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Web scrape data in performance gauge

I'm trying to scrape data in a widget using python and the requests-html library.
The the value I want is in a gauge with an arrow pointing to five possible results.
Each label on the gauge is the same on all pages of the website. The problem I face is I cannot use a css selector on the gauge labels to extract the text, I need to extract the value of the arrow itself as it will be pointing to a label. The arrow doesn't have a text attribute so if I use a css selector I get none as a response.
Each arrow has a unique class name.
<div class="arrow-F-uE7IX8 arrowToStrongBuy-1ydGKDOo arrowStrongBuyShudder-3xsGK8k5">
https://www.tradingview.com/symbols/NASDAQ-MDB/
StrongBuy:
<div class="arrow-F-uE7IX8 arrowToBuy-1R7d8UMJ arrowBuyShudder-3GMCnG5u">
https://www.tradingview.com/symbols/NYSE-XOM/
Buy:
<div class="arrow-F-uE7IX8 arrowToStrongSell-3UWimXJs arrowStrongSellShudder-2UJhm0_C">
https://www.tradingview.com/symbols/NASDAQ-IDEX/
StrongSell:
What can I do to ensure I get the correct value? I'm not sure how I can check if the selector contains the arrowTo{foo} and store as variable.
import pyppdf.patch_pyppeteer
from requests_html import AsyncHTMLSession
asession = AsyncHTMLSession()
async def get_page():
code = 'NASDAQ-MDB'
r = await asession.get(f'https://www.tradingview.com/symbols/{code}/')
await r.html.arender(wait=3)
return r
results = asession.run(get_page)
for result in results:
arrow_class_placeholder = "//div[contains(#class,'arrow-F-uE7IX8 arrowToStrongBuy-1ydGKDOo')]//div[1]"
arrow_class_name = result.html.xpath(arrow_class_placeholder,first=True)
if arrow_class_name == "//div[contains(#class,'arrow-F-uE7IX8 arrowToStrongBuy-1ydGKDOo')]//div[1]":
print('StrongBuy')
else:
print('not strong buy')

You can use BeautifulSoup4 (bs4), which is a a Python library for pulling data out of HTML and XML files, with a combination of Regular Expressions (RegEx). In this case I used the python re library for the RegEx purposes.
Something like this is what you want (source):
In the example above soup.find_all(class_=re.compile("itle")) returns all instances where the word "itle" is found in the class tag, such as class = "title" from the html document shown below.
For your RegEx it would look something like "arrowTo*" or even just "arrowTo". soup.find_all(class_=re.compile("arrowTo")).
Your final code should look something like:
from bs4 import BeautifulSoup
#i think result was your html document from requests library
#the first parameter is your html document variable
soup = BeautifulSoup(result, 'html.parser')
myArrowToList = soup.find_all(class_=re.compile("arrowTo"))
If you wanted "arrowToStrongBuy" just use that in the regex input to the find_all function.
soup.find_all(class_=re.compile("arrowToStrongBuy"))

Webcrawler: extracting string out of array using Python3 on mac

i have a problem with writing a webcrawler to extract currency rates:
import requests
from bs4 import BeautifulSoup
from urllib.parse import urljoin
import re
url = "https://wechselkurse-euro.de/"
r = requests.get(url)
rates = []
status = r.status_code
if status != 200:
print("Something went wrong while parsing the website " + url)
temp = BeautifulSoup(r.text, "html.parser")
current_date = temp.select(".ecb")[0].text.strip().split(" ")[5]
#rates_array = temp.select(".kurz_kurz2.center", limit= 20).string
rates_array = temp.select(".kurz_kurz2.center", limit= 20)
#for i in rates_array:
# rate = rates_array[i].string
# rates.append(rate)
rates = list( map( lambda x: re.search(">\d{1}\.\d{4}",x), rates_array))
print(rates)
#rate_1EUR_to_USD =
#rate_1EUR_to_GBP =
I tried several ways which are commented out - all of them don't work and I don't know why. Especially the .string not working is suprising to me since the rates_array seems to inherit all the different information of the bs4 object, including the information that there is a td tag <td class="kurz_kurz2 center" title="Aktueller Wechselkurs am 3.4.2020">0.5554</td> where I just want the string within the tag (so the value 0.5554 in the example above). This should be easy but nothing works, what am I doing wrong?
The regular expression should not be the problem, I tested it on regExR.
I tried using the map function as currently active but I can't convert the map object to a list as I am supposed to.
The select().string returns an empty list and the same with using relgular expressions to search through the strings I saved in rates_array when I try to do the oldschool way of iterating over every item of my function with a for loop.
String as attribute of bs4-object

