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How do I extract the underlined value in red below and save it as a list?

How do I extract the underlined value in red below and save it as a list?
You want to extract the Memcode value in href to a in p tag using soup.
However, I don't know how to extract it at all.
Please help me.
My code
import urllib.request
from bs4 import BeautifulSoup
url = "https://www.council.ulsan.kr/kor/councillor/viewByPerson.do"
req = urllib.request.Request(url)
sourcecode = urllib.request.urlopen(url).read()
soup = BeautifulSoup(sourcecode, "html.parser")
list = []
for href in soup.find("div", class_="memList memList-col-3").find_all("a"):
print(href)

try this, using css selector
import requests
from bs4 import BeautifulSoup
resp = requests.get('https://www.gjcouncil.go.kr/kr/member/name.do')
soup = BeautifulSoup(resp.text, "html.parser")
for a in soup.select("div[id='member_list'] > ul > li > a"):
print(a['href'].split("/")[2])
08070
00716
08040
....
....

You can use split on the "=" and take the -1 index. I also changed the class .
import urllib.request
from bs4 import BeautifulSoup
url = "https://www.council.ulsan.kr/kor/councillor/viewByPerson.do"
req = urllib.request.Request(url)
sourcecode = urllib.request.urlopen(url).read()
soup = BeautifulSoup(sourcecode, "html.parser")
ids = [i['href'].split('=')[-1] for i in soup.select('.btn-home')]

import urllib.request
from bs4 import BeautifulSoup
url = "https://www.council.ulsan.kr/kor/councillor/viewByPerson.do"
req = urllib.request.Request(url)
sourcecode = urllib.request.urlopen(url).read()
soup = BeautifulSoup(sourcecode, "html.parser")
href_list = []
for href in soup.find("div", class_="memList memList-col-3").find_all("a"):
if href['href'] == '#LINK':
pass
else:
href_list.append(href['href'][-7:])
print(href_list)
['7620212', '7670126', '7670420', '7650601', '7890930', '7800407', '7660925', '7641102', '7731222', '7801011', '7570803', '7770106', '7590808', '7700831', '7580115', '7710713', '7680112', '7621125', '7711117', '7680213', '7640925', '7591214']

One of the best method is using Regular-Expression.
Check out this code :
import urllib.request
from bs4 import BeautifulSoup
import re
url = "https://www.council.ulsan.kr/kor/councillor/viewByPerson.do"
req = urllib.request.Request(url)
sourcecode = urllib.request.urlopen(url).read()
soup = BeautifulSoup(sourcecode, "html.parser")
list_ = []
for href in soup.find("div", class_="memList memList-col-3").find_all("a"):
list_.append(href['href'])
regobj = re.compile(r'memCode=(\w+)')
final = list(filter('#LINK'.__ne__, list_))
result = list(map(lambda i: regobj.search(i).group(1) ,final))
print(result)

Beautiful Soup PYTHON - inside tags

Little problem with BeautifulSoup:
from bs4 import BeautifulSoup
import requests
link = "http://www.cnnvd.org.cn/web/vulnerability/querylist.tag"
req = requests.get(link)
web = req.text
soup = BeautifulSoup(web, "lxml")
cve_name = []
cve_link = []
for par_ in soup.find_all('div', attrs={'class':'fl'}):
for link_ in par_.find_all('p'):
for text_ in link_.find_all('a'):
print (text_.string)
print (text_['href'])
print ("==========")
#cve_name.append(text_.string)
#cve_link.append(text_['href'])
And it gives me twice records :V That probably is easy to solve :V

The same elements are in two places on page so you have to use find()/find_all() to select only one place i.e find(class_='list_list') in
soup.find(class_='list_list').find_all('div', attrs={'class':'fl'}):
Full code:
from bs4 import BeautifulSoup
import requests
link = "http://www.cnnvd.org.cn/web/vulnerability/querylist.tag"
req = requests.get(link)
web = req.text
soup = BeautifulSoup(web, "lxml")
cve_name = []
cve_link = []
for par_ in soup.find(class_='list_list').find_all('div', attrs={'class':'fl'}):
print(len(par_))
for link_ in par_.find_all('p'):
for text_ in link_.find_all('a'):
print (text_.string)
print (text_['href'])
print ("==========")
#cve_name.append(text_.string)
#cve_link.append(text_['href'])

