach result to it.
group = Document.createElement(tagName)
for found in founds:
group.appendNode(found)
Or something like this