I'm dealing with this complex scenario, and I'm not quite sure how to proceed.
Context:
I have this situation:
class Cat(models.Model):
treats = models.ManyToManyFields(Treat)
class Treat(models.Model):
name = models.CharField()
This relation is a legacy one, there's already data in production.
Problem:
A new restriction has come up, in which the Treat model has to be moved to a new database.
That means, in short, I have to separate the constraint with treats from cat.
Proposal:
I've been told that, given my scenario, I have no choice but to implement a custom intermediate model to preserve the m2m but to also allow for the db_constraint=False. The suggestion was something like:
class Cat(models.Model):
treats = models.ManyToManyFields(Treat, through=CatTreat, related_name="cats")
class Treat(models.Model):
name = models.CharField()
class CatTreat(models.Model):
cat = models.ForeignKey(Cat)
treat = models.ForeignKey(Treat, db_constraint=False)
In my local stack, after running the migrations I've found myself that I can't access the data.
from apps.animals.models import Cat
cat = Cat.objects.first()
cat.treats
# => animals.Treat.None
cat.treats.through.objects.all()
# => <Queryset []>
I'm not sure if the new through access is not configured correctly or if I have inadvertently delete my data. Any insight is appreciated.
It turns out a little more configuration was needed.
In the through table, this was missing:
class CatTreat(models.Model):
cat = models.ForeignKey(Cat)
treat = models.ForeignKey(Treat, db_constraint=False)
class Meta:
db_column = "table_name"
cat.treats.all()
# => [...]
and that was it! I had to run the migration as fake though, in order to not lose any data.
Related
I am starting to create a webapp using Django and MongoDB. Everything is working fine when I create a model and save it into the Database. Now, I do a "Class.objects.get()" to get the object I need from my DB and I have one field called "media" which is a ListField(). I had tried doing either:
Concert.media.append(list)
or
Concert.media.extend(list)
and then
Concert.save()
This is my "Concert" object in my models.py:
class Concert(models.Model):
main_artist = models.CharField(max_length=50)
concert_id = models.AutoField(primary_key=True)
openers = ListField(EmbeddedModelField('Opener'))
concert_date = models.DateField()
slug = models.SlugField(unique=True)
media = ListField()
And when I go to see the results in does not update the object. No values where saved. If someone can help me I going to give a super cyber fist bump.
Concert is a class, not an instance. You can't save a class. You need to make an instance of the class and save that. Something like
c = Concert()
c.media.append(list)
c.save()
(btw, just as a note, list is a bad variable name because list is a type in python. Never use types as variable names (though everyone is guilty of this at one point or another, including me.))
When dealing whith model inheritance in django is it possible to remove a instance of model subclass, without removing the superclass itself?
Using the Django example, can you remove just the Resturaunt object and retain the Place object?
Yesterday I was looking for an answer to this question and I came up with this solution, which was enough for my problem but could be scaled up as needed.
Assuming you have a Restaurant and a Place django models, the way to delete a restaurant only without touching the row inside the Place's table is creating a "fake" Restaurant model like this:
class FakeRestaurant(models.Model):
place_ptr = models.PositiveIntegerField(db_column="place_ptr_id", primary_key=True)
serves_hot_dogs = models.BooleanField()
serves_pizza = models.BooleanField()
class Meta:
app_label = Restaurant._meta.app_label
db_table = Restaurant._meta.db_table
managed = False
Now, you can retrieve objects from that table as if it had no bound external relationship:
place = Place.objects.get(pk=1)
restaurant = Restaurant.objects.get(pk=1)
fake_restaurant = FakeRestaurant.objects.get(pk=1)
fake_restaurant.delete()
fake_restaurant and restaurant won't exist anymore, place will remain untouched.
Cheers,
Davide
In Django 1.9 parameter keep_parents was added to model delete() function, so to keep parents just call:
restaurant.delete(keep_parents=True)
Docs: https://docs.djangoproject.com/en/1.10/ref/models/instances/#django.db.models.Model.delete
UPDATE:
Apparently, this feature is not working properly in Django 1.9, please see the comments.
I'm building a personal project with Django, to train myself (because I love Django, but I miss skills). I have the basic requirements, I know Python, I carefully read the Django book twice if not thrice.
My goal is to create a simple monitoring service, with a Django-based web interface allowing me to check status of my "nodes" (servers). Each node has multiple "services". The application checks the availability of each service for each node.
My problem is that I have no idea how to represent different types of services in my database. I thought of two "solutions" :
single service model, with a "serviceType" field, and a big mess with the fields. (I have no great experience in database modeling, but this looks... "bad" to me)
multiple service models. i like this solution, but then I have no idea how I can reference these DIFFERENT services in the same field.