How about this. I used css selectors to do the same.
from bs4 import BeautifulSoup
from urllib.parse import urljoin
import requests
link = "http://www.cnnvd.org.cn/web/vulnerability/querylist.tag"
res = requests.get(link)
soup = BeautifulSoup(res.text, "lxml")
for item in soup.select('.fl p a'):
print("Item: {}\nItem_link: {}".format(item.text,urljoin(link,item['href'])))
Partial Output:
Item: CNNVD-201712-811
Item_link: http://www.cnnvd.org.cn/web/xxk/ldxqById.tag?CNNVD=CNNVD-201712-811
Item: CNNVD-201712-810
Item_link: http://www.cnnvd.org.cn/web/xxk/ldxqById.tag?CNNVD=CNNVD-201712-810
Item: CNNVD-201712-809
Item_link: http://www.cnnvd.org.cn/web/xxk/ldxqById.tag?CNNVD=CNNVD-201712-809

Python: BeautifulSoup extract all the heading text from div class

import requests
from bs4 import BeautifulSoup
res = requests.get('http://aicd.companydirectors.com.au/events/events-calendar')
soup = BeautifulSoup(res.text,"lxml")
event_containers = soup.find_all('div', class_ = "col-xs-12 col-sm-6 col-md-8")
first_event = event_containers[0]
print(first_event.h3.text)
By using this code i'm able to extract the event name,I'm trying for a way to loop and extract all the event names and dates ? and also i'm trying to extract the location information which is visable after clicking on readmore link

event_containers is a bs4.element.ResultSet object, which is basically a list of Tag objects.
Just loop over the tags in event_containers and select h3 for the title, div.date for the date and a for the URL, example:
for tag in event_containers:
print(tag.h3.text)
print(tag.select_one('div.date').text)
print(tag.a['href'])
Now, for the location information you'll have to visit each URL and collect the text in div.date.
Full code:
import requests
from bs4 import BeautifulSoup
res = requests.get('http://aicd.companydirectors.com.au/events/events-calendar')
soup = BeautifulSoup(res.text,"lxml")
event_containers = soup.find_all('div', class_ = "col-xs-12 col-sm-6 col-md-8")
base_url = 'http://aicd.companydirectors.com.au'
for tag in event_containers:
link = base_url + tag.a['href']
soup = BeautifulSoup(requests.get(link).text,"lxml")
location = ', '.join(list(soup.select_one('div.event-add').stripped_strings)[1:-1])
print('Title:', tag.h3.text)
print('Date:', tag.select_one('div.date').text)
print('Link:', link)
print('Location:', location)

Try this to get all the events and dates you are after:
import requests
from bs4 import BeautifulSoup
res = requests.get('http://aicd.companydirectors.com.au/events/events-calendar')
soup = BeautifulSoup(res.text,"lxml")
for item in soup.find_all(class_='lead'):
date = item.find_previous_sibling().text.split(" |")[0]
print(item.text,date)

Scraping links from buttons on a page

I am trying to scrape the links from the "box score" button on this page. The button is supposed to look like this
http://www.espn.com/nfl/boxscore?gameId=400874795
I tried to use this code to see if I could access the buttons but I cannot.
from bs4 import BeautifulSoup
import requests
url = 'http://www.espn.com/nfl/scoreboard/_/year/2016/seasontype/1/week/2'
advanced = url
r = requests.get(advanced)
data = r.text
soup = BeautifulSoup(data,"html.parser")
for link in soup.find_all('a'):
print link