Your rates_array contains Beautiful Soup tag objects, not strings. So you'll have to access their text property in order to get the values. For example:
rates = [o.text for o in rates_array]
Now rates contains:
['0.5554', '0.1758']

I would recommend you to check the locator first.
Are you sure that rates_array is not empty?
Also, try:
rates_array[i].text

Cannot get a CSS class from Google search page

I use BeautifulSoup for parsing a Google search, but I get empty list. I want to make a spellchecker by using Google's "Did you mean?".
import requests
from bs4 import BeautifulSoup
import urllib.parse
text = "i an you ate goode maan"
data = urllib.parse.quote_plus(text)
url = 'https://translate.google.com/?source=osdd#view=home&op=translate&sl=auto&tl=en&text='
rq = requests.get(url + data)
soup = BeautifulSoup(rq.content, 'html.parser')
words = soup.select('.tlid-spelling-correction spelling-correction gt-spell-correct-message')
print(words)
The output is just: [], but expected: "i and you are good man" (sorry for such a bad text example)

First, the element you are looking for is loaded using javascript. Since BeautifulSoup does not run js, the target elements don't get loaded into the DOM hence the query selector can't find them. Try using Selenium instead of BeautifulSoup.
Second, The CSS selector should be
.tlid-spelling-correction.spelling-correction.gt-spell-correct-message`.
Notice the . instead of space in front of every class name.
I have verified it using JS query selector
The selector you were using .tlid-spelling-correction spelling-correction gt-spell-correct-message was looking for an element with class gt-spell-correct-message inside an element with class spelling-correction which itself was inside another element with class tlid-spelling-correction.
By removing the space and putting a dot in front of every class name, the selector looks for an element with all three of the above mentioned classes.

HTML Scraping the website with duplicated div class name

I currently working on the HTML scraping the baka-update.
However, the name of Div Class is duplicated.
As my goal is as csv or json, I would like to use information in [sCat] as column name and [sContent] as to be get stored.....
Is their are way to scrape with this kinds of website?
Thanks,
Sample
https://www.mangaupdates.com/series.html?id=75363
Image 1
Image 2
from lxml import html
import requests
page = requests.get('http://www.mangaupdates.com/series.html?id=153558?')
tree = html.fromstring(page.content)
#Get the name of the columns.... I hope
sCat = tree.xpath('//div[#class="sCat"]/text()')
#Get the actual data
sContent = tree.xpath('//div[#class="sContent"]/text()')
print('sCat: ', sCat)
print('sContent: ', sContent)
I tried but nothing I could find of
#Jasper Nichol M Fabella

I tried to edit your code and got the following output. Maybe it will Help.
from lxml import html
import requests
page = requests.get('http://www.mangaupdates.com/series.html?id=153558?')
tree = html.fromstring(page.content)
# print(page.content)
#Get the name of the columns.... I hope
sCat = tree.xpath('//div[#class="sCat"]')
#Get the actual data
sContent = tree.xpath('//div[#class="sContent"]')
print('sCat: ', len(sCat))
print('sContent: ', len(sContent))
json_dict={}
for i in range(0,len(sCat)):
# print(''.join(i.itertext()))
sCat_text=(''.join(sCat[i].itertext()))
sContent_text=(''.join(sContent[i].itertext()))
json_dict[sCat_text]=sContent_text
print(json_dict)
I got the following output
Hope it Helps

you can use xpath expressions and create an absolute path on what you want to scrape

Here is an example with requests and lxml library:
from lxml import html
import requests
r = requests.get('https://www.mangaupdates.com/series.html?id=75363')
tree = html.fromstring(r.content)
sCat = [i.text_content().strip() for i in tree.xpath('//div[#class="sCat"]')]
sContent = [i.text_content().strip() for i in tree.xpath('//div[#class="sContent"]')]

What are you using to scrape?
If you are using BeautifulSoup? Then you can search for all content on the page with FindAll method with a class identifier and iterate thru that. You can the special "_class" deginator
Something like
import bs4
soup = bs4.BeautifulSoup(html.source)
soup.find_all('div', class_='sCat')
# do rest of your logic work here
Edit: I was typing on my mobile on cached page before you made the edits. So didnt see the changes. Though i see you are using raw lxml library to parse. Yes that's faster but I am not to familiar, as Ive only used raw lxml library for one project but I think you can chain two search methods to distill to something equivalent.

