Hello I have a lot of text files
I want to change their contents to the same phrase. I tried this and it didn't work.
I want to read all the text files open them and change the content to just one same phrase.
import os
text_files = []
os.chdir(os.path.join("data"))
for filename in os.listdir(os.getcwd()):
if filename.endswith(".txt"):
text_files.append("data/" + filename)
with open(filename , "w") as outfile:
for text in text_files:
outfile.write("new content")
outfile.close()
os.chdir("..")
Please fix your indentation. As far as I have understood this is probably what you are trying to do:
import os
text_files = []
# get all file names that end with .txt
for filename in os.listdir("data"):
if filename.endswith(".txt"):
text_files.append(os.path.join("data" , filename))
# open each file and over-write the text "new content"
for file in text_files:
with open(file , "w") as outfile:
outfile.write("new content")
There are a few unnecessary lines of code in your code...
For example:
os.chdir(os.path.join("data"))
isn't neessasary as os.path.join("data") will simply return "data", so os.chdir("data") would have sufficed...
And then again, you can just do os.listdir("data") to get the list of files/folders in "data" without having to change your directory.
In fact, the code above can be simplified even more:
import os
for filename in os.listdir("data"):
if filename.endswith(".txt"):
with open(os.path.join("data" , filename) , "w") as outfile:
outfile.write("new content")
import os
os.chdir("data")
for filename in os.listdir(os.getcwd()):
if filename.endswith(".txt"):
with open(filename, "w") as outfile:
outfile.write("new content")
There's no need to use 'data/' in the path as you change into the directory.
You also don't need two for loops, your indentation is also off.
This works.
Related
It's clear for me how to open one file and it's pretty straight forward by using open() function just like this:
with open('number.txt', 'rb') as myfile:
data=myfile.read()
But what will be my actions if I want to open 5 .txt files and also view them as a string in Python? Should I somehow use os.listdir() possibilities?
Here a flexible/reusable approach for doing exactly what you need:
def read_files(files):
for filename in files:
with open(filename, 'rb') as file:
yield file.read()
def read_files_as_string(files, separator='\n'):
files_content = list(read_files(files=files))
return separator.join(files_content)
# build your files list as you need
files = ['f1.txt', 'f2.txt', 'f3.txt']
files_content_str = read_files_as_string(files)
print(files_content_str)
Looks like you need.
import os
path = "your_path"
for filename in os.listdir(path):
if filename.endswith(".txt"):
with open(os.path.join(path, filename), 'rb') as myfile:
data=myfile.read()
I need to read the contents of a file from the list of files from a directory with os.listdir. My working scriptlet is as follows:
import os
path = "/Users/Desktop/test/"
for filename in os.listdir(path):
with open(filename, 'rU') as f:
t = f.read()
t = t.split()
print(t)
print(t) gives me all the contents from all the files at once present in the directory (path).
But I like to print the contents on first file, then contents of the second and so on, until all the files are read from in dir.
Please guide ! Thanks.
You can print the file name.
Print the content after the file name.
import os
path = "/home/vpraveen/uni_tmp/temp"
for filename in os.listdir(path):
with open(filename, 'rU') as f:
t = f.read()
print filename + " Content : "
print(t)
First, you should find the path of each file using os.path.join(path, filename). Otherwise you'll loop wrong files if you change the variable path. Second, your script already provides the contents of all files starting with the first one. I added a few lines to the script to print the file path and an empty line to see where the contents end and begin:
import os
path = "/Users/Desktop/test/"
for filename in os.listdir(path):
filepath = os.path.join(path, filename)
with open(filepath, 'rU') as f:
content = f.read()
print(filepath)
print(content)
print()
os.listdir returns the name of the files only. you need to os.path.join that name with the path the files live in - otherwise python will look for them in your current working directory (os.getcwd()) and if that happens not to be the same as path python will not find the files:
import os
path = "/Users/Desktop/test/"
for filename in os.listdir(path):
print(filename)
file_path = os.path.join(path, filename)
print(file_path)
..
if you have pathlib at your disposal you can also:
from pathlib import Path
path = "/Users/Desktop/test/"
p = Path(path)
for file in p.iterdir():
if not file.is_file():
continue
print(file)
print(file.read_text())
My intention is to copy the text of all my c# (and later aspx) files to one final text file, but it doesn't work.
