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Convert date string format to a datetime Python Object [duplicate]

This question already has answers here:
Convert string "Jun 1 2005 1:33PM" into datetime
(26 answers)
Closed 2 years ago.
i've one doubt.
I'm doing request to an API which return me event date. I was hope that date will be a timestamp, but i get this value:
{"date":"2020-08-24T21:15:00+00:00"}
I want to get a python datetime object.
How can I do that?

from datetime import datetime
dates = {"date":"2020-08-24T21:15:00+00:00"}
date = dates.get("date")
day = datetime.strptime(date, "%Y-%m-%dT%H:%M:%S+00:00")
Your looking for strptime.
Heres a good article:
https://www.programiz.com/python-programming/datetime/strptime

Use dateutil.parser which smartly parse date string:
import json
import dateutil.parser
result = '{"date":"2020-08-24T21:15:00+00:00"}'
x = json.loads(result)
dt = dateutil.parser.parse(x['date'])
# 2020-08-24 21:15:00+00:00
print(dt)
# <class 'datetime.datetime'>
print(type(dt))

I think you can do it respecting the format while parsing the string:
You have to try to follow the structure of the string and assign each value to the correct time value. For example:
str = '2018-06-29 08:15:27.243860'
time_obj = datetime.datetime.strptime(date_time_str, '%Y-%m-%d %H:%M:%S.%f')
Note that your case is pretty different.
It could be similar to '%Y-%m-%dT%H:%M:%S.f'

Python Convert date to datetime directly [duplicate]

This question already has answers here:
Convert date to datetime in Python
(14 answers)
Closed 2 years ago.
In Python, I convert a date to datetime by:
converting from date to string
converting from string to datetime
Code:
import datetime
dt_format="%d%m%Y"
my_date = datetime.date.today()
datetime.datetime.strptime(my_date.strftime(dt_format), dt_format)
I suspect this is far from the most efficient way to do this. What is the most efficient way to convert a date to datetime in Python?

Use datetime.datetime.combine() with a time object, datetime.time.min represents 00:00 and would match the output of your date-string-datetime path:
datetime.datetime.combine(my_date, datetime.time.min)
Demo:
>>> import datetime
>>> my_date = datetime.date.today()
>>> datetime.datetime.combine(my_date, datetime.time.min)
datetime.datetime(2013, 3, 27, 0, 0)

Alternatively, as suggested here, this might be more readable:
datetime(date.year, date.month, date.day)

How to convert a string to datetime object [duplicate]

This question already has answers here:
How do I parse an ISO 8601-formatted date?
(29 answers)
Closed 5 years ago.
With the time value being:
value = '2017-08-31T02:24:29.000Z'
I try to convert it to a datetime object with:
import datetime
datetime_object = datetime.datetime.strptime(value, '%Y-%b-%d %I:%M%p')
But the command crashes with the exception:
ValueError: time data '2017-08-31T02:24:29.000Z' does not match format '%Y-%b-%d %I:%M%p'

You should be using a builtin Python's datautil module instead of date time:
import dateutil.parser
value = '2017-08-31T02:24:29.000Z'
result = dateutil.parser.parse(value)

First of all, you are missing the formatter for the microsecond.
Second of all, there is no second colon for dividing the minute and second.
Third, the %b operator is for the monthname (Jan,Feb,etc.). You want to use %m.
Final format is '%Y-%m-%dT%I:%M:%S.%fZ'.
This is your code:
datetime_object = datetime.datetime.strptime(value, '%Y-%m-%dT%I:%M:%S.%fZ')
You should get 2017-08-31 02:24:29 as the value of datetime_object.

How to convert API timestamp into python datetime object [duplicate]

This question already has answers here:
How do I parse an ISO 8601-formatted date?
(29 answers)
Closed 8 years ago.
I am getting the following string from an API call:
s = '2014-12-11T20:46:12Z'
How would I then convert this into a python object? Is there an easy way, or should I be splitting up the string, for example:
year = s.split('-')[0]
month = s.split('-')[1]
day = s.split('-')[2]
time = s.split('T')[1]
...etc...

You can use the datetime.datetime.strptime function:
>>> from datetime import datetime
>>> s = '2014-12-11T20:46:12Z'
>>> datetime.strptime(s, '%Y-%m-%dT%H:%M:%SZ')
datetime.datetime(2014, 12, 11, 20, 46, 12)
>>>
For a complete list of the available format codes, see strftime() and strptime() Behavior.

Using datetime should do it, recently I found arrow is also a good library to deal with dates.
import arrow
s = '2014-12-11T20:46:12Z'
your_date = arrow.get(s)
print(t.year) # 2014
print(t.hour) # 20

convert string to date type python [duplicate]

This question already has answers here:
Python date string to date object
(9 answers)
Closed 9 years ago.
How do I convert a string to a date object in python?
The string would be: "30-01-12" (corresponding to the format: "%d-%m-%y")
I don't want a datetime.datetime object, but rather a datetime.date

You still use datetime.datetime but then request just the .date() portion:
datetime.datetime.strptime('30-01-12', '%d-%m-%y').date()
Demonstration:
>>> import datetime
>>> datetime.datetime.strptime('30-01-12', '%d-%m-%y').date()
datetime.date(2012, 1, 30)

This should work:
import datetime
s = "30-01-12"
slist = s.split("-")
sdate = datetime.date(int(slist[2]),int(slist[0]),int(slist[1]))

from datetime import datetime,date
date_str = '30-01-12'
formatter_string = "%d-%m-%y"
datetime_object = datetime.strptime(date_str, formatter_string)
date_object = datetime_object.date()