Python scrape table

I'm new to programming so it's very likely my idea of doing what I'm trying to do is totally not the way to do that.
I'm trying to scrape standings table from this site - http://www.flashscore.com/hockey/finland/liiga/ - for now it would be fine if I could even scrape one column with team names, so I try to find td tags with the class "participant_name col_participant_name col_name" but the code returns empty brackets:
import requests
from bs4 import BeautifulSoup
import lxml
def table(url):
teams = []
source = requests.get(url).content
soup = BeautifulSoup(source, "lxml")
for td in soup.find_all("td"):
team = td.find_all("participant_name col_participant_name col_name")
teams.append(team)
print(teams)
table("http://www.flashscore.com/hockey/finland/liiga/")
I tried using tr tag to retrieve whole rows, but no success either.

I think the main problem here is that you are trying to scrape a dynamically generated content using requests, note that there's no participant_name col_participant_name col_name text at all in the HTML source of the page, which means this is being generated with JavaScript by the website. For that job you should use something like selenium together with ChromeDriver or the driver that you find better, below is an example using both of the mentioned tools:
from bs4 import BeautifulSoup
from selenium import webdriver
url = "http://www.flashscore.com/hockey/finland/liiga/"
driver = webdriver.Chrome()
driver.get(url)
source = driver.page_source
soup = BeautifulSoup(source, "lxml")
elements = soup.findAll('td', {'class':"participant_name col_participant_name col_name"})
I think another issue with your code is the way you were trying to access the tags, if you want to match a specific class or any other specific attribute you can do so using a Python's dictionary as an argument of .findAll function.
Now we can use elements to find all the teams' names, try print(elements[0]) and notice that the team's name is inside an a tag, we can access it using .a.text, so something like this:
teams = []
for item in elements:
team = item.a.text
print(team)
teams.append(team)
print(teams)
teams now should be the desired output:
>>> teams
['Assat', 'Hameenlinna', 'IFK Helsinki', 'Ilves', 'Jyvaskyla', 'KalPa', 'Lukko', 'Pelicans', 'SaiPa', 'Tappara', 'TPS Turku', 'Karpat', 'KooKoo', 'Vaasan Sport', 'Jukurit']
teams could also be created using list comprehension:
teams = [item.a.text for item in elements]

Mr Aguiar beat me to it! I will just point out that you can do it all with selenium alone. Of course he is correct in pointing out that this is one of the many sites that loads most of its content dynamically.
You might be interested in observing that I have used an xpath expression. These often make for compact ways of saying what you want. Not too hard to read once you get used to them.
>>> from selenium import webdriver
>>> driver = webdriver.Chrome()
>>> driver.get('http://www.flashscore.com/hockey/finland/liiga/')
>>> items = driver.find_elements_by_xpath('.//span[#class="team_name_span"]/a[text()]')
>>> for item in items:
... item.text
...
'Assat'
'Hameenlinna'
'IFK Helsinki'
'Ilves'
'Jyvaskyla'
'KalPa'
'Lukko'
'Pelicans'
'SaiPa'
'Tappara'
'TPS Turku'
'Karpat'
'KooKoo'
'Vaasan Sport'
'Jukurit'

You're very close.
Start out being a little less ambitious, and just focus on "participant_name". Take a look at https://www.crummy.com/software/BeautifulSoup/bs4/doc/#find-all . I think you want something like:
for td in soup.find_all("td", "participant_name"):
Also, you must be seeing different web content than I am. After a wget of your URL, grep doesn't find "participant_name" in the text at all. You'll want to verify that your code is looking for an ID or a class that is actually present in the HTML text.

Achieving the same using css selector which will let you make the code more readable and concise:
from selenium import webdriver; driver = webdriver.Chrome()
driver.get('http://www.flashscore.com/hockey/finland/liiga/')
for player_name in driver.find_elements_by_css_selector('.participant_name'):
print(player_name.text)
driver.quit()