This is a short excerpt from my models.py file : (I removed everything that is not related to this problem)
from django.db import models
# Create your models here.
class service(models.Model):
port = models.PositiveIntegerField()
class Meta:
abstract = True
class sshService(service):
username = models.CharField(max_length=64)
pkey = models.TextField()
class telnetService(service):
username = models.CharField(max_length=64)
password = models.CharField(max_length=64)
class genericTcpService(service):
pass
class genericUdpService(service):
pass
class node(models.Model):
name = models.CharField(max_length=64)
# various fields
services = models.ManyToManyField(service)
Of course, the line with the ManyToManyField is bogus. I have no idea what to put in place of "*Service". I honestly searched for solutions about this, I heard of "generic relations", triple-join tables, but I did'nt really understand these things.
Moreover, English is not my native language, so coming to database structure and semantics, my knowledge and understanding of what I read is limited (but that's my problem)
For a start, use Django's multi-table inheritance, rather than the abstract model you have currently.
Your code would then become:
from django.db import models
class Service(models.Model):
port = models.PositiveIntegerField()
class SSHService(Service):
username = models.CharField(max_length=64)
pkey = models.TextField()
class TelnetService(Service):
username = models.CharField(max_length=64)
password = models.CharField(max_length=64)
class GenericTcpService(Service):
pass
class GenericUDPService(Service):
pass
class Node(models.Model):
name = models.CharField(max_length=64)
# various fields
services = models.ManyToManyField(Service)
On the database level, this will create a 'service' table, the rows of which will be linked via one to one relationships with separate tables for each child service.
The only difficulty with this approach is that when you do something like the following:
node = Node.objects.get(pk=node_id)
for service in node.services.all():
# Do something with the service
The 'service' objects you access in the loop will be of the parent type.
If you know what child type these will have beforehand, you can just access the child class in the following way:
from django.core.exceptions import ObjectDoesNotExist
try:
telnet_service = service.telnetservice
except (AttributeError, ObjectDoesNotExist):
# You chose the wrong child type!
telnet_service = None
If you don't know the child type beforehand, it gets a bit trickier. There are a few hacky/messy solutions, including a 'serviceType' field on the parent model, but a better way, as Joe J mentioned, is to use a 'subclassing queryset'. The InheritanceManager class from django-model-utils is probably the easiest to use. Read the documentation for it here, it's a really nice little bit of code.
I think one approach that you might consider is a "subclassing queryset". Basically, it allows you to query the parent model and it will return instances of the child models in the result queryset. It would let you do queries like:
models.service.objects.all()
and have it return to you results like the following:
[ <sshServiceInstance>, <telnetServiceInstance>, <telnetServiceInstance>, ...]
For some examples on how to do this, check out the links on the blog post linked below.
http://jazstudios.blogspot.com/2009/10/django-model-inheritance-with.html
However, if you use this approach, you shouldn't declare your service model as abstract as you do in the example. Granted, you will be introducing an extra join, but overall I've found the subclassing queryset to work pretty well for returning a mixed set of objects in a queryset.
Anyway, hope this helps,
Joe
If you are looking for generic foreign key relations you should check the Django contenttypes framework (built into Django). The docs pretty much explain how to use it and how to work with generic relations.
An actual service can only be on one node, right? In that case when not have a field
node = models.ForeignKey('node', related_name='services')
in the service class?
Howdy. I'm working on migrating an internal system to Django and have run into a few wrinkles.
Intro
Our current system (a billing system) tracks double-entry bookkeeping while allowing users to enter data as invoices, expenses, etc.
Base Objects
So I have two base objects/models:
JournalEntry
JournalEntryItems
defined as follows:
class JournalEntry(models.Model):
gjID = models.AutoField(primary_key=True)
date = models.DateTimeField('entry date');
memo = models.CharField(max_length=100);
class JournalEntryItem(models.Model):
journalEntryID = models.AutoField(primary_key=True)
gjID = models.ForeignKey(JournalEntry, db_column='gjID')
amount = models.DecimalField(max_digits=10,decimal_places=2)
So far, so good. It works quite smoothly on the admin side (inlines work, etc.)
On to the next section.
We then have two more models
InvoiceEntry
InvoiceEntryItem
An InvoiceEntry is a superset of / it inherits from JournalEntry, so I've been using a OneToOneField (which is what we're using in the background on our current site). That works quite smoothly too.
class InvoiceEntry(JournalEntry):
invoiceID = models.AutoField(primary_key=True, db_column='invoiceID', verbose_name='')
journalEntry = models.OneToOneField(JournalEntry, parent_link=True, db_column='gjID')
client = models.ForeignKey(Client, db_column='clientID')
datePaid = models.DateTimeField(null=True, db_column='datePaid', blank=True, verbose_name='date paid')
Where I run into problems is when trying to add an InvoiceEntryItem (which inherits from JournalEntryItem) to an inline related to InvoiceEntry. I'm getting the error:
<class 'billing.models.InvoiceEntryItem'> has more than 1 ForeignKey to <class 'billing.models.InvoiceEntry'>
The way I see it, InvoiceEntryItem has a ForeignKey directly to InvoiceEntry. And it also has an indirect ForeignKey to InvoiceEntry through the JournalEntry 1->M JournalEntryItems relationship.
