Kind of a noob question. Sorry for that.
I have a string path
W:\documents\files
Is it possible to create an hyperlink from that and store it in a csv so that when a click it in Excel it opens the file ?
How about this?
from pathlib import Path
link = Path('W:\\documents\\files\\sample.txt').as_uri()
It should return "file:///W:/documents/files/sample.txt"
I'm guessing you want something like this:
import csv
with open('my_csv_file.csv', 'w', newline='') as file:
writer = csv.writer(file)
writer.writerow(["file:///W:/documents/files"])
the csv module lets you read and write to csv files. Adding file:/// before your file path will let you link to it. Note that this code will write the text to a csv file but it won't become a hyperlink until you put the cursor in front of it and hit enter.
I don't know exactly what you said.
I think maybe you want to write hyperlink path in csv.
That is just use "".
like this.
function("W:\documents\files")
Related
I don't need the entire code but I want a push to help me on the way, I've been searching on the internet for clues on how to start to write a function like this but I haven't gotten any further then just the name of the function.
So I haven't got the slightest clue on how to start with this, I don't know how to work with text files. Any tips?
These text files are CSV (Comma Separated Values). It is a simple file format used to store tabular data.
You may explore Python's inbuilt module called csv.
Following code snippet an example to load .csv file in Python:
import csv
filename = 'us_population.csv'
with open(filename, 'r') as csvfile:
csvreader = csv.reader(csvfile)
I have the following problem:
I have a folder with files.
I want to write into those files their respective file path + filename (home/text.txt) .
How can I achieve this in python?
Thanks in advance for your time and help!
with open('FOLDER_NAME/FILE_NAME','w+') as f:
Assuming the python file is in the same path as the folder.
You can use:
..
to move back a directory.
file = open("path", "w+")
file.write("string you want to write in there")
file.close
With w+ it is for reading and writing to a file, existing data will be overwritten.
Of course, as Landon said, you can simply do this by using with, which will close the file for you after you are done writing to it:
with open("path") as file:
file.write("same string here")
This second snippet only takes up 2 lines, and it is the common way of opening a file.
However if you want append to instead of overwriting a file, use a+ this will open and allow you to read and append. Which means existing data will still be there, whatever you write will be added to the end. The file will also be created if it doesn’t exist.
Read more:
https://www.geeksforgeeks.org/reading-writing-text-files-python/
Correct way to write line to file?
How do I use ParaView's CSVReader in a Python Script? An example would be appreciated.
If you have a .csv file that looks like this:
x,y,z,attribute
0,0,0,0
1,0,0,1
0,1,0,2
1,1,0,3
0,0,1,4
1,0,1,5
0,1,1,6
1,1,1,7
then you can import it with a command that looks like this:
myReader = CSVReader(FileName='C:\foo.csv', guiName='foo.csv')
Also, if you don't add that guiName parameter, you can change the name later using the RenameSource command like this:
RenameSource(proxy = myReader, newName = 'MySuperNewName'
Credit for the renaming part of this answer to Sebastien Jourdain.
Unfortunately, I don't know Paraview at all. But I found "... simply record your work in the desktop application in the form of a python script ..." at their site. If you import a CSV like that, it might give you a hint.
Improving the #GregNash's answer. If you want to include only a single file (called foo.csv):
outcsv = CSVReader(FileName= 'foo.csv')
Or if you want to include all files with certain pattern use glob. For example if files start with string foo (aka foo.csv.0, foo.csv.1, foo.csv.2):
myreader = CSVReader(FileName=glob.glob('foo*'))
To use glob is neccesary import glob in the preamble. In general in Filename you could work with strings generated with python which could contain more complex pattern files and file's path.
I have a csv file looks like:
s555555,7
s333333,10
s666666,9
s111111,10
s999999,9
and when I open it in python it should look something like:
[[’s555555’, ’7’], [’s333333’, ’10’], [’s666666’, ’9’], [’s111111’, ’10’], [’s999999’, ’9’]]
What codes do i need to use for that?
Thanks and any helps would be so grateful!!
Check out the csv module. (http://docs.python.org/library/csv.html)
I have a list with .dbf files which I want to change to .csv files. By hand I open them in excel and re-save them as .csv, but this takes too much time.
Now I made a script which changes the file name, but when I open it, it is still a .dbf file type (although it is called .csv). How can I rename the files in such a way that the file type also changes?
My script uses (the dbf and csv file name are listed in a seperate csv file):
IN = dbffile name
OUT = csvfile name
for output_line in lstRename:
shutil.copyfile(IN,OUT)
Changing the name of a file (and the extension is just part of the complete name) has absolutely no effect on the contents of the file. You need to somehow convert the contents from one format to the other.
Using my dbf module and python it is quite simple:
import dbf
IN = 'some_file.dbf'
OUT = 'new_name.csv'
dbf.Table(IN).export(filename=OUT)
This will create a .csv file that is actually in csv format.
If you have ever used VB or looked into VBA, you can write a simple excel script to open each file, save it as csv and then save it with a new name.
Use the macro recorder to record you once doing it yourself and then edit the resulting script.
I have now created a application that automates this. Its called xlsto (look for the xls.exe release file). It allows you to pick a folder and convert all xls files to csv (or any other type).
You need a converter
Search for dbf2csv in google.
It depends what you want to do. It seems like you want to convert files to other types. There are many converters out there, but a computer alone doesn't know every file type. For that you will need to download some software. If all you want to do is change the file extension,
(ex. .png, .doc, .wav) then you can set your computer to be able to change both the name and the extension. I hoped I helped in some way :)
descargar libreria dbfpy desde http://sourceforge.net/projects/dbfpy/?source=dlp
import csv,glob
from dbfpy import dbf
entrada = raw_input(" entresucarpetadbf ::")
lisDbf = glob.glob(entrada + "\\*dbf")
for db in lisDbf:
print db
try:
dbfFile = dbf.Dbf(open(db,'r'))
csvFile = csv.writer(open(db[:-3] + "csv", 'wb'))
headers = range(len(dbfFile.fieldNames))
allRows = []
for row in dbfFile:
rows = []
for num in headers:
rows.append(row[num])
allRows.append(rows)
csvFile.writerow(dbfFile.fieldNames)
for row in allRows:
print row
csvFile.writerow(row)
except Exception,e:
print e
It might be that the new file name is "xzy.csv.dbf". Usually in C# I put quotes in the filename. This forces the OS to change the filename. Try something like "Xzy.csv" in quotes.