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Indentation error on line 32 with my if statement [closed]

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I'm struggling to find out why I get an indent error in my code. I've tried getting rid of tabs, and adding them. I've only used tabs: no spaces were used.
Here is a link:
https://repl.it/#OwenLagger1/SameReflectingCoderesource#main.py
Thanks for any help
P.S.
Sorry I have a link instead of code

Just copied and pasted into my editor and the if on line 32 is indented for no reason:
def main():
process_file("good_data.txt")
process_file("bad_data.txt")
process_file("empty_file.txt")
process_file("does_not_exist.txt")
def process_file(param_str_file_name):
#Variables
num_rec = 0
total = 0
average = 0
try:
file_name = open(param_str_file_name, 'r')
print("Processing file", param_str_file_name)
one_score = file_name.readline()
while one_score != "":
one_score_int = int(one_score)
num_rec = num_rec + 1
one_score = file_name.readline()
total += one_score_int
average = total / num_rec
file_name.close()
if num_rec == 0:
print("\tError!", param_str_file_name,
" is empty. Cannot calculate average\n")
else:
print("\tRecord count = ", num_rec)
print("\tTotal = ", total)
print("\tAverage = ", f"{average:.2f}", "\n")
except FileNotFoundError:
print("\tError!", param_str_file_name, " File not found\n")
except ValueError:
print("\tError!", param_str_file_name, "contains non-numeric data\n")
if __name__ == "__main__":
main()
It should work now. The output I get is:
Processing file good_data.txt
Record count = 6
Total = 281
Average = 46.83
Processing file bad_data.txt
Error! bad_data.txt contains non-numeric data
Processing file empty_file.txt
Error! empty_file.txt is empty. Cannot calculate average
Error! does_not_exist.txt File not found

From what i saw in your code the "if" on line 32 is not indented well, and the rest of the lines aswell cause of the error on the "if".
If you are using Visual Studio code and other programs they usually have a shortcut to format the code, per example on Visual Studio code if you press "Alt+Shift+F" it formats the code.
U should search for "Format Code Shortcut for ...." for the software you are using.

What causes this return() to create a SyntaxError?

I need this program to create a sheet as a list of strings of ' ' chars and distribute text strings (from a list) into it. I have already coded return statements in python 3 but this one keeps giving
return(riplns)
^
SyntaxError: invalid syntax
It's the return(riplns) on line 39. I want the function to create a number of random numbers (randint) inside a range built around another randint, coming from the function ripimg() that calls this one.
I see clearly where the program declares the list I want this return() to give me. I know its type. I see where I feed variables (of the int type) to it, through .append(). I know from internet research that SyntaxErrors on python's return() functions usually come from mistype but it doesn't seem the case.
#loads the asciified image ("/home/userX/Documents/Programmazione/Python projects/imgascii/myascify/ascimg4")
#creates a sheet "foglio1", same number of lines as the asciified image, and distributes text on it on a randomised line
#create the sheet foglio1
def create():
ref = open("/home/userX/Documents/Programmazione/Python projects/imgascii/myascify/ascimg4")
charcount = ""
field = []
for line in ref:
for c in line:
if c != '\n':
charcount += ' '
if c == '\n':
charcount += '*' #<--- YOU GONNA NEED TO MAKE THIS A SPACE IN A FOLLOWING FUNCTION IN THE WRITER.PY PROGRAM
for i in range(50):#<------- VALUE ADJUSTMENT FROM WRITER.PY GOES HERE(default : 50):
charcount += ' '
charcount += '\n'
break
for line in ref:
field.append(charcount)
return(field)
#turn text in a list of lines and trasforms the lines in a list of strings
def poemln():
txt = open("/home/gcg/Documents/Programmazione/Python projects/imgascii/writer/poem")
arrays = []
for line in txt:
arrays.append(line)
txt.close()
return(arrays)
#rander is to be called in ripimg()
def rander(rando, fldepth):
riplns = []
for i in range(fldepth):
riplns.append(randint((rando)-1,(rando)+1)
return(riplns) #<---- THIS RETURN GIVES SyntaxError upon execution
#opens a rip on the side of the image.
def ripimg():
upmost = randint(160, 168)
positions = []
fldepth = 52 #<-----value is manually input as in DISTRIB function.
positions = rander(upmost,fldepth)
return(positions)
I omitted the rest of the program, I believe these functions are enough to get the idea, please tell me if I need to add more.

You have incomplete set of previous line's parenthesis .
In this line:-
riplns.append(randint((rando)-1,(rando)+1)
You have to add one more brace at the end. This was causing error because python was reading things continuously and thought return statement to be a part of previous uncompleted line.