For some reason, the "yo.txt" file is not created.
I know that the iteration over the files works, but I can't write the data into the .txt file.
The variable 'data' eventually does contain all text from the files . . .
*******Could it be connected to the fact that there are some non-ascii characters in the text of the c# files?
Here is my code:
import os
import sys
src_path = sys.argv[1]
os.chdir(src_path)
data = ""
for file in os.listdir('.'):
if os.path.isfile(file):
if file.split('.')[-1]=="cs" and (len(file.split('.'))==2 or len(file.split('.'))==3):
print "Copying", file
with open(file, "r") as f:
data += f.read()
print data
with open("yo.txt", "w") as f:
f.write(data)
If someone has an idea, it will be great :)
Thanks
You have to ensure the directory the file is created has sufficient write permissions, if not run
chmod -R 777 .
to make the directory writable.
import os
for r, d, f in os.walk(inputdir):
for file in f:
filelist.append(f"{r}\\{file}")
with open(outputfile, 'w') as outfile:
for f in filelist:
with open(f) as infile:
for line in infile:
outfile.write(line)
outfile.write('\n \n')
Trying to extract all the zip files and giving the same name to the folder where all the files are gonna be.
Looping through all the files in the folder and then looping through the lines within those files to write on a different text file.
This is my code so far:
#!usr/bin/env python3
import glob
import os
import zipfile
zip_files = glob.glob('*.zip')
for zip_filename in zip_files:
dir_name = os.path.splitext(zip_filename)[0]
os.mkdir(dir_name)
zip_handler = zipfile.ZipFile(zip_filename, "r")
zip_handler.extractall(dir_name)
path = dir_name
fOut = open("Output.txt", "w")
for filename in os.listdir(path):
for line in filename.read().splitlines():
print(line)
fOut.write(line + "\n")
fOut.close()
This is the error that I encounter:
for line in filename.read().splitlines():
AttributeError: 'str' object has no attribute 'read'
You need to open the file and also join the path to the file, also using splitlines and then adding a newline to each line is a bit redundant:
path = dir_name
with open("Output.txt", "w") as fOut:
for filename in os.listdir(path):
# join filename to path to avoid file not being found
with open(os.path.join(path, filename)):
for line in filename:
fOut.write(line)
You should always use with to open your files as it will close them automatically. If the files are not large you can simply fOut.write(f.read()) and remove the loop.
You also set path = dir_name which means path will be set to whatever the last value of dir_name was in your first loop which may or may not be what you want. You can also use iglob to avoid creating a full list zip_files = glob.iglob('*.zip').
In the code below I'm trying to open a series of text files and copy their contents into a single file. I'm getting an error on the "os.write(out_file, line)" in which it asks me for an integer. I haven't defined what "line" is, so is that the problem? Do I need to specify somehow that "line" is a text string from the in_file? Also, I open the out_file through each iteration of the for-loop. Is that bad? Should I open it once at the beginning? Thanks!
import os
import os.path
import shutil
# This is supposed to read through all the text files in a folder and
# copy the text inside to a master file.
# This defines the master file and gets the source directory
# for reading/writing the files in that directory to the master file.
src_dir = r'D:\Term Search'
out_file = r'D:\master.txt'
files = [(path, f) for path,_,file_list in os.walk(src_dir) for f in file_list]
# This for-loop should open each of the files in the source directory, write
# their content to the master file, and finally close the in_file.
for path, f_name in files:
open(out_file, 'a+')
in_file = open('%s/%s' % (path, f_name), 'r')
for line in in_file:
os.write(out_file, line)
close(file_name)
close(out_file)
print 'Finished'
You're doing it wrong:
You did:
open(out_file, 'a+')
but that doesn't save the reference as a variable, so you have no way to access the file object you just created. What you need to do:
out_file_handle = open(out_file, 'a+')
...
out_file_handle.write(line)
...
out_file_handle.close()
Or, more pythonically:
out_filename = r"D:\master.txt"
...
with open(out_filename, 'a+') as outfile:
for filepath in files:
with open(os.path.join(*filepath)) as infile:
outfile.write(infile.read())
print "finished"