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conn.send('Hi'.encode()) BrokenPipeError: [Errno 32] Broken pipe (SOCKET)

hi i make model server client which works fine and i also create separate GUI which need to two input server IP and port it only check whether server is up or not. But when i run server and then run my GUI and enter server IP and port it display connected on GUI but on server side it throw this error. The Server Client working fine but integration of GUI with server throw below error on server side.
conn.send('Hi'.encode()) # send only takes string BrokenPipeError: [Errno 32] Broken pip
This is server Code:
from socket import *
# Importing all from thread
import threading
# Defining server address and port
host = 'localhost'
port = 52000
data = " "
# Creating socket object
sock = socket()
# Binding socket to a address. bind() takes tuple of host and port.
sock.bind((host, port))
# Listening at the address
sock.listen(5) # 5 denotes the number of clients can queue
def clientthread(conn):
# infinite loop so that function do not terminate and thread do not end.
while True:
# Sending message to connected client
conn.send('Hi'.encode('utf-8')) # send only takes string
data =conn.recv(1024)
print (data.decode())
while True:
# Accepting incoming connections
conn, addr = sock.accept()
# Creating new thread. Calling clientthread function for this function and passing conn as argument.
thread = threading.Thread(target=clientthread, args=(conn,))
thread.start()
conn.close()
sock.close()
This is part of Gui Code which cause problem:
def isOpen(self, ip, port):
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
try:
s.connect((ip, int(port)))
data=s.recv(1024)
if data== b'Hi':
print("connected")
return True
except:
print("not connected")
return False
def check_password(self):
self.isOpen('localhost', 52000)

Your problem is simple.
Your client connects to the server
The server is creating a new thread with an infinite loop
The server sends a simple message
The client receives the message
The client closes the connection by default (!!!), since you returned from its method (no more references)
The server tries to receive a message, then proceeds (Error lies here)
Since the connection has been closed by the client, the server cannot send nor receive the next message inside the loop, since it is infinite. That is the cause of the error! Also there is no error handling in case of closing the connection, nor a protocol for closing on each side.
If you need a function that checks whether the server is online or not, you should create a function, (but I'm sure a simple connect is enough), that works like a ping. Example:
Client function:
def isOpen(self, ip, port):
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
try:
s.connect((str(ip), int(port)))
s.send("ping".encode('utf-8'))
return s.recv(1024).decode('utf-8') == "pong" # return whether the response match or not
except:
return False # cant connect
Server function:
def clientthread(conn):
while True:
msg = conn.recv(1024).decode('utf-8') #receiving a message
if msg == "ping":
conn.send("pong".encode('utf-8')) # sending the response
conn.close() # closing the connection on both sides
break # since we only need to check whether the server is online, we break
From your previous questions I can tell you have some problems understanding how TCP socket communication works. Please take a moment and read a few articles about how to communicate through sockets. If you don't need live communications (continous data stream, like a video, game server, etc), only login forms for example, please stick with well-known protocols, like HTTP. Creating your own reliable protocol might be a little complicated if you just got into socket programming.
You could use flask for an HTTP back-end.

How to make a TCP server handle multiple clients?

