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I am trying to capture any alpha numeric character between ''
Regex
'(.*.doc)' will only capture .doc files.
'(\w)' should capture any alpha numeric character.
But I am looking to capture any character between '' except the ---- characters.
Here you can use the following regular expression: ([^\-\[\][\n']+)
An example:
regexr.com/5btcs
Is this good?
'[^'-]*'
Means a single ', then anything not ' or -, then another '.
If you wish to capture things around the dashes though, you might have to capture inclusively and filter them out.
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I have a string column like this and want to filter content between "/" character:
A
9/17/001.a.x.y.16.04451
006.b.021017006814
2/17/000.c.m.n.15.00668/008
And the expected output is
A
001.a.x.y.16.04451
006.b.021017006814
000.c.m.n.15.00668
How could i make it done with python/R/Mysql
Thank youuu
In MySQL, you can use regexp_replace():
select t.*,
regexp_replace(a, '^[^/]+/[^/]+/([^/]*)[/|^]', '$1')
from t;
The logic is that you seem to want the third component between slashes if there is one. Otherwise, you seem to want the entire string.
Here is a db<>fiddle.
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I have texts in an excel file that looks something like this:
alpha123_4rf
45beta_Frank
Red5Great_Sam_Fun
dan.dan_mmem_ber
huh_k
han.jk_jj
huhu
I am trying to use a regex to match all of these words and save them into a set().
I have tried r"(\w+..*?_.*?\w+)" as seen here . But cant seem to capture the word huhu that does not have special characters.
Your regex is capturing word that have a _ in them, and huhu don't.
You could change your regex to match every letter, number, underscore, and dots, multiple times.
([\w.]+)
I've fork your regex101
If you wish to match something more precise, you might need to give us more information about your context and what exactly you are trying to match.
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I am using scrapy to scrape the date that a comment was posted on a forum. I have been able to scrape the contents of the divider that contains the date, but it has escaped characters on both sides that make the string unusable. I need to create a regex expression which matches everything except for escaped characters.
The string I am working with is "\r\n\t\t\t\r\n\t\t\t\t08-07-2019, 11:37:16 AM\r\n\t\t\t\r\n\t\t\t\r\n\t\t\t". I want only to match the date inside.
The pattern that I was trying to use was (?<!\\\\)\\+[\\w-]+, as was recommended by other topics, but this doesn't match anything in that string.
You don't need regex if you want to match everything. I strongly recommend you to use Item Loaders in Scrapy to process your fields (using .strip() etc).
Also you can remove unwanted characters from your string using XPath normalize-space():
event_time = response.xpath('normalize-space(string(//YOUR/XPATH/HERE))').get()
But if you want to match part of a complex string you can use regular expresssion of course:
event_time = response.xpath('//YOUR/XPATH/HERE').re_first(r'(\d{2}-\d{2}-\d{4},\s+\d{2}:\d{2}:\d{2}\s+\w{2})')
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I work with Python 2.7. It is my first question here.
Here is my code:
import re
string = "0581111105822222749533333"
result = re.findall(r'058',string) # ['058', '058']
I want to add 5 digits after 058 and receive:
# ['05811111','05822222']
How to do this?
Thank you.
You can extract what you need using 058\d{5} pattern. This matches '058' characters and keeps extracting 5 digits after those.
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How can I match strings that are not inside a set of strings using python regular expressions?
Ex: set of strings ('/abc|/bcd')
I want to match any string other than that in the parentheses. That should be exact match.
Here's a fun one for you:
^(?!\/(?:abc|bcd)$).+
It uses a negative lookahead to ensure that the string being matched isn't one of the strings you don't want, then grabs whatever else is left.
Demo on Regex101