Here's the code I'm using at the moment.
class InvoiceEntryItem(JournalEntryItem):
invoiceEntryID = models.AutoField(primary_key=True, db_column='invoiceEntryID', verbose_name='')
invoiceEntry = models.ForeignKey(InvoiceEntry, related_name='invoiceEntries', db_column='invoiceID')
journalEntryItem = models.OneToOneField(JournalEntryItem, db_column='journalEntryID')
I've tried removing the journalEntryItem OneToOneField. Doing that then removes my ability to retrieve the dollar amount for this particular InvoiceEntryItem (which is only stored in journalEntryItem).
I've also tried removing the invoiceEntry ForeignKey relationship. Doing that removes the relationship that allows me to see the InvoiceEntry 1->M InvoiceEntryItems in the admin inline. All I see are blank fields (instead of the actual data that is currently stored in the DB).
It seems like option 2 is closer to what I want to do. But my inexperience with Django seems to be limiting me. I might be able to filter the larger pool of journal entries to see just invoice entries. But it would be really handy to think of these solely as invoices (instead of a subset of journal entries).
Any thoughts on how to do what I'm after?
First, inheriting from a model creates an automatic OneToOneField in the inherited model towards the parents so you don't need to add them. Remove them if you really want to use this form of model inheritance.
If you only want to share the member of the model, you can use Meta inheritance which will create the inherited columns in the table of your inherited model. This way would separate your JournalEntry in 2 tables though but it would be easy to retrieve only the invoices.
All fields in the superclass also exist on the subclass, so having an explicit relation is unnecessary.
Model inheritance in Django is terrible. Don't use it. Python doesn't need it anyway.
I have a couple of models in django which are connected many-to-many. I want to create instances of these models in memory, present them to the user (via custom method-calls inside the view-templates) and if the user is satisfied, save them to the database.
However, if I try to do anything on the model-instances (call rendering methods, e.g.), I get an error message that says that I have to save the instances first. The documentation says that this is because the models are in a many-to-many relationship.
How do I present objects to the user and allowing him/her to save or discard them without cluttering my database?
(I guess I could turn off transactions-handling and do them myself throughout the whole project, but this sounds like a potentially error-prone measure...)
Thx!
I would add a field which indicates whether the objects are "draft" or "live". That way they are persisted across requests, sessions, etc. and django stops complaining.
You can then filter your objects to only show "live" objects in public views and only show "draft" objects to the user that created them. This can also be extended to allow "archived" objects (or any other state that makes sense).
I think that using django forms may be the answer, as outlined in this documentation (search for m2m...).
Edited to add some explanation for other people who might have the same problem:
say you have a model like this:
from django.db import models
from django.forms import ModelForm
class Foo(models.Model):
name = models.CharField(max_length = 30)
class Bar(models.Model):
foos = models.ManyToManyField(Foo)
def __unicode__(self):
return " ".join([x.name for x in foos])
then you cannot call unicode() on an unsaved Bar object. If you do want to print things out before they will be saved, you have to do this:
class BarForm(ModelForm):
class Meta:
model = Bar
def example():
f1 = Foo(name = 'sue')
f1.save()
f2 = foo(name = 'wendy')
f2.save()
bf = BarForm({'foos' : [f1.id, f2.id]})
b = bf.save(commit = false)
# unfortunately, unicode(b) doesn't work before it is saved properly,
# so we need to do it this way:
if(not bf.is_valid()):
print bf.errors
else:
for (key, value) in bf.cleaned_data.items():
print key + " => " + str(value)
So, in this case, you have to have saved Foo objects (which you might validate before saving those, using their own form), and before saving the models with many to many keys, you can validate those as well. All without the need to save data too early and mess up the database or dealing with transactions...
Very late answer, but wagtail's team has made a separate Django extension called django-modelcluster. It's what powers their CMS's draft previews.
It allows you to do something like this (from their README):
from modelcluster.models import ClusterableModel
from modelcluster.fields import ParentalKey
class Band(ClusterableModel):
name = models.CharField(max_length=255)
class BandMember(models.Model):
band = ParentalKey('Band', related_name='members')
name = models.CharField(max_length=255)
Then the models can be used like so:
beatles = Band(name='The Beatles')
beatles.members = [
BandMember(name='John Lennon'),
BandMember(name='Paul McCartney'),
]
Here, ParentalKey is the replacement for Django's ForeignKey. Similarly, they have ParentalManyToManyField to replace Django's ManyToManyField.