I'm trying to make a Python server where multiple clients can connect but I've run into a problem I tried everything that I found on the internet.
I'm running a laptop whit windows 7 and an I3 processor.
This is the file called tcp:
import socket
def make_server (ip,port):
try:
server = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server.bind((ip, port))
server.listen(1)
return server
except Exception as ex:
print(ex)
return None
def accept(server):
conn, addr = server.accept()
return conn
def make_client():
client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
return client
def client_connect(client,ip,port):
client.connect((ip,port))
def sendall(conn,mess):
conn.send(str(mess).encode("utf-8"))
def rec(conn,rate):
mess = conn.recv(rate).decode("utf-8")
return mess
def close(client):
client.close()
This is the server:
from multiprocessing import Process
from random import randint
import tcp
import sys
def start(sip, sport):
print("Making sob server...")
print("id= {}".format(sport))
sserver = tcp.make_server(sip, sport)
print("Sub Server Started!")
sconn = tcp.accept(sserver)
tcp.sendall(sconn, "connected!!")
while True:
try:
tcp.sendall(sconn, randint(0, 100))
except Exception as ex:
print("")
print("From server {} error:".format(port))
print(ex)
print("")
break
ip = "192.168.0.102"
port = 8000
subport = 9000
server = tcp.make_server(ip, port)
if server is None:
sys.exit(0)
print("Started!")
while True:
print("Wating for new connection!")
con = tcp.accept(server)
print("Connected!")
subport = subport + 1
tcp.sendall(con, subport)
print("New Port Sent!")
print("New Port = {}".format(subport))
subs = Process(target=start, args=(ip, subport))
subs.start()
subs.join()
This is the client:
import tcp
import time
nport = 0
ip = "192.168.0.102"
port = 8000
client = tcp.make_client()
tcp.client_connect(client,ip,port)
nport = tcp.rec(client,1024)
print(nport)
tcp.close(client)
nport = int(nport)
time.sleep(1)
print(nport)
client = tcp.make_client()
tcp.client_connect(client,ip,nport)
while True:
mess = tcp.rec(client, 1024)
if(mess):
print(mess)
The error is:
[WinError 10048]Only one usage of each socket address (protocol/network address/port) is normally permitted Python
Feel free to change anything you want.
If you need any info in plus just ask.

You are creating a socket in the client with tcp.make_client. You are then using that socket to connect to the server via tcp.client_connect. Presumably you successfully receive the new port number back from the server. But then you are trying to re-use the same socket to connect to those ports.
This is the proximate cause of your error: A socket can only be used for a single TCP connection. If you want to create a new connection, you must first create a new socket.
That being said, if you are simply trying to create a server that will accept multiple connections, you're making it way too complicated. The server can receive any number of connections on its single listening port, as long as a different address/port combination is used by each client.
One way to structure this in a server is something like this:
# Create and bind listening socket
lsock = socket.socket()
lsock.bind(('', port))
lsock.listen(1)
while True:
csock, addr = lsock.accept()
print("Got connection from {}".format(addr))
# Start sub-process passing it the newly accepted socket as argument
subs = Process(target=start, args=(csock, ))
subs.start()
# Close our handle to the new socket (it will remain open in the
# sub-process which will use it to talk to the client)
csock.close()
# NOTE: do not call subs.join here unless you want the parent to *block*
# waiting for the sub-process to finish (and if so, what is the point in
# creating a sub-process?)
There are several others ways to do it as well: you can create multiple threads to handle multiple connections, or you can handle all connections in a single thread by using select or with asynchronous I/O.
The client is typically much simpler -- as it usually only cares about its own one connection -- and doesn't care which way the server is implemented:
sock = socket.socket()
sock.connect((ip, port))
while True:
sock.send(...)
sock.recv(...)
If the client does wish to connect to the same server again, it simply creates a second socket and call its connect method with the same server IP and port.
Usually, the client never needs to specify its own port, only the server's port. It simply calls connect and the client-side operating system chooses an unused port for it. So the first time, the client creates a socket and connects it (to the server's listening port), the client-side OS may choose port 50001. The next time it creates and connects a socket, it may get 50002 and so on. (The exact port numbers chosen depend on the operating system implementation and other factors, such as what other programs are running and creating connections.)
So, given client IP 192.168.0.101 and server IP 192.168.0.102, and assuming the server is listening on port 8000, this would result in these two connections:
(192.168.0.101/50001) ====> (192.168.0.102/8000)
(192.168.0.101/50002) ====> (192.168.0.102/8000)