Please correct my code Python

I am trying to read from a file and return solutions based on the problem that the user inputs. I have saved the text file in the same location, that is not an issue. At the moment, the program just crashes when I run it and type a problem eg "screen".
Code
file = open("solutions.txt", 'r')
advice = []
read = file.readlines()
file.close()
print (read)
for i in file:
indword = i.strip()
advice.append (indword)
lst = ("screen","unresponsive","frozen","audio")
favcol = input("What is your problem? ")
probs = []
for col in lst:
if col in lst:
probs.append(col)
for line in probs:
for solution in advice:
if line in solution:
print(solution)
The text file called "solutions.txt" holds the following info:
screen: Take the phone to a repair shop where they can replace the damaged screen.
unresponsive: Try to restart the phone by holding the power button for at least 4 seconds.
frozen: Try to restart the phone by holding the power button for at least 4 seconds.
audio: If the audio or sound doesnt work, go to the nearest repair shop to fix it.

Your question reminds me a lot of my learning, so I will try give an answer to expand on your learning with lots of print statements to consider how it works carefully. It's not the most efficient or stable approach but hopefully of some use to you to move forwards.
print "LOADING RAW DATA"
solution_dictionary = {}
with open('solutions.txt', 'r') as infile:
for line in infile:
dict_key, solution = line.split(':')
print "Dictionary 'key' is: ", dict_key
print "Corresponding solution is: ", solution
solution_dictionary[dict_key] = solution.strip('\n')
print '\n'
print 'Final dictionary is:', '\n'
print solution_dictionary
print '\n'
print 'FINISHED LOADING RAW DATA'
solved = False
while not solved: # Will keep looping as long as solved == False
issue = raw_input('What is your problem? ')
solution = solution_dictionary.get(issue)
""" If we can find the 'issue' in the dictionary then 'solution' will have
some kind of value (considered 'True'), otherwise 'None' is returned which
is considered 'False'."""
if solution:
print solution
solved = True
else:
print ("Sorry, no answer found. Valid issues are 'frozen', "
"'screen' 'audio' or 'unresponsive'")
want_to_exit = raw_input('Want to exit? Y or N? ')
if want_to_exit == 'Y':
solved = True
else:
pass
Other points:
- don't use 'file' as a variable name anywhere. It's a python built-in and can cause some weird behaviour that you'll struggle to debug https://docs.python.org/2/library/functions.html
- If you get an error, don't say "crashes", you should provide some form of traceback e.g.:
a = "hello" + 2
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-1-6f5e94f8cf44> in <module>()
----> 1 a = "hello" + 2
TypeError: cannot concatenate 'str' and 'int' objects
your question title will get you down-votes unless you are specific about the problem. "help me do something" is unlikely to get a positive response because the error is ambiguous, there's no sign of Googling the errors (and why the results didn't work) and it's unlikely to be of any help to anyone else in the future.
Best of luck :)

When I change the line "for i in file:" to "for i in read:" everything works well.

To output only the line starting with "screen" just forget the probs variable and change the last for statement to
for line in advice:
if line.startswith( favcol ) :
print line
break
For the startswith() function refer to https://docs.python.org/2/library/stdtypes.html#str.startswith
And: the advices of roganjosh are helpfull. Particularly the one "please don't use python keywords (e.g. file) as variable names". I spent hours of debugging with some bugs like "file = ..." or "dict = ...".

python Printing One result per line

I show below part of a working script to verify twitter accounts that is giving me the results I want one besides the other, while I want to have them one per line including the title of the find
Example, the first three result are for followers, then how many others are being followed, and in how many lists the user is in, and its giving me the results all in one line something like this:
1350 257 27 and I want it to be as follows
Followers:1,350
Following: 257
Number of lists present: 27
I tried to use " ; " commas, "/n " ; but either it does not work or gives me a 500 Error
Here is the script
All help will be nice
Thank you
................
details = twitter.show_user(screen_name='xxxxxx')
print "content-type: text/html;charset=utf-8"
print
print"<html><head></head><body>"
print (details['followers_count']) #followers
print (details['friends_count'])# following
print (details['listed_count'])# In how many lists
... ....

Instead of the last three print lines, use string formatting to pass in the values.
print "Followers:{}\nFollowing: {}\nNumber of lists present: {}".format(
details['followers_count'], details['friends_count'], details['listed_count']
)

Take a look at the print function. You can write multiple arguments in a tab-separated line like:
print details['followers_count'], details['friends_count'], details['listed_count']
If you want more control over what you print use the join function:
# Add the parts you want to show
stringParts = []
for part in ['followers_count','friends_count','listed_count']:
stringParts.append( part + " = " + str(details[part]) )
seperator = "," # This will give you a comma seperated string
print seperator.join( stringParts )

You can use the % operator
print 'Followers: %s \nFollowing: %s \nNumber of lists present: %s' % (
details['followers_count'], details['friends_count'],
details['listed_count'])