As wpercy mentions in his comment, you can't do this using requests, as a suggestion you should use selenium together with Chromedriver/PhantomJS for handling the JavaScript:
from selenium import webdriver
from bs4 import BeautifulSoup
url = "http://www.espn.com/nfl/scoreboard/_/year/2016/seasontype/1/week/2"
browser = webdriver.Chrome()
browser.get(url)
html = browser.page_source
soup = BeautifulSoup(html,'html.parser')
boxList = soup.findAll('a',{'name':'&lpos=nfl:scoreboard:boxscore'})
All score buttons's a tag have the attribute name = &lpos=nfl:scoreboard:boxscore, so we first use .findAll and now a simple list comprehension can extract each href attribute:
>>> links = [box['href'] for box in boxList]
>>> links
['/nfl/boxscore?gameId=400874795', '/nfl/boxscore?gameId=400874854', '/nfl/boxscore?gameId=400874753', '/nfl/boxscore?gameId=400874757', '/nfl/boxscore?gameId=400874772', '/nfl/boxscore?gameId=400874777', '/nfl/boxscore?gameId=400874767', '/nfl/boxscore?gameId=400874812', '/nfl/boxscore?gameId=400874761', '/nfl/boxscore?gameId=400874764', '/nfl/boxscore?gameId=400874781', '/nfl/boxscore?gameId=400874796', '/nfl/boxscore?gameId=400874750', '/nfl/boxscore?gameId=400873867', '/nfl/boxscore?gameId=400874775', '/nfl/boxscore?gameId=400874798']

here is the solution i did , and it scrapes all the link which are there on the url you have provided in your answer . you can check it out
# from BeautifulSoup import *
from bs4 import BeautifulSoup
# import requests
import urllib
url = 'http://www.espn.com/nfl/scoreboard/_/year/2016/seasontype/1/week/2'
# advanced = url
html = urllib.urlopen(url).read()
# r = requests.get(html)
# data = r.text
soup = BeautifulSoup(html)
tags = soup('a')
# for link in soup.find_all('a'):
for i,tag in enumerate(tags):
# print tag;
print i;
ans = tag.get('href',None)
print ans;
print "\n";

The answer from Gopal Chitalia didn't work for me, so I decided to post the working one (for python 3.6.5)
# from BeautifulSoup import *
from bs4 import BeautifulSoup
# import requests
import urllib
url = 'http://www.espn.com/nfl/scoreboard/_/year/2016/seasontype/1/week/2'
# advanced = url
html = urllib.request.urlopen(url)
# urlopen(url).read()
# r = requests.get(html)
# data = r.text
soup = BeautifulSoup(html)
tags = soup('a')
# for link in soup.find_all('a'):
for i,tag in enumerate(tags):
# print tag;
print (i);
ans = tag.get('href',None)
print (ans);
print ("\n");

How to get next page link in python beautifulsoup?

I have this link:
http://www.brothersoft.com/windows/categories.html
I am trying to to get the link for the item inside the div.
Example:
http://www.brothersoft.com/windows/mp3_audio/midi_tools/
I have tried this code:
import urllib
from bs4 import BeautifulSoup
url = 'http://www.brothersoft.com/windows/categories.html'
pageHtml = urllib.urlopen(url).read()
soup = BeautifulSoup(pageHtml)
sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brLeft'})]
for i in sAll:
print "http://www.brothersoft.com"+i['href']
But I only get output:
http://www.brothersoft.com/windows/mp3_audio/
How can I get output that I needed?

Url http://www.brothersoft.com/windows/mp3_audio/midi_tools/ is not in tag <div class='brLeft'>, so if output is http://www.brothersoft.com/windows/mp3_audio/, that's correct.
If you want to get the url you want, change
sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brLeft'})]
to
sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brRight'})]
UPDATE:
an example to get info inside 'midi_tools'
import urllib
from bs4 import BeautifulSoup
url = 'http://www.brothersoft.com/windows/categories.html'
pageHtml = urllib.urlopen(url).read()
soup = BeautifulSoup(pageHtml)
sAll = [div.find('a') for div in soup.findAll('div', attrs={'class':'brRight'})]
for i in sAll:
suburl = "http://www.brothersoft.com"+i['href'] #which is a url like 'midi_tools'
content = urllib.urlopen(suburl).read()
anosoup = BeautifulSoup(content)
ablock = anosoup.find('table',{'id':'courseTab'})
for atr in ablock.findAll('tr',{'class':'border_bot '}):
print atr.find('dt').a.string #name
print "http://www.brothersoft.com" + atr.find('a',{'class':'tabDownload'})['href'] #link