Can`t connect to another PC via Python sockets

I'm trying to make communication via Internet between client and server, both written in Python. I have the next code for server:
def handle_client(clnt):
while True:
data = clnt.recv(1024)
if data:
print data,
del data
sock = socket.socket()
sock.bind(('0.0.0.0', 12345))
sock.listen(5)
while True:
client,addr = sock.accept()
print "[*] Accepted connection from: %s:%d" % (addr[0],addr[1])
# spin up our client thread to handle incoming data
client_handler = threading.Thread(target=handle_client,args=(client,))
client_handler.start()
client.close()
and for client:
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.connect(('my public IP-address', 12345))
sock.send('Some plain text')
When working with localhost, it works properly. After i have loaded it to my Ubuntu-14.04 server, which is not in the same local network, client doesn't want to connect. The output is:
socket.error: [Errno 10060] A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond
I have already created rule for server firewall, run server and client as administrator, disabled client antivirus, checked the Internet connection, pinged each other but it still doesn't seem to work throwing me the same error over and over again (the same error is shown if the server wasn't started).
Any ideas what`s wrong or how to fix this issue?

Errno 111: Connection refused only in python IDLE

When I try to execute Python server socket program and client socket program (both running in same linux machine) in Linux terminal I don't get any error, server accepts connection and sends data to client successfully.
But when I execute the same programs in python IDLE I get "[Errno 111] Connection refused" error.
What is the difference in both execution?
I'm using serversock.bind(('',port#)) in server
and in client i'm using clientsock.connect(('localhost',port#))
Server.py
import socket
serversock = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
host = ''
print host
port = 5800
serversock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
serversock.bind((host,port))
serversock.listen(2)
try:
while True:
csock,addr = serversock.accept()
print 'Recieved address from %s '% str(addr)
csock.send('hello')
csock.close()
except Exception,e:
print e
client.py
import socket
try:
c = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
host = 'localhost'
port = 5800
c.connect((host,port))
data = c.recv(1024)
print data
except Exception,e:
print e
finally:
c.close()

Server side you must use:
serversock.bind(('',port#)) # binds to port
serversock.listen(5) # actually listen to port and allow 5 incoming calls
conv = serversock.accept() # accept first incoming call
The connection will only be accepted after the listen call, before it, you have only bound a socket, but have not declared that you were ready to accept incoming calls, so they are refused.
With added code, another possible error cause is that you close connection (server side) immediately after sending data. That is bad: the close condition can destroy the socket before the data has actually been sent.
You should use a graceful shutdown:
server side:
csock.send('hello')
csock.shutdown(socket.SHUT_WR) # shutdown the socket
csock.read() # wait the close from peer
csock.close()
client side: you can leave the code as is in your use case you do not send anything to server, so when the client has finished reading it can safely close the socket
Anyway you should close serversock when everything is finished
try:
...
except ...:
...
finally:
serversock.close()

Python socket not accepting port as variable from api

I am running a socket script to wait for a connection using a port number from an api response
SELENIUMPORT = cont["Ports"][0]["PublicPort"]
I am converting it to an int using a function then I'm passing it to socket but it errors with
client.connect(('192.168.33.10',SELENIUMPORT))
socket.error: [Errno 111] Connection refused

ECONNREFUSED (111)
Connection refused. This error can occur during an attempt to connect a TCP socket. It is reported when a reset or an unexpected SYNC message is received.
I pretty sure that you are going to have to put that in try loop and wait for the other end to be listening.
Edit:
From your comments you are going to have to print out the SELENIUMPORT at the same time that you have that port number from the program that is supposedly listening to check that they are identical each time.
Arguably, testing by adding let's say 10 to the port number should give you an identical error, ie nothing is listening on the other end.
Short of that, create a script that does listen on a given port and test against that i.e.
import os, socket, time
address = ('localhost',32840)
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(address)
s.listen(1)
sc, client_address = s.accept()
while True:
print ("Connection made ", client_address)
n = 1
try:
data_recv = sc.recv(4096)
if len(data_recv) > 0:
print ("Received ", data_recv,n)
except:
print ("Disconnect")
break
Try running that and get your connection challenged code to connect to it or run something like:
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
address = ('localhost',32840)
s.connect(address)
s.sendall('mystuff')