Python/IPython strange non reproducible list index out of range error

I have recently been learning some Python and how to apply it to my work. I have written a couple of scripts successfully, but I am having an issue I just cannot figure out.
I am opening a file with ~4000 lines, two tab separated columns per line. When reading the input file, I get an index error saying that the list index is out of range. However, while I get the error every time, it doesn't happen on the same line every time (as in, it will throw the error on different lines everytime!). So, for some reason, it works generally but then (seemingly) randomly fails.
As I literally only started learning Python last week, I am stumped. I have looked around for the same problem, but not found anything similar. Furthermore I don't know if this is a problem that is language specific or IPython specific. Any help would be greatly appreciated!
input = open("count.txt", "r")
changelist = []
listtosort = []
second = str()
output = open("output.txt", "w")
for each in input:
splits = each.split("\t")
changelist = list(splits[0])
second = int(splits[1])
print second
if changelist[7] == ";":
changelist.insert(6, "000")
va = "".join(changelist)
var = va + ("\t") + str(second)
listtosort.append(var)
output.write(var)
elif changelist[8] == ";":
changelist.insert(6, "00")
va = "".join(changelist)
var = va + ("\t") + str(second)
listtosort.append(var)
output.write(var)
elif changelist[9] == ";":
changelist.insert(6, "0")
va = "".join(changelist)
var = va + ("\t") + str(second)
listtosort.append(var)
output.write(var)
else:
#output.write(str("".join(changelist)))
va = "".join(changelist)
var = va + ("\t") + str(second)
listtosort.append(var)
output.write(var)
output.close()
The error
---------------------------------------------------------------------------
IndexError Traceback (most recent call last)
/home/a/Desktop/sharedfolder/ipytest/individ.ins.count.test/<ipython-input-87-32f9b0a1951b> in <module>()
57 splits = each.split("\t")
58 changelist = list(splits[0])
---> 59 second = int(splits[1])
60
61 print second
IndexError: list index out of range
Input:
ID=cds0;Name=NP_414542.1;Parent=gene0;Dbxref=ASAP:ABE-0000006,UniProtKB%2FSwiss-Prot:P0AD86,Genbank:NP_414542.1,EcoGene:EG11277,GeneID:944742;gbkey=CDS;product=thr 12
ID=cds1000;Name=NP_415538.1;Parent=gene1035;Dbxref=ASAP:ABE-0003451,UniProtKB%2FSwiss-Prot:P31545,Genbank:NP_415538.1,EcoGene:EG11735,GeneID:946500;gbkey=CDS;product=deferrrochelatase%2C 50
ID=cds1001;Name=NP_415539.1;Parent=gene1036;Note=PhoB-dependent%2C 36
Desired output:
ID=cds0000;Name=NP_414542.1;Parent=gene0;Dbxref=ASAP:ABE-0000006,UniProtKB%2FSwiss-Prot:P0AD86,Genbank:NP_414542.1,EcoGene:EG11277,GeneID:944742;gbkey=CDS;product=thr 12
ID=cds1000;Name=NP_415538.1;Parent=gene1035;Dbxref=ASAP:ABE-0003451,UniProtKB%2FSwiss-Prot:P31545,Genbank:NP_415538.1,EcoGene:EG11735,GeneID:946500;gbkey=CDS;product=deferrrochelatase%2C 50
ID=cds1001;Name=NP_415539.1;Parent=gene1036;Note=PhoB-dependent%2C 36

The reason you're getting the IndexError is that your input-file is apparently not entirely tab delimited. That's why there is nothing at splits[1] when you attempt to access it.
Your code could use some refactoring. First of all you're repeating yourself with the if-checks, it's unnecessary. This just pads the cds0 to 7 characters which is probably not what you want. I threw the following together to demonstrate how you could refactor your code to be a little more pythonic and dry. I can't guarantee it'll work with your dataset, but I'm hoping it might help you understand how to do things differently.
to_sort = []
# We can open two files using the with statement. This will also handle
# closing the files for us, when we exit the block.
with open("count.txt", "r") as inp, open("output.txt", "w") as out:
for each in inp:
# Split at ';'... So you won't have to worry about whether or not
# the file is tab delimited
changed = each.split(";")
# Get the value you want. This is called unpacking.
# The value before '=' will always be 'ID', so we don't really care about it.
# _ is generally used as a variable name when the value is discarded.
_, value = changed[0].split("=")
# 0-pad the desired value to 7 characters. Python string formatting
# makes this very easy. This will replace the current value in the list.
changed[0] = "ID={:0<7}".format(value)
# Join the changed-list with the original separator and
# and append it to the sort list.
to_sort.append(";".join(changed))
# Write the results to the file all at once. Your test data already
# provided the newlines, you can just write it out as it is.
output.writelines(to_sort)
# Do what else you need to do. Maybe to_list.sort()?
You'll notice that this code is reduces your code down to 8 lines but achieves the exact same thing, does not repeat itself and is pretty easy to understand.
Please read the PEP8, the Zen of python, and go through the official tutorial.

This happens when there is a line in count.txt which doesn't contain the tab character. So when you split by tab character there will not be any splits[1]. Hence the error "Index out of range".
To know which line is causing the error, just add a print(each) after splits in line 57. The line printed before the error message is your culprit. If your input file keeps changing, then you will get different locations. Change your script to handle such malformed lines.